Someone please help me

Answer:

Line Segment AB = -9.5

Line Segment CD = 2

Line Segment GE = 6.5

The midpoint of the segments using the number line are :

Recall the midpoint, M formula ;

M = (x1 + x2) ÷ 2

For the segments ;

A = -12 ; B = - 7

M = (A + B) / 2

M = (-12 + (-7)) / 2

M = (-12 - 7) / 2

M = - 19 / 2

M = - 9.5

C = -2 ; D = 6

M = (-2 + 6) / 2

M = (-2 + 6) / 2

M = 4 / 2

M = 2

A = -12 ; E = 10

M = (-12 + 10) / 2

M = - 2 / 2

M = - 1

G = 3 ; E = 10

M = (3 + 10) / 2

M = 13 / 2

M = 6.5

HENCE, THE midpoint of the segments AB, CD, AE and GE are - 9.5, 2, - 1 and 6.5 respectively .

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Answer:

19

Step-by-step explanation:

20% of 95 is 19 :)

Answer:

The probability that a point chosen at random will be in the shaded region is 0.25

Step-by-step explanation:

We have been given a small shaded circle inside a larger un-shaded circle. This is shown in the image attached below.

The area of smaller circle is 78.5 squares inches and the area of larger circle is 314 square inches. We have to find the probability that a point chosen at random will be in the shaded region.

Probability is defined as the ratio of Favorable outcome to the Total outcomes. In this case the favorable outcome is that the point should be inside the shaded region i.e. in an Area of 78.5 square inches. And the total outcome is that the point can be anywhere inside the larger circle i.e. within an Area of 314 square inches. Thus the probability that a point chosen at random will be inside the shaded region will be:

[tex]Probability =favorable-Outcome/total outcome[/tex]

[tex]=78.5/314[/tex]

[tex]=0.25[/tex]

Thus, the the probability that a point chosen at random will be in the shaded region is 0.25. This means there is a 25% chance that a randomly chosen point will be inside the shaded region.

Answer:

1000 meters³

Step-by-step explanation:

20 x 10 x 5 = 1000

the units are in meters and you are measuring the volume so the units is meters³

Volume of rectangular prism is 1000 [tex]m^{3}[/tex]

1000 [tex]m^{3}[/tex] of water can a bath tub hold.

"A rectangular prism can be defined as a 3-dimensional solid shape which has six faces that are rectangles. A rectangular prism is also a cuboid."

Given

Length of a bath tub = 20 m

Width of a bath tub = 10 m

Height of a bath tub = 5 m

Formula to find the volume of the rectangular prism

Volume of the rectangular prism = length × width × height

= 20 × 10 × 5

=200 × 5

V = 1000 [tex]m^{3}[/tex]

Volume of the rectangular prism = 1000 [tex]m^{3}[/tex]

Hence, Volume of rectangular prism is 1000 [tex]m^{3}[/tex]

1000 [tex]m^{3}[/tex] of water can a bath tub hold.

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Answer:

girlfriend

Step-by-step explanation:

Answer:

Answer is 74 square units

Step-by-step explanation:

I took the quiz.

Answer:

D: Jordy used a criterion that does not guarantee congruence.

Step-by-step explanation:

Looking at the various steps, in step five, it says;

ΔABE ≈ ΔBCD

The reason for that is given as;

Angle - Angle - Angle congruence

Now, in test for congruence, we use any of the following criteria;

SSS: Side - Side - Side

SAS: Side - Angle - Side

ASA: Angle - Side - Angle

AAS: Angle - Angle - Side

RHS: Right angle - Hypotenuse - Side

Now, AAA was used and it's not part of the criteria to be used for congruence.

AAA is not used because it's possible for 3 angles to be equal and yet the triangles not congruent.

Thus, we can conclude that Jordy used a criterion that does not guarantee congruence.

Answer: Jordy used a criterion that does not guarentee congruence

Step-by-step explanation: Khan Academy

Answer:

$130/4

Step-by-step explanation:

Answer:

18/30

Step-by-step explanation:

He has been out of town 18 out of the 30 days. You can simplify this to 6/10.

Answer: y(x) = (2/3)*(x + 1)^(3/2) + 1/3.

Step-by-step explanation:

We have the differential equation:

2*y'(x)*y''(x) = 1.

y(0) = 2

y'(0) = 1.

I will use the change:

u = y'

u'= y''

Then we must solve:

2*u*u' = 1.

The product does not depend on x:

u*u' = 1/2.

By looking at the problem, i know that the functions must be something like:

u = a*(x + b)^n

Where a and b are real numbers.

u' = n*a*(x + b)^(n - 1)

such that:

(x + b)^n*(x + b)^(n - 1) does not depend on x

This means that:

(x + b)^n*(x + b)^(n - 1)  = (x + b)^(n + n - 1) = 0

n + n - 1 = 0

2n = 1

n = 1/2

Then:

u = a*(x + b)^(1/2)

u' = (a/2)*(x + b)^(-1/2)

The differential equation becomes:

u*u' = 1/2

a*(x + b)^(1/2)* (a/2)*(x + b)^(-1/2) = 1/2

(1/2)*a^2 = 1/2

a^2 = 1.

And by the initial conditions, we have:

y'(0) = u(0) = 1

then:

u(0) = a*(0 + b)^(1/2) = a*b^(1/2) = 1

now, if a = -1, then b^(1/2) must be negative, this can not really be then we must have:

a = 1

u(0) = 1*b^(1/2) = 1

then b = 1.

u(x) = (x + 1)^(1/2).

And remember that y'(x) = u(x).

Then we need to integrate u(x) over x.

let's use the change of variables:

w = x +  1

dw = dx

Then the integration of u(x) is:

y(w) = ∫(w)^(1/2)dw = (2/3)*w^(3/2) + c

where c is a constant of integration.

now we can go back to x:

y(x) = (2/3)*(x + 1)^(3/2) + c

And we know that:

y(0) = 1 = (2/3)*(0 + 1)^(3/2) + c

         1 = (2/3)*1 + c

1 - 2/3 = c

     1/3 = c

Then:

y(x) = (2/3)*(x + 1)^(3/2) + 1/3.

Answer:

y=-2/5x+3

You subtract 2/5x from both Sides to get your answer

0.0375 did you mean 80÷3 if so 26.6

Answer:

Against the direction of the wind is [tex]x-10=35-10=25\ \text{mph}[/tex] and with the wind is [tex]x+10=35+10=45\ \text{mph}[/tex]

Step-by-step explanation:

Let x be the speed of the hawk in still air

The speed of the wind is 10 mph

So speed of the hawk when flying against the wind is [tex]x-10[/tex] and with the wind is [tex]x+10[/tex].

Distance the hawk travels when going against the wind is 50 miles and going with the wind is 90 miles

The hawk covers the above mentioned distances in the same amount of time.

[tex]\text{Time}=\dfrac{\text{Distance}}{\text{Speed}}[/tex]

[tex]\dfrac{50}{x-10}=\dfrac{90}{x+10}\\\Rightarrow \dfrac{50}{x-10}-\dfrac{90}{x+10}=0\\\Rightarrow \dfrac{50(x+10)-90(x-10)}{x^2-100}=0\\\Rightarrow 50x+500-90x+900=0\\\Rightarrow -40x+1400=0\\\Rightarrow x=\dfrac{1400}{40}\\\Rightarrow x=35\ \text{mph}[/tex]

The speed of the hawk in still air is 35 mph.

Speed of the hawk against the direction of the wind is [tex]x-10=35-10=25\ \text{mph}[/tex] and with the wind is [tex]x+10=35+10=45\ \text{mph}[/tex].

Answer:

17xn

Step-by-step explanation:

Answer:

8

Step-by-step explanation:

uh idrk all ik is that 16,000 punds = 8 tons

Answer:

Rise/Run= 1/2

Step-by-step explanation:

Answer:

Justin, Louise, Franklin

Step-by-step explanation:

The measure of the length of the sides BC of the rectangle will be 24 units.

Let L be the length and W be the width of the rectangle.

Then the perimeter of the rectangle will be

Perimeter of the rectangle = 2(L + W) units

The perimeter of the rectangle below is 174 units.

The length is 3z + 3 and the width is 4z.

Then the value of z will be

174 = 2(3z + 3 + 4z)

87 = 7z + 3

7z = 84

  z = 12

Then the measure of the length of the sides BC of the rectangle will be

BC = 3z + 3

BC = 3(7) + 3

BC = 21 + 3

BC = 24 units

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Answer:

The EOQ formula cannot be used here because the price of the goods varies according to the size of the purchase order. In this case, the order quantity that decreases annual inventory costs is 3,000 units per order, and total annual inventory costs = $89,060.67.

Step-by-step explanation:

if we apply the EOQ formula:

total annual inventory cost = [(6,500 / 348) x $28] + [(348 / 2) x $3] + (6,500 x $16) = $522.99 + $522 + $104,000

but if the company tried to benefit from discounts due to higher order quantities, total annual cost would be lower:

[(6,500 / 1,000) x $28] + [(1,000 / 2) x $3] + (6,500 x $14) = $182 + $1,500 + $91,000 = $92,682

[(6,500 / 3,000) x $28] + [(3,000 / 2) x $3] + (6,500 x $13) = $60.67 + $4,500 + $84,500 = $89,060.67

Answer:Is that the way the question was asked that's confusing

Step-by-step explanation:

Answer:

 A

Step-by-step explanation:

Step-by-step explanation:

Let second side = x

First side = 3+x

Third side = 3(3+x) = 9 +3x

The perimeter of a triangle = 25 cm

Perimeter = sum of all sides

So,

x + 3 + x + 9 +3x = 25

12 + 5x = 25

5x = 13

x = 2.6 cm

First side = 3 + x = 5.6 cm

Second side = x = 2.6 cm

Third side = 9+3(2.6) = 16.8 cm

Answer:

a)  P(X > 50.2) = 0.90

b) P(50.3 < X < 50.8) = 0.25

c) P(X+Y >29) = 0.9167

Step-by-step explanation:

From the given information:

[tex]f(x) = \dfrac{1}{b-a} \ \ \ \ a<x<b[/tex]

[tex]f(x) = \dfrac{1}{52.0-50.0} \ \ \ \ 50.0<x<52.0[/tex]

[tex]f(x) = \dfrac{1}{2} \ \ \ \ 50.0<x<52.0[/tex]

a)

Let X be the random variable that follows a uniform distribution.

Such that [tex]X \sim U (50.0, 52.0)[/tex]

where;

a = 50

b = 52

[tex]P(X> 50.2) = \dfrac{b - x}{b-a}[/tex]

[tex]P(X> 50.2) = \dfrac{52 - 50.2}{52-50}[/tex]

[tex]P(X> 50.2) = \dfrac{1.8}{2.0}[/tex]

P(X > 50.2) = 0.90

b.)

To find the probability that the class length is between 50.3 and 50.8 min.

i.e.

[tex]P(50.3 <X<50.8) = \dfrac{(X_2-X_1)}{(b-a)}[/tex]

[tex]P(50.3 <X<50.8) = \dfrac{(50.8-50.3)}{(52-50)}[/tex]

[tex]P(50.3 <X<50.8) = \dfrac{(0.5)}{(2)}[/tex]

P(50.3 < X < 50.8) = 0.25

c)

Given that:

the interval = (101,16)

The probability that the sum of 2 independent observations of X is greater than 29 can be computed as follows.

here;

[tex]c = \dfrac{a+b}{2}[/tex]

where;

a = 10*2 = 20

b = 16*2 = 32

[tex]c = \dfrac{20+32}{2}[/tex]

c = 52/2

c =26

The required probability:

[tex]P(X+Y >29) = 1 - \dfrac{(b-x)\times 2}{(b-a) \times (b - c)}[/tex]

[tex]P(X+Y >29) = 1 - \dfrac{(32-29)\times 2}{(32-20) \times (32 - 26)}[/tex]

[tex]P(X+Y >29) = 1 - \dfrac{(3)\times 2}{(12) \times (6)}[/tex]

[tex]P(X+Y >29) = 1 - \dfrac{6}{72}[/tex]

P(X+Y >29) = 1 - 0.0833

P(X+Y >29) = 0.9167

Answer:

X could be any number from 1-6

Step-by-step explanation:

Because 2 multiplied by 1-6 equals a number lower than 16