Sitting on a park bench, you see a swing that is 100 feet away and a slide that
is 60 feet away. The angle between them is 30°.
distance between the swing and the slide?
What is the approximate

Answer:

f(x)=9^(x)

Plugging in m+n+p=x, we have

f(m+n+p) = 9^(m+n+p)

Using the properties of exponential a^(b+c) = a^b*a^c, we have

f(m+n+p) = 9^(m)*9^(n)*9^(p)

f(m+n+p) = f(m)*f(n)*f(p)

Answer: The graph DOES represent a function.

Explanation: If you use a vertical line in the function and it only intersects once, that means it is a function. If it intersects twice, it is not a function.

See examples:

Answer:

BELOW IN BOLD.

Step-by-step explanation:

4/5 + 3/8

= 47 / 49 which id Rational

√100 + √5

= 10 + √5; - Irrational

7√5 - √245

=7√5 - 7√5

= 0  RATIONAL

Next one = 56 so Rational

Last one is Irrational

Choice A would be true if it was for 8 years, and not 8 months. The value of t is in years. We would need to convert 8 months to years like so

12 months = 1 year

1 month = 1/12 of a year

8 months = 8/12 of a year

8 months = 2/3 of a year after dividing both parts by 4

So we'll go for choice B as the final answer

Answer:

So, the degree of the polynomial 2x - 3 = 1.

Answer:

Step-by-step explanation:

Answer:

282.7 mi^2

Step-by-step explanation:

Surface area of cone=pi*r*(r+l)=pi*5*18=282.7

If [tex]P(x) = p_nx^n + p_{n-1}x^{n-1}+\ldots+p_0[/tex] is divided by [tex](x-a)[/tex], then [tex]P(x) = (x-a) \cdot Q(x) + R(x)[/tex] for some polynomials [tex]Q,R[/tex]. Moreover, [tex]\deg R < 1[/tex] (because [tex]\deg (x-a) = 1[/tex]), so there exists  [tex]\alpha \in \mathbb{R}[/tex] such that [tex]R(x) = \alpha[/tex] for all [tex]x \in \mathbb{R}[/tex]. But if we calculate [tex]P(a)[/tex], it turns out that [tex]P(a) = (a-a)\cdot Q(a) + \alpha[/tex], so [tex]R(x) = \alpha = P(a)[/tex]. [tex]\blacksquare[/tex]

Answer:

we can use 2 formule to solve your question: One is P*V=n(mol)*R*T(KELVIN)

Step-by-step explanation:

And other is P(first)*V(first)=P(last)*V(last)

8*22=16*?

the ?=11

Answer:

∠ ELM = 149°

Step-by-step explanation:

∠ KLM = ∠ KLE + ∠ ELM  , substitute values

17x - 1 = 20 + 15x - 1

17x - 1 = 15x + 19 ( subtract 15x from both sides )

2x - 1 = 19 ( add 1 to both sides  )

2x = 20 ( divide both sides by 2 )

x = 10

Then

∠ ELM = 15x - 1 = 15(10) - 1 = 150 - 1 = 149°

Answer:

$ 143000

Step-by-step explanation:

her net worth is her assets and income minus her debts and expenses

160000 + 45000 - 22000 - 40000 = 143000

Answer:

the answer is 4

Step-by-step explanation:

2+2

4

4+4: 8 -4 :4

Step-by-step explanation:

-1| 2/3 - 4| / 5/6

=-1 paxi ko sign k hola

Answer:

[tex]=\frac{1}{8568}\ = .00011\\\ =\frac{7}{8568} = .00081[/tex]

Step-by-step explanation:

[tex]5/18\cdot \:4/17\cdot \:3/16\cdot \:2/15\cdot \:1/14=\frac{1}{8568}[/tex]

x = 1 2 3 4 5

Rule:

x = (n+1)

Where n is the number

y = 5 7 9 11 13

Rule:

y = (n+2)

Where n is the number

Must click thanks and mark brainliest

Answer:

6.8 gallions i believe. im not quite sure

Answer:

365.7 km²

hopefully this answer can help you to answer the next question.

Answer:

vertical

Step-by-step explanation:

The line x = -5 includes all points where the value of x is -5, regardless of the value of y. This can be graphed as a vertical line going through (-5, 0), as the line represents the only place where x is the value -5.

Answer:

3300cm²

Step-by-step explanation:

30cm+30cm=60cm 60cm is the lengh of the whole joint structure.We will put it in the equation as "a".

heigh stays the same(10cm) because the pieces are not stacked one on top of the other.They are joined on their sides.We will put it as "c".

Widht also stays the same.its 15 cm and we will put it as letter "b".

So

a=60cm

b=15cm

c=10cm

We need to calculate the surface area of the entire joint structure.

1.First thing to do is to calculate the top part which is:

a*b=15*60=900cm²

2.The bootom side is the same 900cm².

3.The front side is:

a*c=60*10=600cm²

4.The back side is the same as front so it is 600cm².

5.The left side is:

c*b=10*15=150cm²

6.The right side is the same as the left and it is 150cm²

Now we just add it up.

S(surface)=900*2+600*2+150*2=3300cm²

If you want the whole exercise in one equation:

S=2*(a*b)+2*(a*c)+2*(b*c)

Answer:

a times 48

Step-by-step explanation:

a times 2 times p(6) times r(4)

2 times 6 is 12

multiply 12 by 4 to get 48

that is how you get a times 48

Answer:

4 cars fit for 12 students. and

2 vans fit for 16 students.

Answer:

6 students in each van.

Step-by-step explanation:

Having van as x variable and car as y variable.

3x + y = 22

2x + 4y = 28

Step 1: Solve for y in 3x + y =22

y = 22 - 3x

Step 2: Substitute y = 22 - 3x into 2x + 4y =28

2x + 4(22-3x) = 28

2x + 88 - 12x = 28

=> -10x + 88 = 28

Step 3: Solve for x (which is one van) in -10x + 88 = 28,

-10x = 28 - 88

-10x = -60

=> x = 6  

Thus, we have 6 students that can fit in each van.  

Answer:

[tex] = \frac{ - xy + {y}^{4} + {y}^{3} + {x}^{3}y + {x}^{3} - {x}^{2} }{x {y}^{3} + {xy}^{2} - {y}^{3} - {y}^{2} } [/tex]

Step-by-step explanation:

[tex]( \frac{x}{y} + \frac{y}{x - 1} ) + ( \frac{ {x}^{2} }{ {y}^{2} } - \frac{x}{y + 1} )[/tex]

[tex] \frac{xy \times (x - 1) \times (y + 1) + {y}^{3} \times (y + 1) + {x}^{2} \times (x - 1) \times (y + 1) - {xy}^{2} \times (x - 1)}{ {y}^{2} \times (x - 1) \times (y + 1)} [/tex]

[tex]\frac{( {x}^{2} y - xy) \times (y + 1) + {y}^{4} + {y}^{3} + ( {x}^{3} - {x}^{2} ) \times (y + 1) - {x}^{2} {y}^{2} + {xy}^{2} }{( {xy}^{2} - {y}^{2} ) \times (y + 1)}[/tex]

[tex] \frac{ {x}^{2} {y}^{2} + {x}^{2} y - {xy}^{2} - xy + {y}^{4} + {y}^{3} + {x}^{3} y + {x}^{3} - {x}^{2}y - {x}^{2} - {x}^{2} {y}^{2} + {xy}^{2} }{( {xy}^{3} + {xy}^{2} - {y}^{3} - {y}^{2} ) } [/tex]

[tex] = \frac{ - xy + {y}^{4} + {y}^{3} + {x}^{3}y + {x}^{3} - {x}^{2} }{x {y}^{3} + {xy}^{2} - {y}^{3} - {y}^{2} } [/tex]

Answer:

2

Step-by-step explanation:

[tex]{ \boxed{\boxed{\begin{array}{cc} \maltese  \bf \: given \: \\ \\ \rm \: d - \frac{1}{d} = 6 \\ \\ \bf \: now \\ \\ \rm {(d + \frac{1}{d} })^{2} = ( {d - \frac{1}{d} })^{2} + 4 \times d \times \frac{1}{d} \\ \\ = {6}^{2} + 4 \\ \\ = 36 + 4 \\ \\ = 40 \\ \\ \rm \: d + \frac{1}{d} = \pm \sqrt{40} \end{array}}}}[/tex]

Answer:

Step-by-step explanation:

Answer:

[tex]x = 34^\circ[/tex]

Step-by-step explanation:

Note that ∠TSU and ∠PSR are vertical angles. Hence:

[tex]m\angle TSU = m\angle PSR[/tex]

∠PSR is the sum of ∠PSQ and ∠QSR. Hence:

[tex]\displaystyle m\angle TSU = m\angle PSQ + m\angle QSR[/tex]

We know that ∠TSU measures 4x and ∠QSR measures 3x. Thus:

[tex](4x) = m\angle PSQ + (3x)[/tex]

Solve for ∠PSQ:

[tex]m\angle PSQ = x[/tex]

Next, ∠PQS and ∠RQS form a linear pair. Thus:

[tex]m\angle PQS + m\angle RQS = 180^\circ[/tex]

∠RQS measures 68°. Thus:

[tex]m\angle PQS +(68^\circ) = 180^\circ[/tex]

Solve for ∠PQS:

[tex]m\angle PQS = 112^\circ[/tex]

The interior angles of a triangle must total 180°. So, for ΔPQS:

[tex]\displaystyle m\angle SPQ + m\angle PQS + m\angle PSQ = 180^\circ[/tex]

Substitute in the known values:

[tex](x) + (112^\circ) + (x) = 180^\circ[/tex]

Simplify:

[tex]2x = 68^\circ[/tex]

And divide. Hence:

[tex]x = 34^\circ[/tex]

Answer:

A. Correct: When we plug in g(x) for the x in f(x), we get H(x).

B. Correct: When we plug in g(x) for the x in f(x), we get H(x).

C. Correct: When we plug in g(x) for the x in f(x), we get H(x).

D. Correct: When we plug in g(x) for the x in f(x), we get H(x).

Step-by-step explanation:

Brainliest, please!

Answer:

10. x is 15; y is \sqrt104. 11. \sqrt5

Step-by-step explanation:

for 10:

first we find the face on the left side; which according to the pythagorean theorem x is 144 + 81 =225 = x = 15. and y is 11^2 + y^2 = 225 = 225 - 121 = y^2 = y = the square root of 104.

for 11:

144 + y^2 = 169 = y^2 = 25 = y = 5. because the two sides are equivalent, the base is also 5 for the left part of the triangle. therefore, 5^2 + 5^2 = x^2 which means x is the square root of 5.

Answer:

(4, 1)

Step-by-step explanation:

See attachment courtesy of Desmos.