PLEASEE HELP ME ASAPPP (geometry)

Answer:

An ordered pair for a function f(x) looks like (x, f(x)). So the ordered pair here would be (5, f(5)) or (5, 7). Either one would work, as they are the same.

Answer:

9 − (3 x 2) ÷ 3 + 6 is the answer

Answer:

A. If the side lengths are the same, then a triangle is not scalene.

Step-by-step explanation:

A triangle can be defined as a two-dimensional shape that comprises three (3) sides, three (3) vertices and three (3) angles.

Simply stated, any polygon with three (3) lengths of sides is a triangle.

In Geometry, a triangle is considered to be the most important shape.

Generally, there are three (3) main types of triangle based on the length of their sides and these include;

I. Equilateral triangle: it has all of its three (3) sides and interior angles equal.

II. Isosceles triangle: it has two (2) of its sides equal in length and two (2) equal angles.

III. Scalene triangle: it has all of its three (3) sides and interior angles different in length and size respectively.

Let number if boys be x

ATQ

[tex]\\ \sf\longmapsto \dfrac{x+5}{x}=\dfrac{4}{3}[/tex]

[tex]\\ \sf\longmapsto 3(x+5)=4x[/tex]

[tex]\\ \sf\longmapsto 3x+15=4x[/tex]

[tex]\\ \sf\longmapsto 4x-3x=15[/tex]

[tex]\\ \sf\longmapsto x=15[/tex]

[tex]\\ \sf\longmapsto x+5=15+5=20[/tex]

Answer:

r3jehejn wbbwbwbbwmwkwkwjwjwhhejehehehhe

Answer:

1 hour and 40 minutes

Step-by-step explanation:

→ Convert 3 hr and 25 minutes to minutes

( 3 × 60 ) + 25 = 205 minutes

→ Convert 1 hr and 45 minutes to minutes

( 1 × 60 ) + 45 = 105 minutes

→ Minus the answers from each other

205 - 105 = 100 minutes

→ Convert 100 minutes to hours and minutes

1 hour and 40 minutes

Answer:

Qualitative data

Neither discrete or continous

Ordinal

Step-by-step explanation:

Qualitative data simply refers to Non-numeric measure, they make use of data labels which are expressed in words rather than figures or numbers.

For a data to be either discrete or continous, then it has to be numeric, since the data is qualitative and non- numeric, then it is neither continous or discrete.

This is an ordinal scale representation of data as data are ordered or ranked in terms of performance, however, there is no measure of difference between each rank or order. The highest level of performance in the scale is Excellent.

Answer:

3/4

Step-by-step explanation:

add the no. of red marbles and blue marbles

2+4 = 6

Probability so divide 6/8 simplified to 3/4

Answer:

(0.089 ; 0.151)

Step-by-step explanation:

Given :

Sample size, n = 300

Number of defective items, x = 36

The confidence interval required here is that for a one sample proportion :

The confidence interval is defined thus :

Phat ± Zcritical * √[Phat(1 - phat) / n]

Zcritical at 90% = 1.645

Phat = x / n = 36 / 300 = 0.12

Hence,

C.I = 0.12 ± 1.645 * √[0.12(1 - 0.12) / 300]

C.I = 0.12 ± (1.645 * 0.0187616)

C.I = 0.12 ± 0.0308629

C.I = (0.089 ; 0.151)

Answer:

28°C

Step-by-step explanation:

First you do 3*19=57°C

-5+57= 52°C

then you do 4*6=24 °C

as its being cooled you takeaway

52-24=28°C

Answer:

Lines 'p' and 'q' are parallel I believe!

Step-by-step explanation:

They are the only two lines relating to angles 8 and 11 of the three listed pairs.

Answer:

p and q are parallel

Step-by-step explanation:

Given:

The figures of two polygons.

To find:

Whether the polygons are similar and then find the scale factor (if similar).

Solution:

From the given figures it is clear that both polygons are rectangles and their all interior angles are right angles.

The ratio of their longer sides:

[tex]\dfrac{32}{26}=\dfrac{16}{13}[/tex]

The ratio of their shorter sides:

[tex]\dfrac{18}{12}=\dfrac{3}{2}[/tex]

Since the ratio of their corresponding sides are not equal, therefore the two polygons are not similar.

Therefore the required solutions are:

Similar : No

Similarity statement : None

Scale factor : None

Answer:

22hrs

Step-by-step explanation:

hope it is well understood?

Answer:

q = [tex]\sqrt{2}[/tex]

Step-by-step explanation:

Using the sine ratio in the right triangle and the exact value

sin30° = [tex]\frac{1}{2}[/tex] , then

sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{q}{2\sqrt{2} }[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )

2q = 2[tex]\sqrt{2}[/tex] ( divide both sides by 2 )

q = [tex]\sqrt{2}[/tex]

Answer:

24

Step-by-step explanation:

(4+8)×4/2

= 12×4/2

= 24

Answered by GAUTHMATH

Answer: y = x - 7

Slope intercept form: y = mx + b

[tex]2x-2y=14\\\\-2y=-2x+14\\\\y=\frac{-2x+14}{-2} =\frac{-2(x-7)}{-2} =x-7[/tex]

Answer:

√9 × √6

√54

√27 × √2

Step-by-step explanation:

We can obtain the answer to the question given above as illustrated below:

3√6

Recall

a√b = √(a×a×b)

Thus,

3√6 = √(3×3×6)

3√6 = √(9 × 6)

Recall

√(a × b) = √a × √b

√(9 × 6) = √9 × √6

Therefore,

3√6 = √9 × √6

Recall

√9 × √6 = √(9 × 6)

√9 × √6 = √54

Thus,

3√6 = √54

Recall

√54 = √(27 × 2)

√54 = √27 × √2

Therefore,

3√6 = √27 × √2

Therefore,

3√6 = √9 × √6 = √54 = √27 × √2

Answer:

3

256

sq.units

Step-by-step explanation:

Both parabolas cut each other at (0,0) and (16,16)

Area enclosed by these parabolas

=∫

0

16

4

x

dx−∫

0

16

16

x

2

dx

=[

3

2×4×x

3/2

]

0

16

−[

16×3

x

3

]

0

16

=

3

2×4

4

−

3

4

4

=

3

256

sq. units

Answer.

ANSWER

.......

Answer:

Step-by-step explanation:

The ratios of the numbers in the sequence 5, 10, 20, 50 are 2, 2, 2.5. That is, the ratios are not constant. Hence the sequence is not geometric.

Answer:

76K would find this fake but.....

Step-by-step explanation:

Non geometrical

Answer:

?

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

Answer:

[tex]{ \sf{thats \: it}}[/tex]

Answer:

y=-2x+7

Step-by-step explanation:

The Slope is obviously -2, and just add a random y and play around with it until it goes through the point (5,-3)

Answer:

19.5

Step-by-step explanation:

let burger be x and fries be y

2x+y = 6.5

6x+3y = 3(2x+y) =3(6.5) =19.5

Answer:

length = 20 inches

width = 13 inches

Step-by-step explanation:

l = length

w = width

area = l×w

perimeter = (2×l) + (2×w)

l = w + 7

l×w = 4×(2×l + 2×w) - 4

(w+7)×w = 4×(2×(w+7) + 2×w) - 4

w² + 7w = 4×(2w + 14 + 2w) - 4

w² + 7w = 8w + 56 + 8w - 4 = 16w + 52

w² - 9w - 52 = 0

the solution for a quadratic equation is

x = (-b ± sqrt(b² - 4ac))/(2a)

here we use now w instead of x.

and a=1

b=-9

c=-52

w = (9 ± sqrt(81 - -208))/2 = (9 ± sqrt(81+208))/2 =

= (9 ± sqrt(289))/2 = (9 ± 17)/2

w1 = (9+17)/2 = 26/2 = 13

w2 = (9-17)/2 = -8/2 = -4

and a negative length does not make any sense for a geometric shape.

so, only w1 = 13 applies.

l = w + 7 = 13 + 7 = 20

log₉(x - 7) + log₉(x - 7) = 1

2 log₉(x - 7) = 1

log₉(x - 7) = 1/2

Take the base-9 antilogarithm of both sides; in other words, make both sides powers of 9:

[tex]9^{\log_9(x-7)} = 9^{1/2}[/tex]

[tex]9^{1/2}[/tex] can also be written as √9 = 3, and [tex]b^{\log_b(a)}=a[/tex], so the equation reduces to

x - 7 = 3

Solve for x :

x = 10

You're looking for a solution in the form

[tex]y(x) = \displaystyle \sum_{n=0}^\infty a_nx^n[/tex]

Differentiating, we get

[tex]y'(x) = \displaystyle \sum_{n=0}^\infty na_nx^{n-1} = \sum_{n=1}^\infty na_nx^{n-1} = \sum_{n=0}^\infty (n+1)a_{n+1}x^n[/tex]

[tex]y''(x) = \displaystyle \sum_{n=0}^\infty (n+1)na_{n+1}x^{n-1} = \sum_{n=1}^\infty (n+1)na_{n+1}x^{n-1} = \sum_{n=0}^\infty (n+2)(n+1)a_{n+2}x^n[/tex]

Substitute these for y' and y'' in the differential equation:

[tex]\displaystyle \sum_{n=0}^\infty (n+2)(n+1)a_{n+2}x^n - \sum_{n=0}^\infty (n+1)a_{n+1}x^n = 0[/tex]

[tex]\displaystyle \sum_{n=0}^\infty \bigg((n+2)(n+1)a_{n+2}-(n+1)a_{n+1}\bigg)x^n = 0[/tex]

Then the coefficients of y are given by the recurrence

[tex]\begin{cases}a_0=y(0)\\a_1=y'(0)\\a_{n+2}=\frac{a_{n+1}}{n+2}&\text{for }n\ge0\end{cases}[/tex]

or

[tex]a_n = \dfrac{a_{n-1}}n[/tex]

But we cannot assume that [tex]a_0[/tex] and [tex]a_1[/tex] depend on each other; we can only guarantee that the recurrence holds for n ≥ 1, so that

[tex]a_2=\dfrac{a_1}2 \\\\ a_3=\dfrac{a_2}3=\dfrac{a_1}{3\times2} \\\\ a_4=\dfrac{a_3}4=\dfrac{a_1}{4\times3\times2} \\\\ \vdots \\\\ a_n=\dfrac{a_1}{n!}[/tex]

So in the power series solution, we split off the constant term and we're left with

[tex]y(x) = a_0 + a_1 \displaystyle \sum_{n=1}^\infty \frac{x^n}{n!}[/tex]

so that the fundamental solutions are

[tex]y_1=1[/tex]

and

[tex]y_2=x+\dfrac{x^2}{2!}+\dfrac{x^3}{3!}+\dfrac{x^4}{4!}+\cdots[/tex]

Answer:

The two roots a+√b and a-√b are called Conjugate radicals

Step-by-step explanation:

I'd really appreciate a brainleast:)