Step-by-step explanation:
soln no. k
LHS: cosø√1+cot^2ø
= cosø×cosecø
= cosø× 1/sinø
= cosø/sinø
= cotø
=√cosec^2-1. [: cot^2ø=cosec^2ø-1
according to equation
sending the (^2) will be
root over in another Sid]
= RHS proved
for number m take the help of the pic
1.) You plan to cut a board into 3 pieces to repair part of a railing. You are going to cut the two ends of the board off into two equal pieces that are 1.4 feet long, if the remaining piece needs to be 1.17 times longer than the each of the first two cuts what length board should you buy? Round to the nearest tenth.
The board length that will be bought is 4.438 feet
Since the board will be cut into 3 pieces. From the information given in the question, the lengths of the board will be:
= 1.4 feet + 1.4 feet + (1.17 × 1.4 feet)
= 1.4 feet + 1.4 feet + 1.638 feet
= 4.438 feet
In conclusion, the board length that should be bought is 4.438 feet.
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Given f(x) = 3x + 2 and g(x) = 2x - 1, find (g(x))2.
1- 2x2 - 4x + 1
2- 6x²+x-2
3- 4x2 - 4x + 1
4- 9x2 + 12x + 4
Helpppp plzzz
Answer:
C (if the sign after the digit 1,2,3,4 is not minus !!!)
Step-by-step explanation:
[tex]f(x)=3x+2\\\\g(x)=2x-1\\\\\\g^2(x)=(gog)(x)=g(g(x)=g(2x-1)=2(2x-1)-1=4x-2-1=4x-3\\\\\\if \ you\ means \ g(x)*g(x)\ then\\\\(g(x))^2=(2x-1)^2=4x^2-4x+1:\ answer \ C[/tex]
Solve the equation for x and y
Answer:
Step-by-step explanation:
15x + 6y = 0
4x - 6y = -38
19x = -38
x = -2
2(-2) - 3y = -19
-4 - 3y = -19
-3y = -15
y = 5
(-2, 5)
A tank initially has 300 gallons of a solution that contains 50 lb. of dissolved salt. A brine solution with a concentration of 2lb of salt/gallon is admitted into the tank at a rate of 6 gallons per minute. The well-stirred solution is drained at the same rate. How long will it take for the tank to have 100 lb. of dissolved salt
Let s(t) be the amount of salt in the tank at time t. Then s(0) = 50 lb.
Salt flows into the tank at a rate of
(2 gal/min) (6 lb/gal) = 12 lb/min
and flows out at a rate of
(2 gal/min) (s(t)/300 lb/gal) = s(t)/150 lb/min
so that the net rate at which salt is exchanged through the tank is
ds(t)/dt = 12 - s(t)/150 … (lb/min)
Solve for s(t). The DE is separable, so we have
ds/dt = 12 - s/150
150 ds/dt = 1800 - s
150/(1800 - s) ds = dt
Integrate both sides to get
-150 ln|1800 - s| = t + C
Solve for s :
ln|1800 - s| = -t/150 + C
1800 - s = exp(-t/150 + C )
1800 - s = C exp(-t/150)
s = 1800 - C exp(-t/150)
Now given that s(0) = 50, we solve for C :
50 = 1800 - C exp(-0/150)
50 = 1800 - C
C = 1750
Then the amount of salt in the tank at any time t ≥ 0 is
s(t) = 1800 - 1750 exp(-t/150)
To find the time it takes for the tank to hold 100 lb of salt, solve for t in
100 = 1800 - 1750 exp(-t/150)
1700 = 1750 exp(-t/150)
34/35 = exp(-t/150)
ln(34/35) = -t/150
t = -150 ln(34/35) ≈ 4.348
So it would take approximately 4.348 minutes.
By the way, we didn't have to solve for s(t), we could have instead stopped with
-150 ln|1800 - s| = t + C
Solve for C - this C is not the same as the one we found using the other method. s(0) = 50, so
-150 ln|1800 - 50| = 0 + C
C = -150 ln|1750|
==> t = 150 ln(1750) - 150 ln|1800 - s|
Then s(t) = 100 lb when
t = 150 ln(1750) - 150 ln(1700)
t = 150 ln(1750/1700)
t = 150 ln(35/34)
t ≈ 4.348
Plz answer this is important
Answer:
78.5714
Step-by-step explanation:
given,
radius=5cm
now,
area of circle (A)=
[tex] = \frac{22}{7} \times {5}^{2} \\ \\ \\ = \frac{22}{7} \times 25 \\ \\ = 78.5714 {cm}^{2} [/tex]
Please help! :)
An expression is shown below:
10n3 − 15n2 + 20xn2 − 30xn
Part A: Rewrite the expression by factoring out the greatest common factor. (4 points)
Part B: Factor the entire expression completely. Show the steps of your work. (6 points)
The completely factored expression of 5n²(2n − 3) + 10x(2n − 3) is (5n²+ 10x)(2n − 3)
Rewrite the expressionThe expression is given as:
10n³ − 15n² + 20xn² − 30xn
Factor out 5n² and 10xn in the expression
5n²(2n − 3) + 10x(2n − 3)
Factor completelyIn (a), we have:
5n²(2n − 3) + 10x(2n − 3)
Factor out 2n - 3
(5n²+ 10x)(2n − 3)
Hence, the completely factored expression of 5n²(2n − 3) + 10x(2n − 3) is (5n²+ 10x)(2n − 3)
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Need help, only provide the answer
Answer:
<R = 30 degrees
LM = 6 sqrt(3)
Step-by-step explanation:
RST = LMN
We know that angle R equals angle L
<L = 30 degrees so <R = 30 degrees
Side RS = side LM
RS = 6 sqrt(3) so LM = 6 sqrt(3)
ILL MARK BRAINIEST IF YOU DO THIS CORRECTLY!!!
Answer:
55%
Step-by-step explanation:
solve for x.
x=
please help me I need this !!!!!!!! !
Answer:
Step-by-step explanation:
Can you Help me on 23 ?
Answer:
x is 11
Step-by-step explanation:
[tex]{ \sf{ \sqrt{x + 5} - 3 = 1}} \\ { \sf{ \sqrt{x + 5} = 4 }} \\ { \sf{x + 5 = 16}} \\ { \sf{x = 11}}[/tex]
Answer:
[tex]x = 11[/tex]
Step-by-step explanation:
[tex] \sqrt{x + 5} −3=1[/tex]
[tex] \sqrt{x + 5} = 1 + 3[/tex]
[tex] \sqrt{ {x} + 5 } = 4[/tex]
[tex] \sqrt{x + {5}^{2} } = {4}^{2} [/tex]
[tex]x + 5 = 16[/tex]
[tex]x = 16 - 5[/tex]
[tex]x = 11[/tex]
Hope it is helpful....a.convert 150 grades into degree
b.find x and y if : (x+3,4) = (6,y)
c.one angle of a right angled triangle is 60 grades. Find the other angles in degree
Answer:
Hope it helps
Step-by-step explanation:
a)= 1 grade = 9/10 degree
150 = 9/10 × 150 degree
= 135 degree
b ) = solution
x+3 = 6
so, x = 3
y = 4
c) = let the unknown angle be x
now,
converting 60 grades into degree
= 60×9/10
= 54°
now
54° + 90° + x = 180°
144°-180° = -x
so, x = 36°
the sum of three consecutive even integers is 312. Find the integers
Answer:
Therefore, three consecutive integers that add up to 312 are 103, 104, and 105. We know our answer is correct because 103 + 104 + 105 equals 312 as displayed above
Answer:
102, 104, 106
Step-by-step explanation:
If each number is an even integer, then the one's place must be an even number like 2 4 6. 102 + 104 + 106 = 312
Which of the following is the domain of the function based on the input-
output table below?
Answer:
C
Step-by-step explanation:
The domain of the function is the left column of the table, {5,10,15,20,25,30,35}
The admission fee at an amusement park is $3.50 for children and $6.80 for adults. On a certain day, 223 people entered the park, and the admission fees collected totaled 1160 dollars. How many children and how many adults were admitted?
Answer:
108 children and 115 adults were admitted
Step-by-step explanation:
Create a system of equations where c is the number of children admitted and a is the number of adults admitted:
c + a = 223
3.5c + 6.8a = 1160
Solve by elimination by multiplying the top equation by -3.5:
-3.5c - 3.5a = -780.5
3.5c + 6.8a = 1160
Add the equations together and solve for a:
3.3a = 379.5
a = 115
So, 115 adults were admitted.
Find how many children were admitted by subtracting 115 from 223, the total number of people admitted:
223 - 115
= 108
108 children and 115 adults were admitted.
Appreciate answers and any help!
Logan wants to know how many skateboards have defective parts. He inspects 20,000 skateboards and keeps track of the number of defects per board. Use his probability distribution table to find the expected value for defects on a skateboard.
To find the expected value of the distribution, we multiply each outcome by it's probability. Doing this, we get that the expected value of defects on a skateboard is of [tex]\frac{4}{25}[/tex].
Outcomes and probabilities:
0 defects, 9/10 probability
1 defect, 1/20 probability
2 defects, 1/25 probability
3 defects, 1/100 probability.
Expected value:
[tex]E(X) = 0\frac{9}{10} + \frac{1}{20} + 2\frac{1}{25} + 3\frac{1}{100} = \frac{1}{20} + \frac{2}{25} + \frac{3}{100} = \frac{5 + 8 + 3}{100} = \frac{16}{100}[/tex]
Dividing both numerator and denominator by 4:
[tex]\frac{4}{25}[/tex]
Thus, the expected value of defects on a skateboard is of [tex]\frac{4}{25}[/tex].
A similar problem is given at: https://brainly.com/question/23156292.
PLS HELP ME I WILL MARK YOU AS BRAINLIEST!!!
Answer:
volume = length x width x height
v=11x5x11 = 605
hope that answers your question
What is the smallest prime number that is also a multiple of 20?
Answer:
Hello,
Step-by-step explanation:
In order to cut off ( pour couper court)
all multiple of 20 are divisible by 20, so they are not primes.
The sum of two numbers is 52. One number is 3 times as large as the other. What are the numbers?
Answer:
13 and 39
Step-by-step explanation:
The sum of two numbers = 52
One number is 3 times as large as the other
Equation:
x + 3x = 52
4x = 52
52 / 4 = x
x = 13
13 * 3 = 39
The numbers are 13 and 39
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Please help with my math homework
Answer:
Down here:
Step-by-step explanation:
a. 1 , 3 , 9 , 27 , 81, 243, 729
rule, multiply by 3
b. 8, 7, 9, 8, 10, 9, 11, 10, 12
rule, -1 then +2
c. 100, 50, 25, 12.5, 6.25, 3.125
rule, divide by 2
d. 1, 4, 9, 16, 25, 36, 49
rule +3, +5, +7, +9, +11.....
If my answer is incorrect, pls correct me!
If you like my answer and explanation, mark me as brainliest!
-Chetan K
Graph the line for y+1 = - 3(2x - 4) on the coordinate plane.
The volume of a cube is 1000 blocks. What is the length of one side of the cube?
Answer:
A cube has 4 sides
1000÷4
=250
169.2 is what percent of 208
Answer:
The percentage is 81.35% (2.d.p)
Step-by-step explanation:
[tex]\frac{169.2}{208}[/tex] x 100 = 81.34615285
write each of the following expressions without using absolute value. |x-1| of x>1
Answer:
x-1 when x>1
Step-by-step explanation:
|x-1| when x>1
If x is greater than 1 than x-1 will always be greater than 0
|x-1| can be rewritten as x-1
Decide !!!!!!!!!!!!!!!!!!!!!!!!
Answer:
[tex]\displaystyle [CQF]=5[/tex]
Step-by-step explanation:
Note that [tex][n][/tex] refers to the area of some polygon [tex]n[/tex].
Diagonal [tex]\overline{AC}[/tex] forms two triangles, [tex]\triangle ABC[/tex] and [tex]\triangle ADC[/tex]. Both of these triangles have an equal area, and since the area of parallelogram [tex]ABCD[/tex] is given as [tex]210[/tex], each triangle must have an area of [tex]105[/tex].
Furthermore, [tex]\triangle ADC[/tex] is broken up into two smaller triangles, [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex]. We're given that [tex]\frac{DF}{FC}=2[/tex]. Since [tex]DF[/tex] and [tex]FC[/tex] represent bases of [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex] respectively and both triangles extend to point [tex]A[/tex], both triangles must have the same height and hence the ratio of the areas of [tex]\triangle ADF[/tex] and [tex]\triangle ACF[/tex] must be [tex]2:1[/tex] (recall [tex]A=\frac{1}{2}bh[/tex]).
Therefore, the area of each of these triangles is:
[tex][ACF]+[ADF]=105,\\[][ACF]+2[ACF]=105,\\3[ACF]=105,\\[][ACF]=35 \implies [ADF]=70[/tex]
With the same concept, the ratio of the areas of [tex]\triangle AQE[/tex] and [tex]\triangle DQE[/tex] must be [tex]2:1[/tex] respectively, from [tex]\frac{AE}{ED}=2[/tex], and the ratio of the areas of [tex]\triangle DQF[/tex] and [tex]\triangle CQF[/tex] is also [tex]2:1[/tex], from [tex]\frac{DF}{FC}=2[/tex].
Let [tex][DQE]=y[/tex] and [tex][CQF]=x[/tex] (refer to the picture attached). We have the following system of equations:
[tex]\displaystyle \begin{cases}2y+y+2x=70,\\y+2x+x=35\end{cases}[/tex]
Combine like terms:
[tex]\displaystyle \begin{cases}3y+2x=70,\\y+3x=35\end{cases}[/tex]
Multiply the second equation by [tex]-3[/tex], then add both equations:
[tex]\displaystyle \begin{cases}3y+2x=70,\\-3y-9x=-105\end{cases}\\\\\rightarrow 3y-3y+2x-9x=70-105,\\-7x=-35,\\x=[CQF]=\frac{-35}{-7}=\boxed{5}[/tex]
PRACTICE
List the factors of each number.
1. 16,
2. 39
3. 50
for each pair of numbers.
Answer:
1. 1 & 16, 2 & 8, 4 & 4
2. 1 & 39, 3 & 13
3. 1 & 50, 2 & 25, 5 & 10
The total cost of a watch and a radio is Rs 500. If the watch is cheaper than the Equations radio by Rs 150, find their cost.
Answer:
the watch is Rs 175
the radio is Rs 325
Step-by-step explanation:
x = price of the watch
y = price of the radio
x+y = 500
x + 150 = y
=>
x + (x+150) = 500
2x + 150 = 500
2x = 350
x = 175
=>
y = 175 + 150 = 325
What is the approximate value of x in the diagram below
Answer:
x = 8 cm
Step-by-step explanation:
The first step in solving this problem is to determine which trig function applies. The diagram shows that this triangle is a right triangle, that side x is opposite the 25-degree angle, and that the hypotenuse has a length of 18 cm.
The sine function of an angle Ф is defined as the ratio of the opposite side to the hypotenuse. In this case, sin Ф (or sin 25 degrees) equals x/(18 cm).
We need to determine the value of x. Adapt the above equation to this particular situation: sin 25 degrees = x/(18 cm).
To solve for x, multiply both sides of the most recent equation, above, by (18 cm). The following results: (18 cm)(sin 25 degrees) = x.
Next, use a calculator to find the value of sin 25 degrees: It is 0.4226.
Then the desired value of x is (18 cm)(0.4226), or x = 7.61 cm. This should be rounded off to x = 8 cm to reflect the level of accuracy of the given 18 cm.
Hoà tan 0,56 g CaO vào 800 ml nước thu được dung dịch nước vôi trong có nồng độ mol là
Answer:
please ask in English for easy to understand.
PLEASE HELP
What is the area of a triangle having a base of 6m and a height of 27m?
I really just need a answer so please don't joke around and do not send me a website just please with me the correct answer
Answer:
1/2b*h
1/2 6*27
162/2
81 is the answer
Rearrange the formulae to make x the subject:
ay/x - dx= wx
Thanks in advance
Answer:
x = ay/(wx+dx)
Step-by-step explanation:
ay/x - dx = wx
ay/x = wx + dx
ay = x(wx+dx)
x = ay/(wx+dx)