Jane is given a $100 gift to start and saves $35 a month from her allowance.
After 1 month, Jane has saved
After 2 months, Jane has saved
After three months, Jane has saved
and so on
In general, after x months Jane has saved
This means that it makes sense to represent the relationship between the amount saved and the number of months with one constant rate (in this case the constant rate is 35). It makes sense because the amount of money increases by $35 each month. Since the amount of increase is constant, we get constant rate. Also the initial amount is known ($100), so there is a possibility to write the equation of linear function representing this situation.
Step-by-step explanation:
The median of a triangle divides it into two________.
The median of a triangle divides it into two equal triangles of equal areas.
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The graph below represents which of the following functions?
Answer:
D
Step-by-step explanation:
The correct answer is D, try graphing them on desmos.
How do u do this I don’t understand pls and thanks
Answer: Look it up on internet
Step-by-step explanation: INTERNET
The digits 0,1,2,3,4,5 and 6 are used to make 3 digit codes
In case where digits may be repeated, how many codes are numbers that are greater than 300 and exactly divisible by 5?
Answer:
345/5=69
Step-by-step explanation:
345/5=69
355/5=71
The graph of y=x√ is translated 5 units to the left and 7 units up. What is the equation of the graph that results from this translation?
Answer:
[tex]y = \sqrt{x - 5} + 7[/tex]
The blueprints of a house have a scale factor of 30. If one side of the house measures 4 inches on the blueprint, how long is the actual side length (in feet)?
A. 7.5 feet
B.10 feet
C. 90 feet
D. 120 feet
If the scale factor is 30, then all you have to do is multiply each measurement by the scale factor. In this case, 4 · 30 = 120.
NEED HELP ASAP!!!! PLEASEEE
The first answer of the missing blank is 4/5.
The second answer of the missing blank is 2.
The third answer of the missing blank is 25.
*For all of these solutions, I will be using the common rules for logarithms.*
Solution for the first question:
Log9^4/5 must equal log9^4-log9^5, or it could also equal the more proper version, which is simplified: 2log9^2-log9^5.
Solution for the second question:
Log3^22 must equal log3^11+log3^2, if you break it down.
Solution for the third question:
Log9^25 must equal 2log9^5 because it will be like this when simplifying it:
log9^25=2log9^5
log9^5²=2log9^5
2log9^5=2log9^5
These are all of the step-by-step procedures for all three of these given questions. Anyways, I hope that this helped you!
Draw the perpendicular bisector of the given line segment a.9.4 cm b. 8.6cm c. 10 cm
Answer:
Please do it by your shelf because if we measure it and send you may not be able to do by online .So, please do it by by yourself using your scale .
Find the value of m.
L
R
A
3m +21 U
6m
O A. 14
ОВ. 7
Answer:
B
Step-by-step explanation:
Since LR=LA, RU=RA. 3m+21=6m, 3m=21, m=7
How many two-digit numbers are there which are multiples of both 2 and 7?
2 digits number = 10-99
Lets find the multiples of 2 and 7 both
Which are = 14, 28,42,56,70,84,98
Therefore there are 7 two digit multiples of both 2 and 7
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9514 1404 393
Answer:
7
Step-by-step explanation:
Those numbers are 14, 28, 42, 56, 70, 84, 98. There are 7 numbers that are multiples of 2 and 7 (multiples of 14).
Find the remainder when f(x)= 8x^3+ 4x^2
13x + 3 is divided by 2x + 5.
Answer:
-129
Step-by-step explanation:
2x+5=0
x=-5/2 [By the remainder theorem]
f(-5/2)=8(-5/2)^3+4(-5/2)^2+13(-5/2)+3
=-125+25-65/2+3
=-129.
1. In the past, Sam cashed his paycheck each month at Ready Cash, a check cashing service that
charges a 5% fee. He recently opened a checking account at Bank of America so he can now
deposit and/or cash his paycheck without a fee. If Sam is making $28,500 per year, how much will
he save by not going to Ready Cash anymore?
Step-by-step explanation:
28000 ÷ 100
=280
280 × 5
=1400
Find the measure of ZJ, the smallest angle in a triangle
with sides measuring 11, 13, and 19. Round to the
nearest whole degree.
O 30°
O 34°
o 42°
O 47°
A cyclist rides her bike at a speed of 30 kilometers per hour. What is this speed in kilometers per minute? How many kilometers will the cyclist travel in 2
minutes? Do not round your answers.
Answer:
0.5 km/min and 1km
Step-by-step explanation:
30 km in an hour
30 km in 60 mins, 30/60 km in one minute so she cycle 0.5km/min. They will cover 1 km in 2 minutes
Cho A=( căn x -4x /1-4x -1) : (1+2x/1-4x -2căn x/ 2căn x -1 -1)
Answer:
0.85714285714286 x 100 = 85.7143%.
Step-by-step explanation:
Find the least common multiple of 14 and 22.
what number should be added to -5/8 to get -3/2
Answer:
-7/8
Step-by-step explanation:
-5/8+x=-3/2
x= -3/2+5/8=-12/8+5/8= -7/8
What is the value of x?
Enter your answer in the box.
__units.
Please help click the picture to see the problem!
Using basic proportionality theorem
[tex]\\ \sf\longmapsto \dfrac{x}{10}=\dfrac{42}{15}[/tex]
[tex]\\ \sf\longmapsto 15x=42(10)[/tex]
[tex]\\ \sf\longmapsto 15x=420[/tex]
[tex]\\ \sf\longmapsto x=\dfrac{420}{15}[/tex]
[tex]\\ \sf\longmapsto x=28[/tex]
solve for x! please help (show work)
Answer:
[tex]x=4[/tex]
Step-by-step explanation:
Solving for [tex]x[/tex], we get:
[tex]16=2(3x-6)+x[/tex]
[tex]16=2*3x+2(-6)+x[/tex] (Distributive Property of Multiplication)
[tex]16=6x-12+x[/tex] (Multiply distributed terms)
[tex]16=7x-12[/tex] (Combine like terms)
[tex]16+12=7x-12+12[/tex] (Add [tex]12[/tex] to both sides of the equation to isolate [tex]x[/tex])
[tex]28=7x[/tex] (Combine like terms / Simplify)
[tex]\frac{28}{7}=\frac{7x}{7}[/tex] (Divide both sides of the equation by [tex]7[/tex] to get rid of [tex]x[/tex]'s coefficient)
[tex]\bf x=4[/tex] (Simplify / Symmetric Property of Equality)
Hope this helps!
Step-by-step explanation:
[tex]16 = 2(3x - 6) + x \\ 16 = 6x - 12 + x \\ - 6x - x = - 12 - 16 \\ - 7x = - 12 - 16 \\ 7x = 12 + 16 \\ 7x = 28 \\ x = \frac{28}{7} \\ x = 4[/tex]
Question 1 plz show ALL STEPS
Answer:
1a= 10
Step-by-step explanation:
[tex]f(g(1) = 3( - 2(1) + 7) - 5[/tex]
[tex] = 3(5) - 5 [/tex]
[tex]15 - 5 = 10[/tex]
Answer:
Step-by-step explanation:
f(x) = 3x - 5
g(x) = - 2x + 7
(a). f(g(1)) = 10
g(1) = - 2(1) + 7 = 5
f(5) = 3(5) - 5 = 10
(b). f(g( - 4)) = 40
g( - 4) = - 2( - 4) + 7 = 15
f(15) = 3(15) - 5 = 40
(c). g(f( - 2)) = 29
f( - 2) = 3( - 2) - 5 = - 11
g( - 11) = - 2( - 11 ) + 7 = 29
(d). g(f(3)) = - 1
f(3) = 3(3) - 5 = 4
g(4) = - 2(4) + 7 = - 1
What integer is equal to 5!×2!?
Answer:
240
Step-by-step explanation:
! means factorial or to multiply by the previous number down to one so 5!=5*4*3*2*1=120 120*2=240.
Consider the following.
3^5x − 1 = 7
(a) Find the exact solution of the exponential equation in terms of logarithms.
(b) Use a calculator to find an approximation to the solution rounded to six decimal places.
Answer:
Step-by-step explanation:
You've typed the equation incorrectly. 3^5x-1 = 3⁵x-1.
It needs to be typed as 3^(5x-1) = 7.
Which table represents a function?
GO
х
-3
0
-2
8
y
-1
0
-1
1
х
-5
0
-5
6
y
-5
0
5
-6
х
-4
-2
-2
0
у
8
2
4
2
х
-4
3
1
-4
у
2.
5
3
0
The table that represents a function in the options given is: Table A. (see image attached below).
Recall:
If a relation represents a function, the relation must have exactly one y-value assigned or related to each x-value.In the tables given, only the first table has exactly one y-value assigned or related to every x-value given.
Therefore, the table that represents a function in the options given is: Table A. (see image attached below).
Learn more about function table on:
https://brainly.com/question/3632175
Answer:
Graph A
Step-by-step explanation:
Which expressions are equivalent to 5 +(-3)(6x - 5) ?
Choose all answers that apply:
A 182 – 20
B 3.2 - 3
С None of the above
[tex]\\ \sf\longmapsto 5+(-3)(6x-5)[/tex]
[tex]\\ \sf\longmapsto 5-3(6x-5)[/tex]
[tex]\\ \sf\longmapsto 5-18x+15[/tex]
[tex]\\ \sf\longmapsto -18x+15+5[/tex]
[tex]\\ \sf \longmapsto -18x+20[/tex]
Option C is correct
None of the above
Answer:
18x + 20
Step-by-step explanation:
5 + (-3)(6x - 5)
Step 1. start by the parentheses (by multiplying (-3) by (6x - 5)
Answer: (-18x + 15)
Step 2. Add 5 to (-18x + 15)
Answer: (-18x + 20)
Thus, (-18x + 20) isn't a choice so None of the above
a polynomial p has zeros when x=1/5,x=-4, andx=2 what could be the equation of p?
Answer:
x^3 + (9/5)x^2 -(42/5)x + (8/5)
Step-by-step explanation:
since 1/5, -4, and 2 are all zeroes, (x-1/5)(x+4)(x-2) must be a factor of p. if you distribute the statement, you get
Given the sequence 4, 8, 16, 32, 64, ..., find the explicit formula.
128Answer:
128
Step-by-step explanation:
vì 4+4=8
8+8=16
16+16=32
32+32=64
64+64=128
What would the equation be if I multiplied each side by 12
Answer:
It's option a. 36 + 6x^2 = 28x
Step-by-step explanation:
Add 5/20 + 1/20. Simplify your answer.
Answer:
3/10
Step-by-step explanation:
1) 5/20+1/20= 6/20
2) Both 6 and 20 lowest number on dividing: 2
6 divide by 2= 3 20 divide by 2= 10
5/20+1/20
= 5+1/20
= 6/20
= 3/10
Ugh I’m going insane trying to do this. Please help.
Answer:
y(x)=6^(x)-3
Step-by-step explanation:
Let the exponential function be y(x) = ab^(x) but since the graph is translated 3 units down, y(x) = ab^(x)-3. Now, y(0)=-2=a*b^(0)-3. a=1. The equation is nearly complete but we need b, we can find it by using the point y(1)=3. y(x)=b^(x) - 3. y(1)=3=b-3, b=6. The equation of the function is y(x)=6^(x)-3
Answer:
I agree with the first one
Find the reflection of the point (x,y) in the line y=mx+c
Answer:
[tex]\displaystyle \left(\frac{-(m^{2}-1)\, x + 2\, m\, y - 2\, m \, c}{m^{2} + 1},\, \frac{(m^{2} - 1)\, y + 2\, m \, x + 2\, c}{m^{2} + 1}\right)[/tex].
Step-by-step explanation:
Consider the line that is perpendicular to [tex]y = m\, x + c[/tex] and goes through [tex](x,\, y)[/tex].
Both [tex](x,\, y)[/tex] and the reflection would be on this new line. Besides, the two points would be equidistant from the intersection of this new line and line [tex]y = m\, x + c[/tex].
Hence, if the vector between [tex](x,\, y)[/tex] and that intersection could be found, adding twice that vector to [tex](x,\, y)\![/tex] would yield the coordinates of the reflection.
Since this new line is perpendicular to line [tex]y = m\, x + c[/tex], the slope of this new line would be [tex](-1/m)[/tex].
Hence, [tex]\langle 1,\, -1/m\rangle[/tex] would be a direction vector of this new line.
[tex]\langle m,\, -1\rangle[/tex] (a constant multiple of [tex]\langle 1,\, -1/m\rangle[/tex] would also be a direction vector of this new line.)
Both [tex](x,\, y)[/tex] and the aforementioned intersection are on this new line. Hence, their position vectors would differ only by a constant multiple of a direction vector of this new line.
In other words, for some constant [tex]\lambda[/tex], [tex]\langle x,\, y \rangle + \lambda\, \langle m,\, -1 \rangle = \langle x + \lambda \, m,\, y - \lambda \rangle[/tex] would be the position vector of the reflection of [tex](x,\, y)[/tex] (the position vector of [tex](x,\, y)\![/tex] is [tex]\langle x,\, y \rangle[/tex].)
[tex]( x + \lambda \, m,\, y - \lambda )[/tex] would be the coordinates of the intersection between the new line and [tex]y = m\, x + c[/tex]. [tex]\lambda\, \langle m,\, -1 \rangle[/tex] would be the vector between [tex](x,\, y)[/tex] and that intersection.
Since that intersection is on the line [tex]y = m\, x + c[/tex], its coordinates should satisfy:
[tex]y - \lambda = m\, (x + \lambda \, m) + c[/tex].
Solve for [tex]\lambda[/tex]:
[tex]y - \lambda = m\, x + m^{2}\, \lambda + c[/tex].
[tex]\displaystyle \lambda = \frac{y - m\, x - c}{m^{2} + 1}[/tex].
Hence, the vector between the position of [tex](x,\, y)[/tex] and that of the intersection would be:
[tex]\begin{aligned} & \lambda\, \langle m,\, -1 \rangle \\= \; & \left\langle \frac{m\, (y - m\, x - c)}{m^{2} + 1},\, \frac{(-1)\, (y - m\, x - c)}{m^{2} + 1}\right\rangle \\ =\; &\left\langle \frac{-m^{2}\, x + m\, y - m\, c }{m^{2} + 1},\, \frac{-y + m\, x + c}{m^{2} + 1}\right\rangle \end{aligned}[/tex].
Add twice the amount of this vector to position of [tex](x,\, y)[/tex] to find the position of the reflection, [tex]\langle x,\, y \rangle + 2\, \lambda \,\langle m,\, -1 \rangle[/tex].
[tex]x[/tex]-coordinate of the reflection:
[tex]\begin{aligned} & x + 2\, \lambda\, m \\ = \; & x + \frac{-2\, m^{2}\, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1} \\ =\; & \frac{-(m^{2} - 1) \, x + 2\, m \, y - 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].
[tex]y[/tex]-coordinate of the reflection:
[tex]\begin{aligned} & y + (-2\, \lambda)\\ = \; & y + \frac{- 2\, y + 2\, m\, x + 2\, c}{m^{2} + 1} \\ =\; & \frac{(m^{2} - 1) \, y + 2\, m \, x + 2\, m \, c}{m^{2} + 1}\end{aligned}[/tex].
