Please help me answer this question:
(D 3, 3, 5, 5, 6, 7, 8, 9, 11

Answer:

Step-by-step explanation:

150% = 150 ÷ 100 150% = 1.5

Answer:

u=1

v = 10

Step-by-step explanation:

For the triangles to be congruent

IG = PR

50 = u+49

50 - 49 = u

1 = u

GH = RQ

v+6 = 16

v = 16-6

v = 10

Answer:

C. 5.2 in.

Step-by-step explanation:

Answer:

Step-by-step explanation:

[tex]\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\la\la\la\la\ddddddddddddddddddddddddddddddddcleverdddddd\ffffffffffffffffffffffffffffffffffffffff\pppppppppppppppppppppppppppppppppppp\ddddddddddddddddddd\displaystyle\ \Large \boxed{ \boxed{\boldsymbol{Rule : a^{-1}=\frac{1}{a} }}} \\\\\\\\ (2+3)^{-1} \times (2^{-1}+2^{-1}) = \\\\1)\ (2+3)^{-1}=5^{-1}=\frac{1}{5} \\\\2)\ 2^{-1}+2^{-1}=\frac{1}{2} +\frac{1}{2} } =1 \\\\3)\ \frac{1}{5} \cdot 1=\boxed{\frac{1}{5} }[/tex]

Answer:

[tex]\begin{array}{ccl}Year&&End \ of \ year \ balance\\1&&\$4,483.18\\2&& \$3,088.68\\3&&\$1,596.57\\4&&0\end{array}[/tex]

Step-by-step explanation:

The initial amount invested, P = $1,600

Danny's age at which the amount, A, is to be used for his college, t = 19 years

The number of equal annual payments, m, to be withdrawn from the amount = 4

The compound interest on the account, r = 7% = 0.07

Let, A, represent the amount at the year the annual withdrawals starts to be made, we have;

[tex]A = P \times \left(1+\dfrac{r}{n} \right)^{n \times t}[/tex]

n = The number of times the interest is applied annually = 1

Therefore;

[tex]A = 1,600 \times \left(1+\dfrac{0.07}{1} \right)^{1 \times 19} \approx 5,786.444[/tex]

The amount, m, is withdrawn at start of Danny's first year in college to give the amount in the account = A - m

The amount in the account at the end of the first year with compound interest, r = (A - m)×(1 + r)¹ = (A - m)×(1 + r)

At the stat of the second year, the second withdrawal is made to give the starting amount = (A - m)×(1 + r) - m

The amount in the account at the end of the second year = ((A - m)×(1 + r) - m)×(1 + r)

At the start of the third year, the amount in the account =  ((A - m)×(1 + r) - m)×(1 + r) - m

At the end of the third year, we have the amount in the account  = (((A - m)×(1 + r) - m)×(1 + r) - m) × (1 + r)

At the start of the forth year, the last yearly installment is withdrawn from the account and we have 0 balance in the account.

Therefore, on the fourth year, we have the amount in the account = (((A - m)×(1 + r) - m)×(1 + r) - m) × (1 + r) - m = 0

(A - m)×(1 + r)³ - m×(1 + r)² - m × (1 + r) - m = 0

A×(1 + r)³ - m×(1 + r)³ - m×(1 + r)² - m × (1 + r) - m = 0

A×(1 + r)³ = m×(1 + r)³ + m×(1 + r)² + m×(1 + r) + m = m × ((1 + r)³ + (1 + r)² + (1 + r) + 1)

A×(1 + r)³ = m × ((1 + r)³ + (1 + r)² + (1 + r) + 1)

m = A×(1 + r)³/((1 + r)³ + (1 + r)² + (1 + r) + 1)

∴ m = 5,786.444×(1 + 0.07)³/((1 + 0.07)³ + (1 + 0.07)² + (1 + 0.07) + 1) ≈ 1,596.56

The amount withdrawn annually, m ≈ $1,596.56

The amount in the account at the end of the each year is given as follows;

First year = (A - m)×(1 + r) = (5,786.444 - 1,596.56)×(1 + 0.07) ≈ 4,483.17588

Second year = ((A - m)×(1 + r) - m)×(1 + r) = ((5,786.444 - 1,596.56)×(1 + 0.07) - 1,596.56)×(1 + 0.07) = 3,088.68

Third year = (((A - m)×(1 + r) - m)×(1 + r) - m) × (1 + r) = (((5,786.444 - 1,596.56)×(1 + 0.07) - 1,596.56)×(1 + 0.07) - 1,596.56) × (1 + 0.07) = 1,596.57

At the end of the first year, we have $4,483.17588

At the end of the second year, we have $3,088.68

At the end of the third year, we have $1,596.57

At the end of the fourth year, we have 0

Answer:

hello,

answer A c=n+2

Step-by-step explanation:

if n=0 then c=2

if n=2 then c=4

slope=m=(4-2)/(2-0) =2/2=1

c-2=1*(n-0)

c=n+2

Answer:

Option (C)

Step-by-step explanation:

System of the equations have been given as,

[tex]y=x+1[/tex] --------(1)

[tex]y=-\frac{1}{2}x+4[/tex] -------(2)

Substitute the value of y from equation (1) to equation (2),

[tex]x+1=-\frac{1}{2}x+4[/tex]

[tex]x+1=-\frac{1}{2}x+4[/tex]

[tex]x+\frac{1}{2}x=4-1[/tex]

[tex]\frac{3}{2}x=3[/tex]

[tex]x=2[/tex]

Substitute the value of 'x' in equation (1),

[tex]y=2+1[/tex]

[tex]y=3[/tex]

By using a graphing utility, graph of the equations that will intersect each other at a point (2, 3).

Therefore, solution of the system of equations will be [tex](2,3)[/tex].

Option (C) will be the answer.

Answer:

(2,3) C

Step-by-step explanation:

Solve using y = mx + b and graph!

Answer: tan A=4/3

Step-by-step explanation:

Theo đề ta có: 5sinA=4 suy ra: sinA=4/5, mà ta đã biết là: sinA= cạnh đối/cạnh huyền, suy ra: cạnh đối của góc A =4, cạnh huyền =5

Áp dụng định lí py ta go ta đc:

5^2=4^2+x^2

=) x=3

Vậy cạnh kề của góc A=3

Mà tanA = cạnh đối/cạnh kề

Vậy giá trị của tanA=4/3

(bạn vẽ hình ra thì có thể nhìn rõ hơn đấy, cảm ơn bạn đã tham khảo câu trả lời của mik)

Answer:

6

Step-by-step explanation:

4n - 12 < 2n + 2 is for n=6

4×6 -12 < 2×6 +2

24 - 12 < 12 + 2

12 < 14 correct

for n=7

4×7 - 12 < 2×7 + 2

16 < 16 incorrect

for n=8

4×8 - 12 < 2×8 + 2

20 < 18 incorrect

for n=9

4×9 - 12 < 2×9 + 2

24 < 20 incorrect

so, only for n=6 is the expression true.

Answer:

6

Step-by-step explanation:

4n - 12 < 2n + 2 is for n=6

4×6 -12 < 2×6 +2

24 - 12 < 12 + 2

12 < 14 correct

for n=7

4×7 - 12 < 2×7 + 2

16 < 16 incorrect

for n=8

4×8 - 12 < 2×8 + 2

20 < 18 incorrect

for n=9

4×9 - 12 < 2×9 + 2

24 < 20 incorrect

so, only for n=6 is the expression true.Step-by-step explanation:

Answer:

The profit or loss combined is $2.99

Step-by-step explanation:

Given;

cost price of first radio, CP = $25.50

profit percent, = 8%

The profit made is calculated as;

[tex]\frac{Profit}{CP} \times 100\% = \frac{SP-CP}{CP} \times 100\% = 8\%\\\\Profit = SP-CP = 0.08CP = 0.08\times \$25.50 = \$ 2.04[/tex]

Cost price of the second radio, CP = $6.30

loss percent = 15%

The loss incurred is calculated as;

[tex]\frac{Loss}{CP} \times 100\% = 15\%\\\\Loss = 0.15CP\\\\Loss = 0.15 \times \$6.30 = \$0.95[/tex]

The profit or loss combined = $2.04 + $0.95

                                               = $2.99

Answer:

Step-by-step explanation:

This is a geometric means problem. Namely, n is the geometric mean between the 2 smaller triangles within that larger one. Set up the problem accordingly:

[tex]\frac{28}{n}=\frac{n}{7}[/tex] and cross multiply:

[tex]n^2=196[/tex] so

n = 14

Answer:

total pages = 20

Step-by-step explanation:

60% of an unknown number is 12

Let the unknown number (total pages) be x.

60/100 of x = 12

60/100 * x = 12

3/5 x = 12

x = 12 * 5/3

x = 20

Answer:

y =(x-9)^2 +2

Step-by-step explanation:

The vertex form of a quadratic is

y = a(x-h)^2 +k  where (h,k) is the vertex and a is a constant

y = a(x-9)^2 +2

We can choose a if not given another point so I choose a = 1

y =(x-9)^2 +2

Answer:

please i need educere answers

Step-by-step explanation:

i have one day left and i cannot finish please reply with any way to contact you

the probability is made of the desired outcome divided by the total outcome.

desired = wins = 8

total = wins and losses = 15

8/15 is the probability (approx. 53%)

hope it helps :)

Answer:

y^7

Step-by-step explanation:

We know that a^b / a^c = a^( b-c)

y^9/y^2

y^(9-2)

y^7

Answer:

Step-by-step explanation:

The rule for division when the bases are like is to subtract the exponents:

[tex]\frac{y^9}{y^2}=y^{9-2}=y^7[/tex]

Answer:

exponential growth

Step-by-step explanation:

f(x) is in the form  a* b^x

where a is the initial value and b is the growth/ decay factor

since b > 1 it is growth

This is the exponential form of a function

We have exponential growth

Step-by-step explanation:

where is the steps to this question you can't answer it without a question too it SMH

Answer:

1) 800 (read the both) 2) 2200 (read exactly one)

Step-by-step explanation:

Find the people (families) who read neither of them

4000/100*25= 1000

It means that the rest 4000-1000= 3000 families read the newspapers at least  in one language  from the pointed languages. 4000/1oo*50= 2000 - readers in Nepali

4000/100*45= 40*45=1800 - readers in English.

2000+1800= 3800- the special amount, that consists of 1) only Nepali readers

2) only English readers 3) the readers in two languages (but the were counted twice, because we considered them in the group of Nepali readers and group of English readers)

The real quantity of only Nepali readers, only English readers and both language readers is 3000.

S0 3800-3000= 800 people - read in two languages

3000-800=2200 families read exactly one kind of these papers

Answer:

The range is the difference of the greatest and smallest numbers:

Semi-interquartile of the range is:

Since Q1 = 15, find Q3:

Note. Probably the numbers mixed up in the question.

If we swap them:

Given data:

The mean:

Variance, the average of the squared differences from the mean:

Answer:

Step-by-step explanation:

Volume of a cone formula is

[tex]V=\frac{1}{3}\pi r^2h[/tex] where r is radius and h is height. Filling in:

[tex]V=\frac{1}{3}(3.14)(10)^2(7)[/tex] and doing all the math on that and rounding gives us

V = 733 units cubed

[tex]\\ \sf\longmapsto q+12-2(q-22)>0[/tex]

[tex]\\ \sf\longmapsto q+12-2q+44>0[/tex]

[tex]\\ \sf\longmapsto q-2q+12+44>0[/tex]

[tex]\\ \sf\longmapsto -q+56>0[/tex]

[tex]\\ \sf\longmapsto -q>-56[/tex]

[tex]\\ \sf\longmapsto q<56[/tex]

Answer:

1/27

Step-by-step explanation:

The outcomes when rolling a die are 1,2,3,4,5,6

getting less than 3 = 1,2

P( less than 3) = outcomes of less than 3 / total

                        = 2/6 = 1/3

Since the events are independent we can multiply the probabilities

P( less than 3, less than 3, less than 3) = 1/3 * 1/3*1/3 = 1/27

Answer:

554,000

Step-by-step explanation:

that is the answer

Emma earns $554,064.80  in total in the first 11 years of her career

We are to determine the future value of $39,000 each year for 11 years given the growth rate of 5%

The formula for calculating future value:

FV = P (1 + r)^n

Where :

FV = Future value  

P = Present value  

R = interest rate  

N = number of years

First year =  $39,000

Second year = 39,000 x (1.05) = $40,950

Third year = 39,000 x (1.05)^2 = $42,997.50

Fourth year = 39,000 x (1.05)^3 = $45,147.38

Fifth year = 39,000 x (1.05)^4 = $47,404.75

Sixth year = 39,000 x (1.05)^5 = $49,774.99

seventh year = 39,000 x (1.05)^6 = $52,263.74

eighth year = 39,000 x (1.05)^7 = $54,876.93

ninth year = 39,000 x (1.05)^8 = $57,620.78

tenth year = 39,000 x (1.05)^9 = $60,501.82

eleventh year = 39,000 x (1.05)^10 = $63,526.91

Sum of the earnings for the first eleven years = $554,064.80

To learn more about the future value of income, please check : https://brainly.com/question/19407218?referrer=searchResults

Answer:

2

Step-by-step explanation:

The image got bigger in size by a factor of 2

Answer:

should be 1/2 for sure. great day

Answer:

15

Step-by-step explanation:

first find f which is (8-3) × ( 1/4 × 7 + 5)

simplify

5 × (1/4 ×12)

5 × 3

15 is thw answer

Answer:

This is a 4th degree polynomial!

Step-by-step explanation:

Because the polynomial starts of the a number with a 4th degree and decreases down with lower numbers. Simply put, because (x^4) has the largest degree.

Hope this helps, good luck! :)

Answer:

the answer is

tan (B)=p/b

=5/12

Answer: C)5/12

Step-by-step explanation:

Answer:

There is an asymptote at x = 0

There is an asymptote at y = 23

Step-by-step explanation:

Given the function:

(23x+14)/x

Vertical asymptote is gotten by equating the denominator to zero

Since the denominator is x, hence the vertical asymptote is at x = 0. This shows that there is an asymptote at x = 0

Also for the horizontal asymptote, we will take the ratio of the coefficient of the variables in the numerator and denominator

Coefficient of  x at the numerator = 23

Coefficient of x at the denominator = 1

Ratio = 23/1 = 23

This means that there is an asymptote at y = 23