please help again with translations

Please Help Again With Translations

Answers

Answer 1

Answer:

A -1,7

B 1,5

C -2,4

Step-by-step explanation:


Related Questions

7. In which step does a mistake first occur?
8 + 2 + (3 X 3 -2)
Step 1: 8 +2 + (3 x 1)
Step 2: 8 +2 + 3
Step 3: 4 + 3
Step 4: 7

Answers

Answer:

17

Step-by-step explanation:

8+2+(3×3-2)=8+2+(9-2)=8+2+7=17

mistake in the first step

firstly we do × and ÷

then + and -

The diameter of a $1 coin is 26.5 mm. Find the area of one side of the coin. Round to the nearest hundredth.

Answers

The area of one side of the coin is 41.605 mm².

Given that, the diameter of a $1 coin is 26.5 mm.

We need to find the area of one side of the coin.

What is the area of a circle formula?

The area of a circle formula is A=πr².

Now, radius=26.5/2=13.25 mm.

Area of a coin=3.14×13.25=41.605 mm².

Therefore, the area of one side of the coin is 41.605 mm².

To learn more about the area of the circle visit:

https://brainly.com/question/11952845.

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GH bisects LM at K. LK = 5x+2 and LM = 64 Find x

Answers

Answer:

x = 6

Step-by-step explanation:

Since GH bisects LM at K , then

LK = [tex]\frac{1}{2}[/tex] LM , that is

5x + 2 = [tex]\frac{1}{2}[/tex] × 64 = 32 ( subtract 2 from both sides )

5x = 30 ( divide both sides by 5 )

x = 6

The value of x is 6.

Here,

GH bisects LM at K.

LK = 5x+2 and LM = 64

We have to find the value of x.

What is Bisection in line?

Bisecting a line is cutting a line exactly in half. It may also be referred to as constructing a perpendicular bisector as the line you are drawing will be at a right angle to the original line.

Now,

GH bisects LM at K.

LK + KM = LM

2 LK = LM

2 ( 5x + 2 ) = 64

5x + 2 = 32

5x = 30

x = 6

Hence, The value of x is 6.

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What is the slope of a line perpendicular to a line that contains the points (-5, 4) and (-2, 4)?

Select the best answer from the choices provided.
A.
0
B.
no slope
C.
8/3
D.
-3/8

Answers

Answer: B. No slope


Explanation: The slope of a perpendicular line will always be the negative reciprocal of the slope of the given line. That means that you first have to find the slope of the given line by using the two points on that line:

Point 1: (-5, 4)
Point 2: (-2, 4)
Slope=(y2-y1)/(x2-x1)
Slope=(4-4)/((-2)-(-5))
Slope=0/3

If the slope of the initial line is 0/3 and the slope of its perpendicular line is the negative reciprocal of that slope, that means the slope of the perpendicular line will be -3/0 which is undefined because you can’t divide -3 by 0.

Therefore, the slope of the perpendicular line is undefined, or in other words, there isn’t an exact slope.



Hope that helps シ

Solve the equation.
3х - 6 = 6x - 9

Answers

Answer:

x=1

Step-by-step explanation:

3х - 6 = 6x - 9

Subtract 3x from each side

3х-3x - 6 = 6x-3x - 9

-6 = 3x-9

Add 9 to each side

-6+9 = 3x-9+9

3 =3x

Divide by 3

3/3 = 3x/3

1 =x

Answer:

3x-6=6x-9

3x-6x=-9+6

-3x=-3

-3x÷-3=-3÷-3

x=1

Can someone help pls

Answers

Axis of symmetry (blue line): x= -2
X intercepts (green dots): (-3,0), (-1,0)
Y intercept (black dot): (0,9)
Vertex (red dot): (-2,-3)

hi guys good afternoon​

Answers

Hello Good afternoon

Help help help help help

Answers

0 and 4 are the answers

Answer: 0 and 4

Step-by-step explanation:

First you to find the worksheet and download it
plase I need help

Answers

Answer:

a) The horizontal asymptote is y = 0

The y-intercept is (0, 9)

b) The horizontal asymptote is y = 0

The y-intercept is (0, 5)

c) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

d) The horizontal asymptote is y = 3

The y-intercept is (0, 4)

e) The horizontal asymptote is y = -1

The y-intercept is (0, 7)

The x-intercept is (-3, 0)

f) The asymptote is y = 2

The y-intercept is (0, 6)

Step-by-step explanation:

a) f(x) = [tex]3^{x + 2}[/tex]

The asymptote is given as x → -∞, f(x) = [tex]3^{x + 2}[/tex] → 0

∴ The horizontal asymptote is f(x) = y = 0

The y-intercept is given when x = 0, we get;

f(x) = [tex]3^{0 + 2}[/tex] = 9

The y-intercept is f(x) = (0, 9)

b) f(x) = [tex]5^{1 - x}[/tex]

The asymptote is fx) = 0 as x → ∞

The asymptote is y = 0

Similar to question (1) above, the y-intercept is f(x) = [tex]5^{1 - 0}[/tex] = 5

The y-intercept is (0, 5)

c) f(x) = 3ˣ + 3

The asymptote is 3ˣ → 0 and f(x) → 3 as x → ∞

The asymptote is y = 3

The y-intercept is f(x) = 3⁰ + 3= 4

The y-intercept is (0, 4)

d) f(x) = 6⁻ˣ + 3

The asymptote is 6⁻ˣ → 0 and f(x) → 3 as x → ∞

The horizontal asymptote is y = 3

The y-intercept is f(x) = 6⁻⁰ + 3 = 4

The y-intercept is (0, 4)

e) f(x) = [tex]2^{x + 3}[/tex] - 1

The asymptote is [tex]2^{x + 3}[/tex]  → 0 and f(x) → -1 as x → -∞

The horizontal asymptote is y = -1

The y-intercept is f(x) =  [tex]2^{0 + 3}[/tex] - 1 = 7

The y-intercept is (0, 7)

When f(x) = 0, [tex]2^{x + 3}[/tex] - 1 = 0

[tex]2^{x + 3}[/tex] = 1

x + 3 = 0, x = -3

The x-intercept is (-3, 0)

f) [tex]f(x) = \left (\dfrac{1}{2} \right)^{x - 2} + 2[/tex]

The asymptote is [tex]\left (\dfrac{1}{2} \right)^{x - 2}[/tex] → 0 and f(x) → 2 as x → ∞

The asymptote is y = 2

The y-intercept is f(x) = [tex]f(0) = \left (\dfrac{1}{2} \right)^{0 - 2} + 2 = 6[/tex]

The y-intercept is (0, 6)

in two or more complete sentences, describe how to graph the following equation. in your description, include the slope and both the x- and y-intercepts of the line. y=2

Answers

Answer:

Slope: 0

x-intercept: there isnt one

y-intercept: 2

Step-by-step explanation:

the easiest way to look at this is to put it in the form y=mx+b where m is the slope and b is the y intercept.  when we just think about what y=2 would look like, we can imagine a straight horizontal line at y=2.  No matter what x value you choose, y will always equal 2.  We know the slope (m) of any horizontal line is zero because there is no rise and zero divided by anything is going to be zero.  we also know if y is always equal to 2 the y intercept will be 2.  this would give us y=0x+2.  to find the x intercept we just need to set y equal to zero in this equation.  this gives us 0=0x+2 or 0=2 which can never be true, therefore there will be no x intercept.

*insert shrek script*

...................................

Ginkgo for Dementia The herb ginkgo biloba is commonly used as a treatment to prevent dementia. In a study of the effectiveness of

this treatment, 1545 elderly subjects were given ginkgo and 1524 elderly subjects were given a placebo. Among those in the ginkgo

treatment group, 246 later developed dementia, and among those in the placebo group, 277 later developed dementia. We want to

use a 0.01 significance level to test the claim that ginkgo is effective in preventing dementia. Test the claim using a hypothesis test.

Given test Statistic z = -1.66

Write Hypothesis and Critical Value, do you Support or reject the claim.

Answers

Answer:

i) 2.58

ii) We reject the claim

Step-by-step explanation:

The number of subjects in the ginkgo treatment group, n₁ = 1,545

The number of subjects in the placebo group, n₂ = 1,524

The number that developed dementia in the ginkgo group = 246

The number that developed dementia in the placebo group = 277

The proportion that developed dementia in the ginkgo group, [tex]\hat{p}_1[/tex] = 246/1,545 = 82/515

The proportion that developed dementia in the placebo group, [tex]\hat{p}_2[/tex] = 277/1,524

The null hypothesis is H₀; [tex]\hat{p}_1[/tex] = [tex]\hat{p}_2[/tex]

The alternative hypothesis is Hₐ; [tex]\hat{p}_1[/tex] ≠ [tex]\hat{p}_2[/tex]

The z-test statistic is given as follows;

[tex]Z=\dfrac{\hat{p}_1-\hat{p}_2}{\sqrt{\hat{p} \cdot (1-\hat{p}) \cdot \left (\dfrac{1}{n_{1}}+\dfrac{1}{n_{2}} \right )}}[/tex]

Therefore, we get;

[tex]Z=\dfrac{\dfrac{82}{515} -\dfrac{277}{1,524} }{\sqrt{\left (\dfrac{\dfrac{82}{515} \times \left(1 - \dfrac{82}{515} \right) }{1,545}+\dfrac{\dfrac{277}{1,524} \times \left (1 - \dfrac{277}{1,524} \right)}{1,524} \right )}} \approx -1.66[/tex]

From the the p-value at z ≈ -1.66 is p = 0.04846.

i) The z-Critical at 0.01 significant level is 2.58

ii) Given that the p-value, 0.04846, is larger than the significant level, 0.01, the p-value is not significant, and we fail to reject the null hypothesis

There is sufficient statistical evidence to suggest that there is no difference in the proportion of the subject on the ginkgo treatment and the proportion of the subject on the placebo treatment that have dementia, we therefore reject the claim that the herb ginkgo biloba is effective for the treatment of dementia.

The report "Digital Democracy Surveyt describes a large national survey. In a representative sample of Americans ages 14 to 18 years, 45% indicated that they usually use social media while watching
TV. Suppose that the sample size was 760.
(a) Is there convincing evidence that less than half of Americans ages 14 to 18 years usually use social media while watching TV? Use a significance level of 0.05.
State the appropriate null and alternative hypotheses.
O Hop 0.5 versus Hp > 0.5
O Moip 0.5 versus H: = 0.5
O Hp = 0.5 versus HP < 0.5
OH:P < 0.5 versus , p > 0.5
OHOD 0.5 versus H: 0.5
Find the test statistic and P-value. (Use a table or technology. Round your test statistic to two decimal places and your p-value to four decimal places.)
ZE
P-value

Answers

Answer:

H0 : p = 0.5 versus H1: P < 0.5

Test statistic = - 2.76

Pvalue = 0.0029

Step-by-step explanation:

The hypothesis :

We are to test if less Than half of the American population within the of 14 to 18 years usually use social media while watching TV :

Hence, population proportion, p = 0.5

H0: p = 0.5

H1: P < 0.5

Sample size, n = 760

Sample proportion, Phat = 45% = 0.45

The test statistic, Z :

Z = (Phat - P) / √[(P(1 - P)) /n]

Z = (0.45 - 0.5) / √[(0.5(1 - 0.5)) /760]

Z = - 0.05 / √0.0003289

Z = - 2.7568 ; Z = - 2.76 (2 decimal places)

The Pvalue :

Using technology :

Pvalue from Zscore calculator ; Pvalue = 0.0029

Decision region :

Reject H0 if Pvalue < α

α = 0.05

Since 0.0029 < 0.05 ; we reject the Null and conclude that less than half of American within age 14 to 18 years usually use social media while watching TV.

Please hurry I will mark you brainliest
What is the value of p so that the line passing through (6, 2) and (9, p) has a slope of -1?

Answers

Answer:

-1

Step-by-step explanation:

im pretty sure its right

sry if it not good luck!!

5(15-7y/3)+2y=-4
solve for y and plz show steps​

Answers

Answer:

75 - 35y / 3 + 2y = -4

( 75 - 35y + 6y ) / 3 = -4 [ Taking LCM ]

( 75 - 29y ) / 3 = -4

75 - 29y = -12

29y = 75+12

29y = 87

y = 3

hope that helps ✌

When -2(x − 4) + 1 = 7 is solved, the result is:

Answers

Answer:

1

Step-by-step explanation:

-2(x-4)+1=7

First Distribute the -2.

-2x+8+1=7

Subtract the 8 and 1 from the whole equation.

-2x=-2

Divide both sides of the equation by -2.

x=1

I hope this helps!

Answer:

x = 1

Step-by-step explanation:

-2(x − 4) + 1 = 7

-2x  + 8 + 1 = 7

-2x + 9 = 7

-2x = -2

x = 1

I need help with question 4!!!! PLEASE HELP ME!!

Answers

Answer:

4 cm

Step-by-step explanation:

V = πr²h

or, 36π = π(3)²×h

or, 36 = 9h

or, 4 = h

So the height is 4 cm

Answered by GAUTHMATH

maths question please help !! thank u :)​

Answers

Answer:

1350m

Step-by-step explanation:

Let the distance ran by Denise, Farah and Elaine be D, F and E meters respectively.

From the given information,

D= ⅔(E +F) -----(1)

E= ½(D +F) -----(2)

Let's get rid of the fraction so the equations are much easier to work with.

From (1):

3D= 2(E +F) (Multiply both sides by 3)

3D= 2E +2F -----(3) (Expand)

From (2):

2E= D +F -----(4)

Substitute (4) into (3):

3D= D +F +2F

3D -D= 3F

2D= 3F

Given that Farah ran 360m, F= 360.

2D= 3(360)

2D= 1080

D= 1080 ÷2

D= 540

2E= D +F

2E= 540 +360

2E= 900

E= 900 ÷2

E= 450

Total distance the 3 girls ran

= D +F +E

= 540 +360 +450

= 1350m

Alternatively, you could start by substituting F= 360 to equations (1) and (2).

Select the correct answer.
Which statement best describes the solution to this system of equations?
3x + y= 17
x + 2y = 49
Ο Α.
It has no solution.
B.
It has infinite solutions.
O c.
It has a single solution: x = 15, y= 17.
OD.
It has a single solution: x = -3, y = 26.

Answers

A because a is the answer I think I’m pretty sure or it can be b

Please hurry I will mark you brainliest

Answers

Answer:

number of pennies = 54

Step-by-step explanation:

(4,60) ; (6, 65)

Find the slope

Slope = [tex]\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

          [tex]=\frac{65-60}{6-4}\\\\=\frac{5}{2}[/tex]

m = 5/2 and (4,60)

Equation of the line: y - y1 = m (x -x1)

[tex]y - 60 = \frac{5}{2}(x -4)\\\\y - 60 = \frac{5}{2}x-\frac{5}{2}*4\\\\y- 60 = \frac{5}{2}x-10\\\\y =\frac{5}{2}x-10+60\\\\y=\frac{5}{2}x + 50[/tex]

x-----> determine the number of pennies and y determines the mass of pennies.

Here mass (y -value) is given as 185. We have find the corresponding x-value. So plugin  y  = 185 in the above equation,

[tex]185 = \frac{5}{2}x+50\\\\185-50=\frac{5}{2}x\\\\135=\frac{5}{2}x\\\\135*\frac{2}{5}=x\\\\27*2=x[/tex]

x = 54

Solve the right triangle given that mZA = 30°, mZC = 90°, and a = 15. Round
your result to one decimal place,

Answers

Answer:23

Step-by-step explanation:

A(x) = 7 – 4x , A(-1) =

Answers

Answer:

7-4*(-1)

7-4*(-1)7+4

7-4*(-1)7+411

Step-by-step explanation:

hope it will help u

Answer:

A(- 1) = 11

Step-by-step explanation:

Substitute x = - 1 into A(x) , that is

A(- 1) = 7 - 4(- 1) = 7 + 4 = 11

Please help and show work. 60 points

Answers

Answer:

18.

Domain: X E \{-3,2}

Y-Intercept: 1/2

X-Intercept: 3

19.

Domain: (I think it's none)

Y-Intercept: -2

X-Intercept: 2

20.

Domain: X E R\ {-3,1}

y-INTERCEPT: 2/3

x-INTERCEPT: -1

Step-by-step explanation:

18) when you factor the denominator, you get (x+3)((x-2). Since it doesn’t cancel out with any product in the numerator, the discontinuity would be non removable.
19) In this function, x can equal any value, since the denominator will never equal 0. So it’s continuous.
20) then for this one when you factor, you get 2(x-1)(x+1)/ (x+3)((x-1), so it has a removable at x=1 and a non removable one at x=-3.

The following are the ages (years) of 5 people in a room: 16, 25, 23, 12, 17 A person enters the room. The mean age of the 6 people is now 20. What is the age of the person who entered the room?

Answers

Answer: 27

Step-by-step explanation:

Set the age of the person who entered the room as x

[tex]Mean=\frac{16 + 25 + 23 + 12 + 17 + x}{6}=20 \\16 + 25 + 23 + 12 + 17 + x=20(6)\\93+x=120\\x=120-93=27[/tex]

Answer:

27 years old

Step-by-step explanation:

There are originally 5 people in the room.

Their ages are: 16, 25, 23, 12, 17

The sum of their ages is: 93

One person enters the room. That person's age is unknown, so we call it x.

The sum of the ages of the 6 people is:

x + 93

There are 6 people in the room now, so the mean age is (total age divided by number of people):

(x + 93)/6

We are told the mean age is 20.

(x + 93)/6 = 20

x + 93 = 120

x = 27

Answer: 27 years old

Find y when = 22, if y varies directly as x,
and y = 39 when x = 7.

Answers

Answer:

let,

x=ky

y=39 when x=7 so,

7=39k

or, k=7/39

now, when x=22

22=7y/39

or, y=39×22/7

or, y=858/7

or, y=122.57 (rounded to the nearest hundredth)

what is the equation of the line that is parallel to the given line and passes through the point (-3,2)? no links.

Answers

Answer:

D) 4x +3y = -6

Step-by-step explanation:

paralell lines so m1 and m2 are equal

m = (3 +1 )/ (0 - 3 )

m = -4/ 3

y -2 = -4/3 (x +3)

y =-4x/3 -2

3y = -4x -6

4x +3y = -6

will mark brainliest!!

picture included ^^^^

please and THANK YOU


^^!!

Answers

Answer:   choice D) 11.7

============================================

Work Shown:

Apply the Law of Sines to get the following. Make sure your calculator is in degree mode.

[tex]\frac{\sin(A)}{a}=\frac{\sin(B)}{b}=\frac{\sin(C)}{c}\\\\\frac{\sin(A)}{a}=\frac{\sin(C)}{c}\\\\\frac{\sin(20)}{4}=\frac{\sin(87)}{c}\\\\c*\sin(20)=4*\sin(87)\\\\c=\frac{4*\sin(87)}{\sin(20)}\\\\c\approx 11.6791897\\\\c\approx 11.7\\\\[/tex]

So that's why the answer is choice D) 11.7

a senior one student has reported in her class and has settled at her desk the math teacher has asked her to explain how she can access her seat




Answers

Answer:

she can sit

Step-by-step explanation:

30 points please help
Find the volume of the pyramid.
76.34 ft3
458.06 ft3
916.11 ft3
305.37 ft3

Answers

Answer:

With the formula of lwh/3 the answer is 305.37

Step-by-step explanation:

l×w×h /3 =305.37

Answer:

916.11 ft³

Step-by-step explanation:

(9×6)×7.83/2×13/3

= 211.41×13/3

= 916.11 ft³

Answered by GAUTHMATH

Integral of 1 /x+ sq.root x^2-1

Answers

I'm assuming the integral is

[tex]\displaystyle \int \frac{\mathrm dx}{x+\sqrt{x^2-1}}[/tex]

Rationalize the denominator:

[tex]\dfrac1{x+\sqrt{x^2-1}} \times \dfrac{x-\sqrt{x^2-1}}{x-\sqrt{x^2-1}} = \dfrac{x-\sqrt{x^2-1}}{x^2-\left(\sqrt{x^2-1}\right)^2} = x-\sqrt{x^2-1}[/tex]

Then the integral is

[tex]\displaystyle \int\left(x-\sqrt{x^2-1}\right)\,\mathrm dx = \dfrac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx[/tex]

For the remaining integral, substitute x = sec(t ) and dx = sec(t ) tan(t ) dt. Then over an appropriate domain, we have

[tex]\displaystyle\int\sqrt{x^2-1}\,\mathrm dx = \int\sec(t)\tan(t)\sqrt{\sec^2(t)-1}\,\mathrm dt = \int\sec(t)\tan^2(t)\,\mathrm dt[/tex]

Integrate by parts, taking

u = tan(t )   ==>   du = sec²(t ) dt

dv = sec(t ) tan(t ) dt   ==>   v = sec(t )

Then

[tex]\displaystyle\int\sec(t)\tan^2(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt[/tex]

Now for *this* remaining integral, integrate by parts again, taking

u = sec(t )   ==>   du = sec(t ) tan(t ) dt

dv = sec²(t ) dt   ==>   v = tan(t )

so that

[tex]\displaystyle\int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec(t)(\sec^2(t)-1)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \sec(t)\tan(t) - \int\sec^3(t)\,\mathrm dt + \int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t)+\frac12\int\sec(t)\,\mathrm dt \\\\ \int\sec^3(t)\,\mathrm dt = \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]

To summarize, if I denotes the original integral, we have

[tex]\displaystyle I = \frac12x^2 - \int\sqrt{x^2-1}\,\mathrm dx \\\\ I = \frac12x^2 - \int\sec(t)\tan^2(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \int\sec^3(t)\,\mathrm dt \\\\ I = \frac12x^2 - \sec(t)\tan(t) + \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C \\\\ I = \frac12x^2 - \frac12\sec(t)\tan(t) + \frac12\ln\left|\sec(t)+\tan(t)\right| + C[/tex]

Putting everything back in terms of x, we have

sec(t ) = x

tan(t ) = √(x ² - 1)

so that

[tex]\displaystyle I = \boxed{\frac12x^2 - \frac12x\sqrt{x^2-1}+\frac12\ln\left|x+\sqrt{x^2-1}\right|+C}[/tex]

Un deportista de natación necesita mejorar su estilo de clavado, por lo que ha grabado con una cámara ubicada bajo el agua cada uno de sus movimientos hasta obtener el mejor clavado. Los resultados del clavado esperado fueron descritos en una ecuación de la profundidad h en función de la distancia x, a la que vuelve a emerger, donde todas las distancias están en metros, así: h(x) = 6x2+6x
Si se toma el nivel del agua de la piscina como el eje de las abscisas, determine la profundidad máxima, en metros, que alcanzó en su clavado.

ayuda es para mañana

Answers

Answer:yes

Step-by-step explanation:

Yes

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