Multi-part question If a galaxy moving away from the Earth has a speed of 1000 km/s and emits 656 nm light characteristic of hydrogen (the most common element in the universe). What wavelength would we observe on the Earth

Answer:

D. the track exerts a force that is equal and in the opposite direction as the force exerted by the tires

Explanation:

Newton's third law of motion states that for every action, there is an equal and opposite reaction. This speaks of equality in magnitude of force applied but in an opposite direction to one another.

According to this reaction, a car's tires exert a force on the track, this means that in accordance to Newton's third law, the track must exert an equal but opposite force on the car's tires. This causes the car to accelerate forward.

Answer:

(b) 1/sinƟ

Explanation:

A simple machine can be defined as a type of machine with no moving parts but can be used to perform work.

Basically, a simple machine allows for the transformation of energy into work. The six simple machines are; lever, wedge, pulley, screw, wheel and axle, and inclined plane.

Inclined plane is a simple machine set at an angle and then used to lift an object.

In Physics, the velocity ratio of a simple machine is calculated as a ratio of the distance moved by the effort to the vertical distance through which a load is raised.

Mathematically, the velocity ratio of an inclined plane of angle Ɵ, acting as a simple machine is given by the formula;

Velocity ratio (V.R) = 1/sinƟ

Basically, an increase in the angle of inclination (measured in degrees) of an inclined plane increases its velocity ratio.

Answer:

The field strength needed to produce a 24.0 V peak emf is 0.5913 T

Explanation:

From the formula for maximum emf of a generator,

[tex]emf_{max}= NAB\omega[/tex]

∴ [tex]B = \frac{emf_{max} }{NA\omega}[/tex]

Where N is the number of loops

A is cross section of loops

B is magnetic field strength

ω is the angular frequency of loops

From the question, [tex]emf_{max} = 24.0V[/tex]

N = 300 turns

A = l × b ( since it is a rectangular coil)

A = 6.46 cm × 5.00 cm

A = 0.0646 m × 0.05 m

A = 0.00323 m²

ω = 400 rpm = (400/60)×2π rad/s

ω = 41.8879 rad/s

Putting all the parameters into the formula

[tex]B = \frac{emf_{max} }{NA\omega}[/tex]

[tex]B = \frac{24.0}{300\times0.00323\times41.8879}[/tex]

[tex]B = 0.5913T[/tex]

Hence, the field strength needed to produce a 24.0 V peak emf is 0.5913 T

personal to systematic errors

unbiased to random errors

Answer:

The answer is ( D) i. e both b and c.

Explanation:

FALSE

The first periodic table of elements Mendeleev created contained 63 elements.

Answer:

9 lần

Explanation:

Answer:

Kinetic energy (k.e) varies directly as v² from the formula

K.E=(mv²/2)

if v=3 then K.e =v²=(3)²=9

applied force is a contact force

C it reduces the amount of useful work done on objects move it up the ramp

Explanation:

A parallel circuit is often called a current divider for its ability to proportion—or divide—the total current into fractional parts. Once again, it should be apparent that the current through each resistor is related to its resistance, given that the voltage across all resistors is the same

Answer:

At point A, the comet has the least kinetic energy because the comet is resting. 3. From point B to point D its orbit's potential energy is decreasing and its kinetic energy is increasing meaning it's moving more and more

Answer:

mR²/2

Explanation:

Here is the complete question

An object of radius′

R′  and mass ′

M′  is rolling horizontally without slipping with speed ′

V′

. It then rolls up the hill to a maximum height h = 3v²/4g. The moment of inertia of the object is (g= acceleration due to gravity)

Solution

Since it rolls without slipping, there is no friction. So, its initial mechanical energy at the horizontal surface equals its final mechanical energy at the top of the hill.

Since the object is rolling initially, and on horizontal ground, it initial energy is kinetic and made up of rotational and translational kinetic energy.

So, E = K + K'

E = 1/2mv² + 1/2Iω² where m = mass of object, v = speed of object, I = moment of inertia of object and ω = angular speed of object = v/r where v = speed of object and R = radius of object.

Also, the final mechanical energy of the object, E' is its potential energy at the top of the hill. So, E' = mgh.

Since E = E',

1/2mv² + 1/2Iω² = mgh

substituting the values of ω and h into the equation, we have

1/2mv² + 1/2Iω² = mgh

1/2mv² + 1/2I(v/R)²= mg(3v²/4g)

Expanding the brackets, we have

1/2mv² + 1/2Iv²/R²= 3mv²/4

Dividing through by v², we have

1/2m + I/2R²= 3m/4

Subtracting m/2 from both sides, we have

I/2R² = 3m/4 - m/2

Simplifying, we have

I/2R² = m/4

Multiplying through by 2R², we have

I = m/4 × 2R²

I = mR²/2

Answer:

Option D. 9.47 V

Explanation:

We'll begin by calculating the equivalent resistance of the circuit. This can be obtained as follow:

Resistor 1 (R₁) = 20 Ω

Resistor 2 (R₂) = 30 Ω

Resistor 3 (R₃) = 45 Ω

Equivalent Resistance (R) =?

R = R₁ + R₂ + R₃ (series connections)

R = 20 + 30 + 45

R = 95 Ω

Next, we shall determine the current in the circuit. This can be obtained as follow:

Voltage (V) = 45 V

Equivalent Resistance (R) = 95 Ω

Current (I) =?

V = IR

45 = I × 95

Divide both side by 95

I = 45 / 95

I = 0.4737 A

Finally, we shall determine, the voltage across R₁. This can be obtained as follow:

NOTE: Since the resistors are in series connection, the same current will pass through them.

Current (I) = 0.4737 A

Resistor 1 (R₁) = 20 Ω

Voltage 1 (V₁) =?

V₁ = IR₁

V₁ = 0.4737 × 20

V₁ = 9.47 V

Therefore, the voltage across R₁ is 9.47 V.

Answer:

9.47

Explanation:

Just Took the Test

Answer:

3.125J

Explanation:

K.E.= 1/2(mass)(velocity)^2

K.E.=1/2(0.25)(5)^2=3.125

Answer:

hello

Explanation:

hello dost timi kasto cha

Answer:

Distance = 6.667 kilometres

Explanation:

Given the following data;

Speed = 20 km/h

Departure time = 7:00

Arrival time = 7:20

Time taken = 20 minutes

To calculate the distance travelled from home to school;

First of all, we would have to convert the value of time in minutes to hours.

Conversion:

60 minutes = 1 hour

20 minutes = X hours

Cross-multiplying, we have;

X = 20/60 = 1/3 hours

Mathematically, the distance travelled by an object is calculated by using the formula;

Distance = speed * time

Distance = 20 * 1/3

Distance = 20/3 =

Distance = 6.667 kilometres

Answer:

The three primaryfactors of evaporation are heat, atmospheric pressure (which determines the percentage of moisture) and the movementofair. At the molecular level, there is no strict boundary between the liquid state and the vapor state

Answer:

1. a. 3,000 N

b. Repulsión

2. 46.875 × 10⁶ N/C

3. a. 81,000 J

b. 6.75 × 10⁹ V

Explanation:

1. Los parámetros dados son;

Q₁ = +12 μC, Q₂ = +16 μC

La distancia entre las cargas, r = 0.024

La magnitud de la fuerza electrostática, F, entre cargas se da como sigue;

[tex]F = k \times \dfrac{Q_1 \cdot Q_2}{r^2}[/tex]

Donde, k = constante de Coulomb = 9.0 × 10⁹ N · m² / C²

Por lo tanto, obtenemos;

F = 9.0 × 10⁹ × 12 × 10⁻⁶ × 16 × 10⁻⁶ / 0.024² = 3.000

La magnitud de la fuerza electrostática, entre las cargas, F = 3000 N

(b) Dado que tanto Q₁ como Q₂ son cargas positivas, y las cargas iguales se repelen entre sí, la fuerza es la repulsión.

2) La intensidad de un campo eléctrico, E, se da como sigue;

[tex]E = \dfrac{k \cdot Q}{r^2}[/tex]

La magnitud de la carga, Q = 24 μC

La distancia donde se mide el campo, r = 48 mm = 0.048 m

Por lo tanto, E = 9.0 × 10⁹ × 12 × 10⁻⁶ / 0.048² = 46,875,000 N / C

La intensidad de un campo eléctrico, E = 46,875,000 N / C = 46.875 × 10⁶ N / C

3. La magnitud de las cargas son;

Q₁ = 24 mC

Q₂ = -12 μC

La distancia entre las cargas, r = 0.032 m

un. El potencial eléctrico de una carga, [tex]U_E[/tex] , se da de la siguiente manera;

[tex]U_E = k \times \dfrac{Q_1 \cdot Q_2}{r}[/tex]

Por lo tanto;

[tex]U_E[/tex] = 9.0×10⁹ × 24 × 10⁻³ × (-12) × 10⁻⁶ /0.032 = -81,000

La energía potencial eléctrica entre la carga, Q₁ y Q₂= -81,000 J

b. El potencial eléctrico de Q₁ en Q₂, V₁ = [tex]k \times \dfrac{Q_1 }{r}[/tex]

Por lo tanto, V₁ = 9.0×10⁹ × 24 × 10⁻³/0.032 = 6.75 × 10⁹

El potencial eléctrico de Q₁ en Q₂, V₁ = 6.75 × 10⁹ V

Answer:

km/hr

Explanation:

Addition and subtraction are commutative

Meaning you can add or subtract in any order because it doesn't change the sum or the difference. So it doesn't change the units.

Answer:

km/ hr + km/ hr =(km+ km)/hr=2km/hr

Explanation:

A simulation study that is used to learn about a planet by simulating as many conditions as possible, you can visualize what the planet might be like and learn things about it without actually visiting it. The correct option is c.

A simulation is a method of simulating a process or change in the actual world to forecast future events or to explain past events and their causes. These days, simulations are frequently carried out using computers. Scientists use simulations to find answers and to test complicated systems.

A fire drill is used in this instance to get everyone ready for an impending event. In fire drills, the fire alarm is sounded even when there isn't actually a fire.

Therefore, the correct option is c.

To learn more about simulation, refer to the link:

https://brainly.com/question/16359096

#SPJ2

option E

3m/s square

hope it helped u

Answer:

A. When the independent variable is continuous and shows a causal link to the dependent variable.

Explanation:

A graph can be defined as the graphical representation of data (informations) on horizontal and vertical lines i.e x-axis and y-axis respectively.

In an experiment , the variable being manipulated by an experimenter is known as an independent variable while the dependent variable is the event expected to change when the independent variable is manipulated

Generally, a line graph should be used when the independent variable is continuous and shows a causal link to the dependent variable.

This ultimately implies that, a line graph should be used when the data changes continuously over time and as such there exist a linear relationship between the data (variables).

Answer:

Explanation:

Because vectors have direction and x and y components you can't just add them and say that their length is 16 because A is 8 units and so is B. What you're actually finding is the magnitude and direction of the vector that results from this addition. The magnitude is the length of the resultant vector, which comes from the x and y components of A and B, and the direction is the angle between the resultant vector and the positive x axis. To add the vectors, then, we need to find the x and y components of each. We'll do the x components of A and B first so we can add them to get the x component of C. Since x values are directly related to cos, the formula to find the x components of vectors is

[tex]V_x=Vcos\theta[/tex] which is the magnitude of the vector (its length) and the angle. Finding the x components of A:

[tex]A_x=8.0cos45[/tex] so

[tex]A_x=5.7[/tex] and for B:

[tex]B_x=8.0cos180[/tex] since the negative x axis is the 180 degree axis and

[tex]B_x=-8.0[/tex] If we add them, we get

[tex]C_x=-2.3[/tex]

Now onto the y components. The formula for that is almost the same as the x components except use sin instead of cos:

[tex]A_y=8.0sin45[/tex] so

[tex]A_y=5.7[/tex] and

[tex]B_y=8.0sin180[/tex] so

[tex]B_y=0[/tex] If we add them, we get

[tex]C_y=5.7[/tex]

Now for the final magnitude:

[tex]C_{mag}=\sqrt{(-2.3)^2+(5.7)^2}[/tex] and

[tex]C_{mag}=6.1 units[/tex] and now onto the direction.

The x component of C is positive and the y component is negative, which means that the direction has us at an angle is quadrant 2; we add 180 to whatever the angle is. Finding the angle:

[tex]tan^{-1}(\frac{C_y}{C_x})=(\frac{5.7}{-2.3})[/tex] = -68 + 180 = 112 degrees

The resultant vector of A + B has a magnitude of 6.1 and a direction of 112°

Do the same thing for subtraction, except if you're subtracting B from A, the direction that B is pointing has to go the opposite way. That means that A doesn't change anything at all, but B is now pointing towards 0.

[tex]A_x=5.7[/tex] (doesn't change from above)

[tex]B_x=8.0cos0[/tex] and

[tex]B_x=8.0[/tex] so

[tex]C_x=13.7[/tex] and

[tex]A_y=5.7[/tex] (also doesn't change from above)

[tex]B_y=8.0sin0[/tex] so

[tex]B_y=0[/tex] and

[tex]C_y=5.7[/tex] and for the magnitude:

[tex]C_{mag}=\sqrt{(13.7)^2+(5.7)^2[/tex] so

[tex]C_{mag}=15units[/tex] and for the direction:

[tex]tan^{-1}(\frac{5.7}{13.7})=23[/tex] and since both x and y components of C are in Q1, we add nothing.

And you're done!!!

Answer:The answer is A

Explanation:just did it on a test

Answer:

Energy and work

.........

Answer:

Explanation:

Hope my answer is helpful to you ✌️❣️☪️❇️☪️❣️✌️

Answer:

0.25p.a

Explanation:

force=15N area=60m²

so pressure =force/area =15N/60m²=0.25p.a

Answer:

HOPE IT HELP YOU A LOT :)

I prove it also .

Answer:

Newtons Second law of motion states that"The rate of change of momentum is directly proportional to the force applied"