Mr. Allway’s math class surveyed all the seventh-grade students to find out their favorite sport. The following circle graph shows a breakdown of the survey findings.

Find the number of degrees represented by Basketball.

108°
101°
11°
140°

Answer:

The last one

Step-by-step explanation:

What we know:

We have a total of 16 coins

The 16 coins consist of dimes and quarters

The value of the coins is 3.10

The value of a dime is .10

The value of a quarter is .25

Using this information we can create a system of linear equations

First off we know that we have a total of 16 coins which consist of dimes and quarters

The number of Quarters can be represented by q and then number of dimes can be represented by d.

If we have a total of 16 coins then q + d must equal 16

So equation 1 is q + d = 16

Now we need to create a second equation

We know that the total value of the coins is 3.10 and we know that the coins consist of dimes and quarters

As you may know a quarter has a value of .25 cents and a dime has a value of 10 cents

If the total value of the coins is 3.10 the the number of dimes (d) times .10 + the number of Quarters times .25 must equal 3.10

This can also be written as

.25q + .10d = 3.10

So the two equations are

q + d = 16 and .25q + .10d = 3.10

These equations are shown in the last answer choice

Note: b is very similar to d

However the the value of the coins are incorrect in B

In B the value of the dime is represented by 10 which is not correct because the value of a dime is .10 not 10

Answer:

so 1/3 must be subtracted from the sum of 1/4 and 1/6 to have an average of 1/12 of all the two fractions.

Step-by-step explanation:

let the fraction be x

(1/4 + 1/6)-x =  1/12

or, 10/24 - x = 1/12

or, 5/12-1/12 = x

so, x = 4/12 = 1/3

9514 1404 393

Answer:

Step-by-step explanation:

Let s represent the number of orders Scott served. Then we have Joe served 3s, and Laura served (s+9). The total of orders served is ...

  3s +s +(s +9) = 104

  5s = 95 . . . . . . . . . . . subtract 9 and collect terms

  s = 19 . . . . . . . . . divide by 5

  3s = 3×19 = 57

  s+9 = 19+9 = 28

Joe served 57 orders, Scott served 19, and Laura served 28 orders.

Answer:

The exponent of y is 1

Step-by-step explanation:

Given

[tex]6xy^2 - 5x^{[]}y^{[]} + 9x^{[]}[/tex]

[tex]degree = 3[/tex]

Required

The exponent of y (second term)

Since the polynomial has a degree of 3, the exponents of y will decrease from left to right (i.e. 2,1,0) while x will increase from left to right (i.e. 1,2,3)

So, we have:

[tex]6xy^2 - 5x^{[]}y^{[]} + 9x^{[]} = 6xy^2 - 5x^{[2]}y^{[1]} + 9x^{[3]}[/tex]

Remove square brackets

[tex]6xy^2 - 5x^{[]}y^{[]} + 9x^{[]} = 6xy^2 - 5x^2y + 9x^3[/tex]

The second term is:

[tex]T_2 =5x^2y[/tex]

The exponent of y is 1

Answer:

Answer:

five kids .each 6 sweaters and 9 trousers

Step-by-step explanation:

Answer: [tex]y=\frac{1}{3}x+\frac{13}{3}[/tex]

Step-by-step explanation:

(slope = m)

[tex]m=\frac{y_2-y_1}{x_2-x_1}=\frac{4-6}{-1-5}=\frac{-2}{-6}=\frac{1}{3}[/tex]

[tex]y=mx+b, (5,6), (-1,4), m=\frac{1}{3}[/tex]

[tex]y=mx+b\\6=\frac{1}{3}(5)+b\\b=6-\frac{5}{3} \\b=\frac{13}{3}\\y=\frac{1}{3}x+\frac{13}{3}[/tex]

Answer:

The price that maximizes the revenue is $165

Step-by-step explanation:

We can model the price as a function of sold units as a linear relationship.

Remember that a linear relationship is something like:

y = a*x + b

where a is the slope and b is the y-intercept.

We know that if the line passes through the points (x₁, y₁) and (x₂, y₂), then the slope can be written as:

a = (y₂ - y₁)/(x₂ - x₁)

For this line, we have the point (40, $110)

which means that to sell 40 units, the price must be $110

And we know that if the price increases by $11, then he will sell 2 units less.

Then we also have the point (38, $121)

So we know that our line passes through the points (40, $110) and  (38, $121)

Then the slope of the line is:

a = ($121 - $110)/(38 - 40) = $11/-2 = -$5.5

Then the equation of the line is:

p(x) = -$5.5*x + b

to find the value of b, we can use the point (40, $110)

This means that when x = 40, the price is $110

then:

p(40) = $110 = -$5.5*40 + b

            $110 = -$220 + b

       $110 + $220 = b

        $330 = b

Then the price equation is:

p(x) = -$5.5*x + $330

Now we want to find the maximum revenue.

The revenue for selling x items, each at the price p(x), is:

revenue = x*p(x)

replacing the p(x) by the equation we get:

revenue = x*(-$5.5*x + $330)

revenue = -$5.5*x^2 + $330*x

Now we want to find the x-value for the maximum revenue.

You can see that the revenue equation is a quadratic equation with a negative leading coefficient. This means that the maximum is at the vertex.

And remember that for a quadratic equation like:

y = a*x^2 + b*x + c

the x-value of the vertex is:

x = -b/2a

Then for our equation:

revenue = -$5.5*x^2 + $330*x

the x-vale of the vertex will be:

x = -$330/(2*-$5.5) = 30

x = 30

This means that the revenue is maximized when we sell 30 units.

And the price is p(x) evaluated in x = 30

p(30) = -$5.5*30 + $330 = $165

The price that maximizes the revenue is $165

Answer:

B. The average weekly score is less than or equal to 7.

Step-by-step explanation:

The average weekly assignment score of students in a statistics class is 7 out of 10 points. Test if it has increased.

This means that at the null hypothesis it is tested that the mean score of the students has not increased, that is, it still is of at most 7, so:

[tex]H_0: \mu \leq 7[/tex]

And thus, the correct answer is given by option b.

Answer:

y = 4x -1.5

Step-by-step explanation:

The slope intercept form of a line is given by

y = mx+b where m is the slope and b is the y intercept

y = 4x -1.5

Answer:

Years = natural log (Total / Principal) / Rate

Years = natural log (1,000,000 / 2,500) / .02

Years = natural log (400) / .02

Years =  5.9914645471 / .02

It would take  299.573227355 Years

Source: http://www.1728.org/rate2.htm

Step-by-step explanation:

Answer:

48 cm²

Step-by-step explanation:

shaded area = area of rectangle - area of triangle

area of rectangle = 7 × 8 = 56 cm²

area of triangle = [tex]\frac{1}{2}[/tex] bh ( b is the base and h the height )

Here b = 7 - 3 = 4 cm and h = 8 - 4 = 4 cm

area of triangle = [tex]\frac{1}{2}[/tex] × 4 × 4 = 2 × 4 = 8 cm²

Then

shaded area = 56 - 8 = 48 cm²

For all questions, use the concept of angles at a point (360°).

I also suggest and recommend that you specify the questions you need help with. It is best if you don't ask your homework here, because homework should be done by you yourself.

Answer:

A

Step-by-step explanation:

(6.2).10=120cm²

Đáp án đó chúc bạn học tốt

9514 1404 393

Answer:

  C)  12 cm

Step-by-step explanation:

In a 30°-60°-90° triangle, the ratios of side lengths are ...

  1 : √3 : 2

This means the hypotenuse (AC) is 2/√3 times the length of the long side (AB).

  (10 cm)(2/√3) = 20/√3 cm ≈ 11.55 cm

Rounded to the nearest cm, the length of AC is 12 cm.

Answer: A) Economic ordering quantity ==$1,300

B)Orders placed during the year=  65 orders

C)average inventory= 650units

D)total cost of ordering and carrying inventory= $1,560

Step-by-step explanation:

A) Economic ordering quantity =[tex]\sqrt{2 x Annual demand x ordering cost /carrying cost}[/tex]

=[tex]\sqrt{2 x 84,500 x 12} /1.20[/tex]

=[tex]\sqrt{1,690,000}[/tex]

=$1,300

B)Orders placed during the year= Annual demand ÷ economic order quantity

= $84,500 ÷ 1,300 units

= 65 orders

C)average inventory= Economic order quantity ÷ 2

= 1,300 units ÷ 2

=650units

D)total cost of ordering and carrying inventory

Ordering cost = Number of orders × ordering cost per order

                         = 65 orders × $12

                                           = $780

Carrying cost = average inventory × carrying cost per unit

                                 = 650 units × $1.20

                                     = $780

The total would be  = $780 + $780 = $1,560

the required ans is 3√b+b/3b

[tex] \displaystyle \int \bf \: \frac{2 \: tan \: x. {sec}^{2} \: x }{1 + {tan}^{2} \: x } \: \: dx \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = 2 \displaystyle \int \bf \: \frac{tan \: x \: . \: \cancel{ {sec}^{2} \: x}}{ \cancel{ {sec}^{2} \: x}} \: \: dx \: \: \: \: \pink{ \{ \because \: {sec}^{2} \: x - {tan}^{2} \: x = 1 \}} \\ \\ = 2 \displaystyle \int \bf \: tan \: x \: \: dx \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = 2 \displaystyle \int \bf \: \frac{sin \: x}{cos \: x} \: \: dx \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = - 2 \displaystyle \int \bf \: \frac{ - \: sin \: x}{ \: cos \: x} \: \: dx\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ = \bf \: - 2 \ln \: |cos \: x| + c\: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \green{ \{ \because \: \displaystyle \int \bf \: \frac{ {f}^{′} (x)}{f(x)} \: dx = \ln \: |f(x)| + c \}}[/tex]

Answer:

The 99% confidence interval for the difference in two proportions is (0.0456, 0.1944).

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

For a proportion p in a sample of size n, the sampling distribution of the sample proportion will be approximately normal with mean [tex]\mu = p[/tex] and standard deviation [tex]s = \sqrt{\frac{p(1-p)}{n}}[/tex]

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Western residents:

39% out of 640, so:

[tex]p_1 = 0.39[/tex]

[tex]s_1 = \sqrt{\frac{0.39*0.61}{640}} = 0.0193[/tex]

Eastern residents:

51% out of 540, so:

[tex]p_2 = 0.51[/tex]

[tex]s_2 = \sqrt{\frac{0.51*0.49}{540}} = 0.0215[/tex]

Distribution of the difference:

[tex]p = p_2 - p_1 = 0.51 - 0.39 = 0.12[/tex]

[tex]s = \sqrt{s_2^2+s_1^2} = \sqrt{0.0215^2+0.0193^2} = 0.0289[/tex]

Confidence interval:

[tex]p \pm zs[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

99% confidence level

So [tex]\alpha = 0.01[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.01}{2} = 0.995[/tex], so [tex]Z = 2.575[/tex].

The lower bound of the interval is:

[tex]p - zs = 0.12 - 2.575*0.0289 = 0.0456[/tex]

The upper bound of the interval is:

[tex]p + zs = 0.12 + 2.575*0.0289 = 0.1944[/tex]

The 99% confidence interval for the difference in two proportions is (0.0456, 0.1944).

Answer:

the answer is b). z- score.

Answer:

b

Step-by-step explanation:

Answer:

Blablabka

Step-by-step explanation:

Blablabla

Answer:

2nd quadrant

Step-by-step explanation

if an angle is between 90 and 180 degrees, it is in the second quardrant. since 0<x<90, 90+x will be more than 90 but less than 180, hence it lies in the second quadrant

(1) D

[tex]L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt[/tex]

Integrate by parts, taking

[tex]u = t \implies \mathrm du=\mathrm dt[/tex]

[tex]\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}[/tex]

Then

[tex]L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]

[tex]L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt[/tex]

[tex]L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}[/tex]

[tex]L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}[/tex]

(2) A

[tex]L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt[/tex]

[tex]L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}[/tex]

[tex]L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}[/tex]

Answer:

5years, 3months, 16 days

because it's value will always be same

Answer:

This value doesn't depend on x or y

It'll be the same things always

[tex]11.4[/tex]

[tex] \to \: 1.14 \times {10}^{1} [/tex]

Answer:

True

Step-by-step explanation:

64 - x^2

Rewriting as

8^2 - x^2

(8-x)(8+x)

This is the difference of squares

Answer:

it should be letter c 5/3 I could be wrong but I hope this help