9514 1404 393
Answer:
1 11/49 ≈ 1.224 miles
Step-by-step explanation:
Let m represent the length of the morning walk. Then the length of the evening walk is 2.5m, and the total each day is m+2.5m = 3.5m.
The total for 7 days is ...
7(3.5m) = 30
m = 30/24.5 = 60/49 ≈ 1.224 . . . . miles
Mia's morning walks are 1 11/49 miles, about 1.224 miles.
IF ANYONE IS READING THIS AND IS TIRED OF BOTS, MAY I PLEASE GET SOME HELP?
You deposit $400 in an account earning 5% interest compounded annually. How much will you have in the account in 15 years?
I'm a little bit stuck.
A(t)=P(1+r)t
A = accrued amount = what you are solving for
P = principle investment = $400
r = rate of growth = 5% = 0.05
t = time = 10 years
A(10) = 400(1.05)10 (use calculator to solve)
A(10) ≈ 4,200
Describe and correct the error in determining the formula for the sequence below
Answer:An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. For instance, the sequence 5, 7, 9, 11, 13, 15.. . is an arithmetic progression with a common difference of 2.
Step-by-step explanation:
I need help completing this answer are you available
Answer:
Step-by-step explanation:
4. Tony bought a computer, a cell
phone, and a television. The
computer costs 2.5 times as much
as the television. The television cost 5 times as much as the cell phone. If Tony spent a total of $925, how much did the cell phone
cost?
Answer:
$50
Step-by-step explanation:
Let x represent the cost of the cell phone.
Since the TV cost 5 times as much as the cell phone, its cost can be represented by 5x.
Since the computer cost 2.5 times as much as the TV, its cost can be represented by 12.5x.
Create an equation to represent the situation, and solve for x:
x + 5x + 12.5x = 925
18.5x = 925
x = 50
So, the cell phone cost $50
Answer:
$50
Step-by-step explanation:
Let x represent the cost of the cell phone.
Since the TV cost 5 times as much as the cell phone, its cost can be represented by 5x.
Since the computer cost 2.5 times as much as the TV, its cost can be represented by 12.5x.
Create an equation to represent the situation, and solve for x:
x + 5x + 12.5x = 925
18.5x = 925
x = 50
So, the cell phone cost $50
A bicyclist is at point A on a paved road and must ride to point C on another paved road. The two roads meet at
an angle of 38° at point B. The distance from A to B is 18 mi, and the distance from B to C is 12 mi (see
the figure). If the bicyclist can ride 22 mph on the paved roads and 6.8 mph off-road, would it be faster for the bicyclist to ride from A to C on the paved roads or to ride a direct line from A to C off-road? Explain.
Answer:
Step-by-step explanation:
The diagrammatic expression to understand this question very well is attached in the image below.
By applying the law of cosine rule; we have:
a² = b² + c² - 2bc Cos A --- (1)b² = a² + c² - 2ac Cos B --- (2)c² = a² + b² - 2ab Cos C --- (3)From the diagram attached below, we need to determine the side "b" by using equation (2) from above:
b² = a² + c² - 2ac Cos B
From the information given:
a = 12 miles; c = 18 miles; ∠B = 38°
∴
replacing the values into the above equation:
b² = 12² + 18² - 2(12)(18) Cos (38°)
b² = 144 + 324 - 432 × (0.7880)
b² = 468 - 340.416
b² = 127.584
[tex]b = \sqrt{127.584}[/tex]
b = 11.30 miles
However, we are also being told that the speed from A → C = 6.8 mph
Thus, the time required to go from A → C can be determined by using the relation:
[tex]\mathbf{speed = \dfrac{distance}{time}}[/tex]
making time the subject of the formula, we have:
[tex]\mathbf{time= \dfrac{distance}{speed }}[/tex]
[tex]\mathbf{time= \dfrac{11.30}{6.8}}[/tex]
time = 1.66 hours
By using the paved roads, the speed is given as = 22 mph
thus, the total distance covered = |AB| + |BC|
= (18+12) miles
= 30 miles
∴
[tex]\mathbf{time= \dfrac{distance}{speed }}[/tex]
[tex]\mathbf{time= \dfrac{30}{22}}[/tex]
time = 1.36 hours
Therefore, the time used off-road = 1.661 hours while the time used on the paved road is 1.36 hours.
Since we are considering the shortest time possible;
We can conclude that it would be faster for the bicyclist to ride from A to C on the paved roads since it takes a shorter time to reach its destination compared to the time used off-road.
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It would be faster for the bicyclist to ride from A to C on the paved roads since the time to go from A to C on the paved roads is 1.4 h and the time to go from A to C off-road is 1.7 h.
To calculate which way would be faster we need to find the distance from point A to C with the law of cosines:
[tex] \overline{AC}^{2} = \overline{AB}^{2} + \overline{BC}^{2} - 2\overline{AB}\overline{BC}cos(38) [/tex]
Where:
[tex]\overline{AB}[/tex]: is the distance between the point A and B = 18 mi
[tex]\overline{BC}[/tex]: is the distance between the point B and C = 12 mi
[tex] \overline{AC} = \sqrt{(18 mi)^{2} + (12 mi)^{2} - 2*18 mi*12 mi*cos(38)} = 11.3 mi [/tex]
Now, let's find the time for the two following cases.
1. From point A to C on the paved roads (t₁)
[tex] t_{1} = t_{AB} + t_{BC} [/tex]
The time can be calculated with the following equation:
[tex] t = \frac{d}{v} [/tex] (1)
Where:
d: is the distance
v: is the velocity
Then, the total time that it takes the bicyclist to go from point A to C on the paved roads is:
[tex] t_{1} = t_{AB} + t_{BC} = \frac{18 mi}{22 mph} + \frac{12 mi}{22 mph} = 1.4 h = 84 min [/tex]
2. From point A to C off-road (t₂)
With equation (1) we can calculate the time to go from point A to C off-road:
[tex] t_{2} = \frac{\overline{AC}}{v_{2}} = \frac{11.3 mi}{6.8 mph} = 1.7 h = 102 min [/tex]
Therefore, it would be faster for the bicyclist to ride from A to C on the paved roads.
To find more about the law of cosines, go here: https://brainly.com/question/15740431?referrer=searchResults
I hope it helps you!
Help!!
A.) find f^-1 and use it to evaluate: f^-1(12)
B.) write a formula for the function g(x) that results when the parent function: f(x) = x^3 is vertically stretched by a factor of three, shifted to the left by 4 units and shifted down by 5 units
Answer:
Step-by-step explanation:
y = x³
x = ∛y
Switch x and y:
y = ∛x
f⁻¹(x) = ∛x
f⁻¹(12) = ∛12 ≅ 2.29
check:
x = 2.29
f(x) = 2.29³ ≅ 12
Prove that if (c, f(c)) is a point of inflection of the graph of f and f'' exists in an open interval that contains c, then f''(c)=0 Hint: Apply the First Derivative Test and Fermat's Theorem to the function g=f'
We can conclude that if (c, f(c)) is a point of inflection of the graph of f and f'' exists in an open interval that contains c, then f''(c)=0.
What is the differentiation?The process of finding derivatives of a function is called differentiation in calculus. A derivative is the rate of change of a function with respect to another quantity.
We can prove this statement using the First Derivative Test and Fermat's Theorem.
First, we know from the First Derivative Test that at a point of inflection, the first derivative of the function (in this case, f') must equal 0. Therefore, at the point (c, f(c)), f'(c) = 0.
Next, we can apply Fermat's Theorem. This theorem states that if a function f has a local maximum or minimum at c, then f'(c) = 0. Since the point (c, f(c)) is a point of inflection, we can apply Fermat's Theorem to say that f'(c) = 0.
Now, since f'' exists in an open interval that contains c, we can use the fact that if f'(c) = 0, then f''(c) = 0.
Therefore, we can conclude that if (c, f(c)) is a point of inflection of the graph of f and f'' exists in an open interval that contains c, then f''(c)=0.
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Suppose there is a 11.3% probability that a randomly selected person aged 30 years or older is a smoker. In addition, there is a 23.3% probability that a randomly selected person aged 30 years or older is male given that he or she smokes. What is the probability that a randomly selected person aged 30 years or older is male and smokes? Would it be unusual to randomly select a person aged 30 years or older who is
male and smokes?
Answer:
2.63%
Step-by-step explanation:
11.3/100*23.3/100*100%
the ordered pairs belonging to the relation
S = {(x, y): 2x = 3y}
Answer:
{(0, 0), (1, ⅔), (2, 4/3), (3, 2)…}
The fraction model below shows the steps that a student performed to find a quotient. Which statement best interprets the quotient? A: There are 5 1/5 five-sixths in 4 1/3. B: There 6 1/6 five sixths-in 4 1/3. C: There are 5 1/5 four and one-thirds in 5/6. D: There are 6 1/6 four and one-thirds in 5/6.
Answer:
The answer is D
Step-by-step explanation:
there are 8 1/6 five and one sixth in 2/3
Please
Help me asap!!
Answer:
z -2 = 10
Step-by-step explanation:
11z-9-10z+7 = 10
Combine like terms on the left side
11z -10z -9+7 =10
z -2 = 10
Answer: z=12
Step-by-step explanation:
[tex]11z-9-10z+7=10\\z-9+7=10\\z-2=10\\z=12[/tex]
solve x, DO NOT GIVE EXPLANATION
Answer:
Step-by-step explanation:
Find the length of side
x in simplest radical form with a rational denominator.
Thanks in advance
Answer:
2
Step-by-step explanation:
Pythagoras. c² = a² + b²
since both "side angles" are equal (45 degrees), we know it is an isosceles triangle, that means also the other side = x.
and so,
8 = x² + x² = 2x²
4 = x²
x = 2
Answer:
x = 2
Step-by-step explanation:
sin(45)/x = sin(90)/[tex]\sqrt{8}[/tex]
[tex]\sin \left(45^{\circ \:}\right)=\frac{\sqrt{2}}{2}[/tex]
x = [tex]\sqrt{8}[/tex] [tex]\sin \left(45^{\circ \:}\right)[/tex]
[tex]x = \sqrt{8} \frac{\sqrt{2}}{2}[/tex]
x = [tex]\frac{\sqrt{16} }{2}[/tex]
x = 4/2
x = 2
g) Find the mean, median and mode
(11points)
Answer:
Mean = 36.67
Median = 36.5
Mode = 38
Step-by-step explanation:
Mean = [(35*8) + (37*7) + (37*4) + (38*9) + (39*2)] / (8+7+4+9+2)
Mean = (280 + 252 + 148 + 342 + 78) / 30
Mean = 1100 / 30 = 36.67
Median = Frequency of 35 and 36 is 15 total. Frequency of 37, 38, and 39 is the remainder 15 total. (36+37)/2 = 36.5
Mode = the most frequently-ocurring number = 38 (frequency of 9)
Which of the following theorems verifies that A DEF - AXZY?
O A. LL
B. HA
C. HL
D. AA
HA
Step-by-step explanation:See In Triangle DEF and Triangle XZY
[tex]\because\begin{cases}\sf \angle E=\angle Z=90° \\ \sf \ FD\sim XY=Hypotenuse\end{cases}[/tex]
Hence
[tex]\sf \Delta DEF\sim \Delta XZY(Angle-Angle)[/tex]
The theorems that verify that Δ DEF ~ Δ XZY is AA theorem of similarity.
What are similar triangles?Two triangles are said to be similar if their corresponding angles are congruent and the corresponding sides are in proportion.
Given that, two triangles, Δ DEF and Δ XZY, we need to find a theorem that will verify that, Δ DEF and Δ XZY are similar,
So, we have, ∠ X = 40°,
Therefore, ∠ Y = 90°-40° = 50°
Now, we get,
∠ Y = ∠ F = 50°
∠ E = ∠ Z = 90°
We know that,
if two pairs of corresponding angles are congruent, then the triangles are similar.
Therefore, Δ DEF ~ Δ XZY by AA rule
Hence, the theorems that verify that Δ DEF ~ Δ XZY is AA theorem of similarity.
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The length of a picture is 14.25 inches shorter than twice the width period if the perimeter of the picture is 133.5 inches, find its dimensions
Answer: Dimension = 27 inches by 39.75 inches
Concept:
A perimeter is a path that encompasses/surrounds/outlines a shape.
Perimeter (rectangle) = 2 (l + w)
l = length
w = width
Solve:
l = 2w - 14.25
w = w
P = 133.5
Given equation
P = 2 (l + w)
Substitute values into the equation
133.5 = 2 (2w - 14.25 + w)
Combine like terms
133.5 = 2 (3w - 14.25)
Distributive property
133.5 = 6w - 28.5
Add 28.5 on both sides
133.5 + 28.5 = 6w - 28.5 + 28.5
162 = 6w
Divide 6 on both sides
162 / 6 = 6w / 6
w = 27 in
l = 2w - 14.25 = 2 (27) - 14.25 = 39.75 in
Hope this helps!! :)
Please let me know if you have any questions
What's the measure of an arc with a central angle of 120°?
Answer:
the answer is 240 degrees
What is the length of BC in the right triangle below?
B
00
A
15
с
A. 17
B. 60
C. 17
D. 289
Using Pythagorean Theorem
[tex]\\ \sf\longmapsto H^2=P^2+B^2[/tex]
[tex]\\ \sf\longmapsto H^2=8^2+15^2[/tex]
[tex]\\ \sf\longmapsto H^2=64+225[/tex]
[tex]\\ \sf\longmapsto H^2=289[/tex]
[tex]\\ \sf\longmapsto H=\sqrt{289}[/tex]
[tex]\\ \sf\longmapsto H=17[/tex]
BC=17I will mark as brainliest:)
Answer:
Point E.
.................
In the figure, ΔABC and ΔDEF are similar. What’s the scale factor from ΔABC to ΔDEF?
How do we solve this?
Answer:
[tex] = - \frac{1}{36(6x + 1) ^{6} } + c[/tex]
I hope I helped you^_^Answer:
[tex]-\frac{1}{36\left(6x+1\right)^6} +C[/tex]
Step-by-step explanation:
we're going to us u substitution
[tex]\int (6x+1)^-7 dx[/tex]
[tex]u=6x+1[/tex]
[tex]\int\frac{1}{6u^7} du[/tex]
take out the constant, [tex]\frac{1}{6}[/tex]
[tex]\frac{1}{6}[/tex] · [tex]\int u^-7du[/tex]
next use the power rule, [tex]\int x^adx=\frac{x^{a+1}}{a+1},\:\quad \:a\ne -1[/tex]
[tex]\frac{1}{6}\cdot \frac{u^{-7+1}}{-7+1}[/tex]
simplify by substituting [tex]6x+1[/tex] for [tex]u[/tex]
[tex]\frac{1}{6}\cdot \frac{(6x+1)^{-7+1}}{-7+1} = -\frac{1}{36\left(6x+1\right)^6}[/tex]
add a constant, [tex]C[/tex]
[tex]-\frac{1}{36\left(6x+1\right)^6} +C[/tex]
Two metal spheres of diameter 2.3cm and 3.86cm are melted. The molten material is used to cast equal cylindrical slabs of radius 8mm and length 70mm. If 1/2 of the metal is lost during casting. Calculate the number of complete slabs casted.
Answer:
4
Step-by-step explanation:
If 1/20 of the metal is lost during casting. Calculate the number of complete slabs casted. (4mks)
The enrollment of students in evening classes at a local university decreased by 8% between two recent years. If the total number of students attending
evening classes in both years was 13,876, find how many students enrolled in evening classes in each of the years.
9514 1404 393
Answer:
72276649Step-by-step explanation:
Let x represent the enrollment the first year. Then x(1 -8%) = 0.92x represents the enrollment the second year. The total for the two years is ...
x + 0.92x = 13,876
x = 13,876/1.92 = 7227.083 ≈ 7227 . . . . students the first year
13876 -7227 = 6649 . . . . students the second year
Suppose the bacteria population in a specimen increases at a rate proportional to the population at each moment. There were 100 bacteria 4 days ago and 100,000 bacteria 2 days ago. How many bacteria will there be by tomorrow
9514 1404 393
Answer:
about 3,160,000,000
Step-by-step explanation:
"Increases at a rate proportional to population" means the growth is exponential. It can be modeled by the equation ...
p = ab^t
We can find 'a' and 'b' using the given data points.
100 = ab^(-4) . . . . . . . population 4 days ago
100,000 = ab^(-2) . . . population 2 days ago
Dividing the second equation by the first, we find ...
1000 = b^2
b = 1000^(1/2)
Substituting for b in the first equation, we have ...
100 = a(1000^(1/2))^(-4) = a(1000^-2)
100,000,000 = a
Then the population model is ...
p = 100,000,000×1000^(t/2)
__
Tomorrow (t=1), the population will be ...
p = 100,000,000 × 1000^(1/2) ≈ 31.6 × 100,000,000
p ≈ 3,160,000,000 . . . . . bacteria by tomorrow
_____
Additional comment
We could write this as ...
p = 10^(8+1.5t)
Then for t=1, this is p = 10^(8+1.5) = 10^0.5 × 10^9 = 3.16×10^9
Using the identity. (a - b) ²= (a² - 2ab + b²), evaluate 699²
Step-by-step explanation:
hope it helps you.......
[tex]\\ \sf\longmapsto 699^2[/tex]
[tex]\\ \sf\longmapsto (700-1)^2[/tex]
[tex]\\ \sf\longmapsto 700^2-2(700(1)+(1)^2[/tex]
[tex]\\ \sf\longmapsto 490000-1400+1[/tex]
[tex]\\ \sf\longmapsto 488600+1[/tex]
[tex]\\ \sf\longmapsto 488601[/tex]
In the following problem, the ratios are directly proportional. Find the missing variable.
If y1 = 4, x2 = 6, and y2 = 8, what is the value of x1?
Answer:
x1 = 3
Step-by-step explanation:
first set up the proportion (write as fractions):
(y1/x1) = (y2/x2)
then fill in the variables:
4/x1 = 8/6
now cross multiply:
8 • x1 = 6 • 4
simple algebra:
8 • x1 = 24
x1 = 24/8
x1 = 3
If y1 = 4, x2 = 6, and y2 = 8, then the value of x1 is 3 which we can solve using ratios.
In a directly proportional relationship, the ratios between the corresponding values of two variables remain constant. This constant ratio is often referred to as the "proportionality constant."
In this problem, you have two pairs of values: (x1, y1) and (x2, y2). We're given that the ratios are directly proportional, which means:
x1 / y1 = x2 / y2
Plugging in the given values:
x1 / 4 = 6 / 8
Now, cross-multiply to solve for x1:
x1 * 8 = 4 * 6
x1 = 24 / 8
x1 = 3
Therefore, the value of x1 is 3.
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[tex]3^n^+^1+9/3^n^-^1+1[/tex]
how do i solve it?
Answer:
Hello,
Step-by-step explanation:
[tex]\dfrac{3^{n+1}+9}{3^{n-1}+1} \\\\=\dfrac{9*(3^{n-1}+1)}{3^{n-1}+1}\\\\=9\\[/tex]
Which equation is represented by the table?
Find the length of the segment indicated.
A. 16.4
B. 11.4
C. 12.1
D. 13.3
using Pythagorean triplet
[tex]\\ \sf\longmapsto P^2=H^2-B^2[/tex]
[tex]\\ \sf\longmapsto x^2=19.6^2-15.4^2[/tex]
[tex]\\ \sf\longmapsto x^2=384.16-237.16[/tex]
[tex]\\ \sf\longmapsto x^2=147[/tex]
[tex]\\ \sf\longmapsto x=\sqrt{147}[/tex]
[tex]\\ \sf\longmapsto x=12.1[/tex]
Answer:
C.) 12.1
Step-by-step explanation:
I got it correct on founders edtell
Find the slope of the line passing through the points (-1, 7) and (-5, 1)
Answer:
3/2
Step-by-step explanation:
y2 - y1 / x2 - x1
1 - 7 / -5 - (-1)
-6 / -4
= 3/2
Answer:
m=3/2
Step-by-step explanation:
m=y2-y1/x2-x1
m=1-7/-5-(-1)
m=-6/-4
m=3/2
