Answer:
F = 27
Step-by-step explanation:
50/2 = (F - 3) + 1
25 = F - 2
F = 27
Complete the function table
I am planning to attend a company-paid conference. My charges will include $412.00 for airfare, $378.00 for conference registration, and $210.00 for food.”
Supervisor: “Please submit an expense form for a total of __________ when you return.”
Answer:
$1000.00
Step-by-step explanation:
The supervisor is asking for an expense form of a total (?) when you return.
Given the charges given in the word problem, it is only logical to assume the supervisor wants a expense form of how much you spent (total) on the trip. Thus, you add!
Evaluate: 2-4
1
O A.
loo
O B.-8
O c.
1
16
O D.-16
Answer:
c is the answer
[tex] \frac{1}{16} [/tex]
Simplify: 6x^-2
a) 1/6x^2
b) 6/x^2
c) x^2/6
d) 1/36x^2
Answer:
The correct answer choice is option B. 6/x^2
Step-by-step explanation:
Answer:
6/x^2
Step-by-step explanation:
6 * x^-2
We know that a^ -b = 1/a^b
6 * 1/x^2
6/x^2
Rosa brought d drawings to an art show. After selling 15 of them, she had 38
left. Identify the equation that represents this situation and the correct
solution
Answer:
38= d - 15
Step-by-step explanation:
Someone help please
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Answer:
B.
Step-by-step explanation:
The relation between a function f(x) and its inverse g(x) is ...
f(g(x)) = g(f(x)) = x
On can compute these functions of functions, or take an easier route and do the computation with a couple of numbers. It is often easiest to use x=0 or x=1. If we find g(f(x)) ≠ x, then we know the functions are not inverses. If we find g(f(x)) = x for one particular value of x, then we need to try at least one more to verify the relation.
__
If we call the two given functions f and g, then we have ...
A. f(0) = -2/3, g(-2/3) ≠ 0 . . . . not inverses
__
B. f(0) = -3/2, g(-3/2) = 0 . . . . possible inverses
f(1) = 4/2 = 2, g(2) = 7/7 = 1 . . . . probable inverses
__
C. f(0) = -2, g(-2) = 0 . . . . possible inverses
f(1) = 1/2, g(1/2) = -5/3 . . . . not inverses
__
D. f(0) = 5, g(5) = 27 . . . . not inverses
_____
Additional comment
Our assessment above is sufficiently convincing to let us choose an answer. If we want to verify the functions are inverses, we need to graph them or compute f(g(x)). The graph in the second attachment shows each appears to be the reflection of the other in the line y=x, as required of function inverses.
When graphing the inequality y ≤ 2x − 4, the boundary line needs to be graphed first. Which graph correctly shows the boundary line?
Answer:
See Below
Step-by-step explanation:
The boundary line follows the graph of y = 2x - 4 because it represents the line of maximum or minimum values the graph could take. y = 2x - 4 has a y-intercept of -4 because it is in slope-intercept form. It also has a slope of 2, so to find another point on the line, you can go up two and right one. Also, this inequality has a solid line because it is "less than or equal to" and a solid line represents the values that equal.
If f(x)=logx, show that f(x+h)-f(x)/h=log[1+h/x]^1/h, h=/=0 (Picture attached, thank you!)
Answer:
Step by step proof shown below.
Step-by-step explanation:
To prove the equation, you need to apply the Logarithm quotient rule and the Logarithm power rule. Here's how the quotient rule looks like.
[tex]log_b(x/y) = log_b(x) - log_b(y)[/tex]
And here's how the power rule looks like
[tex]log_a(x)^n = nlog_a(x)[/tex]
First let's apply the quotient rule.
[tex]\frac{f(x+h)-f(x)}{h} = \frac{log_a(x+h)-log_a(x) }{h} = \frac{log_a(\frac{x+h}{x} )}{h}[/tex]
Now we can do some quick simplification, and apply the power rule.
[tex]\frac{1}{h} log_a(1 + \frac{h}{x} ) = log_a(1+\frac{h}{x} )^\frac{1}{h}[/tex]
Find the cosine of the angle between the planes x+y+z=0 and 4x+3y+z=1.
Answer: cosθ=
The angle between the planes is the same as the angle between their normal vectors, which are
n₁ = ⟨1, 1, 1⟩
n₂ = ⟨4, 3, 1⟩
The angle θ between the vectors is such that
⟨1, 1, 1⟩ • ⟨4, 3, 1⟩ = ||⟨1, 1, 1⟩|| ||⟨4, 3, 1⟩|| cos(θ)
Solve for cos(θ) :
4 + 3 + 1 = √(1² + 1² + 1²) √(4² + 3² + 1²) cos(θ)
8 = √3 √26 cos(θ)
cos(θ) = 8/√78
What is the mean for the data shown in the line plot?
5 and 7
5
4
8
Answer:
The mean of the data: 5,7,5,4,8 is 5.8
Step-by-step explanation:
To find the mean, add up the numbers, then divide them by the number of data points. So 5 + 7 + 5 + 4 + 8 = 29, and 29 divided by 5 is 5.8
express 24.123eight to base ten
To convert [tex]24.123[/tex] in base 8, also notated with [tex]24.123_8[/tex] into base 10 simply multiply each digit with 8 to the power of its position relative to the decimal point.
So,
[tex]24.123_8=2\cdot8^1+4\cdot8^0+1\cdot8^{-1}+2\cdot8^{-2}+3\cdot8^{-3}=20.162109375_{10}[/tex]
Hope this helps :)
What is the point-slope form of a line with slope -4 that contains the point
(-2, 3)?
A. y + 3 = 4(x + 2)
B. y - 3 = -4(x + 2)
c. y + 3 = -4(x - 2)
D. y - 3 = 4(x + 2)
Answer:
y-3 = -4(x+2)
Step-by-step explanation:
Point slope form is
y-y1 = m(x-x1) where m is the slope and (x1,y1) is a point on the line
y-3 = -4(x --2)
y-3 = -4(x+2)
write each equation explicitly in terms of x. then indicate whether the equation is a function.
3xy+x=y-6
We usually write explicit functions as one variable in terms of another variable. A simple example of an explicit function is a linear function, such as y = 4x - 7. This function is written as the dependent variable y in terms of the independent variable x.
What is the solution to the system of equations?
y = 2/3x+3
x=-2
Answer:
solution (-2, 5/3 ).
Step-by-step explanation:
Given : y = + 3 and x = –2.
To find : What is the solution to the system of equations.
Solution : We have given that y = + 3 ------equation (1)
and x = –2. ------equation (2)
On plugging the x = -2 in equation (1)
y = + 3
y = + 3 .
On simplification we get ,
y = .
Therefore, solution (-2, 5/3 ).
Evaluate the line integral
Soydx + zdy + xdz,
[»= f (t)=dw= f'(t)dt
where C is the parametric curve
x=t, y=t, z=ť, Ost<1.
It looks like you're asked to compute
[tex]\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz[/tex]
where C is parameterized by ⟨t, t, t⟩ with 0 ≤ t ≤ 1.
In other words, x = y = z = t, so dx = dy = dz = dt, and the integral reduces to
[tex]\displaystyle\int_C y\,\mathrm dx + z\,\mathrm dy + x\,\mathrm dz = \int_0^1 t\,\mathrm dt + t\,\mathrm dt + t\,\mathrm dt \\\\ = 3 \int_0^1 t\,\mathrm dt \\\\ =\frac32t^2\bigg|_{t=0}^{t=1} \\\\ =\boxed{\frac32}[/tex]
Find the length of the arc.
A. 539π/12 km
B. 9π/3 km
C. 9π/2 km
D. 18π km
Answer:
b because it is I found out cus I took test
The length of the arc 9π/2 km.
The answer is option C.9π/2 km.
What is the arc of the circle?
The arc period of a circle can be calculated with the radius and relevant perspective using the arc period method.
⇒angle= arc/radius
⇒ 135°=arc/6km
⇒ arc =135°*6km
⇒arc=135°*π/180° * 6km
⇒arc = 9π/2 km
Learn more about circle here:-https://brainly.com/question/24375372
#SPJ2
1.8 times 15.42 please this question has me stuck
Answer:
27.756
Step-by-step explanation:
1) Move all the decimal points to the right and do the multiplication
18 * 1524 = 27756
1.8 to 19 = one move
15.42 to 1542 = two moves
total three decimal point shifts
2) count the number (total) that you moved the decimal points
3) starting from the right move the decimal point that many times to the LEFT in for the answer
27.756
Using stoke theorem evaluate integral F.dr given that F(x,y,z) = z^2i + 2xj + y^2k and the normal surface is given by s: z = 1-x^2-y^2
Your description of the surface is incomplete. But it looks like you're considering some subset of the paraboloid z = 1 - x ² - y ², so I'll go ahead and assume it's the part of said paraboloid above the x,y-plane, so that the boundary is a circle centered at the origin with radius 1.
By Stokes' theorem, the line integral of F along this boundary (∂S) is equal to the surface integral of curl(F ) over the surface itself (S). We have
F(x, y, z) = z ² i + 2x j + y ² k
which has curl
curl(F ) = (∂(y ²)/∂y - ∂(2x)/∂z) i - (∂(y ²)/∂x - ∂(z ²)/∂z) j + (∂(2x)/∂x - ∂(z ²)/∂y) k
curl(F ) = 2y i + 2z j + 2k
Parameterize S by the vector function,
r(u, v) = u cos(v) i + u sin(v) j + (1 - u ²) k
with 0 ≤ u ≤ 1 and 0 ≤ v ≤ 2π.
Take the upward-pointing normal vector to S to be
n = ∂r/∂v × ∂r/∂u
n = (-u sin(v) i + u cos(v) j ) × (cos(v) i + sin(v) j - 2u k)
n = 2u ² cos(v) i + 2u ² sin(v) j + u k
Then the integral of curl(F ) over S - and hence the line integral of F over ∂S - is
[tex]\displaystyle \iint_S \mathrm{curl}(\mathbf F(x,y,z))\cdot\mathbf S \\\\ = \iint_S \mathrm{curl}(\mathbf F(\mathbf r(u,v)))\cdot\mathbf n\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\int_0^1 \left(2u\sin(v)\,\mathbf i + 2(1-u^2)\,\mathbf j + 2\,\mathbf k\right)\cdot\left(2u^2\cos(v)\,\mathbf i+2u^2\sin(v)\,\mathbf j+u\,\mathbf k\right)\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\int_0^1 \left(4u^3\sin(v)\cos(v)+4(1-u^2)u^2\sin(v)+2u\right)\,\mathrm du\,\mathrm dv \\\\ = \int_0^{2\pi}\left(\sin(v)\cos(v)+\frac8{15}\sin(v)+1\right)\,\mathrm dv \\\\ = \boxed{2\pi}[/tex]
Just to confirm this result, we can compute the line integral directly, since it's not so difficult to deal with. Parameterize ∂S by the vector function
r(t) = cos(t ) i + sin(t ) j
with 0 ≤ t ≤ 2π. (Note that there is a k component, but its coefficient is 0.) Then
dr/dt = -sin(t ) i + cos(t ) j
and the line integral is again
[tex]\displaystyle \int_{\partial S}\mathbf F(x,y,z)\cdot\mathrm d\mathbf r \\\\ = \int_{\partial S} \mathbf F(\mathbf r(t))\cdot\frac{\mathrm d\mathbf r}{\mathrm dt}\,\mathrm dt \\\\= \int_0^{2\pi} (\cos(t)\,\mathbf i+\sin(t)\,\mathbf j)\cdot(-\sin(t)\,\mathbf i+\cos(t)\,\mathbf j)\,\mathrm dt \\\\ = \int_0^{2\pi}2\cos^2(t)\,\mathrm dt \\\\ = \boxed{2\pi}[/tex]
Which graph best represents the equation –x + 2y = 4?
Answer:
C
Step-by-step explanation:
Convert the equation into slope intercept form : y=mx+b
2y=x+4
y=1/2x + 2
The m is the slope and the b is the y intercept
In this equation, the slope is 1/2 and the y intercept is 2
The only graph with y intercept 2 is C
Express 456782 to 2 significant figures
Answer:
the answer for this is 45*10^4
ASAP ITS TIMED 109
4 2
3 3
Which expression is equivalent to X X
?
o
NO
NIC
X
27
o
7
3
х
Answer:
x^2/3
Step-by-step explanation:
We know that a^b * a^c = a^(b+c)
x ^ 4/3 * x^ 2/3 = x^(4/3+2/3) = x^(6/3) = x^2
x^2 ^ 1/3
We know that a^b^c = a^(b*c)
x^(2*1/3) = x^2/3
Tina invests $3,700 into an account with a 4.4% interest that is compounded quarterly. How much money will she have in
this account if she keeps it for 8 years?
Round your answer to the nearest cent.
Do NOT round until you have calculated the final answer.
Answer:
bacoot anjing
lo siapa hah kan bisa jawab sendiri sok sok minta bantuuuu
Step-by-step explanation:
maluiiin
Answer:
$5250.96
Step-by-step explanation:
Future value= Present value(1+r)^n
=3700(1+0.011)^32
r=4.4÷100÷4
n=8×4
A bank quotes an interest rate as 0.06341 annual effective yield. What interest rate, compounded monthly, will provide that
annual effective interest rate? Round your answer to five decimal places and do not round any intermediate calculations to
less than seven decimal places.
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Answer:
0.06164
Step-by-step explanation:
The effective annual rate obtained by compounding nominal annual rate r monthly is ...
eff rate = (1 +r/12)^12 -1
Then the value of r is ...
r = 12×((eff rate) +1)^(1/12) -1)
For the given effective rate, that is ...
r = 12×(1.06341^(1/12) -1) ≈ 0.06164 . . . . nominal annual interest rate
Side note: It’s ratio math
In the 15 years from 1991 through 2006, a musical performance was performed on a famous street 5579 times. What was the average rate of performances per year?
The average rate was performances per year
(Simplify your answer. Round to the nearest whole number as needed.)
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[2 ÷ (4 - 2) + 8^2] - [2 - (-1) ] ^2
A. 62
B.60
C.56
Answer:
56
Step-by-step explanation:
[2 ÷ (4 - 2) + 8^2] - [2 - (-1) ] ^2
Brackets first
Then parentheses in the brackets
[2 ÷ 2 + 8^2] - [2 - (-1) ] ^2
Exponents in the brackets
[2 ÷ 2 + 64] - [2 - (-1) ] ^2
Divide
[1+64] - [2 - (-1) ] ^2
Add and subtract in the brackets
[65] - [3 ] ^2
Exponents
[65] - [9 ]
Subtract
56
Find out vector product of 3i+8j-5k and -2i+9j+7k.
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Answer:
101i -11j +43k
Step-by-step explanation:
A suitable calculator can find the cross product for you, or you can evaluate the determinant ...
[tex]\left|\begin{array}{ccc}i&j&k\\3&8&-5\\-2&9&7\end{array}\right|=i(8\cdot7-9(-5))-j(3\cdot7-(-2)(-5))+k(3\cdot9-(-2)(8))\\\\=\boxed{101i-11j+43k}[/tex]
All quesions please. As fast as possible would be nice
Answer:
Vhjaakkjvvkllmn aar
Step-by-step explanation:
Vbkisavn
Vhikjsqiol
NG Jill quolk
Hill s njknbn
How do I determine which is y=-1/3x+2?
Step-by-step explanation:
This is a linear equation in slope intercept form which is
[tex]y = mx + b[/tex]
where m is the slope and b is the y intercept.
The equation
[tex]y = - \frac{1}{3} x + 2[/tex]
Has a slope of -1/3 so this means that the slope will be decreasing. A negative linear equation increases as we go left. and decreases as we go right. The y intercept is 2. So this means the graph must pass through (0,2) and when x=0, y must be 2.
In other words, look for a line that the y values increase as we go left and decrease we go right. Also look for a point (0,2) and make sure the graph pass through it.
The Pool Fun Company has learned that, by pricing a newly released Fun Noodle at $2, sales will reach 6000 Fun Noodles per day during the summer. Raising the price to 3$ will cause the sales to fall to 5000 Fun Noodles per day.
a. Assume that the relationship between sales price, x, and number of Fun Noodles sold, y, is linear. Write an equation in slope-intercept form describing this relationship. Use ordered pairs of the form (sales price, number sold).
b. Predict the daily sales of Fun Noodles if the price is 2.50
Answer:
don't know if i'm right but i think it's B
Find the equation of the tangent line at the point (0,1) of the graph of the function f(x) = x^3 - 2x + 1 ?
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Answer:
y = -2x +1
Step-by-step explanation:
The derivative of the function is ...
f'(x) = 3x^2 -2
so the slope at x=0 is f'(0) = -2. In slope-intercept form, the equation of the tangent line is ...
y = -2x +1
