kaiden and her brother both open savings accounts. each begin with a balance of zero dollars. for every two dollars that kaiden saves in her account, her brother saves five dollars. if kaiden saves 300 dollars how much did her brother save

Answers

Answer 1

The ratio is 2:5

Kaiden saves=300$Let her brother saves x

ATQ

[tex]\\ \sf\longmapsto \dfrac{300}{x}=\dfrac{2}{5}[/tex]

[tex]\\ \sf\longmapsto 2x=300(5)[/tex]

[tex]\\ \sf\longmapsto 2x=1500[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{1500}{2}[/tex]

[tex]\\ \sf\longmapsto x=750\$[/tex]


Related Questions

If you have 2 distinct black playing cards and 2 distinct red playing cards, how many ways can you arrange the four cards given that the red cards can never be next to each other

Answers

Answer:

I'm not 100% on the interoperation of this question...

are the two red cars out of a 52 card deck and you can try all the combinations of two red and black cards ????

for this answer i will assume that you have 4 coins two nickels and 2 quarters

and the question is " how many ways can you arrange the four coins given that the nickels can not be next to the quarters"

in that case I think the answer is 8

Step-by-step explanation:

1- N1 Q1 N2 Q2

2- N1 Q2 N2 Q1

3- N2 Q1 N1 Q2

4- N2 Q2 N1 Q1

5- Q1 N2 Q2 N1

6- Q2 N2 Q1 N1

7- Q1 N1 Q2 N2

8- Q2 N1 Q1 N2

[tex]2\cdot \left(\left(2\:choose\:1\right)\:\cdot \:\left(2\:choose\:1\right)\right)[/tex]

Which choice shows 14 •(8 . 2) correctly rewritten using the associative property and then correctly simplified?
(14.8.2 = 112 · 2 = 224
(14.82) = 1, 148
14. (2. 8) = 14 · 16 = 224
14.2.8 = 28. 8 = 224

Answers

Step-by-step explanation:

=14×(8×2)

=14(16)

=224

Savannah used 2 quarts of paint on a summer project. She still had 5.
quarts of paint left when she was finished. How much paint did Savannah
have at first?
la cloud

Answers

Answer:

7 quarts

Step-by-step explanation:

total paint = paint used + paint left

total paint = 2 +5

total paint 7

5 quarts left +2 quarts used = 7 so the answer is 7 yw

Please help me to find this answer

Answers

Answer:

37

Step-by-step explanation:

Tan(B) = 6/8

B= arctan(3/4)=37

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW. Ch. 15 part 1a

How can a matrix be used to solve a system of equations. Demonstrate by solving the following system. Show your work. ​

Answers

We are given the equations:

x - 3y = 2

3x - 4y = 0

writing the system as matrices

[tex]\left[\begin{array}{ccc}1&-3\\3&-4\end{array}\right][/tex][tex]\left[\begin{array}{ccc}x\\y\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}2\\0\\\end{array}\right][/tex]

which is in the form:

AX = B

solving for X(the matrix holding the variables), we get:

X = (A⁻¹)B

Finding A⁻¹:

now, to do this, we need to find the inverse of A

[tex]\left[\begin{array}{ccc}w&x\\y&z\end{array}\right]^{-1} = \frac{1}{wz-xy}\left[\begin{array}{ccc}z&-x\\-y&w\end{array}\right][/tex]

using this formula to find the inverse of matrix A:

[tex]A^{-1} = \frac{1}{(1*-4)-(-3*3)}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right][/tex]

[tex]A^{-1} = \frac{1}{5}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right][/tex]

Matrix X:

We know that:

X = A⁻¹B

[tex]X = \frac{1}{5}\left[\begin{array}{ccc}-4&3\\-3&1\end{array}\right] * \left[\begin{array}{ccc}2\\0\end{array}\right][/tex]

[tex]X = \frac{1}{5}\left[\begin{array}{ccc}-8\\-6\end{array}\right][/tex]

since matrix X is just a matrix with the variables

[tex]\left[\begin{array}{ccc}x\\y\end{array}\right] = \left[\begin{array}{ccc}\frac{-8}{5}\\\frac{-6}{5}\end{array}\right][/tex]

x = -8/5

y = -6/5

round 32.68 to the nearest hundredth​

Answers

Answer:

32.70

Step-by-step explanation:

round up

According to this diagram, what is tan 62°?
62°
17
18
280
90°
15
O A.
8
17
OB.끝
O c. 1
8
15
D.
15
8
O
E.
17
15
F.
15
17

Answers

Answer:

15/8

Step-by-step explanation:

tan(62)=P/B

tan(62)=15/8

What is word and expanded form of 5,901,452

Answers

Word: Five million nine hundred one thousand four hundred fifty two.
Expanded: 5,000,000 + 900,000 + 1,000 + 400 + 50 + 2
Hii!

Five Million nine hundred and one thousand four hundred fifty two!

5000000+900000+1000+400+50+2

Have a fabulous day

After leaving an airport, a plane flies for 2 hours on a course of 60 degrees at a speed of 200 kilometers per hour. The plane then flies for 3 hours on a course of 210 degrees at a speed of 100 kilometers per hour What is the distance of the airport from the plane in kilometers? Round to the nearest tenth​

Answers

Answer: 205.3

I suppose all measures of angles are done from the same axis (for example x-axis)

Step-by-step explanation:

You just have to use the theorem of Al'Kashi:

[tex]d^2=400^2+300^2-2*300*400*cos(30^o)\\\\d\approx{205.3(km)}[/tex]

FInd the volume of the figure

Answers

Answer:

785.4

I think it is right

Answer:

Solution: Here, Radius of cylindrical tank (r)=2ml Height of cylindrical tank (h)=8ml volume of that cylindrical tank (v)=?

Now,

we know that,

Volume of cylindrical(v)=V=πr2h=3.14×2×2×8=100.48ans.

QUESTION 5 - 1 POINT
An investment of $32,000 is worth $38,302 after being compounded monthly at 3%. How many years was the investment
for? (Round to the nearest whole year).

Answers

9514 1404 393

Answer:

  6

Step-by-step explanation:

The compound interest formula tells you the future value of principal P invested at annual rate r compounded n times per year for t years is ...

  A = P(1 +r/n)^(nt)

Solving for t, we get ...

  t = log(A/P)/(n·log(1 +r/n))

Using the given values, we find t to be ...

  t = log(38302/32000)/(12·log(1 +0.03/12)) ≈ 5.9997

The investment was for 6 years.

Complete the equation describing how x
and y are related.
х у
y = [ ? ]x
-2
-1
0
1
2
3
-6
-3
0
3
6
9
Enter the answer that
belongs in [?]

Answers

Answer:

y=3x

Step-by-step explanation:

-6/-2=3, -3/-1=3, 3/1=3. 6/2=3

NO LINKS OR ANSWERING QUESTIONS YOU DON'T KNOW!! Chapt 15 part 2a

Explain the process of matrix multiplication. What are the dimensions 9f of the resulting matrix? Use the following matrices for your explanation of the process. AB. Show your work. ​

Answers

We are given the matrices A and B

[tex]A = \left[\begin{array}{ccc}2&3&-1\\0&2&5\\2&4&0\end{array}\right][/tex]

[tex]B = \left[\begin{array}{ccc}2\\1\\2\end{array}\right][/tex]

Multiplying these matrices:

We multiply matrices by taking the first column of the first matrix and the first row of the second matrix

we will multiply all the terms of the first column of the first matrix and multiply them by the terms of the first row of the second matrix, one by one

[tex]AB = \left[\begin{array}{ccc}2(2) + 3(1) + -1(2)\\0(2) + 2(1) + 5(2)\\2(2) + 4(1) + 0(2)\end{array}\right][/tex]

[tex]AB = \left[\begin{array}{ccc}5\\12\\8\end{array}\right][/tex]

9514 1404 393

Explanation:

Two matrices with dimensions (numbers of (rows, columns)) of (a, b) and (c, d) can only be multiplied if the number of columns in the left matrix is equal to the number of rows in the right matrix. That is, b=c. The dimensions of the product matrix will be (a, d).

For row i of the left matrix and column j of the right matrix, element a(i,j) of the product matrix is the dot-product of row i with column j. (The dot-product of two vectors is the sum of the products of corresponding elements.)

__

The example matrices have (row, column) dimensions (3, 3) and (3, 1), so can be multiplied with a result having dimensions (3, 1).

It is useful to refer to an element of a matrix by specifying the row and column in which it resides. An element of matrix 'A' in row 2 and column 3 can be referred to as A(2,3). Often, subscripts are used, as in ...

  [tex]A_{i,j}[/tex]

For matrix C = A·B, the element C(1,1) will be the sum ...

  A(1,1)B(1,1) +A(1,2)B(2,1) +A(1,3)B(3,1)

Calculators, apps, spreadsheets, and web sites are available that will perform this arithmetic for you. It can be a bit tedious to do by hand.

Here the product is ...

  [tex]A\cdot B=\left[\begin{array}{ccc}2&3&-1\\0&2&5\\2&4&0\end{array}\right] \cdot\left[\begin{array}{c}2&1&2\end{array}\right] =\left[\begin{array}{c}2(2)+3(1)+(-1)(2)&0(2)+2(1)+5(2)&2(2)+4(1)+0(2)\end{array}\right] \\\\=\left[\begin{array}{c}5&12&8\end{array}\right][/tex]

Simplify this radical.
90
3/10
6/10
9/10
103
Need help please on this

Answers

Answer:

3[tex]\sqrt{10}[/tex]

Step-by-step explanation:

Assuming you mean [tex]\sqrt{90}[/tex]

Using the rule of radicals

[tex]\sqrt{a}[/tex] × [tex]\sqrt{b}[/tex] ⇔ [tex]\sqrt{ab}[/tex] , then

[tex]\sqrt{90}[/tex]

= [tex]\sqrt{9(10)}[/tex]

= [tex]\sqrt{9[/tex] × [tex]\sqrt{10}[/tex]

= 3[tex]\sqrt{10}[/tex]

What is the solution to each system
3) y=3x+1
3x+y=1
4) y=2x+1
y=2x+4
5) y= -5x+1
y=2x+4

Answers

Answer:

3)x=0 y=1

Step-by-step explanation:

3) y=3x+1

   

    3x+y=1

    y=1-3x

1-3x=3x+1

1-1=3x+3x

0=6x

x=0

by substitute in 1

     y=3x+1

     y=3*0+1

     y=1

   5)  -5x+1=2x+4

         -5x-2x=4-1

         -7x=3

          x=-3/7

  by substitute in (y=2x+4)

            y=2*-3/7+4

              =25/7

To make sky blue Sam uses two drops of blue paint for every eight drops of white paint. He wants to
make a large amount of sky blue paint. If he uses sixteen drops of blue, how many drops of white will he
need?

Answers

Answer:

64

Step-by-step explanation:

The Ratio of Blue to White drops is 2:8

16*4=64,... 16:64 Have a nice day!

what principle will amount to Rs. 4000 in 20 yrs at 2.5%?​

Answers

Answer:

3200

Step-by-step explanation:

Consider principle =Rs.P, Time (T)=4 years

Consider principle =Rs.P, Time (T)=4 yearsRate =6

Consider principle =Rs.P, Time (T)=4 yearsRate =6 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P×

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P =

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 4

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200

Consider principle =Rs.P, Time (T)=4 yearsRate =6 41 = 425 %Simple interest = 100P×T×R = 100P× 425 ×4 = 4P =∴ Amount =P+ 4P = 45P = 45P =40005P=4×4000P=Rs.3200Therefore, Principle =Rs.3200

e/22 = 6/15, What does e equal? Please answer with work!

Answers

Answer:

e = 44/5 = 8.800

Step-by-step explanation:

Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation :

                    e/22-(6/15)=0

Step by step solution :

STEP

1

:

           2

Simplify   —

           5

Equation at the end of step

1

:

  e    2

 —— -  —  = 0

 22    5

STEP

2

:

            e

Simplify   ——

           22

Equation at the end of step

2

:

  e    2

 —— -  —  = 0

 22    5

STEP

3

:

Calculating the Least Common Multiple :

3.1    Find the Least Common Multiple

     The left denominator is :       22

     The right denominator is :       5

       Number of times each prime factor

       appears in the factorization of:

Prime

Factor   Left

Denominator   Right

Denominator   L.C.M = Max

{Left,Right}

2 1 0 1

11 1 0 1

5 0 1 1

Product of all

Prime Factors  22 5 110

     Least Common Multiple:

     110

Calculating Multipliers :

3.2    Calculate multipliers for the two fractions

   Denote the Least Common Multiple by  L.C.M

   Denote the Left Multiplier by  Left_M

   Denote the Right Multiplier by  Right_M

   Denote the Left Deniminator by  L_Deno

   Denote the Right Multiplier by  R_Deno

  Left_M = L.C.M / L_Deno = 5

  Right_M = L.C.M / R_Deno = 22

Making Equivalent Fractions :

3.3      Rewrite the two fractions into equivalent fractions

Two fractions are called equivalent if they have the same numeric value.

For example :  1/2   and  2/4  are equivalent,  y/(y+1)2   and  (y2+y)/(y+1)3  are equivalent as well.

To calculate equivalent fraction , multiply the Numerator of each fraction, by its respective Multiplier.

  L. Mult. • L. Num.      e • 5

  ——————————————————  =   —————

        L.C.M              110

  R. Mult. • R. Num.      2 • 22

  ——————————————————  =   ——————

        L.C.M              110  

Adding fractions that have a common denominator :

3.4       Adding up the two equivalent fractions

Add the two equivalent fractions which now have a common denominator

Combine the numerators together, put the sum or difference over the common denominator then reduce to lowest terms if possible:

e • 5 - (2 • 22)     5e - 44

————————————————  =  ———————

      110              110  

Equation at the end of step

3

:

 5e - 44

 ———————  = 0

   110  

STEP

4

:

When a fraction equals zero :

4.1    When a fraction equals zero ...

Where a fraction equals zero, its numerator, the part which is above the fraction line, must equal zero.

Now,to get rid of the denominator, Tiger multiplys both sides of the equation by the denominator.

Here's how:

 5e-44

 ————— • 110 = 0 • 110

  110

Now, on the left hand side, the  110  cancels out the denominator, while, on the right hand side, zero times anything is still zero.

The equation now takes the shape :

  5e-44  = 0

Solving a Single Variable Equation:

4.2      Solve  :    5e-44 = 0

Add  44  to both sides of the equation :

                     5e = 44

Divide both sides of the equation by 5:

                    e = 44/5 = 8.800

One solution was found :

e = 44/5 = 8.800

Answer:

e =44/5

Step-by-step explanation:

e          6

----- = --------

22         15

Using cross products

e * 15 = 6 *22

15e = 132

Divide by 15

15e/15 = 132/15

e =44/5

How do we find the second and the third derivative of this equation? Please help!

Answers

Answer:

[tex]\frac{7}{2\sqrt{2} }[/tex]

Step-by-step explanation:

substitute 2 in for x. the square root of 2 is already in radical form

Solve the equation for y. Identify the slope and y- intercept. Then graph the equation. 2y-3x=10

Answers

Answer:

y=3/2x+5

The slope is 3/2 and the y-intercept is 5

Step-by-step explanation:

Solving for y will give us the slope and y-intercept

Isolate y

2y/2=10+3x/2

y=5+3/2x

The slope is 3/2 and the y-intercept is 5

Graph it by graphing (0,5) and using the slope (up 3 over 2) to put other points

joe went to to the store and spent a total of $37 .84. if paid with a $50 then how much change did he get back?

Answers

Answer:

$ 12.16

Step-by-step explanation:

Spent = $ 37.84

Paid = $ 50

Change = $50 - $37.84

Change = $ 12.16

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

~AH1807Peace!

Answer:

$12.16

Step-by-step explanation:

You must subtract his total from his payment. $50-$37.84=$12.16

What number x gives maximum value for c(12,x)?

Answers

Answer:

i will say methods try yourself:

How to Determine Maximum Value

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...-x2 + 4x - 2.

How to Determine Maximum ValueIf your equation is in the form ax2 + bx + c, you can find the maximum by using the equation:max = c - (b2 / 4a).The first step is to determine whether your equation gives a maximum or minimum. ...-x2 + 4x - 2.Since the term with the x2 is negative, you know there will be a maximum point.

.

.

.

.

plzz follow and make brainlist

Solve for y 2y+1>-9/5y-6

Answers

Answer: All real numbers

Step-by-step explanation:

Let's find the critical points of the inequality.

2y2+1=

−9

5

y−6

2y2+1−(

−9

5

y−6)=

−9

5

y−6−(

−9

5

y−6)(Subtract (-9)/5y-6 from both sides)

2y2+

9

5

y+7=0

For this equation: a=2, b=1.8, c=7

2y2+1.8y+7=0

y=

−b±√b2−4ac

2a

(Use quadratic formula with a=2, b=1.8, c=7)

y=

−(1.8)±√(1.8)2−4(2)(7)

2(2)

y=

−1.8±√−52.76

4

A man earns RS.95 in a day how much does we earn in 18 days​

Answers

Answer:

RS 17.10

Step-by-step explanation:

If they earn 0.95 a day, you can multiply that income by the number of days, which is 18.

RS 17.10

which is the graph of the function fx=x^2+2x+3​

Answers

Answer:

see below

Step-by-step explanation:

fx=x^2+2x+3​

This is a parabola that opens upward

f(x) = (x^2 +2x)+3

     = (x^2+2x+1) +3-1

   = (x+1)^2 +2

This is in vertex form  y =a(x-h)^2 +h where the vertex is (h,k)

This has a vertex as (-1,2)

And has a y intercept at (0,3)

this does not cross the x axis

look at the image below

Answers

Answer:

16

Step-by-step explanation:

volume= Length x width x height

Answer:

Volume: [tex]1/3\times Area\; of\; base\;\times height[/tex]

[tex]= 1/3\times2\times 2\times 4[/tex]

[tex]=16/3\; ft^{3}[/tex]

[tex]=5.3\; ft^{3}[/tex]

OAmalOHopeO

-p/3-8=3 what is the variable​

Answers

Answer:

-33

Step-by-step explanation:

-p/3-8=3

or,(-p-24)/3=3

or,(-p-24)=9

or,-p=33

Therefore, p=-33

She arrived at the car park at 2.15pm and leaves at 4.45pm on Thursday. how much does Diane pay for her car parking? Monday - Friday up to 2 hours £3.00 2-4 hours £4.50 5 hours + £5.50

Answers

Answer:

£4.50

Step-by-step explanation:

She is at the car park for 2 hours and 30 minutes.

It would be £4.50 because 2 hours and 30 minutes is between 2-4 hours.

It can't be £3.00 because it would be too little time (2 hours or less) and it wouldn't be £5.50 because she would be paying for more time than she was there for (5 hours or more).

Hope this helps :)

Which equation describes this graph?

Answers

Step-by-step explanation:

The graph clearly has a positive slope. So Answer D couldn't be correct. Next: the y-intercept of this line is (0, -2), so b in the formula y = mx÷ b must be -2.

Therefore the correct equation of this line is

y = x - 2 (choice a)

Which one
Dndns sjsjsjsj

Answers

Answer:

Step-by-step explanation:

It's the first / top most option. This is because n < -3 means the variable n is less than 3. It's also the open circle because the less than symbol is not underlined. Hope this helps!

-The first one is correct

-The closed circle means greater than or equal to so it can’t be that

-The open circle just means less than or greater than (not equal)
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