Jessie needs $125.00 to buy the BMX bike. He has $20.00 in his savings account. Write and solve an equation to find out how much money Jessie needs to save to buy the BMX bike.

Answer:

y = 4x...

Step-by-step explanation:

answer:

0

step by step explanation:

Answer:

Step-by-step explanation:

5^4 = 625. I hope your calculator will do this.

625 / 5 = 125

There is a more general way to do this which will be in harmony with the rest of the question.

5^4 / 5^1 = 5^(4 - 1) = 5^3 = 125

b^4 / b2 = b^(4 - 2) = b^2

a remains as it is at a^3

So the answer is 125 a^3 b^2

Answer:4.12

Step-by-step explanation: I need brainliest for next rank I’d appreciate it

Answer:

The answer is "2653".

Step-by-step explanation:

[tex]Sample \ Size = 99\% \ Cl\\\\ E =60 \\\\\sigma= 1200\\\\[/tex]

Minimum sample size for Cl level [tex]= 99\%[/tex] and Desired Margin of Error, [tex]E = 60[/tex] is:  

[tex]\to P(|\bar{x}-\mu| < E) \geq 1-\alpha \\\\\to P(\frac{\bar{x}-\mu}{\frac{\sigma}{\sqrt{n}}} <- \frac{E}{\frac{\sigma}{\sqrt{n}}}) \leq \frac{\alpha}{2} \\\\\to - \frac{E}{\frac{\sigma}{\sqrt{n}}} \leq -z_{\frac{\alpha}{2}} \\\\\to n\geq (\frac{ z_{\frac{\alpha}{2} \times \alpha} }{E})^2 \\\\[/tex]

[tex]Margin \ Error = \frac{\text{length of the CI}}{2}\\\\\sigma=1200\\\\\alpha=1 - Confidence =1-0.99=0.01\\\\Z_{\frac{\alpha}{2}}=z_{0.005}=2.58\\\\n\geq (\frac{z_{0.005} \times \sigma }{E})^2 \\\\= (\frac{2.58 \times 1200 }{60})^2\\\\=2662.560\\[/tex]

The minimum n has to be integer, we take the ceiling Of above number and get n = 2663

The exact z-value.

[tex]n \geq (\frac{2.5758293035489 \times 1200}{60})^2 \\\\= 2653.95864[/tex]

using critical value of 2,575, which gives 2652.25  

[tex]\to n =2653[/tex]

9514 1404 393

Answer:

  3. x = 39°; other angle is 51°

  4a. x = 4.1 cm

  4b. x = 16.9 cm

Step-by-step explanation:

Ordinarily, I'd start with SOH CAH TOA, which gives you the relations you use to get the formula for the solution. Since you want to start with the formula, we'll do that.

3. x = arcsin(opposite/hypotenuse) = arcsin((5 cm)/(8 cm)) ≈ 39°.

The other missing angle is its complement, 90° -39° = 51°.

The missing angles are x = 39°, and 51°.

__

4a. adjacent = opposite/tan(angle)

  x = (8 cm)/tan(63°) ≈ 4.1 cm

x is about 4.1 cm.

__

4b. adjacent = hypotenuse · cos(angle)

  x = (40 cm)cos(65°) ≈ 16.9 cm

x is about 16.9 cm

Answer:   Yeah ik i have to do it too lol

but the answer is -2

Step-by-step explanation:

Answer:

-2

Step-by-step explanation:

Answer:

B

Step-by-step explanation:

Answer:

Step-by-step explanation:

Use intersecting chords theorem:

Answer:

i think its b

Step-by-step explanation:

Answer:

option 2

Step-by-step explanation:

Answer:

Option 2

Step-by-step explanation:

Option 2

x is 4

y is -4

Answer:

-90 degree is the correct answer

Given:

The table of values.

To find:

Whether the given relation in the table is proportional or non proportional.

Solution:

If y is directly proportional to x, then

[tex]y\propto x[/tex]

[tex]y=kx[/tex]

[tex]\dfrac{y}{x}=k[/tex]

Where, k is the constant of proportionality.

It means the ratio of y and x remains same for proportional relation.

From the given table, the points are (10,18), (11,18.6) and (12,19.2). The ratio of y to x for these points are:

[tex]\dfrac{18}{10}=1.8[/tex]

[tex]\dfrac{18.6}{11}\approx 1.69[/tex]

[tex]\dfrac{19.2}{12}=1.6[/tex]

Since the ratio of y to x for the given points are not equal, therefore the given relation is a non proportional relation.

Answer:

C

Step-by-step explanation:

hope this helps with the work

Answer:

Step-by-step explanation:

Answer:

352

Step-by-step explanation:

originally 351.86 but 352 when rounded

Answer:

21708

Step-by-step explanation

Ok I am not so sure about this one, since this was a LOT of counting, and unless you want to see 5 pages of calculations, I'm just going to go on a limb and say trust me. However, if you really want to see for yourself, I'll give you a hint. For the first 1***1 numbers, the sum is 1440. For the 2***2 numbers, the sum is 1683. Try to calculate this to 9***9 to find the answer! Again, not sure about my answer if it's wrong, sorry!

Answer:

Solutions given:

opposite side [0pp]=x

hypotenuse [Hypo]=7

angle A=36°

Now

relationship between opposite side and hypotenuse is given by Sin angle

Sin A=[tex] \frac{oppo}{hypo} [/tex]

Sin 36=[tex] \frac{x}{7} [/tex]

x=Sin36*7

x=4.11

So second one x=4.1 is your answer

Answer:

5, 9,13,17

Step-by-step explanation:

5 +4 +4+4

Answer:

The circle's area is 380.13 square miles.

Step-by-step explanation:

A = pie * r^2 = pie * 11^2 = 380.13

I hope this somewhat helped you find your answer.

Answer:

379.94

Step-by-step explanation:

3.14 x (11x11) = 379.94

Answer:

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}[/tex]

Step-by-step explanation:

Given

[tex]\cos(\theta) = -\frac{2}{3}[/tex]

[tex]\theta \to[/tex] Quadrant III

Required

Determine [tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta)[/tex]

We have:

[tex]\cos(\theta) = -\frac{2}{3}[/tex]

We know that:

[tex]\sin^2(\theta) + \cos^2(\theta) = 1[/tex]

This gives:

[tex]\sin^2(\theta) + (-\frac{2}{3})^2 = 1[/tex]

[tex]\sin^2(\theta) + (\frac{4}{9}) = 1[/tex]

Collect like terms

[tex]\sin^2(\theta) = 1 - \frac{4}{9}[/tex]

Take LCM and solve

[tex]\sin^2(\theta) = \frac{9 -4}{9}[/tex]

[tex]\sin^2(\theta) = \frac{5}{9}[/tex]

Take the square roots of both sides

[tex]\sin(\theta) = \±\frac{\sqrt 5}{3}[/tex]

Sin is negative in quadrant III. So:

[tex]\sin(\theta) = -\frac{\sqrt 5}{3}[/tex]

Calculate [tex]\csc(\theta)[/tex]

[tex]\csc(\theta) = \frac{1}{\sin(\theta)}[/tex]

We have: [tex]\sin(\theta) = -\frac{\sqrt 5}{3}[/tex]

So:

[tex]\csc(\theta) = \frac{1}{-\frac{\sqrt 5}{3}}[/tex]

[tex]\csc(\theta) = \frac{-3}{\sqrt 5}[/tex]

Rationalize

[tex]\csc(\theta) = \frac{-3}{\sqrt 5}*\frac{\sqrt 5}{\sqrt 5}[/tex]

[tex]\csc(\theta) = \frac{-3\sqrt 5}{5}[/tex]

So, we have:

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta)[/tex]

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \tan(\theta) \cdot \frac{1}{\tan(\theta)} + \csc(\theta)[/tex]

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 + \csc(\theta)[/tex]

Substitute: [tex]\csc(\theta) = \frac{-3\sqrt 5}{5}[/tex]

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = 1 -\frac{3\sqrt 5}{5}[/tex]

Take LCM

[tex]\tan(\theta) \cdot \cot(\theta) + \csc(\theta) = \frac{5 - 3\sqrt 5}{5}[/tex]

Answer:

Translation

Step-by-step explanation:

Answer:

238

Step-by-step explanation:

Important note: ∠FAH is an inscribed angle and arc mFGH is it's intercepted arc

opposite angles in a quadrilateral formed inside of a circle area supplementary

Supplementary meaning that they add up to equal 180

So 13x + 15 + 8x - 3 = 180

We now solve for x

step 1 combine like terms

13x + 8x = 21x

15 - 3 = 12

12 + 21x = 180

step 2 subtract 12 from each side

12 - 12 cancels out

180 - 12 = 168  

21x = 168

step 3 divide each side by 21

21x / 21 = x

168 / 21 = 8

we're left with x = 8

Now we substitute 8 for x in 13x + 15

13 ( 8 ) + 15

13 * 8 = 104

104 + 15 = 119

So ∠FAH = 119

Recall that an included angle is equal to half the measure of its intercepted arc.

so arc mFGH = 2 (119)

2 * 119 = 238

Therefore your answer is A