In the right situations, the use of multi-threads can allow for application speedup. Provide a small code example that illustrates how threads can be used to arrive at an appropriate result. Identify if there is a point where too many threads might impact performance of the application. g

Answer:

Explanation:

The following code is written in Java. It has the main method (source process) and a function called fork() which contains the filter process as described in the question. fork() takes in the file information as a parameter and prints out the information to the screen. The test can be seen with the output in the attached image below.

import java.io.File;

import java.io.FileNotFoundException;

import java.util.Scanner;

class Brainly {

   public static void main(String[] args) {

       String data = "";

       try {

           File myObj = new File("C:\\Users\\Gabriel2\\AppData\\Roaming\\JetBrains\\IdeaIC2020.2\\scratches\\input.txt"); //USE YOUR FILE LOCATION

           Scanner myReader = new Scanner(myObj);

           while (myReader.hasNextLine()) {

               data += myReader.nextLine();

               data += "\n";

           }

           myReader.close();

       } catch (FileNotFoundException e) {

           System.out.println("An error occurred.");

           e.printStackTrace();

       }

       System.out.println("Original: \n" + data);

       fork(data);

   }

   public static void fork(String data) {

       String output = "";

       for (int i = 0; i < data.length(); i++) {

           if (Character.isUpperCase(data.charAt(i)) == true) {

               output += Character.toLowerCase(data.charAt(i));

           } else if (Character.isLowerCase(data.charAt(i)) == true) {

               output += Character.toUpperCase(data.charAt(i));

           } else {

               output += data.charAt(i);

           }

       }

       System.out.println("Modified: \n" + output );

   }

}

Answer:

see picture. let me know if you have questions.

Answer:

integer userInput

userInput = Get next input

if userInput % 400 == 0

  Put userInput to output

  Put " is a leap year" to output

else

  if userInput % 4 == 0

     Put userInput to output

     Put " is a leap year" to output

  else

     Put userInput to output

     Put " is not a leap year" to output

Explanation:

I don't know what is so special about Coral but here we go. I couldn't find and IDE that supported Coral so I just used their Coral simulator on their website. The first if statement on line 5 determines if the number is divisible by 400. If so, the leap year is on a century year e.g 1900 1800. If not, the else statement will be executed and the second if statement will execute. If the number is divisible by 4, it is a leap year. If not, the else statement gets executed in which case the number was not a century leap year or a leap year. After that the program terminates.

Hope this helped :)  If it didn't let me know and I do my best to find out what went wrong.

Have a good day :)

Answer:

1.8 * 10^11 m

Explanation:

Given that :

Time taken for tweet to me posted after been sent, t = 10 minutes

t in seconds :

60 seconds = 1 minute

10 minutes = (10 * 60) = 600 seconds

Tweet sent will br transmitted at the speed of light, c = 3 * 10^8 m/s

Recall :

Speed = distance / time

Distance = speed * time

Distance of Curiosity from Earth = (3 * 10^8 * 600)

Distance of curiosity from earth = 1.8 * 10^11 m

But you can't use this device alone to connect two microphones to your USB C port and expect it to have usable volume. So the description is somewhat misleading ...

Answer:

universal design

Explanation:

Using simplified language and numbers, using large font type with more spacing between questions, and having students record answers directly on their tests are all examples of universal design.

Universal Design can be regarded as design that allows the a system, set up , program or lab and others to be

accessible by many users, this design allows broad range of abilities, reading levels as well as learning styles and ages and others to have access to particular set up or program.

it gives encouragment to the development of ICTS which can be

usable as well as accessible to the widest range of people.

Answer:

aahdbdnsjajaissjdjdhskakwjdhbebs

Answer:

Based on what the graph does on the number line, I would say 1100110

Every time the graph spikes up, that is a one, otherwise it is a zero.

Explanation:

Why is cloud better than on-premise? Dubbed better than on-premise due to its flexibility, reliability and security, cloud removes the hassle of maintaining and updating systems, allowing you to invest your time, money and resources into fulfilling your core business strategies.

The security of the cloud vs. on-premises is a key consideration in this debate. Cloud security controls have historically been considered less robust than onprem ones, but cloud computing is no longer a new technology. . A company running its own on-premises servers retains more complete control over security.

Believe it!!

Pls follow me.

Answer:

use loop

for(int i =10;i>2; i--)

{

System.out.println(i+"\n")

}

Answer:

Salespeople and marketers waste tons of their time finding the right leads.

A lot of people think that LinkedIn Sales Navigator is only for advanced search but there are plenty of other perks as well. Its features and capabilities help you find the right people so you don’t waste your time and energy on manual searching.

Using sales navigator, you get access to a lot more features that are not present in the free version. You get limited searching with the free version.

With this LinkedIn automation tool, you can:

Answer:

A programming language is a formal language comprising a set of strings that produce various kinds of machine code output. Programming languages are one kind of computer language, and are used in computer programming to implement algorithms. Most programming languages consist of instructions for computers

Answer:

The artificial languages that are used to develop computer programs are called programming language . hope this help!

Answer:

I will fix it by my mind by thinking

Based on the above scenario, the steps to take is given below\

The first thing is to Right-click Start and click on Device Manager and then you expand Network adapters.

Later you Disable the network adapter  and then Update the driver .

Learn more about Ethernet from

https://brainly.com/question/1637942

#SPJ2

Answer:

i don't know the answer please tell me

Answer:yes

Explanation:

Yup

Try to appear relaxed, but not to relaxed .

Answer:

for the 5 segments, the utilization is 3.8%

Explanation:

Given the data in the question;

segment size = 1090 bytes

Receiver window size = 5,718 bytes

Link transmission rate or Bandwidth = 26 Mbps = 26 × 10⁶ bps

propagation delay = 22.1 ms

so,

Round trip time = 2 × propagation delay = 2 × 22.1 ms = 44.2 ms

we determine the total segments;

Total segments = Receiver window size / sender segment or segment size

we substitute

Total segments = 5718 bytes / 1090 bytes

Total segments = 5.24587 ≈ 5

Next is the throughput

Throughput = Segment / Round trip

Throughput = 1090 bytes / 44.2 ms

1byte = 8 bits and 1ms = 10⁻³ s

Throughput = ( 1090 × 8 )bits / ( 44.2 × 10⁻³ )s

Throughput = 8720 bits / ( 44.2 × 10⁻³ s )

Throughput = 197.285 × 10³ bps

Now Utilization will be;

Utilization = Throughput / Bandwidth

we substitute

Utilization = ( 197.285 × 10³ bps ) / ( 26 × 10⁶ bps )

Utilization = 0.0076

Utilization is percentage will be ( 0.0076 × 100)% = 0.76%

∴ Over all utilization for the 5 segments will be;

⇒ 5 × 0.76% = 3.8%

Therefore, for the 5 segments, the utilization is 3.8%

Answer:

The program is as follows:

def get_price(fruits):

   AllPrice = fruits.values()

   value_iterator = iter(AllPrice)

   mostExpensive = next(value_iterator)  

   for item in fruits:

       if fruits[item]>=mostExpensive:

           mostExpensive = fruits[item]

           fruitName = item

   print(fruitName)

fruits = {}

n = int(input("Number of Fruits: "))

for i in range(n):

   name = input("Fruit name: ")

   price = int(input("Fruit price: "))

   fruits[name] = price

get_price(fruits)

Explanation:

This defines the get_price function

def get_price(fruits):

This gets all price in the dictionary fruit

   AllPrice = fruits.values()

This passes the values to a value iterator

   value_iterator = iter(AllPrice)

This initializes mostExpensive to the first price in the dictionary

   mostExpensive = next(value_iterator)

This iterates through the elements of the dictionary  

   for item in fruits:

If current element is greater than or equals most expensive

       if fruits[item]>=mostExpensive:

Set most expensive to the current element

           mostExpensive = fruits[item]

Get the corresponding fruit name

           fruitName = item

Print fruit name

   print(fruitName)

The main begins here

This initializes the fruit dictionary

fruits = {}

This gets input for the number of fruits

n = int(input("Number of Fruits: "))

This is repeated for every inputs

for i in range(n):

Get fruit name

   name = input("Fruit name: ")

Get fruit price

   price = int(input("Fruit price: "))

Append name and price to dictionary

   fruits[name] = price

Call the get_price function

get_price(fruits)

Answer:

The program is as follows:

#include <iostream>

#include <string>

using namespace std;

class Student{

string studName, indexNo, remarks; int marks;  char grade;

public:

 void getData(){

     cin.ignore();

     cout<<"ID: "; getline(cin,indexNo);

  cout<<"Name:"; getline(cin,studName);

  cout<<"Marks: ";cin>>marks;  }

 void calculate(){

  if(marks>=70 && marks<=100){

      remarks ="Excellent";       grade = 'A';   }

  else if(marks>=60 && marks<=69){

      remarks ="Very Good";       grade = 'B';   }

  else if(marks>=50 && marks<=59){

      remarks ="Pass";       grade = 'D';   }

  else{

      remarks ="Fail";       grade = 'F';   }

  cout << "Grade : " << grade << endl;

  cout << "Remark : " << remarks << endl;  }

};

int main(){

int numStudents;

cout<<"Number of students: "; cin>>numStudents;

Student students[numStudents];

for( int i=0; i<numStudents; i++ ) {

 cout << "Student " << i + 1 << endl;

 students[i].getData();

 students[i].calculate(); }

return 0;}

Explanation:

This defines the student class

class Student{

This declares all variables

string studName, indexNo, remarks; int marks;  char grade;

This declares function getData()

public:

 void getData(){

     cin.ignore();

Prompt and get input for indexNo

     cout<<"ID: "; getline(cin,indexNo);

Prompt and get input for studName

  cout<<"Name:"; getline(cin,studName);

Prompt and get input for marks

  cout<<"Marks: ";cin>>marks;  }

This declares funcion calculate()

 void calculate(){

The following if conditions determine the remark and grade, respectively

  if(marks>=70 && marks<=100){

      remarks ="Excellent";       grade = 'A';   }

  else if(marks>=60 && marks<=69){

      remarks ="Very Good";       grade = 'B';   }

  else if(marks>=50 && marks<=59){

      remarks ="Pass";       grade = 'D';   }

  else{

      remarks ="Fail";       grade = 'F';   }

This prints the grade

  cout << "Grade : " << grade << endl;

This prints the remark

  cout << "Remark : " << remarks << endl;  }

};

The main begins here

int main(){

This declares number of students as integer

int numStudents;

Prompt and get input for number of students

cout<<"Number of students: "; cin>>numStudents;

This calls the student object to declare array students

Student students[numStudents];

This is repeated for all students

for( int i=0; i<numStudents; i++ ) {

Print number

 cout << "Student " << i + 1 << endl;

Call function to get data

 students[i].getData();

Call function to calculate

 students[i].calculate(); }

return 0;}

Answer:

a. cout << Product ::name;

Explanation:

Computer software use different languages which helps user to initiate command. When a user initiates command the results are displayed according to input command. If product name is required as output then insert command should be product::name; this will display names of different products present in the system.

Answer:

The updated program in C is as follows:

#include <stdio.h>

union myUnion{ char c; short s; int i; long l; };

int main(){

   union myUnion inputs;

   printf("Character: ");    scanf("%c", &inputs.c);

   printf("Output: %c", inputs.c);

   printf("\nShort: ");    scanf("%hd", &inputs.s);

   printf("Short: %hd", inputs.s);

   printf("\nInteger: ");    scanf("%d", &inputs.i);

   printf("Output: %d", inputs.i);

   printf("\nLong: ");    scanf("%ld", &inputs.l);

   printf("Long: %ld", inputs.l);

   return 0;

   }

The pseudocode is as follows:

Function union myUnion {

character; short; int; long

}

main() {

myUnion inputs;

Input inputs.c;  Print inputs.c

Input inputs.s; Print inputs.s

Input inputs.i; Print inputs.i;

Input inputs.l; Print inputs.l

}

Explanation:

This defines the union function

union myUnion{ char c; short s; int i; long l; };

The main begins here

int main(){

This calls the union function to main

   union myUnion inputs;

This prompts and gets input for character variable

   printf("Character: ");    scanf("%c", &inputs.c);

This prints the character input

   printf("Output: %c", inputs.c);

This prompts and gets input for short variable

   printf("\nShort: ");    scanf("%hd", &inputs.s);

This prints the short input

   printf("Short: %hd", inputs.s);

This prompts and gets input for integer variable

   printf("\nInteger: ");    scanf("%d", &inputs.i);

This prints the integer input

   printf("Output: %d", inputs.i);

This prompts and gets input for long variable

   printf("\nLong: ");    scanf("%ld", &inputs.l);

This prints the long input

   printf("Long: %ld", inputs.l);

   return 0;

   }

Answer:

Three basic functions of language: Informative, Expressive, and Directive Language

Hi, I provided some explanation of key terms.

Explanation:

Wireless hacking: basically the term refers to any unethical activity carried over a radio wave-connected network (eg Internet or Wifi connection) that would provide unauthorized access to information.

Hardware hacking: On the other hand, hardware hacking involves resetting physical hardware with the objective of using it in a way not originally intended by the manufacturer.

Answer:

d. All of the above

Explanation:

A software can be defined as a set of executable instructions (codes) or collection of data that is used typically to instruct a computer how to perform a specific task and to solve a particular problem.

A software development life cycle (SDLC) can be defined as a strategic process or methodology that defines the key steps or stages for creating and implementing high quality software applications.

In Computer science, management of software development consist of;

a. Process: it involves the stages through which a software application is analyzed, designed, developed, tested, etc.

b. People: it refers to the individuals involved in the software development process.

c. Project: it's the entirety of the stages a software goes through before it gets to the end user.

Answer:

Bike Frame Flow Time

The value-added percentage of the flow time for this bike frame is:

= 46.

Explanation:

a) Data and Calculations:

Bike Frame Flow Time:

Setup time = 7 hours

Processing time = 6 hours

Storage time = 7 hours

Flow time of the bike frame = 13 hours (7 + 6)

Value-added percentage of the flow time for this bike frame = 6/13 * 100

= 46%

b) Flow time represents the amount of time a bicycle frame spends in the manufacturing process from setup to end.  It is called the total processing time. Unless there is one path through the process, the flow time equals the length of the longest process path.  The storage time is not included in the flow time since it is not a manufacturing process.

Answer:

Error reports

Explanation: