Imagine that you are given two linear equations in slope-intercept form. You
notice that both the slopes and the y-intercepts are the same. How many
solutions would you expect for this system of equations?
O A. 1
ОВ. о
C. infinitely many
O D. cannot be determined
SURAT

Answer:

Step-by-step explanation:

It's never negative.

D is indeed correct, the function's values never go below 0, meaning never below the x-axis

Answer:

3/2

Step-by-step explanation:

Recall that slope is y2 - y1 / x2 - x1.

Excellent. The question provides us with two points: (2,4) and (0,1). We can insert these two points into our equation.

Slope = (4 - 1) / (2 - 0) = 3 / 2.

Hope this helps!

Answer:

3/2

Step-by-step explanation:

(0,1) and (2,4)

(y2-y1)/(x2-x1)

= (4-1)/(2-0)

=3/2

Answered by GAUTHMATH

Answer:

4

similar right triangles

[tex]\frac{8}{x} = \frac{x}{2}[/tex]

[tex]x^{2} = 16\\x=4[/tex]

Step-by-step explanation:

Answer:

(a) 4 sample points

(b) See attachment for tree diagram

(c) The probability that no tail is appeared is 1/4

(d) The probability that exactly 1 tail is appeared is 1/2

(e) The probability that 2 tails are appeared is 1/4

(f) The probability that at least 1 tail appeared is 3/4

Step-by-step explanation:

Given

[tex]Coins = 2[/tex]

Solving (a): Counting principle to determine the number of sample points

We have:

[tex]Coin\ 1 = \{H,T\}[/tex]

[tex]Coin\ 2 = \{H,T\}[/tex]

To determine the sample space using counting principle, we simply pick one outcome in each coin. So, the sample space (S) is:

[tex]S = \{HH,HT,TH,TT\}[/tex]

The number of sample points is:

[tex]n(S) = 4[/tex]

Solving (b): The tree diagram

See attachment for tree diagram

From the tree diagram, the sample space is:

[tex]S = \{HH,HT,TH,TT\}[/tex]

Solving (c): Probability that no tail is appeared

This implies that:

[tex]P(T = 0)[/tex]

From the sample points, we have:

[tex]n(T = 0) = 1[/tex] --- i.e. 1 occurrence where no tail is appeared

So, the probability is:

[tex]P(T = 0) = \frac{n(T = 0)}{n(S)}[/tex]

This gives:

[tex]P(T = 0) = \frac{1}{4}[/tex]

Solving (d): Probability that exactly 1 tail is appeared

This implies that:

[tex]P(T = 1)[/tex]

From the sample points, we have:

[tex]n(T = 1) = 2[/tex] --- i.e. 2 occurrences where exactly 1 tail appeared

So, the probability is:

[tex]P(T = 1) = \frac{n(T = 1)}{n(S)}[/tex]

This gives:

[tex]P(T = 1) = \frac{2}{4}[/tex]

[tex]P(T = 1) = \frac{1}{2}[/tex]

Solving (e): Probability that 2 tails appeared

This implies that:

[tex]P(T = 2)[/tex]

From the sample points, we have:

[tex]n(T = 2) = 1[/tex] --- i.e. 1 occurrences where 2 tails appeared

So, the probability is:

[tex]P(T = 2) = \frac{n(T = 2)}{n(S)}[/tex]

This gives:

[tex]P(T = 2) = \frac{1}{4}[/tex]

Solving (f): Probability that at least 1 tail appeared

This implies that:

[tex]P(T \ge 1)[/tex]

In (c), we have:

[tex]P(T = 0) = \frac{1}{4}[/tex]

Using the complement rule, we have:

[tex]P(T \ge 1) + P(T = 0) = 1[/tex]

Rewrite as:

[tex]P(T \ge 1) = 1-P(T = 0)[/tex]

Substitute known value

[tex]P(T \ge 1) = 1-\frac{1}{4}[/tex]

Take LCM

[tex]P(T \ge 1) = \frac{4-1}{4}[/tex]

[tex]P(T \ge 1) = \frac{3}{4}[/tex]

Answer:

Step-by-step explanation:

16x-8y = 16 ⇒ 8x - 4y = 8, which is identical to the second equation.

The equations are equivalent, so there are an infinite number of solutions.

Answer:

Ben traveled 93.75% of his usual distance.

Step-by-step explanation:

Given that Ben travels a regular distance of 80 miles to reach office, and today he used an alternative route that covered a distance of only 75 miles, to determine what is the decrease in the percentage of the distance traveled by Ben, the following calculation must be done:

80 = 100

75 = X

75 x 100/80 = X

93.75 = X

Therefore, Ben traveled 93.75% of his usual distance.

From the analysis of the discriminant, you obtain that the quadratic function has no real solutions.

In first place, you must know that the roots or solutions of a quadratic function are those values ​​of x for which the expression is 0. This is the values ​​of x such that y = 0. That is, f (x) = 0.

Being the quadratic function f (x)=a*x² + b*x + c, then the solution must be when: 0 =a*x² + b*x + c

The solutions of a quadratic equation can be calculated with the quadratic formula:

[tex]Solutions=\frac{-b+-\sqrt{b^{2} -4*a*c} }{2*a}[/tex]

The discriminant is the part of the quadratic formula under the square root, that is, b² - 4*a*c

The discriminant can be positive, zero or negative and this determines how many solutions (or roots) there are for the given quadratic equation.

If the discriminant:

In this case, a= -40, b=10 and c= -1. Then, replacing in the discriminant expression:

discriminant= 10² -4*(-40)*(-1)

Solving:

discriminant= 100 - 160

discriminant= -60

The discriminant is negative, so the quadratic function has no real solutions.

Answer:

12

Step-by-step explanation:

2²×3

I hope its correct

Answer:

4

[tex] {( - 2 + 1)}^{2} + 5(12 \div 3) - 9 \\ 2 + 1 + 5 \times 4 - 9 \\ 3 + 20 - 9 \\ 23 - 9 \\ 14[/tex]

Answer:

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Answer:

yes

Step-by-step explanation:

Answer:

The interval 52% to 58% is based on a procedure that includes the true population value 95% of the time.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

95% confidence

We are 95% sure that the interval contains the true mean/proportion, and thus, the correct option is:

The interval 52% to 58% is based on a procedure that includes the true population value 95% of the time.

The equation of the line is.

y = (3/8)*x - 1.5

A general linear relationship can be written as:

y = a*x + b

Where a is the slope, and b is the y-intercept.

If the line passes through the points (x₁, y₁) and (x₂, y₂), we can write the slope as:

a = ( y₂ - y₁)/(x₂- x₁)

We define the y-intercept and the x-intercept as the points where the graph intersects the y-axis or the x-axis correspondingly.

Here we know that the x-intercept is 4, or we can write this as (4, 0)

we also know that the y-intercept is -1.5, or we can write this as (0, -1.5)

So we know two points of the line, this means that we can find the slope of the line:

a = (-1.5 - 0)/(0 - 4) = (1.5)/(4) = (3/2)*(1/4) = 3/8

Then the line is:

y = (3/8)*x + b

And remember that b is the y-intercept, which we know is equal to -1.5, so we can just replace it:

Then the equation of the line is.

y = (3/8)*x - 1.5

If you want to learn more about this topic, you can read:

https://brainly.com/question/24329241

Answer:

14w -14

Step-by-step explanation:

6w + 2(4w - 7)

Distribute

6w+ 8w -14

Combine like terms

14w -14

Answer:

6w+(2×4w)-(2×7)

(6w+8w)-14=14w-14

Look at the file, it has every bit of the answer

Answer:

The polynomial is:

[tex]p(x) = -x^3 - 2x^2 + 5x + 6[/tex]

Step-by-step explanation:

Zeros of a function:

Given a polynomial f(x), this polynomial has roots [tex]x_{1}, x_{2}, x_{n}[/tex] such that it can be written as: [tex]a(x - x_{1})*(x - x_{2})*...*(x-x_n)[/tex], in which a is the leading coefficient.

Zeros of −3, −1, and 2

This means that [tex]x_1 = -3, x_2 = -1, x_3 = 2[/tex]. Thus

[tex]p(x) = a(x - x_{1})*(x - x_{2})*(x-x_3)[/tex]

[tex]p(x) = a(x - (-3))*(x - (-1))*(x-2)[/tex]

[tex]p(x) = a(x+3)(x+1)(x-2)[/tex]

[tex]p(x) = a(x^2+4x+3)(x-2)[/tex]

[tex]p(x) = a(x^3+2x^2-5x-6)[/tex]

Passes through the point (1,12).

This means that when [tex]x = 1, p(x) = 12[/tex]. We use this to find a.

[tex]12 = a(1 + 2 - 5 - 6)[/tex]

[tex]-12a = 12[/tex]

[tex]a = -\frac{12}{12}[/tex]

[tex]a = -1[/tex]

Thus

[tex]p(x) = -(x^3+2x^2-5x-6)[/tex]

[tex]p(x) = -x^3 - 2x^2 + 5x + 6[/tex]

Answer:

use the formula y = a(x-h)^2 + k

the a stretches or flattens the parabola,

The h shifts left to right , and the k shifts up/down

Step-by-step explanation:

Step-by-step explanation:

7 times a certain number :

Let the unknown number be x

[tex]7 \times x[/tex]

is less four times that same number -2 is 58 :

7x - 4x -2 = 58

Collect like terms

7x-4x = 58+2

3x = 60

3x/3 = 60/3

x = 20

Let the number be x

ATQ

[tex]\\ \sf\longmapsto 7x-4x-2=58[/tex]

[tex]\\ \sf\longmapsto 3x-2=58[/tex]

[tex]\\ \sf\longmapsto 3x=58+2[/tex]

[tex]\\ \sf\longmapsto 3x=60[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{60}{3}[/tex]

[tex]\\ \sf\longmapsto x=20[/tex]

Answer:

The expectation for an event with outcomes:

{x₁, x₂, ..., xₙ}

Each one with probability:

{p₁, p₂, ..., pₙ}

Is:

Ev = x₁*p₁ + ... + xₙ*pₙ

There are 500 tickets sold.

1 of these, wins $3,000  (this is the event x₁)

4 of these, wins $100     (this is the event x₂)

2 of these, wins $75        (this is the event x₃)

The others do not have a prize.

So the probability of winning the $3000 is equal to the quotient between the number of tickets with that prize (1) and the total number of tickets (500)

p₁ = 1/500

Similarly, the probability of winning $100 will be:

p₂ = 4/500

And for the $75 prize:

p₃ = 2/500

Then the probability of not winning is:

p₄ = 493/500

Then the expected value for a single ticket is:

Ev = $0*493/500 + $75*2/500 + $100*4/500 + $3000*1/500

Ev = $7.1

If you take in account that you pay $50 for the ticket, the actual expectation should be:

E = $7.10 - $50 = -$42.90

Step-by-step explanation:

Let the husband's income be x

Wife's income be x + 9000

X + X + 9000 = 81000

2X + 9000 – 9000 = 81000 – 9000

2X= 72000

X = 36000

Husband, 36000,

Wife, 9000+36000, 45000

Answer:

9.6

Step-by-step explanation:

20 divided by 25 = 0.8

Then, 0.8 times 12 = 9.6

I bet that helped! :D

The identity as been verified/proved as:

[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]

Given that:

[tex]\frac{\cos(a + b)}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]

Apply cosine identity to the numerator

[tex]\frac{\cos\ a\ cos\ b - \sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]

Split the fraction:

[tex]\frac{\cos\ a\ cos\ b}{\cos\ a\cos b} - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]

Cancel out common terms

[tex]1 - \frac{\sin a\ sin\ b}{\cos\ a\cos b} = 1 - \tan\ a\ tan\ b[/tex]

In trigonometry, we have:

[tex]\frac{\sin \theta}{\cos \theta} = \tan \theta[/tex]

So, the equation becomes:

[tex]1 - \tan\ a\ tan\ b = 1 - \tan\ a\ tan\ b[/tex]

Hence, the identity has been verified

Read more about trigonometry identities at:

https://brainly.com/question/21055284

Answer:

FH ≈ 6.0

Step-by-step explanation:

Using the sine ratio in the right triangle

sin49° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{FH}{FG}[/tex] = [tex]\frac{FH}{8}[/tex] ( multiply both sides by 8 )

8 × sin49° = FH , then

FH ≈ 6.0 ( to the nearest tenth )

Answer:

6

Step-by-step explanation:

sin = opposite/hypotenuse

opposite = sin * hypotenuse

sin (49) = 0,75471

opposite = 0,75471 * 8 = 6,037677 = 6

Answer:

∠ SPQ = 75°

Step-by-step explanation:

The sum of the 4 angles in a quadrilateral = 360°

Subtract the sum of the 3 angles from 360 for ∠ SPQ

∠ SPQ = 360° - (90 + 74 + 121)° = 360° - 285° = 75°

Answer:

The parent cubic function has been vertically stretched by a factor of 4.

Equation:G(x)= 4[tex]\sqrt[3]{x}[/tex]

Answer: Option B

OAmalOHopeO

Answer:

0.5555 = 55.55% probability that Max will get the job.

Step-by-step explanation:

What is the probability that Max will get the job?

The sum of all probabilities is 100% = 1, so, considering Max's probability as x:

[tex]x + \frac{1}{3} + \frac{1}{9} = 1[/tex]

[tex]\frac{9x + 3 + 1}{9} = 1[/tex]

[tex]9x + 4 = 9[/tex]

[tex]9x = 5[/tex]

[tex]x = \frac{5}{9}[/tex]

[tex]x = 0.5555[/tex]

0.5555 = 55.55% probability that Max will get the job.

The max has probability of getting this job is x= 0.5555 and 55.55%

Suppose that ;

Max has probability of getting this job is = x

and other two companies have probability to get job is [tex]\frac{1}{3} or \frac{1}{9}[/tex].

Sum of the probability have bid a job is 100% which is equal to 1.

According to given question ;

Sum of all the companies having probability to get the job = 1

[tex]x + \frac{1}{3} + \frac{1}{9} = 1[/tex]

[tex]\frac{9.x+1.3+1.1}{9} = 1\\9x+3+1 = 9.1\\9x+4 =9\\9x = 9-4\\9x = 5\\x = \frac{5}{9}[/tex]

x = 0.5555

The Max has probability of getting this job is x= 0.5555 or 55.55%

For the more information about probability click the link given below

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plug-in

-2(4) - 2

-8 - 2

-10

-10^2 + 1

-100 + 1

Your answer: -99

9514 1404 393

Answer:

  184 m

Step-by-step explanation:

The direct distance from Kayla's car (C) to the door of her office building (B) can be found using the Law of Cosines. The interior angle of the triangle at the turning point is 180° -30° = 150°, so the distance is ...

  t² = b² +c² -2bc·cos(T)

  t² = 80² +100² -2·80·100·cos(150°) = 30256.406

The direct distance from her window to the car can be found from the Pythagorean theorem. The legs of the right triangle are the distance from the car to the building (CB) and the height from the building entrance to the window (BW).

  CW = √(t² +60²) ≈ 184.001

The direct line distance from Kayla to her car is 184 meters.

_____

For the first computation, we used the usual notation for a triangle, where capital letters (CTB) are the vertices and angles, and corresponding lower-case letters are their opposite sides.

Answer:

2) Add 21 to both sides

Step-by-step explanation:

When solving [tex]16x-21=52[/tex] for [tex]x[/tex], our goal to isolate [tex]x[/tex] such that we have [tex]x[/tex] set equal to something.

Therefore, we want to start by adding 21 to both sides. This leaves us with [tex]16x=73[/tex] and we are one step closer to isolating [tex]x[/tex].