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Answer:

1/2

Step-by-step explanation:

2/5 + 1/10

Get a common denominator of 10

2/5 * 2/2 + 1/10

4/10 + 1/10

5/10

simplify

Divide the top and bottom by 5

1/2

Answer:

[tex] \frac{1}{2} [/tex]

Step-by-step explanation:

[tex] \frac{2}{5} + \frac{1}{10} \\ \frac{2 \times 2}{5 \times 2} + \frac{1}{10} \\ \frac{4}{10} + \frac{1}{10} \\ \frac{5}{10} \\ \frac{5 \div 5}{10 \div 5} \\ = \frac{1}{2} [/tex]

Answer:

what this makes bi sense haha

Step-by-step explanation:

but ok

The number of edges in the given figure is 15. The correct option is B.

One of the first areas of mathematics is geometry, along with arithmetic. It is concerned with spatial characteristics like the separation, shape, size, and relative placement of objects.

The shape is made up of the triangular prism and the trapezoidal prism the total number of edges in the shape will be 15.

Therefore, the number of edges in the given figure is 15. The correct option is B.

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Answer:

Apply Hooke's Law to the integral application for work: W = int_a^b F dx , we get:

W = int_a^b kx dx

W = k * int_a^b x dx

Apply Power rule for integration: int x^n(dx) = x^(n+1)/(n+1)

W = k * x^(1+1)/(1+1)|_a^b

W = k * x^2/2|_a^b

From the given work: seven and one-half foot-pounds (7.5 ft-lbs) , note that the units has "ft" instead of inches.   To be consistent, apply the conversion factor: 12 inches = 1 foot then:

2 inches = 1/6 ft

1/2 or 0.5 inches =1/24 ft

To solve for k, we consider the initial condition of applying 7.5 ft-lbs to compress a spring  2 inches or 1/6 ft from its natural length. Compressing 1/6 ft of it natural length implies the boundary values: a=0 to b=1/6 ft.

Applying  W = k * x^2/2|_a^b , we get:

7.5= k * x^2/2|_0^(1/6)

Apply definite integral formula: F(x)|_a^b = F(b)-F(a) .

7.5 =k [(1/6)^2/2-(0)^2/2]

7.5 = k * [(1/36)/2 -0]

7.5= k *[1/72]

k =7.5*72

k =540

To solve for the work needed to compress the spring with additional 1/24 ft, we  plug-in: k =540 , a=1/6 , and b = 5/24 on W = k * x^2/2|_a^b .

Note that compressing "additional one-half inches" from its 2 inches compression is the same as to  compress a spring 2.5 inches or 5/24 ft from its natural length.

W= 540 * x^2/2|_((1/6))^((5/24))

W = 540 [ (5/24)^2/2-(1/6)^2/2 ]

W =540 [25/1152- 1/72 ]

W =540[1/128]

W=135/32 or 4.21875 ft-lbs

Step-by-step explanation:

Answer: -1

Step-by-step explanation:

sum of 2 and 3   subtracted   from the product of 2    difference of 7 and 4

            (2+3)            -                         2                                 (  7    -    4   )   =  -1  

       (2+3)-2(7-4) =

        5 - 2(3) =

         5-6 = -1

The sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4 is equivalent to 1.

Equation modelling is the process of writing a mathematical verbal expression in the form of a mathematical expression for correct analysis, observations and results of the given problem.

We have the sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4

From the question, we can model the equation as -

x = 2 × (7 - 4) - (2 + 3)

x = 2(3) - 5

x = 6 - 5

x = 1

Therefore, the sum of 2 and 3 subtracted from the product of 2 and the difference of 7 and 4 is equivalent to 1.

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Answer:

1,-3,-5

Step-by-step explanation:

Given:

f(x)=x^3+7x^2+7x-15

Finding all the possible rational zeros of f(x)

p= ±1,±3,±5,±15 (factors of coefficient of last term)

q=±1(factors of coefficient of leading term)

p/q=±1,±3,±5,±15

Now finding the rational zeros using rational root theorem

f(p/q)

f(1)=1+7+7-15

  =0

f(-1)= -1 +7-7-15

    = -16

f(3)=27+7(9)+21-15

   =96

f(-3)= (-3)^3+7(-3)^2+7(-3)-15

    = 0

f(5)=5^3+7(5)^2+7(5)-15

   =320

f(-5)=(-5)^3+7(-5)^2+7(-5)-15

     =0    

f(15)=(15)^3+7(15)^2+7(15)-15

    =5040

f(-15)=(-15)^3+7(-15)^2+7(-15)-15

     =-1920

Hence the rational roots are 1,-3,-5 !

Answer:

The solution according to the problem given is provided below in the explanation segment.

Step-by-step explanation:

According to the question,

[tex]H_o: \mu_1=\mu_2[/tex]

[tex]H_a: \mu_1 \neq \mu_2[/tex]

Level of significance,

[tex]\alpha = .05[/tex]

The test statistics will be:

⇒ [tex]Z = \frac{(\bar x_1 - \bar x_2)}{\sqrt{\frac{\sigma_1^2}{n_1} +\frac{\sigma_2^2}{n_2} } }[/tex]

       [tex]=\frac{(38-35)}{\sqrt{\frac{(3)^2}{30} +\frac{(5)^2}{30} } }[/tex]

       [tex]=2.82[/tex]

The p-value will be:

= [tex]0.0024[/tex]

Answer:

23,000,550

Step-by-step explanation:

A million has six zeroes, so twenty three million is

23,000,000

Since five hundred fifty is not in the thousands, it replaces the last trio of zeroes.

We have the number in standard form as

23,000,550

Answer:

23000550

Step-by-step explanation:

Answer:

please tell me the complete question

Answer:

The sample size needed is 3115.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.

[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

In which

z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].

The margin of error is:

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

Point estimate:

[tex]\pi = 0.76[/tex]

95% confidence level

So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].

Calculate the sample size needed to be 95% confident that the error in estimating the true value of p is less than 0.015?

This is n for which M = 0.015. So

[tex]M = z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]

[tex]0.015 = 1.96\sqrt{\frac{0.76*0.24}{n}}[/tex]

[tex]0.015\sqrt{n} = 1.96\sqrt{0.76*0.24}[/tex]

[tex]\sqrt{n} = \frac{1.96\sqrt{0.76*0.24}}{0.015}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96\sqrt{0.76*0.24}}{0.015})^2[/tex]

[tex]n = 3114.26[/tex]

Rounding up:

The sample size needed is 3115.

Given the definition above and the fact that top points of the function are at y=9 and the low point are at y=1, the center line must be halfway at y=5.

the amplitude therefore is 4. it's also just half the difference of 1 and 9.

I did this graphically with desmos. Doing it algebraicly would have taken much more time i guess.

Answer:

63.4

Step-by-step explanation:

Area of sector=pi*r^2*(theta/360)

Area of sector=pi*121*(60/360)

Area of sector=63.4

Answer:

tan A = 1.375

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

tan theta = opp / adj

tan A = CB/ AC

tan A = 11/8

tan A = 1.375

Answer:

Peter can make 10 tacos.

Step-by-step explanation:

Jaqueline's recipe calls for .1 pounds of beef per taco.

Given only 1 pound, multiply by, taking the reciprocal of .1 gives us 10 tacos.

Answer:

0.1008 = 10.08% probability of thunderstorms on both memorial day and independence day.

Step-by-step explanation:

Probability of independent events:

If two events are independent, the probability of both happening is the multiplication of the probabilities of each happening, that is:

[tex]P(A \cap B) = P(A)P(B)[/tex]

In this question:

Event A: Thunderstorm on memorial day.

Event B: Thunderstorm on memorial day

The probability of a thunderstorm on memorial day 0.72

This means that [tex]P(A) = 0.72[/tex]

The probability of a thunderstorm on independance day is 0.14.

This means that [tex]P(B) = 0.14[/tex]

What is the probability of thunderstorms on both memorial day and independence day?

[tex]P(A \cap B) = P(A)P(B) = 0.72*0.14 = 0.1008[/tex]

0.1008 = 10.08% probability of thunderstorms on both memorial day and independence day.

Probabilities are used to determine the chances of events

The probability of thunderstorm on both days is 0.1008

Represent the event that there is thunderstorm on Memorial Day with A, and the event that there is thunderstorm on Independence Day with B

So, we have:

P(A) = 0.72

P(B) = 0.14

The probability of thunderstorm on both days is then calculated as;

P(Both) = P(A) * P(B) - P(A or B)

Given that the events are independent, the equation becomes

P(Both) = P(A) * P(B)

So, we have:

P(Both) = 0.72 * 0.14

Multiply

P(Both) = 0.1008

Hence, the probability of thunderstorm on both days is 0.1008

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Answer:

Step-by-step explanation:

45 - (8 x 3 + 15)

45 - (24 + 15)  ---> do parentheses first

45 - ( 39 )

45 -  39

6

The value of the expression Becca should get after simplification is 6.

Given is an expression 45 - (8 × 3 + 15), Becca is trying to solve the same,

To evaluate the expression 45 - (8 × 3 + 15), Becca should follow the order of operations, which is often remembered using the acronym PEMDAS (Parentheses, Exponents, Multiplication and Division, Addition and Subtraction):

First, calculate the value inside the parentheses: 8 × 3 + 15

= 24 + 15

= 39.

Now, substitute this value back into the original expression: 45 - 39.

Finally, perform the subtraction: 45 - 39 = 6.

So, the value of the expression is 6.

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Answer:

the probability of taking a clear picture of a California candor is .24

Answer:

C. Hexagon

Step-by-step explanation:

The answer is clearly C. Hexagon. This is because the question is referring to the shape shown on Plane P as if it were 2D. Therefore, the shape with 6 sides is a hexagon and cannot be anything else.

The shape is the cross-section is a hexagon.

In geometry, a hexagon may be described as a closed two-dimensional polygon with six aspects. The hexagon has 6 vertices and 6 angles also. Hexa means six and gonia approach angles.

All hexagons have six facets, regardless of the sort of hexagon it is. which means that normal hexagons, irregular hexagons, concave hexagons, and convex hexagons all have six facets.

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Answer:

1/3

Step-by-step explanation:

Parallel lines have the same slope.  Thus, a line parallel to one with a slope of 1/3 is just 1/3.

Answer:

[tex]\displaystyle y' = \frac{y - 5x}{x + 6y^2}[/tex]

General Formulas and Concepts:

Algebra I

Calculus

Differentiation

Derivative Property [Multiplied Constant]:                                                           [tex]\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)[/tex]

Derivative Property [Addition/Subtraction]:                                                         [tex]\displaystyle \frac{d}{dx}[f(x) + g(x)] = \frac{d}{dx}[f(x)] + \frac{d}{dx}[g(x)][/tex]

Basic Power Rule:

Derivative Rule [Product Rule]:                                                                             [tex]\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)[/tex]

Derivative Rule [Chain Rule]:                                                                                 [tex]\displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)[/tex]

Step-by-step explanation:

Step 1: Define

Identify

[tex]\displaystyle 5x^2 - 2xy + 4y^3 = 5[/tex]

Step 2: Differentiate

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit: Differentiation

Book: College Calculus 10e

Answer: y = 30x

Step-by-step explanation:

Because we are talking about over 8 hours. The question states that you get 30$ per hour for overtime hours. That means if you work over 8 hours your dollars per hour increases to 30. So because the amount of dollars increases to 30 you can infer that all you have to do is make the same equation as the 20 dollar's per hour equation. Except you put 30 making it y = 30x.

Answer:

Determination of type of error arising from the situations

Situation       Type of Error

1.                    Nonresponse

2.                   Bad sampling method

3.                   Question wording

4.                   Undercoverage

Step-by-step explanation:

Types of errors:

a. question wording means that the manner a question is worded elicits some particular responses, which may not accurately reflect reality.

b. undercoverage occurs when some elements of the target population is not represented on the survey frame.

c. processing error arises from data processing

d. bad sampling method is caused by the voluntariness of those who choose to respond.

e. response error is caused by a questionnaire that requires framing improvements, misinterpretation of questions by interviewers or respondents, and errors in respondents' statements.

f. nonresponse error arises as a result of incomplete information or partial response.

g. random sampling error arises from the limited sample size when compared with the population size.

Answer:

0.9378 = 93.78% probability that a randomly selected person has diabetes, given that his test is positive.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]

In which

P(B|A) is the probability of event B happening, given that A happened.

[tex]P(A \cap B)[/tex] is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Positive test

Event B: Person has diabetes.

Probability of a positive test:

0.95 out of 0.1(person has diabetes).

0.007 out of 1 - 0.1 = 0.9(person does not has diabetes). So

[tex]P(A) = 0.95*0.1 + 0.007*0.9 = 0.1013[/tex]

Probability of a positive test and having diabetes:

0.95 out of 0.1. So

[tex]P(A \cap B) = 0.95*0.1 = 0.095[/tex]

What is the probability that a randomly selected person has diabetes, given that his test is positive?

[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.095}{0.1013} = 0.9378[/tex]

0.9378 = 93.78% probability that a randomly selected person has diabetes, given that his test is positive.

Answer:

Mean = 52

Standard Deviation = 13.64

Step-by-step explanation:

mean = 260/5

= 52

Standard Deviation = [tex]\sqrt{\frac{930}{5} }[/tex] = 13.64

I wasn't sure about my answer so used the Gauthmath app

Your answer iss...

It is 51º

The line PQ of the triangle is an altitude. The correct option is A.

A line segment passing through a triangle's vertex and running perpendicular to the line containing the base is the triangle's height in geometry.

The extended base of the altitude is the name given to this line that contains the opposing side. The foot of the altitude is the point at where, the extended base and the height converge.

In the given triangle the line segment PQ is passing through a triangle's vertex and running perpendicular to the line containing the base is the triangle's height in geometry.

Therefore, the line PQ of the triangle is an altitude. The correct option is A.

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Answer:

The mean is of -0.4 hours.

Step-by-step explanation:

To solve this question, we need to understand the central limit theorem and subtraction of normal variables.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction between normal variables:

When two normal variables are subtracted, the mean is the difference of the means, while the standard deviation is the square root of the sum of the variances.

Mean of the sample of 64 Duracell:

By the Central Limit Theorem, 4.1 hours.

Mean of the sample of 64 Eveready:

By the Central Limit Theorem, 4.5 hours.

Mean of the difference?

Subtraction of normal variables, so we subtract the means.

4.1 - 4.5 = -0.4

The mean is of -0.4 hours.

Answer:

7 square are 0resent on aaaaaa

Answer:

the probability that a truck drives less than 159 miles in a day = 0.9374

Step-by-step explanation:

Given;

mean of the truck's speed, (m) = 120 miles per day

standard deviation, d = 23 miles per day

If the mileage per day is normally distributed, we use the following conceptual method to determine the probability of less than 159 miles per day;

1 standard deviation above the mean = m + d, = 120 + 23 = 143

2 standard deviation above the mean = m + 2d, = 120 + 46 = 166

159 is below 2 standard deviation above the mean but greater than 1 standard deviation above the mean.

For normal districution, 1 standard deviation above the mean = 84 percentile

Also, 2 standard deviation above the mean = 98 percentile

143 --------> 84%

159 ---------> x

166 --------- 98%

[tex]\frac{159-143}{166-143} = \frac{x-84}{98-84} \\\\\frac{16}{23} = \frac{x-84}{14} \\\\23(x-84) = 224\\\\x-84 = 9.7391\\\\x = 93.7391\ \%[/tex]

Therefore, the probability that a truck drives less than 159 miles in a day = 0.9374