If 6x^3 - (k+6)x^2 + 2kx - 25 is divided by 2x-5 remainder is o find the value of k.​

Answer:

y = - [tex]\frac{3}{2}[/tex] x + 1

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = [tex]\frac{2}{3}[/tex] x + [tex]\frac{2}{3}[/tex] ← is in slope- intercept form

with slope m = [tex]\frac{2}{3}[/tex]

Given a line with slope m then the slope of a line perpendicular to it is

[tex]m_{perpendicular}[/tex] = - [tex]\frac{1}{m}[/tex] = - [tex]\frac{1}{\frac{2}{3} }[/tex] = - [tex]\frac{3}{2}[/tex] , then

y = - [tex]\frac{3}{2}[/tex] x + c ← is the partial equation

To find c substitute (- 2, 4) into the partial equation

4 = 3 + c ⇒ c = 4 - 3 = 1

y = - [tex]\frac{3}{2}[/tex] x + 1 ← equation of line

Answer:

Step-by-step explanation:

Assuming you want to find x, we can set two equations:

x-3=0

2x-3=0

This is so that we can individually find x within the two paranthesis and not have to do more work. It helps for standardized tests.

solve for x on both sides, and you get 3 and 1.5

Answer:

[tex]x=3, x=\frac{3}{2}[/tex]

Step-by-step explanation:

[tex]\left(x-3\right)\left(2x-3\right)=0[/tex]

The zero product theorem will be used here to solve this non-linear problem.

means that in the original equation, each variable component must be set to zero.

[tex]\begin{cases} x-3=0\\2x -3=0\end{cases}[/tex]

To solve this linear equation, we need to group all of the variable terms on one side of the equation and all of the constant terms on the other.

so,  -3  will be moved to the right side

Notice that when a term moves from one side of the equation to the other, it changes sign.

[tex]\begin{cases} (x-3)+3=3\\(2x-3)+3=3 \end{cases}[/tex]

[tex]x\left \{ 3,\frac{3}{2} \}[/tex]

OAmalOHopeO

Step-by-step explanation:

first of all you times every number with two 2(n-7) then collect like terms then divide

Answer:

B

Step-by-step explanation:

f(x) = 2x+5

f^(-1) (x) = (x-5)/2

f^(-1) (8) = 3/2

Answer:

3.5, 4.2

Step-by-step explanation:

reflect make it not negative and its on y axis so y not affected

Answer: 45 books?

Step-by-step explanation:

10+15+20

=45

Answer:

[tex]5 \frac{1}{16}[/tex]

Step-by-step explanation:

I did this before. Also sometimes once I look at the question I just find out the answer without steps.

Answer:

Hello,

Step-by-step explanation:

a)

[tex]\Large h(x)=\sqrt[3]{x+2} \ -3\\\\h(x)=-3\\\Longrightarrow\ \sqrt[3]{x+2} \ -3=-3 \\\\\Longrightarrow\ \sqrt[3]{x+2} =0\\\\\Longrightarrow\ (\sqrt[3]{x+2}) ^3=0^3\\\\\Longrightarrow\ x+2=0\\\\\Longrightarrow\ x=-2\\[/tex]

b)

[tex]-3=k(x)=h(x-1)+2=\sqrt[3]{(x-1)+2} -3=\large \sqrt[3]{x+1} -3\\\\\\\Longrightarrow\ \sqrt[3]{x+1}=0\\\\x+1=0\\\\x=-1\\\\[/tex]

Answer:

When one solves, they arrive at a step where |x| is equal to a negative number. Since | x| can never be negative, there is no solution.

Step-by-step explanation:

6|x| + 25 = 15

Subtract 25 from each side

6|x| + 25-25 = 15-25

6|x|  = -10

Divide by 6

6|x| /6 = -10/6

|x|  = -5/3

There is no solution because the absolute value must be greater than or equal to zero.  This equation has it negative.

Answer:

Round to Tens

7,580

Round to hundredths

7,582.15

Answer:

[tex]\displaystyle x=\left \{\frac{2\pi}{3}+2\pi k,\frac{4\pi}{3}+2\pi k, \frac{8\pi}{3}+2\pi k, \frac{10\pi}{3}+2\pi k\right \}k\in \mathbb{Z}[/tex]

Step-by-step explanation:

Hi there!

We want to solve for [tex]x[/tex] in:

[tex]4\sin^2(\frac{x}{2})=3[/tex]

Since [tex]x[/tex] is in the argument of [tex]\sin^2[/tex], let's first isolate [tex]\sin^2[/tex] by dividing both sides by 4:

[tex]\displaystyle \sin^2\left(\frac{x}{2}\right)=\frac{3}{4}[/tex]

Next, recall that [tex]\sin^2x[/tex] is just shorthand notation for [tex](\sin x)^2[/tex]. Therefore, take the square root of both sides:

[tex]\displaystyle \sqrt{\sin^2\left(\frac{x}{2}\right)}=\sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}}[/tex]

Simplify using [tex]\displaystyle \sqrt{\frac{a}{b}}=\frac{\sqrt{a}}{\sqrt{b}}[/tex]:

[tex]\displaystyle \sin\left(\frac{x}{2}\right)=\pm \sqrt{\frac{3}{4}},\\\sin\left(\frac{x}{2}\right)=\pm \frac{\sqrt{3}}{\sqrt{4}}=\pm \frac{\sqrt{3}}{2}[/tex]

Let [tex]\phi = \frac{x}{2}[/tex].

[tex]\displaystyle \sin(\phi)=\frac{\sqrt{3}}{2},\\\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}[/tex]

Therefore, we have:

[tex]\displaystyle \frac{x}{2}=\phi = \frac{\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\frac{x}{2}=\phi =\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z},\\\\\begin{cases}x=\boxed{\frac{2\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{4\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}[/tex]

[tex]\displaystyle \sin(\phi)=-\frac{\sqrt{3}}{2},\\\phi = \frac{4\pi}{3}+2\pi k, k\in \mathbb{Z}, \\\\\phi =\frac{5\pi}{3}+2\pi k, k\in \mathbb{Z},\\\begin{cases}x=\boxed{\frac{8\pi}{3}+2\pi k, k\in \mathbb{Z}},\\x=\boxed{\frac{10\pi}{3}+2\pi k , k \in \mathbb{Z}}\end{cases}[/tex]

Answer:

41 cm Hg

Step-by-step explanation:

Answer:

Hello,

Step-by-step explanation:

[tex]P(3000<x<4000)\\\\=P(\dfrac{3000-3262}{1100} \leq z\leq \dfrac{4000-3262}{1100})\\\\=P(z\leq 0,6709)-(1-P(z\leq 3524) \leq z))\\\\=0.7515-0.5941\\\\=0.1574\\[/tex]

My table have 4 digits but i have made a linear interpolation .

Answer:

-.238, .67, .7486, .4052, .3434

Step-by-step explanation:

standardize them both

(3000-3262)/1100= -.238 which rounds to -.24 which has a probability of .4052

(4000-3262)/1100= .67 which has a probability of .7486

subtract them

.7486-.4052=.3434

Answer:

x = 30

Step-by-step explanation:

The diagonals are bisected so DE =EB

67 = 2x+7

Subtract 7

67-7 = 2x+7-7

60 =2x

Divide by 2

60/2 =2x/2

30 = x

Step-by-step explanation:

3. First, let's find the length of AB:

22²+14² = AB²

680 = AB²

AB = √680

AB ≈ 26.08

The sin of x° is equal to 14/2608

14/26.08 ≈ 0.54

Now you do the asin of 0.54:

asin(0.54) = 32.68°

4. The cos(41°) = x/34, and also the value of cos(41°) ≈ 0.75, so:

0.75 = x/34

x = 34•0.75

x = 25.5°

Answer:

13 is answer

Step-by-step explanation:

hope it helps

Answer:

40*8.5=340

6*90=540

total=880/2.5=352bags

Answer:

305.11

Step-by-step explanation:

Just use a calculator. A centimeter is 2.5 inches. Divide 775 by that.

Step-by-step explanation:

P(-1,1), Q(2,3), R(2,1)

Let P(-1,1)be x1and y1

Q(2,3)be x2 and y2

therefore, by distance formula

d(PQ)= root (x2-x1)^2+(y2-y1)^2

= root[ 2-(-1)] + (3-1)

=root (2+1)^2+2^2

= root (3square +2square )

= root 9+4

d( PQ) = root 13.........(1)

Now find distance QR and PR then prove that the three sides are not equal and therefore it is a scalene triangle

2nd also do the same.

Step-by-step explanation:

[tex] \frac{6a + 18b - 12c}{6} \\ = \frac{6a}{6} + \frac{18b}{6} - \frac{12c}{6} \\ = a + 3b - 2c \\ thank \: you[/tex]

[tex] \large\begin{gathered} {\underline{\boxed{ \rm {\red{Volume \: of \: Cone \: = \: \pi \: {r}^{2} \: \frac{h}{3} }}}}}\end{gathered}[/tex]

‌ ⇛76/2 = 38

‌ ⇛radius = 38 cm

[tex]\bf \Large \longrightarrow \:π \: × \: (38 \: cm)² \: × \: \frac{90 }{3} [/tex]

[tex]\bf \Large \longrightarrow \: \pi \: \times \: \:1444 \: {cm}^{2} \: \times \: \cancel\frac{90}{3} \: \: ^{30 \: cm} [/tex]

Option ( B ) is the correct answer

Answer:

Option A is correct

Step-by-step explanation:

Hope it is helpful....

Answer:

i don't know

Step-by-step explanation:

i don't know

It is a graph of a function

Answer:

y= - 1.4

x= 0.2

Step-by-step explanation:

2x-Y= -1

x-2y=4

Answer: Option B - 13

Explanation:

The mode is the value that appears most frequently in a data set

So 13 appears 5 times so it is the mode

Must click thanks and mark brainliest

Answer:

B

Step-by-step explanation:

The mode is the score which occurs most often.

From the table a score of 13 occurs 5 times, that is

The mode is 13 → B

Answer:  Choice A

[tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex]

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Explanation:

Recall that [tex]\tan(x) = \frac{\sin(x)}{\cos(x)}[/tex] and [tex]\cot(x) = \frac{\cos(x)}{\sin(x)}[/tex]. The connection between tangent and cotangent is simply involving the reciprocal

From this, we can say,

[tex]\tan(\alpha)*\cot^2(\alpha)\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\left(\frac{\cos(\alpha)}{\sin(\alpha)}\right)^2\\\\\\\frac{\sin(\alpha)}{\cos(\alpha)}*\frac{\cos^2(\alpha)}{\sin^2(\alpha)}\\\\\\\frac{\sin(\alpha)*\cos^2(\alpha)}{\cos(\alpha)*\sin^2(\alpha)}\\\\\\\frac{\cos^2(\alpha)}{\cos(\alpha)*\sin(\alpha)}\\\\\\\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]

In the second to last step, a pair of sine terms cancel. In the last step, a pair of cosine terms cancel.

All of this shows why [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is identical to [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex]

Therefore, [tex]\tan(\alpha)*\cot^2(\alpha)=\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] is an identity. In mathematics, an identity is when both sides are the same thing for any allowed input in the domain.

You can visually confirm that [tex]\tan(\alpha)*\cot^2(\alpha)\\\\[/tex] is the same as [tex]\frac{\cos(\alpha)}{\sin(\alpha)}\\\\[/tex] by graphing each function (use x instead of alpha). You should note that both curves use the exact same set of points to form them. In other words, one curve is perfectly on top of the other. I recommend making the curves different colors so you can distinguish them a bit better.

Answer:

Is this answer correct.Does the anwer help you