Identify a transformation of the function f(x) = x2 by observing the equation of the function g(x) = (x - 1)
Answers
Answer:
2nd option
Step-by-step explanation:
Given f(x) then f(x + a) is a horizontal translation of f(x)
• If a > 0 then a shift left of a units
• If a < 0 then a shift right of a units
Here g(x) = (x - 1)²
The base graph f(x) has been shifted right 1 unit
Related Questions
pls answer pls pls pls
Answers
= 3×4+3×3-5×2/12
=12+9-10/12
=21-10/12
=11/12
Simplify the radical expression
Answers
Answer:
The above equals
(32x^2*y^5)1/2
Therefore
32^1/2*x*y^5/2
4(x — 8)+10 = -10
What is the solution to this equation?
Answers
Answer:
x = 3
Step-by-step explanation:
We are given the equation 4(x - 8) + 10 = -10 and are asked to find the solution, solution meaning to get x alone.
To do so, first distribute the 4 on the outside of the parenthesis to both values on the inside of the parenthesis :
4(x - 8)
(4 * x - 4 * 8)
4x - 32
4x - 32 + 10 = -10
Now combine like terms :
4x - 22 = -10
Now it's time to get x alone, first get rid of -22 by adding 22 to both sides :
4x = 12
Now get x alone by dividing both sides by 4 :
x = 3
#3 1/3x = 15 Find value of X
Answers
Answer:
x = 45
Step-by-step explanation:
1/3x = 15 (Given)
3(1/3x) = 15(3) (Multiply 3 on both sides)
x = 45 (Simplify)
Answer:
45
Step-by-step explanation:
1/3x = 15
Multiplying 3 on both sides,
3(1/3x) = 15(3)
x = 15 x 3
x = 45
Hello! can anyone help me with this question
Answers
Answer:
3
Step-by-step explanation:
m = y2 - y1 / X2 - X1
-1 is your X1 . -4 is your y1
2 is your X2 . 5 is your y2
just replace what's in the equation
m= 5 - (-4) / 2 - (-1)
m= 9 / 3
m = 3
hi there
the explanation is in the picture
PLS HELP ME ON THIS QUESTION I WILL MARK YOU AS BRAINLIEST IF YOU KNOW THE ANSWER PLS GIVE ME A STEP BY STEP EXPLANATION!!
Answers
Solve for b.
-32 + 10b = -22
Answers
Answer: b = 1
Step-by-step explanation:
= -32 + 10b = -22
-32 + 10 = -22
b = 1
Check: -32 + 10(1) = -22
= -22
Answer:
b=1
Step-by-step explanation:
Hello,
We would like to solve for b in the equation -32+10b=-22.
When we want to solve for a variable, we want to isolate it on one side (have it on one side by itself. No other numbers.)
So to start, add 32 to both sides to remove it from the left side (-32+32=0).
-32+10b=-22
+32 +32
______________
10b=10
Now, there isn't anything with 10b, but we want the value of b by itself (1b), as 10b is 10 times the value of what b is.
So divide both sides by 10
b=1
Hope this helps!
A candy store owner wants to mix some candy costing $1.25 a pound
with some candy costing $1.45 a pound to make 50 pounds of candy
costing $1.30 a pound. How much of the $1.25 a pound candy should
she use?
Answers
The candy store owner should use 37.5 pounds of the candy costing $1.25 a pound.
Given:
Candy costing $1.25 a pound is to be mixed with candy costing $1.45 a poundThe resulting mixture should be 50 pounds of candyThe resulting mixture should cost $1.30 a poundTo find: The amount of candy costing $1.25 a pound that should be mixed
Let us assume that the resulting mixture should be made by mixing 'x' pounds of candy costing $1.25 a pound.
Since the total weight of the resulting mixture should be 50 pounds, 'x' pounds of candy costing $1.25 a pound should be mixed with '[tex]50-x[/tex]' pounds of candy costing $1.45 a pound.
Then, the resulting mixture contains 'x' pounds of candy costing $1.25 a pound and '[tex]50-x[/tex]' pounds of candy costing $1.45 a pound.
Accordingly, the total cost of the resulting mixture is [tex]1.25x+1.45(50-x)[/tex]
However, the resulting mixture should be 50 pounds and should cost $1.30 a pound. Accordingly, the total cost of the resulting mixture is [tex]1.30 \times 50[/tex]
Equating the total cost of the resulting mixture obtained in two ways, we get,
[tex]1.25x+1.45(50-x)=1.30 \times 50[/tex]
[tex]1.25x+72.5-1.45x=65[/tex]
[tex]0.2x=7.5[/tex]
[tex]x=\frac{7.5}{0.2}[/tex]
[tex]x=37.5[/tex]
This implies that the resulting mixture should be made by mixing 37.5 pounds of candy costing $1.25 a pound.
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[tex]\to \bold{ 1.25x+1.45(50-x)= 1.30 \times 50}\\\\ \to \bold{ 1.25x+72.5-1.45x= 65}\\\\ \to \bold{ -0.2x= -7.5}\\\\ \to \bold{ x=\frac{7.5}{0.2}}\\\\ \to \bold{ x=37.5}\\\\[/tex]
It implies that [tex]\bold{37.5\ pounds}[/tex] of candy at [tex]\bold{\$1.25}[/tex] a pound must be used to make the final concoction.Learn more:
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which value of g makes 26=7(g-9)+12 a true statment
Answers
Answer:
11
Step-by-step explanation:
26=7(g-9)+12
14=7(g-9)
2=g-9
g=11
Is this right answer??????………
Answers
Answer:
6 is correct....
actually this problem is quite si,p;e to see that it is correct
notice that the length of the triangle is 4 and the height is 3
thus a rectangle 4*3 area is twelve ...
if you make a copy of the triangle and flip it you will see it makes
a 4x3 rectangle ... the original and copy = 12 thus 1/2 of the 12 is the area of the original triangle
Step-by-step explanation:
I need help ASAP!!!Please explain your answer
Answers
Answer:
Step-by-step explanation:
There are 2 possibilities. Either you need to know the angles connect to the common side (that would give you ASA) or you need to know GF = UT. The latter would give you SAS
a cylinder with radius 7 and height 4 is in table,then find its volume?
Answers
Answer:
V = ≈615.75
Step-by-step explanation:
hopefully that helped
In an interview for a secretary position at the dealer, a typist claims a tying speed of 45 words per minute. On the basis of 70 trials, she demonstrated an average speed of 43 words per minute with a standard deviation of 15 words per minute. Test at 5% significance level on the typist’s claim.
Answers
According to the typist claim, we build an hypothesis test, find the test statistic and the p-value relative to this test statistic, reaching a conclusion that:
The p-value of the test is 0.1333 > 0.05, which means that there is not enough evidence to reject the typist's claim.
-------------------------------------------------------------
In an interview for a secretary position at the dealer, a typist claims a tying speed of 45 words per minute.
At the null hypothesis, we test if the mean is of at least 45, that is:
[tex]H_0: \mu \geq 45[/tex]
At the alternative hypothesis, we test if the mean is of less than 45, that is:
[tex]H_1: \mu < 45[/tex]
-------------------------------------------------------------
The test statistic is:
We have the standard deviation for the sample, so the t-distribution is used to solve this question
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
In which X is the sample mean, [tex]\mu[/tex] is the value tested at the null hypothesis, s is the standard deviation and n is the size of the sample.
-------------------------------------------------------------
45 is tested at the null hypothesis:
This means that [tex]\mu = 45[/tex]
On the basis of 70 trials, she demonstrated an average speed of 43 words per minute with a standard deviation of 15 words per minute.
This means that [tex]n = 70, X = 43, s = 15[/tex]
Value of the test statistic:
[tex]t = \frac{X - \mu}{\frac{s}{\sqrt{n}}}[/tex]
[tex]t = \frac{43 - 45}{\frac{15}{\sqrt{70}}}[/tex]
[tex]t = -1.12[/tex]
-------------------------------------------------------------
P-value of the test and decision:
The p-value of the test is found using a left-tailed test(test if the mean is less than a value), with 70 - 1 = 69 degrees of freedom and t = -1.12.
Using a t-distribution calculator, the p-value is of 0.1333.
The p-value of the test is 0.1333 > 0.05, which means that there is not enough evidence to reject the typist's claim.
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Lisa is on the west shore of Mighty River, which is 1 mile wide and has two parallel shorelines running exactly north-to-south. She wishes to get to a point on the opposite shore that is 1 mile south of where she is now as quickly as possible. (So this point is sqrt (2) miles due southeast from her starting position.) Assuming that Lisa can walk twice as fast as she can swim, and that she wants to swim across the river first before walking any necessary distance along the opposite shoreline, at what course (in degrees) should she start swimming?
(The angle is measured from north, so 90 degrees is due east, meaning she swims directly across the river, and 135 degrees is due southeast, meaning she swims directly to her destination point.)
Answers
Lisa should start swimming at an angle of [tex]120^{\circ}[/tex] to reach her destination as quickly as possible.
Given:
The river is 1 mile wideThe end point is 1 mile south of the starting pointLisa's speed of walking is twice that of her speed of swimmingLisa wants to swim across the river first before walking the rest of the distance along the opposite shorelineTo find: The course (in degrees) at which she should start swimming so that she can reach the end point as quickly as possible
To solve this problem, we need to know the following:
Pythagoras theorem states that in a right angled triangle, the square of the length of hypotenuse is the sum of the squares of lengths of perpendicular and baseCosine of an angle is the ratio of base and hypotenuse in the right angled triangleA single variable function is minimized by a value for which, the first derivative of the function is zero and the second derivative of the function is positiveLet us assume that Lisa starts swimming at a course such that she needs to swim for 'x' miles to reach the opposite shore, as shown in the figure.
Labelling the points in the figure, we can say that,
AB = 1 mile (given)
BD = 1 mile (given)
AC = x miles (by our assumption)
It is clear that ABC forms a right angled triangle where,
Perpendicular: BC
Base: AB
Hypotenuse: AC
Using Pythagoras Theorem for triangle ABC, we have,
[tex](Hypotenuse)^{2} =(Perpendicular)^{2} +(Base)^{2}[/tex], which implies,
[tex](AC)^{2} =(BC)^{2} +(AB)^{2}[/tex]
Put AC = x, AB = 1 in the above equation to get,
[tex]x^{2} =(BC)^{2} +1^{2}[/tex]
[tex]x^{2} =(BC)^{2} +1[/tex]
[tex](BC)^{2}=x^{2} -1[/tex]
[tex]BC=\sqrt{x^{2} -1}[/tex]
From the figure, we can say that,
[tex]CD=BD-BC[/tex]
Put [tex]BC=\sqrt{x^{2} -1}[/tex] and [tex]BD=1[/tex] in the above equation to get,
[tex]CD=1-\sqrt{x^{2} -1}[/tex]
According to our assumption, Lisa swims the distance of AC and walks the distance of CD, that is, she swims a distance of [tex]x[/tex] miles and walks a distance of [tex]1-\sqrt{x^{2} -1}[/tex] miles.
Now, let us assume that Lisa's speed of swimming is [tex]k[/tex] miles/hour. It is given that Lisa's speed of walking is twice that of her speed of swimming. Then, accordingly, Lisa's speed of walking must be [tex]2k[/tex] miles/hour. We note that these speeds are constants for Lisa.
We know that,
[tex]Speed=\frac{Distance}{Time}[/tex]
Then,
[tex]Time=\frac{Distance}{Speed}[/tex]
This implies that,
Time spent by Lisa on swimming = [tex]\frac{x}{k}[/tex]
Similarly, time spent by Lisa on walking = [tex]\frac{1-\sqrt{x^{2} -1} }{2k}[/tex]
Then, total time taken by Lisa to travel the whole distance from the starting point to the end point is,
[tex]\frac{1-\sqrt{x^{2} -1} }{2k} +\frac{x}{k}[/tex]
[tex]\frac{1}{2k}( 1-\sqrt{x^{2} -1} +2x )[/tex]
Since Lisa wishes to get to the end point as quickly as possible, we must minimize the total time taken by her to travel the entire distance.
Total time taken: [tex]T=\frac{1}{2k}( 1-\sqrt{x^{2} -1} +2x )[/tex]
Differentiating with respect to 'x', we have,
[tex]T'=\frac{1}{2k}( -\frac{x}{\sqrt{x^{2} -1}} +2 )[/tex]
Differentiating with respect to 'x' again, we have,
[tex]T''=\frac{1}{2k(\sqrt{x^{2} -1})^{3}}[/tex]
Equating the first derivative to 0, we have,
[tex]\frac{1}{2k}( -\frac{x}{\sqrt{x^{2} -1}} +2 )=0[/tex]
[tex]-\frac{x}{\sqrt{x^{2} -1}} +2 =0[/tex]
[tex]\frac{x}{\sqrt{x^{2} -1}} =2[/tex]
[tex]2\sqrt{x^{2} -1}= x[/tex]
Squaring both sides,
[tex]4(x^{2} -1)= x^{2}[/tex]
[tex]4x^{2} -4= x^{2}[/tex]
[tex]3x^{2} =4[/tex]
[tex]x^{2} =\frac{4}{3}[/tex]
[tex]x=\frac{2}{\sqrt{3}}[/tex]
Note that we assumed the positive square root for 'x' because 'x' denotes a distance which cannot be negative.
Put [tex]x=\frac{2}{\sqrt{3}}[/tex] in the expression for second derivative to get,
[tex]T''=\frac{1}{2k(\sqrt{(\frac{2}{\sqrt{3}} )^{2} -1})^{3}}[/tex]
[tex]T''=\frac{1}{2k(\sqrt{\frac{4}{3} -1})^{3}}[/tex]
[tex]T''=\frac{1}{2k(\sqrt{\frac{1}{3}})^{3}}>0[/tex]
The last expression is positive because 'k' denotes a speed which is always positive.
This implies that the obtained value [tex]x=\frac{2}{\sqrt{3}}[/tex] minimizes the quantity of total time taken.
Now, from the figure, we can say that,
[tex]cos(\angle BAC)=\frac{AB}{AC}[/tex]
Put AC = x, AB = 1 in the above equation to get,
[tex]cos(\angle BAC)=\frac{1}{x}[/tex]
Put the obtained minimizing value, [tex]x=\frac{2}{\sqrt{3}}[/tex] in the above equation to get,
[tex]cos(\angle BAC)=\frac{1}{\frac{2}{\sqrt{3}} }[/tex]
[tex]cos(\angle BAC)=\frac{\sqrt{3}}{2 }[/tex]
[tex]cos(\angle BAC)=cos(30^{\circ})[/tex]
Then,
[tex]\angle BAC=30^{\circ}[/tex]
Since the angle is measured from the north, the required angle is, [tex]90^{\circ}+30^{\circ}=120^{\circ}[/tex]
Thus, Lisa should start swimming at an angle of [tex]120^{\circ}[/tex] to reach her destination as quickly as possible.
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Evaluate the expression for x=-5,y=-7, and z=9
Answers
Answer:
Is 11
Step-by-step explanation:
x+(-y)+z —> -5 +(+7)+9 = -5+7+9 = 11
Farmer McDonald raises ducks and cows. His animals have a total of 20 heads and
64 legs. How many ducks and how many cows does Mr. McDonald have?
Answers
Answer:
8 ducks, 12 cows
Step-by-step explanation:
Let the ducks be x in number and cows be y in number
ATQ, x+y=20 and 2x+4y=64, solving we get y=12 and x=8.
If farmer McDonald raises ducks and cows. His animals have a total of 20 heads and 64 legs. Mr. McDonald has 8 ducks and 12 cows.
What is the equation?An equation is a statement that two expressions, which include variables and/or numbers, are equal. In essence, equations are questions, and efforts to systematically find solutions to these questions have been the driving forces behind the creation of mathematics.
It is given that, Farmer McDonald raises ducks and cows. His animals have a total of 20 heads and 64 legs.
Suppose the number of head and legs be x and y respectively.
If His animals have a total of 20 heads and 64 legs,
x+y=20
2x+4y=64,
Solving the above equations we get y=12 and x=8.
Thus, if a farmer McDonald raises ducks and cows. His animals have a total of 20 heads and 64 legs. Mr. McDonald has 8 ducks and 12 cows.
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A landscaping company placed an order for 40 new trees. The red oak trees cost $25 a piece and the sugar maples trees cost $18. If the total order was for $790, how many of each type of tree did they order?
Answers
Answer:
its 30 sugar maple trees and 10 red oak trees
Step-by-step explanation:
Number of red oak trees = 10
And, Number of sugar maples trees = 30
What is an expression?
Mathematical expression is defined as the collection of the numbers variables and functions by using operations like addition, subtraction, multiplication, and division.
Given that;
A landscaping company placed an order for 40 new trees.
And, The red oak trees cost $25 a piece and the sugar maples trees cost $18. the total order was for $790.
Let number of red oak trees = x
And, Number of sugar maples trees = y
Hence, We can formulate;
⇒ x + y = 40
⇒ 25x + 18y = 790
By solving we get;
y = 30
x = 10
Thus, Number of red oak trees = 10
And, Number of sugar maples trees = 30
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m/HCB = 60°, m/DCB = 9x-1, and m/DCH = 2x+ 16. Find x
Answers
Answer:
[tex]x=11[/tex]
Step-by-step explanation:
Note that ∠DCB is the sum of ∠HCB and ∠DCH. Hence:
[tex]m\angle DCB = m\angle HCB + m\angle DCH[/tex]
Substitute in the appropriate values/expressions:
[tex](9x-1) = (60) + (2x+16)[/tex]
Solve for x. Combine like terms:
[tex]9x - 1 = 2x + 76[/tex]
Subtract 2x from both sides:
[tex]7x - 1 = 76[/tex]
Add one to both sides:
[tex]7x = 77[/tex]
And divide. Hence:
[tex]x=11[/tex]
Answer:
x=11
Step-by-step explanation:
<DCB = <DCH + < HCB
9x-1 = 2x+16 + 60
Combine like terms
9x-1 = 2x+76
Subtract 2x from each side
9x-1-2x= 2x+76-2x
7x-1 = 76
Add 1 to each side
7x-1 +1 = 76+1
7x = 77
Divide by 7
7x/7 = 77/7
x=11
1. Rebecca was asked to create five pairs of like terms. Determine if she completed the task
correctly and correct any errors.
Answers
Answer:
everything but 2 and 5 was correct
Step-by-step explanation:
Like terms are those terms that are having the same variables, also the variables are of the same order as well. There are two wrong pairs in given pairs of like terms.
What are Like terms?Like terms are those terms that are having the same variables, also the variables are of the same order as well.
For example, 25x and 5x are like terms; 30xy and 7xy are like terms, 9x³ and 4x² are not like terms, etc.
Rebecca is wrong because she had made a pair of (1/2)x and (1/2), which is wrong. Also, pairs 5a and 5b are wrong. This is because in each of the two pairs the terms do not have the same constant term with them.
Therefore, we can write the terms as,
2.5w and -8w → Already correct(1/2)x and (1/2) → (1/2)x and (1/2)x38 and -15 → Already correct-7c² and c² → Already correct5a and 5b → 5a and 5a or 5b and 5bHence, there are two wrong pairs in given pairs of like terms.
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Write the equation of the directrix of the parabola shown below.
y^2+16y+4x+4=0
Answers
Answer:
Hello,
F=(14,-8)
directrice: x=16
Step-by-step explanation:
Making reduce form:
[tex]y^2+16y+4x+4=0\\y^2+2*8y+64-64+4x+4=0\\\\(y+8)^2-60+4x=0\\\\x=-\dfrac{(x+8)^2}{4} +15\\[/tex]
Since i prefere working with y=...: exchanging x and y
[tex]y=-\dfrac{(x+8)^2}{4} +15\\\\Comparing\ to\ y=\dfrac{(x-a)^2}{2(b-k)} +\dfrac{b+k}{2} \\\\a=-8 :\ S=(-8,15)\\\\\\b-k=-2\ and\ b+k=30 \ \longrightarrow\ b=14\ and\ k=16\\\\Exchanging\ x\ and\ y:\\\\Focus=(14,-8)\\\\x=16[/tex]
(y+3) solve by using the distributive property
Answers
Answer:
y-3
Step-by-step explanation:
The revenue, in dollars, of a company that manufactures televisions can be modeled by the polynomial 3x²+180x . The cost, in dollars of producing the televisions can be modeled by 3x² - 160x +300. The variable x is the number of televisions sold. If 150 televisions are sold, what is the profit?
Answers
We use the profit concept, and doing this, it is found that if 150 televisions are sold, the profit is $50,700.
-------------------------------------------
Profit is given by revenue subtracted by cost.
In this question:
Revenue: [tex]R(x) = 3x^2 + 180x[/tex]Cost: [tex]C(x) = 3x^2 - 160x + 300[/tex]Thus, the profit of selling x televisions is:
[tex]P(x) = R(x) - C(x)[/tex]
[tex]P(x) = 3x^2 + 180x - (3x^2 - 160x + 300)[/tex]
[tex]P(x) = 3x^2 + 180x - 3x^2 + 160x - 300[/tex]
[tex]P(x) = 340x - 300[/tex]
-------------------------------------------
For 150 televisions, we have P(150), so:
[tex]P(150) = 340(150) - 300 = 50700[/tex]
If 150 televisions are sold, the profit is $50,700.
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Two trains leave the station at the same, one heading west and the other east. The westbound train travels at 55 miles per hour. The eastbound train travels at 75 miles per hour. How long will it take for the two trains to be 156 miles apart?
Answers
The time that taken for the two trains is 1.2 hours.
The computation of the time taken for the two trains is shown below:
Given that
The westbound train travels 55 miles per hour.
And, the eastbound train travels 75 miles per hour.
So, the total speed is
= 55 miles per hour + 75 miles per hour
= 130 miles per hour
The distance is 156 miles
So, the time taken is
[tex]= \frac{distance}{speed}\\\\= \frac{156\ miles}{130\ miles\ per\ hour}\\\\[/tex]
= 1.2 hours
Therefore we can conclude that the time that taken for the two trains is 1.2 hours.
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Answer:
1.2 hours
Step-by-step explanation:
Given data:
Speed of the westbound train = [tex]55 miles/hr[/tex]
Speed of the eastbound train = [tex]75 miles/hr[/tex]
Since the trains are moving in the opposite direction their relative speed becomes,
[tex]55 miles/hr +75 miles/hr=130 miles/hr[/tex].
Since, time = distance / speed
Now the time taken for the two trains to be 156 miles apart
[tex]time = \frac{156 miles}{130 miles/hr} \\=1.2 hours[/tex]
Hence, the time taken for the two trains to be 156 miles apart = [tex]1.2 hours[/tex]
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Help me pls pls help me
Answers
Answer:
F. 1/2
Step-by-step explanation:
If the ratio of team assistants to players are 1/6 and there are 36 players that means that there are 6 team assistants. If we do the ratio of coaches to assistant that would be 3/6 or F. 1/2
Warren has money to go see a movie after he pays $8 for the MOVIE he will have $14 left right and solve an equation to show how much money Warren has before paying for the movie
Answers
Answer:
$(8+14)
Step-by-step explanation:
Amount of money Warren has at first=$8+$14=$22
Solve for x.
5x – 3 = 2x +12
Answers
Answer:
X = 5
HOPE IT IS HELPFULLY.Find the area and the perimeter of a triangle (shown below)
PLZZZ
Answers
Answer:
A = 120, P = 55
Step-by-step explanation:
Triangle
Area = (bh)/2
A = (20x12)/2
A =240/2
A = 120
Perimeter = a + b + c
to find c, use a^2 +b^2 = c^2
20^2 + 12^2 = c^2
400 + 144 = c^2
544 = c^2
c = about 23
20 + 12 + 23 = 55
Who has hegarty maths as there school home work?
If you do please let me know below :):):):):):):)
Answers
Answer:
1200$
Step-by-step explanation:
All right, you usually pay 160 dollars but with the extra 25% off sale, you pay 120(160 ÷ 4 = 40, 160 - 40 = 120). BUT you have the extra VAT charge you will pay 150 dollars every day. You stay for 8 nights so 150 × 8 = 1200
1/6 of a loop around the circle would be a rotation of how many degrees (q)?
A=6
B=60
C=30
D=36
Answers
Answer:
60
Step-by-step explanation:
A circle is 360 degrees
1/6 of 360
1/6 * 360 = 60
Finance A bicycle shop hires road bikes for £25 per day and tandems for £40 per day. One day a family pays £155.
a Which type of bicycles did they hire?
b How many people are in the family?
Answers
Answer:
3 road bikes and 2 tandems
7 people
Step-by-step explanation:
25b + 40t = 155
b=3 and t = 2
Check
25*3 + 40*2 = 155
75+80 = 155
Assuming 1 person per road bike and 2 people per tandem
3*1 + 2*2 = 3+4 = 7
