How do you do 111? Explanation pls

the first one is, yes by AA

the second is no you cannot

Answer:

a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]

Step-by-step explanation:

[tex]a^{2} +b^{2} = 5 ^{2}[/tex]

a = b

[tex]2a^{2} = 5 ^{2}[/tex]

[tex]2a^{2} = 25\\[/tex]

[tex]a^{2} = \frac{25}{5}[/tex]

a = [tex]\frac{5}{\sqrt{5} }[/tex]

must rationalize...

a =b = [tex]\frac{5\sqrt{5} }{5}[/tex]

Answer:

4

Step-by-step explanation:

ln(e)=1 since ln= log_e

log(x^y)=y*log(x) so ln(e^4)=4*ln(4)=4*1=4

Answer:

D

Step-by-step explanation:

ln(e^4)

The 4 comes down in front of the natural log (ln). You get 4 ln(e)

The natural log of e (ln e )  is 1.

So the answer is 4 * 1 = 4

That may not be clear to you. We could try it another way.

e = 2.718281828

ln (2.718281828) = 1

ln(2.718281828)^4 = 4.  The calculator gags until you get it right.  You need the y^x key (or the x^y key of ^) It does come back with 4.

You have to monkey around with the calculator to get this to happen.  

Answer:

Below

Step-by-step explanation:

It's 66

To find a percentage of a number just multiply it by 0.whatever the percentage if that makes sense...

In this case you would do 55 x 1.2 = 66

Hope this helps!

[tex]\huge\text{Hey there!}[/tex]

[tex]\huge\boxed{\mathsf{120\% \ of\ 55}}\\\huge\boxed{= \dfrac{120}{100}\times55}\\\huge\boxed{= \dfrac{6}{5}\times\dfrac{55}{\bf 1}}\\\huge\boxed{= \dfrac{6\times55}{5\times 1}}\\\\\\\huge\boxed{6\times55=\bf 330}\\\boxed{5\times1=\bf 5}\\\\\\\huge\boxed{= \dfrac{330\div5}{5\div5}}\\\huge\boxed{=\dfrac{66}{1}}\\\huge\boxed{= \bf 66}[/tex]

[tex]\huge\boxed{\textsf{Therefore, your ANSWER is: 66}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\huge\boxed{\frak{Amphitrite1040:)}}[/tex]

Answer:

64percents

Step-by-step explanation:

25-9=16 grams - weight of copper

(16/25)*100=64 percents

Answer:

(2x+3y)^2

= (2x)^2 + 2(2x)(3y) + (3y)^2

= 4x^2 + 12xy + 9y^2

Answer:

4x^2 12xy +9y^2

Step-by-step explanation:

(2x+3y)^2

(2x+3y)(2x+3y)

FOIL

4x^2 + 6xy+6xy + 9y^2

4x^2 12xy +9y^2

Answer:

[tex]x=-\frac{11}{8}[/tex]

Step-by-step explanation:

Hi there!

[tex](x - 4) - (x + 7) = 8x[/tex]

Open up the parentheses

[tex]x - 4 - x - 7 = 8x[/tex]

Combine like terms

[tex]x -x - 4 - 7 = 8x\\-4-7=8x\\-11=8x[/tex]

Divide both sides by 8 to isolate [tex]x[/tex]

[tex]-\frac{11}{8}=x[/tex]

I hope this helps!

Answer:

the required value of c is [ -11 -1

2 5]

Step-by-step explanation:

Answer 1

x+x+y+3y+z+2z

2x+4y+3z

Answer 2

2x+4y+3z

( no like terms are there so it cannot be added)

Answer 3

9xyz

last two answers will also be similar as the question because unlike terms cannot be added..

Answer:

x=5.5

Step-by-step explanation:

Perimeter of ABCD=85

The perimeter is everything around the outside added together.

Form an equation:

3x+4+4x+6x-11+5x-7=85

Collect the like terms:

Like terms are terms that have the same powers and coefficient.

3x+4x+6x+5x=18x

4-11-7= -14

Put it back into an equation:

18x-14=85

Do inverse operations to find out what x is:

85+14=99

18x=99

99÷18=5.5 (we divide because, in algebra, when a number is next to a letter, it means times and as we want the inverse, you would have to divide)

x=5.5

Hope this helps :)

Answer:

348

Step-by-step explanation:

Volume = Area of cross section x height

Area of cross section = 1/2bh

1/2 (12x5.8) = 34.8

34.8 x 10 = 348

Volume = 348km^3

Answered by g a u t h m a t h

Answer:

18 feet

Step-by-step explanation:

To convert : multiply the length value by 3

=> 6 x 3

=> 18 feet

Answer:

550

Step-by-step explanation:

To round 553 to the tens place, we would need to identify the value of the digit in the ones place.

If the digit in the ones place is greater than 5, we increase the tens place by 1 & convert the ones place into a 0.

If not, we leave the tens place as is & convert the ones place into a 0.

Since 3 is less than 5, we round 553 to 550 so you are correct.

Answer:

Yes

550 has 2 sig figs

553 has 3

Step-by-step explanation:

Step-by-step explanation:

A1= 3.5×9=31.5

A2=2×2=4

A3=(1/2) × 5×2=5

A4= (1/2)×2×2=2

At=A1+A2+A3+A4

At= 31.5+4+5+2

At=42.5

Answer: f(x-2) which is choice A.

The blue f(x) curve is shifted 2 units to the right to get the red g(x) dashed curve.

============================================================

Explanation:

For now, ignore the red dashed curve g(x). Imagine that the blue curve f(x) is fixed in place. If we shifted the xy axis to the left 2 units, then this gives the illusion the blue curve is moving even though the curve is fixed in place.

The operation "shift xy axis 2 units to the left" means each x input is 2 units smaller. So each x input is now x-2.

Therefore, going from f(x) to f(x-2) will shift the blue curve 2 units to the right to land perfectly on the red dashed g(x) curve.

Answer:

(-4,-6)

Step-by-step explanation:

3x-4y=12

5x-2y=-8

multiply #2 by "-2"

3x-4y=12

-10x-4y=16

add two equations

-7 x = 28

x= -4

plug in -4 to equation (1 or 2)

-12 - 4y = 12

-4y = 24

y = -6

(-4,-6)

Answer:

x = -4.

y = -6.

Step-by-step explanation:

3x-4y=12

5x-2y=-8       Multiply this equation by 2:

10x-4y = -16    Subtract this from the first equation:

-7x  = 28

x = -4

Substitute thin in equation 2:

3*(-4)  - 4y = 12

-12 - 4y = 12

-4y = 24

y = -6.

Answer:

6ft by 8ft

Step-by-step explanation:

12 / 2 is 6 and 16 / 2 is 8

Answer:

proportion

Step-by-step explanation:

In a proportion, the means or the extremes (or both) may be interchanged. In proportion, the product of the means equals the product of the extremes.

hope it helps :)

mark brainliest!

Answer:

[tex]28.07^{\circ}[/tex]

Step-by-step explanation:

We can use basic trig. for a right triangle to solve this problem. In any right triangle, the tangent of an angle is equal to its opposite side divided by the hypotenuse (longest side) of the triangle.

The right triangle we're looking at involves the two dotted lines and an edge of the prism.

The bottom dotted line is a diagonal of the rectangular base of the prism. We can use the Pythagorean Theorem to find its length.

The Pythagorean Theorem states that for any right triangle, [tex]a^2+b^2=c^2[/tex], where [tex]a[/tex] and [tex]b[/tex] are the two legs of the triangle and [tex]c[/tex] is the hypotenuse.

In this case, the two legs are 9 and 12 and we are solving for [tex]c[/tex]:

[tex]9^2+12^2=c^2,\\81+144=c^2,\\225=c^2,\\c=15[/tex]

This is theta's adjacent side. Its opposite side is an edge of the prism labelled as 8 inches. Therefore, we have the following equation:

[tex]\tan \theta = \frac{8}{15}[/tex]

Take the inverse tangent of both sides:

[tex]\arctan(\tan \theta)=\arctan(\frac{8}{15})[/tex]

Simplify using [tex]\arctan(\tan\theta)=\theta, \theta \in (-90^{\circ}, 90^{\circ})[/tex]:

[tex]\theta=\arctan(\frac{8}{15}),\\\theta=28.07248694\approx \boxed{28.07^{\circ}}[/tex]

Answer:

140

Step-by-step explanation:

Left column = x

Right column = y

Rule = 3.5x = y

Because 42/12 = 3.5

3.5 * 40 = 120 + 20 = 140

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

Answer:

4000 rupees

Step-by-step explanation:

20000×10×2/100

= 4000 rupees

Answer:

ab+bc+ac=47

Step-by-step explanation:

(a+b+c)=12

Square both sides

a^2+b^2+c^2+2(ab+bc+ac)=144

2(ab+bc+ac)=94

ab+bc+ac=47

Answer:

ab + bc + ca = 47

Step-by-step explanation:

Using the algebraic identity

(a + b + c) = a² + b² + c² + 2(ab + bc + ca) , then

12² = 50 + 2(ab + bc + ca)

144 = 50 + 2(ab + bc + ca) ← subtract 50 from both sides

94 = 2(ab + bc + ca) ← divide both sides by 2

47 = ab + bc + ca

Answer:

The name of the given figure in two different ways are - J⇔U and U⇔J

Answer:

mostly rational but sometimes irrational

Answer:

c  a = 2.4b

Step-by-step explanation:

y = kx is the form of the equation where k is the constant of proportionality

y and x can be any letters

Replacing y and x with a and b  and k with 2.4

a = 2.4b

Answer:

cold to hot hope it helps

The solution to each of the question takes different approach, as the questions are taken from different concepts; however, a common operation among all questions, is factorization.

[tex](1)\ (-xy)^3(xz)[/tex]

Expand

[tex](-xy)^3(xz) = (-x)^3* y^3*(xz)[/tex]

[tex](-xy)^3(xz) = -x^3* y^3*xz[/tex]

Rewrite as:

[tex](-xy)^3(xz) = -x^3*x* y^3*z[/tex]

Apply law of indices

[tex](-xy)^3(xz) = -x^4y^3z[/tex]

[tex](2)\ (\frac{1}{3}mn^{-4})^2[/tex]

Expand

[tex](\frac{1}{3}mn^{-4})^2 =(\frac{1}{3})^2m^2n^{-4*2}[/tex]

[tex](\frac{1}{3}mn^{-4})^2 =\frac{1}{9}m^2n^{-8[/tex]

[tex](3)\ (\frac{1}{5x^4})^{-2}[/tex]

Apply negative power rule of indices

[tex](\frac{1}{5x^4})^{-2}= (5x^4)^2[/tex]

Expand

[tex](\frac{1}{5x^4})^{-2}= 5^2x^{4*2}[/tex]

[tex](\frac{1}{5x^4})^{-2}= 25x^{8[/tex]

[tex](4)\ -x(2x^2 - 4x) - 6x^2[/tex]

Expand

[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 + 4x^2 - 6x^2[/tex]

Evaluate like terms

[tex]-x(2x^2 - 4x) - 6x^2 = -2x^3 -2x^2[/tex]

Factor out x^2

[tex]-x(2x^2 - 4x) - 6x^2 = (-2x-2)x^2[/tex]

Factor out -2

[tex]-x(2x^2 - 4x) - 6x^2 = -2(x+1)x^2[/tex]

[tex](5)\ \sqrt{\frac{4y}{3y^2}}[/tex]

Divide by y

[tex]\sqrt{\frac{4y}{3y^2}} = \sqrt{\frac{4}{3y}}[/tex]

Split

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{\sqrt{4}}{\sqrt{3y}}[/tex]

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}}[/tex]

Rationalize

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2}{\sqrt{3y}} * \frac{\sqrt{3y}}{\sqrt{3y}}[/tex]

[tex]\sqrt{\frac{4y}{3y^2}} = \frac{2\sqrt{3y}}{3y}[/tex]

[tex](6)\ \frac{8}{3 + \sqrt 3}[/tex]

Rationalize

[tex]\frac{8}{3 + \sqrt 3} = \frac{3 - \sqrt 3}{3 - \sqrt 3}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{(3 + \sqrt 3)(3 - \sqrt 3)}[/tex]

Apply difference of two squares to the denominator

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{3^2 - (\sqrt 3)^2}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{9 - 3}[/tex]

[tex]\frac{8}{3 + \sqrt 3} = \frac{8(3 - \sqrt 3)}{6}[/tex]

Simplify

[tex]\frac{8}{3 + \sqrt 3} = \frac{4(3 - \sqrt 3)}{3}[/tex]

[tex](7)\ \sqrt{40} - \sqrt{10} + \sqrt{90}[/tex]

Expand

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4*10} - \sqrt{10} + \sqrt{9*10}[/tex]

Split

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =\sqrt{4}*\sqrt{10} - \sqrt{10} + \sqrt{9}*\sqrt{10}[/tex]

Evaluate all roots

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2*\sqrt{10} - \sqrt{10} + 3*\sqrt{10}[/tex]

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =2\sqrt{10} - \sqrt{10} + 3\sqrt{10}[/tex]

[tex]\sqrt{40} - \sqrt{10} + \sqrt{90} =4\sqrt{10}[/tex]

[tex](8)\ \frac{r^2 + r - 6}{r^2 + 4r -12}[/tex]

Expand

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r^2 + 3r-2r - 6}{r^2 + 6r-2r -12}[/tex]

Factorize each

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r(r + 3)-2(r + 3)}{r(r + 6)-2(r +6)}[/tex]

Factor out (r+3) in the numerator and (r + 6) in the denominator

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{(r -2)(r + 3)}{(r - 2)(r +6)}[/tex]

Cancel out r - 2

[tex]\frac{r^2 + r - 6}{r^2 + 4r -12}=\frac{r + 3}{r +6}[/tex]

[tex](9)\ \frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14}[/tex]

Cancel out x

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 5x - 14}[/tex]

Expand the numerator of the 2nd fraction

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x^2 - 7x+2x - 14}[/tex]

Factorize

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{x(x - 7)+2(x - 7)}[/tex]

Factor out x - 7

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4x + 8}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]

Factor out 4 from 4x + 8

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4(x + 2)}{x} \cdot \frac{1}{(x + 2)(x - 7)}[/tex]

Cancel out x + 2

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x} \cdot \frac{1}{(x - 7)}[/tex]

[tex]\frac{4x + 8}{x^2} \cdot \frac{x}{x^2 - 5x - 14} = \frac{4}{x(x - 7)}[/tex]

[tex](10)\ (3x^3 + 15x^2 -21x) \div 3x[/tex]

Factorize

[tex](3x^3 + 15x^2 -21x) \div 3x = 3x(x^2 + 5x -7) \div 3x[/tex]

Cancel out 3x

[tex](3x^3 + 15x^2 -21x) \div 3x = x^2 + 5x -7[/tex]

[tex](11)\ \frac{m}{6m + 6} - \frac{1}{m+1}[/tex]

Take LCM

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m(m + 1) - 1(6m + 6)}{(6m + 6)(m + 1)}[/tex]

Expand

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 + m- 6m - 6}{(6m + 6)(m + 1)}[/tex]

[tex]\frac{m}{6m + 6} - \frac{1}{m+1} = \frac{m^2 - 5m - 6}{(6m + 6)(m + 1)}[/tex]

[tex](12)\ \frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}}[/tex]

Rewrite as:

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} \div \frac{2}{y^2 - 9}[/tex]

Express as multiplication

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 9}{2}[/tex]

Express y^2 - 9 as y^2 - 3^2

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{y^2 - 3^2}{2}[/tex]

Express as difference of two squares

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{y - 3} * \frac{(y - 3)(y+3)}{2}[/tex]

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{1}{1} * \frac{(y+3)}{2}[/tex]

[tex]\frac{\frac{1}{y - 3}}{\frac{2}{y^2 - 9}} = \frac{y+3}{2}[/tex]

Read more at:

https://brainly.com/question/4372544