Help please ……………….zzzz

Help Please .zzzz

Answers

Answer 1

1) I think 15 choose (d)

2) The choose (C) -4fg+4g

3) The choose (d) 3xy/2

4) The choose (a) ab/6

5) The choose (C) 2p+4q-6

6)

[tex]\pi {r}^{2} h = 3.14 \times {3}^{2} \times 1.5 = 42.39 {m}^{3} = 42.390 {m}^{3} [/tex]

Point 6 I think there is an error because the unit m must be m³ because it is r² (m²) and h(m) becomes m³.

I hope I helped you^_^


Related Questions

An article describes an experiment to determine the effectiveness of mushroom compost in removing petroleum contaminants from soil. Out of 155 seeds planted in soil containing 3% mushroom compost by weight, 74 germinated. Out of 155 seeds planted in soil containing 5% mushroom compost by weight, 86 germinated. Can you conclude that the proportion of seeds that germinate differs with the percent of mushroom compost in the soil

Answers

Solution :

Let [tex]p_1[/tex] and [tex]p_2[/tex]  represents the proportions of the seeds which germinate among the seeds planted in the soil containing [tex]3\%[/tex] and [tex]5\%[/tex] mushroom compost by weight respectively.

To test the null hypothesis [tex]H_0: p_1=p_2[/tex] against the alternate hypothesis  [tex]H_1:p_1 \neq p_2[/tex] .

Let [tex]\hat p_1, \hat p_2[/tex] denotes the respective sample proportions and the [tex]n_1, n_2[/tex] represents the sample size respectively.

[tex]$\hat p_1 = \frac{74}{155} = 0.477419[/tex]

[tex]n_1=155[/tex]

[tex]$p_2=\frac{86}{155}=0.554839[/tex]

[tex]n_2=155[/tex]

The test statistic can be written as :

[tex]$z=\frac{(\hat p_1 - \hat p_2)}{\sqrt{\frac{\hat p_1 \times (1-\hat p_1)}{n_1}} + \frac{\hat p_2 \times (1-\hat p_2)}{n_2}}}[/tex]

which under [tex]H_0[/tex]  follows the standard normal distribution.

We reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance, if the P-value [tex]<0.05[/tex] or if [tex]|z_{obs}|>Z_{0.025}[/tex]

Now, the value of the test statistics = -1.368928

The critical value = [tex]\pm 1.959964[/tex]

P-value = [tex]$P(|z|> z_{obs})= 2 \times P(z< -1.367928)$[/tex]

                                     [tex]$=2 \times 0.085667$[/tex]

                                     = 0.171335

Since the p-value > 0.05 and [tex]$|z_{obs}| \ngtr z_{critical} = 1.959964$[/tex], so we fail to reject [tex]H_0[/tex] at [tex]0.05[/tex] level of significance.

Hence we conclude that the two population proportion are not significantly different.

Conclusion :

There is not sufficient evidence to conclude that the [tex]\text{proportion}[/tex] of the seeds that [tex]\text{germinate differs}[/tex] with the percent of the [tex]\text{mushroom compost}[/tex] in the soil.

Does anyone know the answer??

Answers

Answer:

I think the answer is 39x, 13y

Step-by-step explanation:

point : extra points

1 : 3

y : 39

y= 39÷3

y= 13

The number of basic trigonometric ratios is....

A.3
B.4
C.5
D.6

Answers

Answer:

There are three basic trigonometric ratios: sine , cosine , and tangent .

Step-by-step explanation:

The answer to this math problem need help

Answers

Step-by-step explanation:

you know that you can copy and paste and give the answer

if 2 shirts cost 18.80, how much would 9 shirt cost.

Answers

Answer:

84.60

Step-by-step explanation:

We can write a ratio to solve

18.80             x

---------   = --------------

2 shirts    9 shirts

Using cross products

18.80 *9 = 2x

169.2 =2x

Divide each side by 2

169.2/2 =2x/2

84.60 =x

An office manager has received a report from a consultant that includes a section on equipment replacement. The report indicates that scanners have a service life that is normally distributed with a mean of 41 months and a standard deviation of 4 months. On the basis of this information, determine the proportion of scanners that can be expected to fail within plus or minus 6 months of the mean. (Enter your answer as a percentage without the percent sign; keep 2 decimal places)

Answers

Answer:

The answer is "36.14%"

Step-by-step explanation:

The complete question is given in the attached file please find it.

[tex]\mu =41\\\\\sigma= 4\\\\P(42<\bar{x}<48)= p(\bar{x}<48)-p(\bar{x}<42)\\\\Z =\frac{(42-41)}{4} = \frac{1}{4} =0.25\\\\Z =\frac{(48-41)}{4} = \frac{7}{4} = 1.75\\\\[/tex]

Using z-table to find the value.

[tex]\to P(41<\bar{x}<48) = 0.9599- 0.5987 = 0.3614\times 100= 36.14\%[/tex]

This means that between 42 and 48 months, 36.14 % of scanners could be predicted will break down.

(x - 7)2 = x2 - 49
O True
O False

Answers

Answer:

False

Step-by-step explanation:

Find the length of BC again

Answers

Since this is a right triangle, we can use one of the three main trigonometric functions: sine, cosine, or tangent.

Remember: SOH-CAH-TOA

Looking from the angle, we know the opposite side and want to know the adjacent side. Therefore, we should use the tangent function.

tan(61) = 47 / BC

BC = 47 / tan(61)

BC = 26.05 units

Hope this helps!

Answer:

BC = 26.05

Step-by-step explanation:

SOH CAH TOA

tan 61 = 47/BC

BC = 47/tan 61

Please help! I will give you a lot of points if you do and the brainiest!

Answers

Answer:

First truth table:

~q      p V ~q      ~(p V ~q)

F        T               F

T        T               F

F        F               T

T        T               F

Second truth table:

~q      p V ~q      ~(p V ~q)

F        T                F

Step-by-step explanation:

The ~ operator is a negator (or NOT), such that it is the opposite of the sign.

The first column wants the negation of [tex]q[/tex], and the values of q are

T, F, T, F, for the columns starting from the top. The negation for the columns are F, T, F, T.

For the second column, The 'V' operator is the OR operator, so a single True, or T will result in a True.

For the first row, not q is F, and T OR F will result in T.

For the second row, not q is T, and T OR T will result in T.

For the third row, not q is F, and F OR F will result in F.

For the fourth row, not q is T, and F OR T will result in T.

In the last column, we must figure out not p OR not q, which we did in the last column, so all we must do is figure out the NOT of values of the last column.

The values of the last column are T, T, F, T, respectively, so the not of the columns will be F, F, T, F.

In the bottom truth table, not q, will be F because the value of q is T. The second column wants p OR not q, and we already know that not q is F, and the value of p is T. T OR F is equal to T. In the last column, the question wants the not of p OR not q, which we did in the last column, so we must figure out the not value of the last column, which is T. The not of T is F.

Given $f(x) = \frac{\sqrt{2x-6}}{x-3}$, what is the smallest possible integer value for $x$ such that $f(x)$ has a real number value? Please show steps. Thank you!

(I rewrote the question without the symbols, they are the same question)

Given f(x) = {2x-6}/{x-3}, what is the smallest possible integer value for x such that f(x) has a real number value? Thank you!​

Answers

Answer:   x = 4

===========================================================

Explanation:

The given function is

[tex]f(x) = \frac{\sqrt{2x-6}}{x-3}[/tex]

which is the same as writing f(x) = ( sqrt(2x-6) )/(x-3)

The key for now is the square root term. Specifically, the stuff underneath. This stuff is called the radicand.

Recall that the radicand cannot be negative, or else the square root stuff will result in a complex number. Eg: [tex]\sqrt{-4} = 0+2i[/tex]

The question is basically asking: what is the smallest x such that [tex]\sqrt{2x-6}[/tex] is a real number?

Well if we made 2x-6 as small as possible, ie set it equal to 0, then we can find the answer

[tex]2x-6 = 0\\\\2x = 6\\\\x = 6/2\\\\x = 3\\\\[/tex]

I set the radicand equal to 0 because that's as small as the radicand can get (otherwise, we're dipping into negative territory).

So 2x-6 set equal to 0 leads to x = 3.

This means x = 3 produces the smallest radicand (zero) and therefore, it is the smallest allowed x value for that square root term.

But wait, if we tried x = 3 in f(x), then we get...

[tex]f(x) = \frac{\sqrt{2x-6}}{x-3}\\\\f(3) = \frac{\sqrt{2*3-6}}{3-3}\\\\f(3) = \frac{\sqrt{0}}{0}\\\\[/tex]

which isn't good. We cannot have 0 in the denominator. Dividing by zero is not allowed. The result is undefined. It doesn't even lead to a complex number. So we'll need to bump x = 3 up to x = 4. You should find that x = 4 doesn't make the denominator 0.

----------------

In short, we found that x = 3 makes the square root as small as possible while staying a real number, but it causes a division by zero error with f(x) overall. So we bump up to x = 4 instead.

Answer pleaseeeeeeee

Answers

Answer:

17x^2-9x-9 -->B

Step-by-step explanation:

7x^2 -12x +3 +10x^2+3x-12

Let a=⟨1,−4,2⟩ and b=⟨−5,−5,−2⟩. Compute:

a+b=⟨ ,, ⟩
a−b=⟨ ,,⟩
2a=⟨ ,,⟩
3a+4b=⟨ ,, ⟩
|a|=

Answers

Answer:

a + b = ⟨-4, -9, 0⟩

a - b = ⟨6, 1, 4⟩

2a = ⟨2, -8, 4⟩

3a + 4b = ⟨-17, -32, -2⟩

|a| = √21

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to Right

Pre-Calculus

Vectors

OperationsScalars[Magnitude] ||v|| = √(x² + y² + z²)

Step-by-step explanation:

Adding and subtracting vectors are follow the similar pattern of normal order of operations:

a + b = ⟨1 - 5, -4 - 5, 2 - 2⟩ = ⟨-4, -9, 0⟩

a - b = ⟨1 + 5, -4 + 5, 2 + 2⟩ = ⟨6, 1, 4⟩

Scalar multiplication multiplies each component:

2a = ⟨2(1), 2(-4), 2(2)⟩ = ⟨2, -8, 4⟩

Remember to multiply in the scalar before doing basic operations:

3a + 4b = ⟨3(1), 3(-4), 3(2)⟩ + ⟨4(-5), 4(-5), 4(-2)⟩ = ⟨3, -12, 6⟩ + ⟨-20, -20, -8⟩ = ⟨-17, -32, -2⟩

Absolute values surrounding a vector signifies magnitude of a vector. Follow the formula:

|a| = √[1² + (-4)² + 2²] = √21

Find the Antilog of 547.840​

Answers

Answer:

It's impossible because the figure is greater than 10

Step-by-step explanation:

[tex]{ \boxed{ \bf{antilog \: of \: x = \frac{x}{ log} = {10}^{x} }}}[/tex]

Therefore:

[tex]{ \sf{anti(547.840) = {10}^{547.840} }} \\ { \tt{ \red{math \: error \: !}}}[/tex]

OMG!! I’m stuck on 4a) b) c)
Help please

Answers

Answer:

a) 750 cmb) 288 cmc) 2112 cm

Step-by-step explanation:

Formula for getting the surface area of a rectangular prism: SA = 2 (WL + HL + HW)a) SA = 2 (WL + HL + HW) = 2(75) + 2(225) + 2(75) = 150 + 450 + 150 = 750 cm^2b) SA = 2 (WL + HL + HW)= 2(48) + 2(72) + 2(24)= 96 + 144 + 48=288 cm^2c) SA = 2 (WL + HL + HW)= 2(400) + 2(400) + 2(256)= 800 + 800 + 512= 2112 cm^2

[tex]\tt{ \green{P} \orange{s} \red{y} \blue{x} \pink{c} \purple{h} \green{i} e}[/tex]

Answer:

Below in bold.

Step-by-step explanation:

(a) The surface area  consists of the sum of the area of 3 sets of 2 congruent rectangles. The 2 rectangles are on opposite sides of the solid.

= 2(15*15) + 2(5*15) + 2(5&15)

= 450 + 150 + 150

= 750 unit^2.

(b). Similarly to the above:

Surface area = 2(12*6) + 2(4*12) + 2(4*6)

= 144 + 96 + 48

= 288 unit^2.

(c)  Again:

Surface area =  2(25*16) + 2(25*16) + 2(16*16)

= 400 + 400 + 256

= 1056 unit^2.

convert the following decimals to a simplified fraction. showing all work

Answers

Hello.

Answer:

1/200, 667/500

I hoped this helped

Consider the triangle ΔXYZ . Find the angle Z given that ZY=30 , ZX=15 , and YX=21

Answers

Step-by-step explanation:

hey bro can get the diagram

Answer:

where is the diagram plz show the diagram

Step-by-step explanation:

Will mark brainliest

Plz solve on a paper or draw on the picture thx in advance

Answers

The answer is Acute hdushsjdjd

9514 1404 393

Answer:

  the red angle has no specific value

Step-by-step explanation:

There is sufficient information here to specify all of the angles except the two unknown angles in the 70° (dark blue) triangle. Those two angles must total 110°, but that measure cannot be allocated between them based on the information in the diagram.

The attachments show that all of the given angle constraints can be met while the red angle may vary considerably. It can range through the interval (0°, 110°), but cannot be either of those end values.

Please help! Identify which of the following is not equivalent to a1/4

Answers (images below)
no links please!

Answers

Answer: B

Step-by-step explanation:

A) [tex]a^\frac{3}{4}[/tex]÷[tex]a^\frac{1}{2}[/tex] cannot be the answer. When a to the power of x is divided by a to the power of y it is a to the power of x-y. Ex: [tex]a^x[/tex]÷[tex]a^y=a^x^-^y[/tex]

So 3/4-1/2 is 1/4 giving us [tex]a^{\frac{1}{4} }[/tex]

B is the answer because taking the square root of a is the same as [tex]a^\frac{1}{2}[/tex] which isn't the same as [tex]a^\frac{1}{4}[/tex]

C is not the answer because when a to the power of x is multiplied by a to the power of y it is a to the power of x+y. Ex:  [tex]a^x[/tex]·[tex]a^y[/tex]=[tex]a^{x+y}[/tex]

1/8+1/8=1/4 so it is [tex]a^\frac{1}{4}[/tex]

D can't be the answer. [tex]a^\frac{1}{8}[/tex] squared is the same as [tex]a^\frac{1}{8}[/tex]·[tex]a^\frac{1}{8}[/tex] so the same explanation of c applies to d

The perimeter of a rectangle is 202 the length is 26 more than 4 times the width find the dimensions

Answers

Answer:

Width = xLength = 26 + 4x

Perimeter

[tex]202 = x + x + 26 + 4x + 26 + 4x\\202-26-26=10x\\150=10x\\x=15[/tex]

Therefore, the dimensions are

Width = x = 15Length = 26 + 4x = 26 + 4(15) = 86


Find the face value of the 20-year zero-coupon bond at 4.4%, compounded semiannually, with a price of $8,375.
$45.000
$53.000

Answers

The correct face value will be Option C ($20,000). A further solution id provided below.

Given:

Time,

t = 20 years

Rate,

r = 4.4%

Price

= $8,375

Now,

The yield will be:

= [tex]\frac{4.4}{2}[/tex]

= [tex]1.1[/tex] (%)

Time will be:

= [tex]20\times 2[/tex]

= [tex]40 \ periods[/tex]

As we know the formula,

⇒ [tex]Price \ of \ bond = \frac{Face \ value}{(1+\frac{r}{2} )^{n\times 2}}[/tex]

By substituting the values, we get

                   [tex]8375=\frac{Face \ value}{(1+\frac{0.044}{2} )^{20\times 2}}[/tex]

                   [tex]8375=\frac{Face \ value}{(1.022)^{40}}[/tex]

                   [tex]8375=\frac{Face \ value}{2.3880083}[/tex]

The face value will be:

        [tex]Face \ value = 2.3880083\times 8375[/tex]

                          [tex]=20,000[/tex] ($)

Learn more about face value here:

https://brainly.com/question/14862802

Suppose taxi fares from Logan Airport to downtown Boston is known to be normally distributed and a sample of seven taxi fares produces a mean fare of $21.51 and a 95% confidence interval of [$20.52, $22.48]. Which of the following statements is a valid interpretation of the confidence interval?
a. we are 95% confident that a randomly selected taxi fare will be between $2051 and $2421.
b. 95% of all taxi fares are between $2051 and $2421.
c. We are 95% confident that the average tau fare between Logan Airport and downtown Boston will fall between $2051 and $2421.
d. The mean amount of a taxi fare is $22.31, 95% of the time.

Answers

Answer:

c. We are 95% confident that the average taxi fare between Logan Airport and downtown Boston will fall between $20.51 and $24.21.

Step-by-step explanation:

x% confidence interval:

A confidence interval is built from a sample, has bounds a and b, and has a confidence level of x%. It means that we are x% confident that the population mean is between a and b.

95% confidence interval of [$20.52, $22.48].

We can be 95% sure that the true mean amount of taxis fares in downtown Boston is in this interval, and thus, the correct answer is given by option C.

Martha, Lee, Nancy, Paul, and Armando have all been invited to a dinner party. They arrive randomly, and each person arrives at a different time.

a. In how many ways can they arrive?

b. In how many ways can Martha arrive first and Armando last?

c. Find the probability that Martha will arrive first and Armando last.

Show your work

Answers

Answer:

a) 120

b) 6

c) 1/20

Step-by-step explanation:

a) 5! = 120

b) (5 - 2)! = 6

c) 6/120 = 1/20

The true length of recovery for patients with knee surgery is normally distributed with a mean of 123 days and a standard deviation of 1 day. What proportion of the patients will recover between 121 and 124 days?

Answers

Answer:

0.81859

Step-by-step explanation:

Given that the length of recovery days for patients with knee surgery is normally distributed with :

Mean, μ = 123 days

Standard deviation, σ = 1 day

The proportion of patients that will recover with 121 and 124 days :

We obtain the Probability of Z score :

Z = (x - μ) / σ

P(Z < (x - μ) / σ) < Z < P(Z < (x - μ) / σ)

P(Z < (121 - 123) / 1) < Z < P(Z < (124 - 123) / 1)

P(Z < - 2) < Z < P(Z < 1)

Using the normal distribution table :

P(Z < 1) - P(Z < - 2)

0.84134 - 0.02275

= 0.81859

(1,-19),(-2,-7) finding slope

Answers

Answer:

The slope is -4.

Step-by-step explanation:

Slope(m)=(y2-y1)/(x2-x1)

y2=-7, y1=-19, x2=-2, x1=1

(-7+19)/(-2-1)

=12/-3

=-4

Answer: -4

Step-by-step explanation:

The slope formula is: [tex]y_{2} -y_{1}/x_{2}-x_{1} \\[/tex]

So it is: (-7+19)/(-2-1) = 12/-3 = -4

I hope this helped!

find the slope of the line that passes through these two points

Answers

Answer:

Step-by-step explanation:

A boat is pulled into a dock by means of a winch 12 feet above the deck of the boat. (a) The winch pulls in rope at a rate of 4 feet per second. Determine the speed of the boat when there is 15 feet of rope out.

Answers

Answer:

the speed of the boat is 6.67 ft/s

Step-by-step explanation:

Given;

height of the winch, h = 12 ft

the rate at which the winch pulls, the rope, = 4 ft/s

This form a right triangle problem;

let the height of the right triangle = h

let the base of the triangle = b (this corresponds to the horizontal displacement of the boat)

let the hypotenuse side = c

c² = b² + h²

[tex]2c\frac{dc}{dt} = 2b\frac{db}{dt} + 2h \frac{dh}{dt}\\\\The \ height \ of \ the \ winch \ is \ not \ changing \\\\2c\frac{dc}{dt} = 2b\frac{db}{dt} + 2h (0)\\\\2c\frac{dc}{dt} = 2b\frac{db}{dt} \\\\c\frac{dc}{dt} = b\frac{db}{dt} ----(*) \\\\when;\\\\the\ hypotenuse \ c = 15 \ ft\\\\the \ the \ the \ height, h = 12 \ ft\\\\the \ base, b \ becomes ;\\\\b^2 = c^2 -h^2\\\\b^2 = 15^2 - 12^2\\\\b^2 = 81\\\\b = \sqrt{81} \\\\b = 9 \ ft\\\\\\from \ the \ equation (*) \ above;\\\\[/tex]

[tex]c\frac{dc}{dt} = b \frac{db}{dt} \\\\dc/dt = 4 \ ft/s, \ \ c = 15 \ ft, \ \ b = 9 \ ft\\\\15 (4) = 9\frac{db}{dt} \\\\60 = 9 \frac{db}{dt} \\\\\frac{db}{dt} = \frac{60}{9} = 6.67 \ ft/s[/tex]

Therefore, the speed of the boat is 6.67 ft/s

When multiplying by 10 how many spaces do you move the decimal point

Answers

Answer:

If you multiply a decimal by 10, the decimal point will move one place to the right. If you divide a decimal by 10, the decimal point will move one place to the left.

Step-by-step explanation:

Multiplying a decimal by 10 increases the value of each digit by 10. Multiplying a decimal by a power of 10 increases the value of each digit by a number of times that is equivalent to that power of 10. When a digit's value is changed, that digit is moved to the appropriate place.

If two angles are complementary, find the measure of each of angle.

Answers

Answer:

B: 30 and 60

Step-by-step explanation:

First, let's set up an equation. Since the two angles are complementary, we can write the equation like this:

2p + p = 90

Now, let's solve it!

2p + p = 90

Combine like terms:

3p = 90

Divide each side by 3 to isolate p:

3p/3 = 90/3

p = 30

Now that we know how many degrees one of our angles is, we can subtract that from 90 to get both of the complementary angles.

90 - 30 = 60

Therefore, the two angles that are complementary in this case are 30 and 60 degrees.

Alice wants to estimate the percentage of people who plan
on voting yes for the upcoming school levy. She surveys
380 individuals and finds that 260 plan on voting yes.
Identify the values needed to calculate a confidence interval
at the 90% confidence level. Then find the confidence interval.
zo10 z0.05 zo.025 zo01 z0.005
1.282 1.645 1.960 2.326 2.576
Use the table of common z-scores above.

Answers

Answer:

"[tex]0.6450 < p < 0.723[/tex]" is the right solution.

Step-by-step explanation:

Given:

n = 380

x = 260

Point estimate,

[tex]\hat p = \frac{x}{n}[/tex]

  [tex]=\frac{260}{380}[/tex]

  [tex]=0.6842[/tex]

Critical value,

[tex]Zc = 1.645[/tex]

Standard error will be:

[tex]S.E = \sqrt{\frac{0.6842(1-0.6842)}{380} }[/tex]

      [tex]=0.0238[/tex]

Margin of error will be:

[tex]E = Zc\times S.E[/tex]

   [tex]=1.645\times 0.0238[/tex]

   [tex]=0.0392[/tex]

hence,

Confidence level will be:

= [tex]\hat p \pm E[/tex]

= [tex]0.6842 \pm 0.0392[/tex]

= [tex]0.6450 < p < 0.723[/tex]

Select the correct answer.

What is the value of this expression when x = -6 and ?
4(x2 + 3) − 2y

Answers

Answer:

D. 157

Step-by-step explanation:

4(x^2+3)-2y

4(6^2+3)-2(-1/2) add in given values

4(39)+1.     start with parentheses

156+1.        combine like terms

157.            answer

Answer:

D. 157

Step-by-step explanation:

Hi there!

We want to find the value of the expression 4(x²+3)-2y is when x=-6 and y=-1/2

Let's first simplify the expression, as that will likely make it easier

Distribute 4 to both x² and 3

4x²+12-2y

That's the expression

Substitute -6 as x into the expression

4(-6)²+12-2y

Raise (-6) to the second power

4*36+12-2y

Multiply 36 by 4

144+12-2y

Add 12 and 144 together

156-2y

Now the expression is 156-2y

But remember that we know that y=-1/2, and we haven't substituted it into the expression yet

Substitute -1/2  as y into the expression

156-2(-1/2)

Multiply

156+2/2

Simplify

156+1

Add

157

Hope this helps!

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