Gym A charges a registration fee of $74 plus $33 per month for members. Gym B charges a registration fee of $164 plus $18 per month for members. After how many months would the total cost at Gym A and Gym B be the same for members?
Answers
Answer:
The total charge at Gym A and Gym B would be the same at 6 months
Step-by-step explanation:
The model for the charges of both Gyms is made of the registration fee plus a variable quantity per month.
Let's call m the number of months for members.
Gym A charges $74 plus $33 per month, thus:
[tex]C_a=74+33m[/tex]
Gym B charges $164 plus $18 per month, thus:
[tex]C_b=164+18m[/tex]
We want to find out the number of months needed for both charges to be the same, thus:
[tex]74+33m=164+18m[/tex]
Subtracting 74 and 18m:
[tex]33m-18m=164-74[/tex]
Simplifying:
[tex]15m=90[/tex]
Dividing by 15:
[tex]m=90/15=6[/tex]
m=6
The total charge at Gym A and Gym B would be the same at 6 months
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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Answers
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Step-by-step explanation:
Did it on Edge 2020! have fun
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Maria had 20 dollar gift card to an online music store. She spent the entire amount on songs which cost 1 dollar each and the music videos which cost 2 dollars each Maria bought five more songs than music videos. Write down the system of equations to represent the situation
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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Answer:
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Step-by-step explanation:
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Answers
Answer:
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Step-by-step explanation:
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The ratio of the number of boys to the number of girls at your school is 5 to 8. Which statements are accurate according to this ratio?
a. If a class has 16 girls it is reasonable to expect there are approximately 10 boys in the same class.
b. In a group of 52 students about 20 are boys.
c. The ratio of girls to total students is 8 to 13.
d. The Algebra class has 24 girls and 16 boys. This is the same ratio as girls to boys in the school.
e. If there are 208 students in the school it is reasonable to expect there are 128 girls.
Please help!!
Answers
The ratio of the number of boys to the number of girls at your school is 5 to 8. Which statements are accurate according to this ratio?
The ratio of number of boys to girls is [tex]\frac{5}{8}[/tex]. That means:
[tex]\frac{boys}{girls} =\frac{5}{8}[/tex]
Let's look at the first choice.
a. If a class has 16 girls, it is reasonable to expect there are approximately 10 boys in the same class.
Make the amount as a fraction with boys over girls.
[tex]\frac{boys}{girls} =\frac{10}{16}[/tex]
10 and 16 can be simplified. The greatest common factor of 10 and 16 is 2, so divide by 2.
[tex]\frac{boys}{girls} =\frac{10 \div 2}{16 \div 2} =\frac{5}{8}[/tex]
Since the ratio is the same, choice a is correct.
Let's move onto the second choice.
b. In a group of 52 students, about 20 are boys.
If 20 students are boys, then the amount of girls is equal to 52 - 20, which is 32. Make the amount as a fraction with boys over girls.
[tex]\frac{boys}{girls} =\frac{20}{32}[/tex]
20 and 32 can be simplified. The greatest common factor of 10 and 16 is 4, so divide by 4.
[tex]\frac{boys}{girls} =\frac{20 \div 4}{32 \div 4}=\frac{5}{8}[/tex]
Since the ratio is the same, choice b is correct.
Let's go to the third choice.
c. The ratio of girls to total students is 8 to 13.
If the ratio of girls to total students is 13, that means there are 8 girls. The number of boys can be found by subtracting 8 from 13, which is 5. Make the amount as a fraction with boys over girls.
[tex]\frac{boys}{girls} =\frac{5}{8}[/tex]
Since the ratio is the same, choice c is correct.
Let's go to the fourth choice.
d. The Algebra class has 24 girls and 16 boys. This is the same ratio as girls to boys in the school.
Make the amount as a fraction with boys over girls.
[tex]\frac{boys}{girls} =\frac{16}{24}[/tex]
16 and 24 can be simplified. The greatest common factor of 16 and 24 is 8, so divide by 8.
[tex]\frac{boys}{girls} =\frac{16 \div 8}{24 \div 8} =\frac{2}{3}[/tex]
Since the ratio is not the same, choice d is not correct.
Lastly, the fifth choice.
e. If there are 208 students in the school, it is reasonable to expect there are 128 girls.
If there are 128 girls out of 208 students, the number of boys can be found by subtracting the number of girls from the amount of total students. 208 - 128 is 80, so there are 80 boys. Make the amount as a fraction with boys over girls.
[tex]\frac{boys}{girls} =\frac{80}{128}[/tex]
80 and 128 can be simplified. The greatest common factor of 80 and 128 is 16, so divide by 16.
[tex]\frac{boys}{girls} =\frac{80 \div 16}{128 \div 16}=\frac{5}{8}[/tex]
Since the ratio is the same, choice e is correct.
choice a ✔
choice b ✔
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Does the point (3,9) satisfy the inequality y<_2x + 2?
yes
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Which set of transformations would prove triangle GFE ~ triangle GHI?
Answers
Answer:
Dilation of 1/2 and then a reflection over y=2
Answer:
reflect GHI over x= -2, and dilatate G'H'I' by a scale factor of 2 from point G
Step-by-step explanation:
EFG is turned the other way, meaning that GHI was flipped. because EFG is bigger, and having a scale factor that's a whole number means it gets bigger, then this answer is correct because its both bigger and flipped in the picture.
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asp please explain!
Answers
Someone know how to do this Im very confusing about how to do it
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If f(x) = 3(x+5) + 4/x, what is f(a + 2)?
A. 3(a + 2) + 4/a +2
B. 3(f(a)+5)+ 4/f(a)+2
C. 3(a + 7) + 4/a+2
Answers
Answer:
C. 3(a+7) + 4/a+2
Step-by-step explanation:
f(x) = 3(x+5) + 4/x
f(a+2) = 3(a+2+5) + 4 /(a+2)
= 3(a+7) + 4/a+2
URGENT I NEED THIS ASAP ILL GIVE BRAINLEST TO THE FIRST PERSON WHO ANSWERS
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Answer: Constant rate of change linear
Step-by-step explanation:
What is the least common multiple (LCM) of 15, 24 and 27?
Answers
Answer:
1080
Step-by-step explanation:
Find and list multiples of each number until the first common multiple is found. This is the lowest common multiple.
Multiples of 15:
15, 30, 45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195, 210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375, 390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, 735, 750, 765, 780, 795, 810, 825, 840, 855, 870, 885, 900, 915, 930, 945, 960, 975, 990, 1005, 1020, 1035, 1050, 1065, 1080, 1095, 1110
Multiples of 24:
24, 48, 72, 96, 120, 144, 168, 192, 216, 240, 264, 288, 312, 336, 360, 384, 408, 432, 456, 480, 504, 528, 552, 576, 600, 624, 648, 672, 696, 720, 744, 768, 792, 816, 840, 864, 888, 912, 936, 960, 984, 1008, 1032, 1056, 1080, 1104, 1128
Multiples of 27:
27, 54, 81, 108, 135, 162, 189, 216, 243, 270, 297, 324, 351, 378, 405, 432, 459, 486, 513, 540, 567, 594, 621, 648, 675, 702, 729, 756, 783, 810, 837, 864, 891, 918, 945, 972, 999, 1026, 1053, 1080, 1107, 1134
Therefore,
LCM(15, 24, 27) = 1080
hope it helps :)
