Answer:
metal seat belt and door handle
Explanation:
bc its all medal it _____ heat (forgot the word mybad)
A 7.5 Kg cannon ball leaves a canon with a speed of 185 meters per second. Find the average net force applied to the ball is the canon muzzle is 3.6 meters long
Answer:
F = 35651 [N]
Explanation:
To solve this problem we must use the following equation of kinematics
[tex]v_{f} ^{2} =v_{o} ^{2} +2*a*x[/tex]
where:
Vf = final velocity = 185 [m/s]
Vo = initial velocity = 0 (starts from the rest)
a = acceleration [m/s²]
x = distance = 3.6 [m]
Now we can find the acceleration.
185² = 0 + 2*a*3.6
34225 = 7.2*a
a = 4753.47 [m/s²]
Now we must use Newton's second law which tells us that the total force on a body is equal to the product of mass by acceleration.
F = m*a
where:
m = mass = 7.5 [kg]
F = force [N] (units of Newtons)
F = 7.5*4753.47
F = 35651 [N]
Sara goes to her apartment on the fifth floor by elevator from
the ground floor. The whole journey is 18.0 meters. If Sara hasmass 60 kg, what is the gravitational potential energy gained
by her? Estimate gas 9.81m/s2.
Answer: 10595 J
Explanation: cK-12 Potential Energy
The gravitational potential energy gained by Sara if she has a mass of 60 kg and the distance of the journey is 18 meters is 10584 Joules.
What is gravitational potential energy?The potential energy that a huge item has in relation to another massive object due to gravity is known as gravitational energy or gravitational potential energy. When two objects descend toward one another, the potential energy associated with the gravitational field is released (transformed into kinetic energy). Bringing two things farther apart increases the gravitational potential energy.
Given:
The distance of the journey, d = 18 meters,
The mass of Sara, m = 60 kg,
Calculate the potential energy by the following formula,
PE = m × g × d
Here, PE is the potential energy and g is gravitational acceleration,
Substitute the values,
PE = 60 × 18 × 9.8
PE = 10584 Joules
Therefore, the gravitational potential energy gained by Sara if she has a mass of 60 kg and the distance of the journey is 18 meters is 10584 joules.
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Can someone help quickly please and thank you
Answer:
I think D??
Explanation:
1. Find the magnitude of the gravitational force (in N) between a planet with mass 8.00 ✕ 1024 kg and its moon, with mass 2.75 ✕ 1022 kg, if the average distance between their centers is 2.40 ✕ 108 m.2. What is the moon's acceleration (in m/s2) toward the planet? 3. What is the planet's acceleration (in m/s2) toward the moon?
Answer:
1.358 10e8 have good day please mark brainliest
A ball is attached to one end of a string such that the ball travels in a vertical circular path near Earth's surface. The force diagram
of the ball at its lowest point in the circular path is shown above. What is the net centripetal force exerted on the ball?
A) 10N
B) 15 N
C
25 N
D
35 N
Complete Question
The complete question is shown on the first uploaded image
Answer:
The value is [tex]F_{centripetal} = 15 \ N[/tex]
Explanation:
From the diagram we see that
The tension force on the ball is [tex]F_{Tension} = 25 \ N[/tex]
The gravitational force on the ball is [tex]F_{Gravity } = 10 \ N[/tex]
Generally the net centripetal force exerted on the ball is mathematically represented as
[tex]F_{centripetal} = F_{Tension} - F_{Gravity}[/tex]
=> [tex]F_{centripetal} = 25 - 10[/tex]
=> [tex]F_{centripetal} = 15 \ N[/tex]
The net centripetal force exerted on the ball is 15 Newton.
Hence, Option B) 15N is the correct answer.
Given the data in the question;
Tension force on the ball; [tex]F_{Tension} = 25N[/tex]Gravitational force on the ball; [tex]F_{Gravity} = 10N[/tex]Net centripetal force exerted on the ball; [tex]F_{centripetal} = \ ?[/tex]
From the diagram below, net force acting on the ball gives rise to centripetal force. Hence
[tex]F{net} = F_1 + f_2 = F_{centripetal}[/tex]
Now, from the diagram, force acting towards the center of the circular track is is positive while force directly pointing away from center is negative.
Hence
[tex]F{net} = F_1 + f_2 = F_{centripetal} = F_{Tension} - F_{Gravity}[/tex]
We substitute in our given values
[tex]F_{centripetal} = 25N - 10N\\\\ F_{centripetal} = 15N[/tex]
The net centripetal force exerted on the ball is 15 Newton.
Hence, Option B) 15N is the correct answer.
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Water flows with constant speed through a garden hose that goes up to 27.5 cm high. if the water pressure is 132kpa at the bottom of the step, what is its pressure at the top of the step?
Answer:
The pressure at the top of the step is 129.303 kilopascals.
Explanation:
From Hydrostatics we find that the pressure difference between extremes of the water column is defined by the following formula, which is a particular case of the Bernoulli's Principle ([tex]v_{bottom}\approx v_{top}[/tex]):
[tex]p_{bottom}-p_{top} = \rho\cdot g\cdot \Delta h[/tex] (1)
[tex]p_{bottom}[/tex], [tex]p_{top}[/tex] - Total pressures at the bottom and at the top, measured in pascals.
[tex]\rho[/tex] - Density of the water, measured in kilograms per cubic meter.
[tex]\Delta h[/tex] - Height difference of the step, measured in meters.
If we know that [tex]p_{bottom} = 132000\,Pa[/tex], [tex]\rho = 1000\,\frac{kg}{m^{3}}[/tex], [tex]g = 9.807\,\frac{m}{s^{2}}[/tex] and [tex]\Delta h = 0.275\,m[/tex], then the pressure at the top of the step is:
[tex]p_{top} = p_{bottom}-\rho\cdot g\cdot \Delta h[/tex]
[tex]p_{top} = 132000\,Pa-\left(1000\,\frac{kg}{m^{3}} \right)\cdot \left(9.807\,\frac{m}{s^{2}} \right)\cdot (0.275\,m)[/tex]
[tex]p_{top} = 129303.075\,Pa[/tex]
[tex]p_{top} = 129.303\,kPa[/tex]
The pressure at the top of the step is 129.303 kilopascals.
The pressure of the water at the top of the step is 1.293 x 10⁵ Pa.
The given parameters:
Height of the hose, h = 27.5 cm = 0.275 mPressure of the water at bottom, Pb = 132 kPaThe pressure of the water at the top of the step is calculated as follows;
[tex]P_b - P_t = \rho gh\\\\P_t = P_b - \rho gh[/tex]
where;
[tex]\rho[/tex] is the density of the water
[tex]P_t = (132,000 \ Pa) \ - \ (1000 \times 9.8 \times 0.275)\\\\P_t = 1.293 \times 10^5 \ Pa[/tex]
Thus, the pressure of the water at the top of the step is 1.293 x 10⁵ Pa.
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A marble is dropped from rest and falls for 2.3 seconds. Find its final velocity.
Answer:
23 m/s downward
__________________________________________________________
Taking the downward direction as positive
We are given:
Initial velocity of the marble (u) = 0 m/s
Time interval (t) = 2.3 seconds
Final velocity (v) = x m/s
Solving for the Final velocity:
Acceleration of the Marble:
We know that gravity will make the marble accelerate at a constant acceleration of 10 m/s
Final velocity:
v = u + at [First equation of motion]
x = 0 + (10)(2.3) [replacing the given values]
x = 23 m/s
Hence, after 2.3 seconds, the marble will move at a velocity of 23 m/s in the downward direction
A merry-go-round rotates from rest with an angular acceleration of 1.45 rad/s2. How long does it take to rotate through (a) the first 3.70 rev and (b) the next 3.70 rev?
Answer:
(a) t = 5.66 s
(b) t = 8 s
Explanation:
(a)
Here we will use 2nd equation of motion for angular motion:
θ = ωi t + (1/2)∝t²
where,
θ = Angular Displacement = (3.7 rev)(2π rad/1 rev) = 23.25 rad
ωi = initial angular speed = 0 rad/s
t = time = ?
∝ = angular acceleration = 1.45 rad/s²
Therefore,
23.25 rad = (0 rad/s)(t) + (1/2)(1.45 rad/s²)t²
t² = (23.25 rad)(2)/(1.45 rad/s²)
t = √(32.06 s²)
t = 5.66 s
(b)For next 3.7 rev
θ = ωi t + (1/2)∝t²
where,
θ = Angular Displacement = (3.7 rev + 3.7 rev)(2π rad/1 rev) = 46.5 rad
ωi = initial angular speed = 0 rad/s
t = time = ?
∝ = angular acceleration = 1.45 rad/s²
Therefore,
46.5 rad = (0 rad/s)(t) + (1/2)(1.45 rad/s²)t²
t² = (46.5 rad)(2)/(1.45 rad/s²)
t = √(64.13 s²)
t = 8 s
The time taken in each case is 2.55 s
Let us recall that the equations of circular motion are almost like those of linear motion;
α = ω2 - ω1/t
α = angular acceleration
ω2 = final angular velocity
ω1 = initial angular velocity
t = time taken
a) 1.45 rad/s2 =3.70 rev/s - 0 rev/s/t
t = 3.70 rev/s/1.45 rad/s2
t = 2.55 s
b) For, ) the next 3.70 rev:
1.45 rad/s2 =3.70 rev/s - 0 rev/s/t
t = 3.70 rev/s/1.45 rad/s2
t = 2.55 s
Learn more about angular velocity; https://brainly.com/question/1301963
Which statement describes how a machine can help make work easier? It can put out more force than the input force by decreasing the distance over which force is applied. It can increase the amount of work performed if the output force is in the same direction as the input force. It can apply a greater output force over a greater distance compared to the input force and distance. It can increase the distance over which output force acts by applying less output force than input force.
Answer:
It can apply a greater output force over a greater distance compared to the input force and distance.
Explanation:
A machine helps to multiply force input and makes it easier to do work. Simple and complex machines are need to make work easier.
Most machines are designed to increase the input force by a system of mechanics. Machines allow force to be applied over great distances and this allows for the input work done to be duly compensated for.Answer:
C. It can apply a greater output force over a greater distance compared to the input force and distance.
Explanation:
A small object with momentum 7.0 kg∙m/s approaches head-on a large object at rest. The small object bounces straight back with a momentum of magnitude 4.0 kg∙ m/s. What is the magnitude of the large object's momentum change?
Answer:
The magnitude of the large object's momentum change is 3 kilogram-meters per second.
Explanation:
Under the assumption that no external forces are exerted on both the small object and the big object, whose situation is described by the Principle of Momentum Conservation:
[tex]p_{S,1}+p_{B,1} = p_{S,2}+p_{B,2}[/tex] (1)
Where:
[tex]p_{S,1}[/tex], [tex]p_{S,2}[/tex] - Initial and final momemtums of the small object, measured in kilogram-meters per second.
[tex]p_{B,1}[/tex], [tex]p_{B,2}[/tex] - Initial and final momentums of the big object, measured in kilogram-meters per second.
If we know that [tex]p_{S,1} = 7\,\frac{kg\cdot m}{s}[/tex], [tex]p_{B,1} = 0\,\frac{kg\cdot m}{s}[/tex] and [tex]p_{S, 2} = 4\,\frac{kg\cdot m}{s}[/tex], then the final momentum of the big object is:
[tex]7\,\frac{kg\cdot m}{s} + 0\,\frac{kg\cdot m}{s} = 4\,\frac{kg\cdot m}{s}+p_{B,2}[/tex]
[tex]p_{B,2} = 3\,\frac{kg\cdot m}{s}[/tex]
The magnitude of the large object's momentum change is:
[tex]p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}-0\,\frac{kg\cdot m}{s}[/tex]
[tex]p_{B,2}-p_{B,1} = 3\,\frac{kg\cdot m}{s}[/tex]
The magnitude of the large object's momentum change is 3 kilogram-meters per second.
If the population of penguins increased, then this would have a direct effect on the populations of?
Answer:
Globel warming
Explanation:
hope this helpex
If a 6 volt battery is connected in series to resistances of 2 ohms, 8 ohms, and 14 ohms, what is the amount of the current that is flowing?
Answer:
I = 0.25 [amp]
Explanation:
To solve this problem we must use ohm's law which tells us that the voltage is equal to the product of the current by the resistance.
V = I*R
where:
V = voltage [Volt]
I = amperage or current [amp]
R = resistance [ohm]
Since all resistors are connected in series, the total resistance will be equal to the arithmetic sum of all resistors.
Rt = 2 + 8 + 14
Rt = 24 [ohm]
Now clearing I for amperage
I = V/Rt
I = 6/24
I = 0.25 [amp]
Answer: 0.25
Explanation:
3). If you record a light wave at 400 nm long, what is its frequency?
Pleassee helppp!!
Answer:
Violet light has a wavelength of ~400 nm, and a frequency of ~7.5*1014 Hz.
Explanation:
According to the scientific theory of atoms, which of the following statements best describes the location of electrons ?
Answer:
According to the scientific theory of atoms, which of the following statements best describes the location of electrons? answer choices. in the nucleus of the atom.
Explanation:
Answer: D
Explanation: trust me
Can someone let me know if I got these questions right please
If a feather and an iron bar were fired at the same height in a room without any air resistance, which would fall first and why?
MY weenie hurts ;( pls help am so sad ;(((((((((
Answer:
What??? maybe not keep doing what you are doing.
Explanation:
I don't know
What statement best describes how wind weathered this rock
The rock slowly moved over time due to the force of the wind.
The shape of the rock changed when the pressure of wind increased.
The rock broke down when the wind blew particles of sand against it.
The rock broke down when the temperature in the air decreased.
Answer:
the rock breaks down when the wind blows particles of sand against it.
Explanation:
because the sand can easily be decomposed and temperature easily accessible to it cause line of weaknesses of the rock to break down
A freely falling object near the Earth's surface has a constant?
acceleration of 1.0 m/s
acceleration of 9.8 m/s
velocity of 1.0 m/s
velocity of 9.8 m/s
Answer:
answer is B (CROWN ME)
Explanation:
One should revise his/ her research questions very well in the week before the exam. They should contribute at least 15-20 hours for going through these questions in that particular week. They must put some extra efforts on weekends.
A freely falling object near the Earth's surface has a constant: B. acceleration of 9.8 [tex]m/s^2[/tex].
Gravity can be defined as a force that controls the movement of the planets such as Earth around the Sun, hold stars grouped in galaxies together, and galaxies grouped in clusters. This ultimately implies that, gravity is a universal force of attraction that acts between all objects that are having both mass and energy, and can occupy space.
Furthermore, the gravity near the Earth's surface makes it possible for all physical objects to possess weight and experience a free fall.
Generally, the acceleration due to gravity for an object experiencing a free fall near the Earth's surface is 9.8 [tex]m/s^2[/tex].
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A spring-loaded gun has a spring for which
k =180N /m
and is initially compressed by
14cm
. It fires
a
0.024kg
projectile vertically. Find the maximum height above the initial position?
Answer:
7.5 m
Explanation:
k = Spring constant = 180 N/m
x = Displacement of spring = 14 cm
m = Mass of projectile = 0.024 kg
a = g = Acceleration due to gravity = [tex]9.81\ \text{m/s}^2[/tex]
s = Displacement of projectile
v = Final velocity = 0
u = Initial velocity
The potential energy of the spring will be equal to the kinetic energy of the object
[tex]\dfrac{1}{2}kx^2=\dfrac{1}{2}mu^2\\\Rightarrow u=\sqrt{\dfrac{kx^2}{m}}\\\Rightarrow u=\sqrt{\dfrac{180\times 0.14^2}{0.024}}\\\Rightarrow u=12.12\ \text{m/s}[/tex]
[tex]v^2-u^2=2as\\\Rightarrow s=\dfrac{v^2-u^2}{2a}\\\Rightarrow s=\dfrac{0-12.12^2}{2\times -9.81}\\\Rightarrow s=7.5\ \text{m}[/tex]
The maximum height reached above the initial position is 7.5 m
5) True or False: Inertia is the ability for an object to keep its motion
O True
O False
Answer:
true
Explanation:
In central Texas there is a large domed hill of pink granite surronund by low hills of more common bedrock of Texas, limestone. Develop and explain your hypothesis for how this mineral dome was formed.
Answer:
It was probably formed by when the particles were pressed together.
Explanation:
Answer:
Formed by particles pressed against each other
Explanation:
Which object would be the best insulator of electricity?
a nail
a coin
a can
a rubber band
Answer:
a rubber band
Explanation:
hope this helps!
Answer:
a rubber band
Explanation:
thank you
a car accelerates from rest to a speed of 36 km/hour in 10 seconds. find
the acceleration
the distance travelled
the speed at the end of the 5th second
Answer: ok, so there should be no speed at the 5th second but there was somehow it was the car fault
∞ω∞
Which statement best explains why running on a track with constant speed at 3m/s is not work but climbing a mountain at 1m/s is work?
1. At constant speed, change in the kinetic energy is zero but climbing a mountain produces change in the potential energy
2. At constant speed, change in the potential energy is zero, but climbing a mountain produces change in the kinetic energy.
3. At constant speed, change in the kinetic energy is finite, but climbing a mountain produces no change in the potential energy.
4. At constant speed, change in the potential energy is finite, but climbing a mountain produces no change in the kinetic energy.
Answer:
1. At constant speed, change in the kinetic energy is zero but climbing a mountain produces change in the potential energy
Explanation:
According to work-energy theorem, work done in moving an object from one point to another is equal to change in mechanical energy ( kinetic energy or potential energy ) of the object.
Kinetic energy is given by;
K.E = ¹/₂m(Δv)²
where;
Δv is change in speed
at constant speed, Δv = 0
Potential energy is given by;
P.E = mgΔh
where;
Δh is change in height,
there is change in height in climbing a mountain
Therefore, the best explanation in the given options is "1".
"At constant speed, change in the kinetic energy is zero but climbing a mountain produces change in the potential energy"
What is the area around an object that can attract or repel other objects in that area?
A - field
B - force
C - fission
D - friction
Answer:
A
Explanation:
I got it right with that :>
Determine the density of a sphere with a diameter of 4.50 cm and m = 250 g. Express the most realistic result possible, with 2 decimal numbers next to the unit of measurement
What is the purpose of using an ammeter to demonstrate that a moving
magnet causes an electric current to flow in a wire coil?
A. It detects any current in the wire.
B. It protects the investigators from receiving an electric shock.
C. It increases the strength of the permanent magnet.
D. It takes the place of the battery needed for an electromagnet.
Answer: A
Explanation:
Answer:
The answer is A. It detects any current in the wire.
Explanation:
I took the quiz.
A cart is pulled by a force of 250 N at an angle of 35° above the horizontal. The cart accelerates at 1.4 m/s2. The free-body diagram shows the forces acting on the cart.
A free body diagram with 3 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline. The second vector is pointing up, labeled F Subscript N Baseline. The third vector is pointing up to the right at an angle of 35 degrees, labeled F Subscript p Baseline = 250 N. The up and down vectors are the same length.
The mass of the cart, to the nearest whole number, is
Answer:
m=146.277kg which is rounded to 146kg
Explanation:
Remember that F=ma
But F represents not 250N, but 250cos(35)N since the force is being pulled above the horizontal.
So 250cos(35)=204.7880111 approximately, and since a=1.4m/s^2, we have 204.7880111=m(1.4m/s^2). Then we divide both sides by the acceleration to get the mass. So m=146.2771508kg which the nearest number is 146kg
Mass is always in kg, unless stated otherwise.
Answer:
146kg
Explanation:
right on edge
The solid shaft with a 20 mm radius is used to transmit the torques applied to the gears. Determine the maximum torsional shear stress developed in in the shaft.
Answer:
τ = (7.96 x 10⁴ m⁻³)T
This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.
Explanation:
The maximum allowable shear stress on the solid shaft can be given by the torsional formula as follows:
τ = Tc/J
where,
τ = Maximum Allowable Shear Stress = ?
T = Maximum Torque Applied to the Shaft
c = maximum distance from center to edge = radius in this case = 20 mm = 0.02 m
J = Polar Moment of inertia = πr⁴/2 = π(0.02 m)⁴/2 = 2.51 x 10⁻⁷ m⁴
Therefore,
τ = T(0.02 m)/(2.51 x 10⁻⁷ m⁴)
τ = (7.96 x 10⁴ m⁻³)T
This is the expression for maximum allowable shear stress in terms of the maximum torque applied in Nm.