Given that x : 3 : 9/2 = 15/4 : 4 1/2 : y, find the value of x and y.

Answer:

A = 21

Step-by-step explanation:

Complementary angles add to 90

x-21 + 2x-15 = 90

Combine like terms

3x -36 = 90

3x-36+36 = 90+36

3x = 126

Divide by 3

3x/3 =126/3

x = 42

We want to find ZA = x-21

A = 42-21

A = 21

If the sum of the measures of two angles is 90° they are known as complementary angles.

[tex] \bf \large \longrightarrow \: \:( x \: - \: 21) \: + \: (2x \: - \: 15) \: = \: 90 \degree[/tex]

Now , Opening brackets and simplifying

[tex] \bf \large \longrightarrow \: \: x \: - \: 21 \: + \: 2x \: - \: 15\: = \: 90 \degree[/tex]

[tex]\bf \large \longrightarrow \: \:3x \: - \: 36 \: = \: 90 \degree[/tex]

[tex]\bf \large \longrightarrow \: \:3x \: = \: 90 \: + \: 36[/tex]

[tex]\bf \large \longrightarrow \: \:3x \: = \: 126[/tex]

[tex]\bf \large \longrightarrow \: \:x \: = \: \frac{126}{3} \\ [/tex]

[tex]\bf \large \longrightarrow \: \:x \: = \: \cancel\frac{126}{3} \: \: \large \: ^{42} \\ [/tex]

[tex]\bf \large \longrightarrow \: \: x \: = \: 42[/tex]

Now , we have to find ZA .

[tex]\bf \large \implies \: \:A \: = \: 42 \: - \: 21[/tex]

[tex]\bf \large \implies \: \:A \: = \: 21[/tex]

The measure of angle ZA is 21°

Answer:

Step-by-step explanation:

The zeros are located at x = 1 and x = 9. If x = 1 is a solution, then the factor is (x - 1); if x = 9 is a solution, then the factor is (x - 9). Choice A is the one you want. FOIL these out and you will get the equation for the quadratic.

Answer:

the answer is the number 6

To find the time in which all the bells ring together, we need to find the LCM of 36,40,48.

Prime factorization of 36=2×2×3×3

Prime factorization of 40=2×2×2×5

Prime factorization of 48=2×2×2×2×3

Hence, LCM of 36,40,48=2×2×2×2×3×3×5=720 seconds.

720seconds=  

60

720

​

minutes=12minutes

Hence, all the bells will ring together after 12 mi

Answer:

9pm or 12 hours from 9am.

Answer:

28.9°

Step-by-step explanation:

The golfer, hole and spectator form a triangle. Let ABC be the triangle and let the angle the spectator has between the golfer and the hole be A = 110°, the angle the golfer has between the spectator and the hole be B and the angle the hole has between the golfer and the spectator be C. Let the angle between the golfer and the hole be a = 200 yards, the distance between the spectator and the hole be b and the distance between the golfer and the spectator be c = 140 yards,

Using the sine rule for the triangle, we find angle C.

So, a/sinA = b/SinB = c/SinC

So, a/sinA = c/sinC

sinC = csinA/a

C = sin⁻¹(csinA/a)

Substituting the values of the variables into the equation, we have

C = sin⁻¹(csinA/a)

C = sin⁻¹( 140sin110°/200)

C = sin⁻¹( 7 × 0.9397/10)

C = sin⁻¹(6.5778/10)

C = sin⁻¹(0.65778)

C = 41.13°

We know that A + B + C = 180°  (sum of angles in a triangle)

And since the angle the golfer has between the spectator and the hole be B

So, B = 180° - (A + C)

B = 180° - (110° + 41.13°)

B = 180° - 151.13°

B = 28.87°

B ≅ 28.9°

The angle that the golfer has between the spectator and the hole is 28.9°.

Using the law of sines:

BC/SinΔBAC=AB/SinΔACB

Hence,

200/Sin110°=140/SinΔACB

ΔACB=41.1°

Thus,

ΔABC=180°-ΔBAC-ΔACB

ΔABC= 180° - (110° + 41.1°)

ΔABC= 180° - 151.1°

ΔABC= 28.9°

Inconclusion the angle that the golfer has between the spectator and the hole is 28.9°.

Learn more angle here:https://brainly.com/question/25770607

Answer:

for the second one,

f(4)= 2⁴-7= 9

g(4)= 1.5x4-3= 3

therefore 9>3

f(4)>g(4)

Answer:

[tex]h = \frac{2A}{b + c}[/tex]

Step-by-step explanation:

Given

[tex]A = \frac{1}{2}(b + c)h[/tex]

Required

Solve for h

We have:

[tex]A = \frac{1}{2}(b + c)h[/tex]

Multiply sides by 2

[tex]2A = (b + c)h[/tex]

Make h the subject

[tex]h = \frac{2A}{b + c}[/tex]

Answer:

Step-by-step explanation:

Let d and r be the diameter and radius, respectively.

d² + 12² = 15²

d² = 15² - 12² = 81

d = √81 = 9

r = d÷2 = 4.5 mm

Answer:

3?

Step-by-step explanation:

A little confused by the question but is it just

1/5 2/5 3/5 4/5

1     2     3     4

so theres 3 in between

Answer:

phthagoras

Step-by-step explanation:

Hi there!

[tex]\large\boxed{log_b3b = 1.8397}[/tex]

Keep in mind the following log property:

logₓab = logₓa + logₓb

Thus:

[tex]log_{b}3b = log_{b}3 + log_{b}b\\\\[/tex]

We know the value of log_b3, and a log with the same values for the base equals 1. Thus:

[tex]log_b3b = 0.8397 + 1 = 1.8397[/tex]

Answer:

22 m/s

Step-by-step explanation:

Take the distance and divide by the time

1210 m/55s

22 m/s

Answer:

Step-by-step explanation:

[tex]speed = \frac{distantce}{time} \\ = \frac{1210m}{55s} \\ = 22m {s}^{ - 1} [/tex]

Answer:

X = 32, y = 16

Step-by-step explanation:

Cos 30 = (16√3) ÷ x

x = (16√3) ÷ cos 30

x = 32

Sin 30 = y ÷ 32

y = 32 sin 30

y = 16

Step-by-step explanation:

5.

[tex]3\cdot 10^{8} : 1000 = 3\cdot 10^{8} : 10^{3} =3 \cdot 10^{8-3} =3 \cdot 10^{5}[/tex]

Answer:   [tex]3 \cdot 10^{5}[/tex]

6.

[tex]\dfrac{0.0046}{0.000000000513} =\dfrac{46 \cdot 10^{-4} }{5.13 \cdot 10^{-10} } =\dfrac{46 \cdot 10^{-4-(-10)}}{5.13} =\dfrac{46 \cdot 10^{6}}{5.13} \approx 9 \cdot 10^{6}[/tex]

Answer:   [tex]9 \cdot 10^{6}[/tex]

value of x should be 3.2 units

Answered by Gauthmath must click thanks and mark brainliest

Start with the answer format we want, and work your way toward forming a single fraction like so

[tex]a + \frac{b}{x+2}\\\\a*1+\frac{b}{x+2}\\\\a*\frac{x+2}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)}{x+2}+\frac{b}{x+2}\\\\\frac{a(x+2)+b}{x+2}\\\\\frac{ax+2a+b}{x+2}\\\\\frac{ax+(2a+b)}{x+2}\\\\[/tex]

Compare that last expression to (2x+1)/(x+2). Notice how the ax and 2x match up, so a = 2 must be the case.

Then we have 2a+b as the remaining portion in the numerator. Plugging in a = 2 leads to 2a+b = 2*2+b = 4+b. Set this equal to the +1 found in (2x+1)/(x+2) to have the terms match.

So, 4+b = 1 leads to b = -3

Therefore, a = 2 and b = -3

------------------------------------------------

An alternative route:

[tex]\frac{2x+1}{x+2}\\\\\frac{2x+1+0}{x+2}\\\\\frac{2x+1+4-4}{x+2}\\\\\frac{(2x+4)+1-4}{x+2}\\\\\frac{2(x+2)-3}{x+2}\\\\\frac{2(x+2)}{x+2}+\frac{-3}{x+2}\\\\2-\frac{3}{x+2}\\\\[/tex]

I added and subtracted 4 in the third step so that I could form 2x+4, which then factors to 2(x+2). That way I could cancel out a pair of (x+2) terms toward the very end.

------------------------------------------------

Other alternative methods involve synthetic division or polynomial long division. They are slightly separate but related concepts.

Answer:

a = 2

b = -3

Step-by-step explanation:

the secret is seeing that the numerator (top part of the division) contains 2x. that means 2 times the factor of x in the denominator (bottom part of the division).

so, we want to change the numerator that we can simply say the result is 2 and some rest (remainder).

2×(x+2) would be 2x + 4

aha !

and we have 2x+1 up there. so, what had to happen to get from 2x+4 to 2x+1 ? we had to subtract 3. it to get to 2x+4 we have to add 3.

but if we add 3, we need also to subtract 3 to keep the value of the whole expression the same.

therefore we get

(2x+1)/(x+2) = (2x+4)/(x+2) - 3/(x+2) =

= 2×(x+2)/(x+2) - 3/(x+2) = 2 - 3/(x+2)

Answer:

2.02 m

or 2 m 2 cm

Step-by-step explanation:

Imagine a triangle containing the 40° angle and that this angle is at the left.  Then the height of the truck bed is 1.3 m and the "shortest possible length of the ramp" is the hypotenuse of this triangle.  We need to find the length of this ramp, that is, the length of the hypotenuse.  

The sine function relates this 40° angle and the 1.3 m height of the truck bed:

sin 40° = opp / hyp = 1.3 m / hyp

which can be solved for 'hyp' as follows:

              1.3 m

hyp = ----------------- = (1.3 m) / 0.6428)

             sin 40°

                                                                                  1.3 m

Thus, the length of the ramp must be less than -------------- or 2.02 m

                                                                                 0.6428

where this last result is to the nearest cm.

If the ramp is shorter the angle of the ramp will be smaller and the ramp angle considered safer.

Answer:

k = [tex]\frac{1}{3}[/tex]

Step-by-step explanation:

X| 1    2   5   10   30

Y| 3    6   15 30   90

Answer:

4.7

Step-by-step explanation:

The red I think is hinting to the x.

Answer:

217.5

Step-by-step explanation:

There are two ways to do this problem, first dividing to find the missing value. It will look like this:

217.5 ÷ 30 = 7.25

Or, using random numbers and multiplying it by 30, which is like this:

30 × 10 = 300

30 × 4 = 120

30 × 7 = 210

30 × 7.1 = 213

30 × 7.25 = 217.5

5x+4-2x là biểu thức đại số

Step-by-step explanation:

sL=6+W

A=27square

A=L×W

=(6+w) ×W

Answer:

C.

–5; –135; –10,935

Step-by-step explanation:

Answer:

C. -5; -135, -10,935

Step-by-step explanation:

...............................................................................................................................................

Answer: (0, 12)

Step-by-step explanation:

2x + 3y = 36

2(0) + 3y = 36

3y = 36

3/3 36\3

= 12

On edge

Answer:

a

Step-by-step explanation:

Answer:

dame like y muchísimas estrella

Answer:

308.2

Step-by-step explanation:

= 308.2

Answer:

El problema esta incompleto, pero es facil ver que se desea estudiar el enfriamiento de la olla.

Sabemos que la ecuación de enfriamiento de Newton es:

[tex]T (t) = T_s + (T_0 - T_s)*e^{-k*t}[/tex]

Donde t es el tiempo.

[tex]T_s[/tex] es la temperatura del ambiente, en este caso es 12°C

[tex]T_0[/tex] es la temperatura inicial del objeto, en este caso 175°C

k es una constante, que es lo que usualmente se pide obtener en este tipo de problemas.

Reemplazando esos valores en nuestra ecuación obtenemos:

[tex]T(t) = 12 + (175 - 12)*e^{-k*t}\\\\T(t) = 12 + (163)*e^{-k*t}[/tex]

Ahora se nos dice:

"Luego de 10 minutos, la temperatura de la olla será de 100°C"

(estos valores no son necesariamente los del problema, son unos valores genéricos para poder mostrar como se resuelve este tipo de ejercicio)

Entonces, T(10 min) = 100°C

Reemplazando eso en nuestra ecación, obtenemos:

[tex]T(10 min) = 100 = 12 + (163)*e^{-k*10min}[/tex]

Ahora podemos despejar el valor de k resolviendo la ecuación de arriba.

[tex]100 - 12 = (163)*e^{-k*10min}\\\\88 = (163)*e^{-k*10min}\\\\88/163 = e^{{-k*10min}[/tex]

Ahora podemos recordar que:

ln(e^x) = x

Entonces aplicando el logaritmo natural a ambos lados, obtenemos:

[tex]ln(88/163) = ln(e^{-k*10min}) = -k*10min\\\\ln(88/163)/(-10 min) = k = 0.062 min^{-1}[/tex]

Así hemos encontrado el valor de k, y con exactamente el mismo método podríamos encontrar k en cualquier situación de este tipo.

Answer:

y -1 = 3/ 2( x + 3)

Step-by-step explanation:

m = (2 +4)/( 2+2)

m = 3/2