Answer:
1.20 L = 1200 mL
Explanation:
P1V1/T1 = P2V2/T2
V2 = P1*V1*T2/(T1*P2)
V1 = 700ml =0.700 L
P1 = 106.6 kPa
T1 = 7+273.15 = 280.15 K
T2 = 27 + 273.15 = 300.15 K
P2 = 66.6 kPa
V2 = 106.6*0.700*300.15/(280.15*66.6)= 1.20 L=1200 mL
In this equation, what should be the coefficients of the reactants and products? I2 + O2 → I4O9
Answer:
4 i2 + 9 O2 --> 2 i4O9
Explanation:
Explain what is wrong with the following structure.
Answer:
H = 1+
O = 2-
O Has 8 protons weight 16g/mole
H has 1 proton weight 1g/mole
H - O - H
Oxygen is in group 6 which means it holds 6 valence electrons, leaving 2 for bonds.
A valence electron is an outer shell electron that can form a chemical bond if the outer shell is not closed.
Now when an atom bonds to another in a single bond, both atoms contribute one valence electron in order to form a shared pair.
In the picture O has 7 Valence electrons, so it would have a negative charge of 1.
The middle Hydrogen has 3 valence electrons which would make hydrogen have a charge of negative 1.
Should look like this
.. ..
H . .O. .H = H-O-H
.. ..
someone tell me how to balance the equation by hit and trial method...
Answer:
1. 3H2S + 2HNO3 -----> 2NO + 4H2O + 3S
Explanation:
H2S + HNO3 -----> NO + H2O + S
There are 3 O's on left and only 2 on right so put 2 before NO:
H2S + HNO3 ----> 2NO + H2O + S
Now we have 2 N's on left so put 2 before HNO3:
H2S + 2HNO3 -----> 2NO + H2O + S
4 H's on the left so
H2S + 2HNO3 -----> 2NO + 2H2O + S
That makes 6 O's on left so we write
H2S + 2HNO3 ----> 2NO + 4H2O + S
Now there 8 H's on the right but only 4 on the right so we adjust H2S and S:
3H2S + 2HNO3 -----> 2NO + 4H2O + 3S
Now it balances!
Basically you 'play around' with the quantities of each element in this way.
Homogeneous mixtures are:
a. Mixtures that have 1 phase or layers
b. Solutions that consists of only one type of atom
c. Two or more elements that have been chemically combined
d. Solutions that consists of two or more elements
35. The hydrocarbon formed during electrolysis of potassium maleate is
a)methane
b)ethane
c)ethene
d)ethyne
Answer:
methane
Explanation:
In the reaction AgNO3(aq) + NaCl(aq) –
NaNO3(aq) + AgCl(s), the reactants
(1) gain electrons only
(2) lose electrons only
(3) both gain and lose electrons
(4) neither gain nor lose electrons
You’re trying to remove dissolved iron from a solution. The theoretical yield for a reaction between sodium sulfide and iron(III) bromide is 0.721 kilogram of solid iron(II) sulfide. When you carried out the reaction, you got 530.0 grams. What is the percent yield?
FREEBE HAVENT SEEN THIS QUESTION YET
ANSWER!!!
The percent yield of the reaction is 73.5%
Answer:
73.5%
Explanation:
Step 1:
Data obtained from the question.
Theoretical yield = 0.721Kg
Actual yield = 530g
Percentage yield =..?
Step 2:
Conversion of 0.721Kg to grams. This is illustrated below:
1Kg = 1000g
Therefore, 0.721Kg = 0.721 x 1000 = 721g
Step 3:
Determination of the percentage yield.
The percentage yield can be obtained by using the following formula:
Percentage yield = Actual yield /Theoretical yield x 100
Percentage yield = 530/721 x 100
Percentage yield = 73.5%
Therefore, the percentage yield is 73.5%
Answer:
73.5%
Explanation:
plato
If anyone can answer all these questions you can get 35 points
Answer:
6) 225.8 g
7) 1.01 g
8) 21.624 g
Explanation:
6) Molar Mass of Lithium Bromine: 86.845
86.845 * 2.6 = 225.8 g
7) Molar Mass of Neon: 20.180
20.180 * 0.05 = 1.01 g
8) Molar Mass of Water Vapor: 18.02
18.02 * 1.2 = 21.624 g
what are the properties of sound waves
Answer:
The 5 properties are wavelength, amplitude, time-period, frequency and velocity/speed.
Explanation:
Answer:
the correct answer is sound wave can be described by five chacteristics:wavelength, amplitude,time-period, frequency and velocity or speed.
Explanation:
hope this helps !!!!
9. Determine the number of protons, neutrons, and electrons in one 'H' ion. Explain how you found your
answer.
Answer:
'H' ion has only one proton and do not have any electron and neutron.
Explanation:
Hydrogen atom has only one electron and one proton and when it loses that electron, hydrogen ion (H+) is formed which is positively charged (charge of +1) and referred as a proton.
So, hydrogen ion do not left with any electrons or have zero electrons.
Hydrogen (H) atom do not have any neutrons in its tiny nucleus, so hydrogen ion (H+) also do not have neutrons.
Hence, 'H' ion (H+) has only proton and zero electron and neutron.
10 grams of sodium hydroxide, NaOH, is dissolved in 0.25 liters of solution. Determine the molarity (M)
Answer:
1M
Explanation:
The molarity of a substance is defined as the number of moles of the substance divided by how many liters the solution is. NaOH has a molar mass of about 40 grams, meaning that 10 grams of it would be 0.25 moles. 0.25/0.25= a molarity of 1.
Hope this helps!
Four satellites are in orbit around the Earth. The heights of their four orbits
are identical. The masses of the four satellites are given in the table. For
which satellite is the gravitational pull of Earth the strongest?
Satellite
Mass (kg)
A
500
B
400
700
600
O A. Satellite A
O B. Satellite B
O C. Satellite
O D. Satellite D
Answer:
Option C. Satellite C.
Explanation:
The gravitational pull of the earth talls about the weight of an object.
To know which of them has the greatest gravitational pull, let us determine the weight of each satellite.
For satellite A:
Mass = 500Kg
Acceleration due to gravity (g) = 9.8m/s²
Weight (W) =.?
Weight (W) = mass (m) x Acceleration due to gravity (g)
W = m x g
W = 500 x 9.8
W = 4900N
For satellite B:
Mass = 400Kg
Acceleration due to gravity (g) = 9.8m/s²
Weight (W) =.?
W = m x g
W = 400 x 9.8
W = 3920N
For satellite C:
Mass = 700Kg
Acceleration due to gravity (g) = 9.8m/s²
Weight (W) =.?
W = m x g
W = 700 x 9.8
W = 6860N
For satellite D:
Mass = 600Kg
Acceleration due to gravity (g) = 9.8m/s²
Weight (W) =.?
W = m x g
W = 600 x 9.8
W = 5880N
Satellite >> Mass >>> Gravitational pull
A >>>>>>>> 500Kg >> 4900N
B >>>>>>>> 400Kg >> 3920N
C >>>>>>>> 700Kg >> 6860N
D >>>>>>>> 600Kg >> 5880N
From the above calculations we can see that satellite C has the greatest gravitational pull.
Solve for P2 when P1 = 2.0 atm V1 = 8.0 L and V2 = 32 L
This is a Boyle’s law has problem
name two gases which are supplied in compressed form in homes and hospitals
Explanation:
lpg and oxygen are two gases which are supplied in compressed form in homes and hospitals
Answer:
lpg and oxygen
they are the two gases which are supplied in either a gas form or any other medical forms in homes and hospitals to look after the ill patients or family members
Carbon monoxide reacts with oxygen to produce carbon
dioxide. The given reaction is an example of
Estimate the freezing point depression of 0.19
m C12H22O11(aq). The freezing point constant of water is 1.86 K · kg/mol.
Answer in units of ◦C.
Answer:
0.3634 °C
Explanation:
In this question, we are tasked with calculating the freezing point depression of 0.19 M C12H12O11( sucrose)
Mathematically this can be calculated using the formula;
ΔTf = i * kf * m
where ΔTf is the freezing point depression
i is Van’t Hoff factor
kf is the molal freezing point depression for the solvent
m is the molality of the solution
From the question we identify the following;
Since sucrose is a non-electrolyte, i = 1 ( i refers to the number of moles of particles obtained when 1 mol of solute dissolves)
m is 0.19
kf = 1.86
substituting these values into the equation, we have
ΔTf = 1 * 1.86 * 0.19 = 0.3534 °C
state true or false soil contains only in organic materials
Answer:
false
Explanation:
the soil contain: organic materials, and inorganic materials
Which instrument would be used to measure
the mass of a small stone?
I
1. graduated cylinder
2. Celsius thermometer
3. triple-beam balance
4. metric ruler
Answer:
3. Triple Beam Balance
Explanation:
A triple beam will be most suitable for measuring the mass of a small stone because it is very accurate, and has a reading error of +/- 0.05 gram.
Need help please help
Explanation:
a)phenotype= 100% big
b) genotype=1:2:1 (FF-25%, Ff-50%, ff-25%)
phenotype=3:1 (big=75%, small= 25%)
What is the number of moles of KF in a 29-gram sample of the compound?
A) 1.0 mol
B) 2.0 mol
C) 0.50 mol
D) 5.0 mol
Answer:
C. 0.50 mol
Explanation:
Number of mole= mass /molar mass
Mass of KF is given as 29g
The molar mass of KF= 39+19= 58g/mol
No of mole= mass/ molar mass
= 29g/58g/mol
1/2 mol= 0.5 mol
Answer:
C) 0.50 mol
Explanation:
Hello,
In this case, we study this mole-mass relationship by using the molar mass of potassium fluoride (KF) which is 58.1 g/mol to compute the required number of moles in the 29-g sample as shown below:
[tex]n_{KF}=29gKF*\frac{1molKF}{58.1gKF} \\\\n_{KF}=0.50molKF[/tex]
Therefore answer is C) 0.50 mol.
Best regards.
Explain how the molecular structure of soap allows it to clean many types of stains. What is a micelle? What is emulsification? How does soap work? Your answer should include a diagram of a micelle, and a discussion of polarity and intermolecular attractions. please write everything asked to be included in the response!! i am giving many points for this so please answer everything.
Answer:
1. The soap molecule is made up of two different ends that include polar head which is hydrophilic carrying carboxylate group (-CO2) (binds with water) and the other is non-polar hydrocarbon tail that is hydrophobic carrying hydrocarbon chain (binds with stain) .
When soap water is added with stain or oil, soap molecules form micelles which are the tiny clusters of soap molecules representing hydrophilic head (water-loving) points outwards that sticks to the water and hydrophobic tail (oil-loving) points inwards that stick to the oil and trap oil in the center.
As micelle is soluble in water, the trapped oil or stain is rinsed away along with soapy water.
2. A micelle is defined as a cluster of surfactant molecules that are dispersed water and form a colloidal solution.
3. Emulsification is the process in which soap act as an emulsifier that allows dispersion of immiscible liquid. It means soap will disperse stain or dirt in such a way that it can be removed.
4. As we discussed earlier, Soap has hydrophilic (water-loving) carboxylate group (-CO2) that form hydrogen bonds and ion-dipole interactions with water and the hydrophobic (water-fearing) tail carry nonpolar hydrocarbon chain that interacts with a stain by forming micelles through dispersion force.
The negatively charged carboxylate group (hydrophilic) repels each other and hydrocarbon chain (hydrophobic) trap stain inside and remove the dirt along with water.
What is the concentration of a solution with a volume of 660L that contains 33.4g of AlCO3?
Answer:
The concentration of the solution is 5.8168 × [tex]10^{-4}[/tex] mol.[tex]dm^{-3}[/tex]
Explanation:
Here, we want to calculate the concentration of the solution.
The unit of this is mol/dm^3
So the first thing to do here is to calculate the number of moles of the solute present, which is the number of moles of AlCO3
The number of moles = mass/molar mass
molar mass of AlCO3 = 27 + 12 + 3(16) = 27 + 12 + 48 = 87g/mol
Number of moles = 33.4/87 = 0.384 moles
This 0.384 moles is present in 660 L
x moles will be present in 1 dm^3
Recall 1 dm^3 = 1L
x * 660 = 0.384 * 1
x = 0.384/660 = 0.00058168 = 5.8168 * 10^-4 mol/dm^3
Determine the relative formula mass of hexasodium difluoride using the periodic table below. A. 138 g/mol B. 176 g/mol C. 20 g/mol D. 42 g/mol
Answer:
Option B. 176g/mol
Explanation:
We'll begin by writing the chemical formula for hexasodium difluoride. This is given below:
Hexasodium means 6 sodium atom
Difluoride means 2 fluorine atom.
Therefore, the formula for hexasodium difluoride is Na6F2.
The relative formula mass of a compound is obtained by simply adding the atomic masses of the elements present in the compound.
Thus, the relative formula mass of hexasodium difluoride, Na6F2 can be obtained as follow:
Molar mass of Na = 23g/mol
Molar mass of F = 19g/mol
Relative formula mass Na6F2 = (23x6) + (19x2)
= 138 + 38
= 176g/mol
Therefore, the relative formula mass of hexasodium difluoride, Na6F2 is 176g/mol
Answer:
B. 176 g/mol
Explanation:
chemistry ed tell
Can someone help me for one of these questions it would mean a lot pls
Answer:
Hope this helps you
Which compound is a saturated hydrocarbon?
A) 2-pentanone B) 2-pentene C) pentane D) pentanal
Which compound is an isomer of propanoic acid (CH3CH2COOH)?
A) CH2CHCOOH
B) CH3CH2CH2COOH
C) CH3CH(OH)CH2OH
D) HCOOCH2CH3
Answer:
D) HCOOCH2CH3
Explanation:
An isomer of a compound is defined as a chemical substances with the same formula (That is, same atoms) but in different structures.
For propanoic acid, there are 3 atoms of C, 6 atoms of H and 2 atoms of oxygen.
A) CH2CHCOOH . Here you have 3 atoms of C but 4 atoms of H. That means this compound is not an isomer.
B) CH3CH2CH2COOH . Here, there are 4 atoms of C. Thus, is not an isomer.
C) CH3CH(OH)CH2OH. This structure has 3 atoms of C, but 8 atoms of H. Thus, is not an isomer.
D) HCOOCH2CH3. Here, there are 3 atoms of C, 6 atoms of H and 2 atoms of O. Thus, this structure is an isomer of propanoic acid.
Answer:
D) HCOOCH2CH3
Explanation:
Option D is an isomer of propanoic acid because this compound has the same number of atoms as the acid; 3 carbons, 6 hydrogens and 2 oxygen. They may differ in some properties but their main difference must be their molecular structure, that is, the arrangement of their atoms.
Examine the reaction. NH4OH(aq) →H2O(l) + NH3(g)
What coefficients will balance the equation?
A) 1, 1, 1
B) 3, 3, 4
C) 2, 1, 2
D) 1, 2, 2
Answer: A. 1,1,1
Explanation:
The coefficients that will balance the equation; NH4OH(aq) →H2O(l) + NH3(g), is 1, 1, 1, because it proves the total number of atoms of each element on the LHS and RHS of the equation are equal, hence balanced.
LHS RHS
N = 1 1
H = 5 5
O = 1 1
. Se dispone de una muestra impura de aluminio de 50g. Se hace reaccionar con sulfú rico para encontrar su riqueza. Hallar la riqueza sabiendo que se obtienen 28g de sal.
Answer:
9.32% de riqueza de Al en la muestra
Explanation:
La reacción de aluminio (Al) con ácido sulfúrico (H₂SO₄) es:
2 Al + 3 H₂SO₄ → Al₂(SO₄)₃ + 3 H₂
Dos moles de aluminio reaccionan con 3 moles de ácido sulfúrico para producir una mol de sulfato de aluminio (Sal).
Las moles de 28g de sulfato de aluminio (Masa molar: 324.15g) son:
28g ₓ (1 mol / 324.15) = 0.0864 moles de Al₂(SO₄)₃
Así, las moles de aluminio que reaccionaron fueron:
0.0864 moles de Al₂(SO₄)₃ ₓ ( 2 moles Al / 1 mol Al₂(SO₄)₃) =
0.1728 moles de Al. En gramos (Masa atómica: 26.98g/mol):
0.1728 moles Al ₓ (26.98g / mol) = 4.66g de aluminio.
Así, la riqueza de la muestra es:
4.66g Al / 50g muestra ₓ100 = 9.32% de riqueza de Al en la muestra
When calcium is allowed to react with nitrogen, calcium nitride is formed. If 24.0 g of calcium and 12.0 g of nitrogen are available for this reaction, the limiting reagent will be?
Round to 3 significant figures.
1.235
Answer:
1.24
Explanation:
According to the concept of significant figures, rounding off to 3 significant figures gives 1.24.
What are significant figures?Significant figures are used for establishment of a number which is presented in the form of digits. These digits give a meaningful representation to the numbers.
The significant figures are the significant digits which convey the meaning according to the accuracy. These provide precision to the numbers and hence are called as significant numbers.There are rules for counting significant figures which are as follows:
1)All non-zero digits are significant .
2)All zeroes which occur between non-zero digits are significant.
3)All zeroes to the left and right of a non-zero digit are not significant.
4) All zeroes on right of decimal are significant if a non-zero number follows them.
5)All zeroes on right side of non-zero digit are significant.
Learn more about significant figures,here:
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