g Suppose that the Red cart has a mass of 500 grams, and the blue cart has a mass of 250 grams, and they are connected with a spring of spring constant 100 N/m. If the Red cart is held, and the Blue cart is pulled away with a force 19.2 N, what will be the force on the Red cart (write your answer in newtons, magnitude only)

Answers

Answer 1

Answer:

19.2 N

Explanation:

After any transients dissipate, all forces must balance. The red cart never moves.


Related Questions

For example, we can take Water
In (A) Water has same mass and great volume
In (B) Water has same mass and lower volume
Will there be any change in its density then?

Answers

Answer:

yes there will be change in its density

Which of the following exhibit the Tyndall Effect?


A flashlight beam through air in a room.

A laser beam through salt water.

Car headlights on a foggy night.

A laser beam through a soda drink.

Answers

Answer:

Probably all but (a)

The Tyndall Effect is caused by dispersion of the incident light by the individual molecules in the liquid.

Salt water and a foggy night will cause dispersion of the incident light.

A soda drink may also cause this dispersion, but and not sure.

A bicyclist moves along a straight line with an initial velocity vo and slows downs. Which of the following the best describes the signs set for the initial position, initial velocity and the acceleration ?​

Answers

The sign set after the slowdown of the bicycle will be positive for the position,  negative for velocity, and negative for acceleration.

What is velocity?

The rate at which an object's position changes when observed from a specific point of view and when measured against a specific unit of time is known as its velocity.

According to Que, when a bicyclist moves in a straight line and slows down, then the velocity decrease as displacement is decreasing, and the acceleration also decreases only displacement increases.

Therefore, the sign set for the position is +ve, for velocity it is -ve, and for acceleration also -ve

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A biker slows down after traveling in a long, straight line at initial velocity v0. Which of the following the best \sdescribes the signs set for the initial position, initial velocity and the acceleration? Initial position Initial velocity Acceleration

A. Positive Negative Negative

B. Positive Positive Negative

C. Negative Positive Negative

D. Negative Negative Positive

E. Negative Negative Negative

What is the final velocity if you have an initial velocity of 5 m/s with an acceleration of 3 m/s2 over a 4 second interval?

Answers

Answer: 17 m/s

Explanation:

Using the formula Vf=Vi+at

Vf=5m/s+3m/s^2(4s)

Vf= 17m/s

Which nucleus complete the following equation

Answers

(C) [tex]^{208}_{84}\text{Po}[/tex]

Explanation:

[tex]^{212}_{86}\text{Rn} \rightarrow \:^4_2\text{He} + \:^{208}_{84}\text{Po}[/tex]

Help again! Thank you all xoxo

Answers

Answer:

Amount of charge

Explanation:

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A car is running with the velocity of 72 km per hour what will be its velocity after 5 seconds if its acceleration is -2 metre per second square​

Answers

Answer:

initial velocity (u)=72×1000/60×60

=72000/3600

=20m/s

final velocity(v)=v

Time(t)=5s

acceleration(a)=-2m/s

now,

acceleration(a)=v-u/t

-2=v-20/5

-2×5=v-20

-10=v-20

-10+20=v

v=10m/s



b) Calculate the equivalent capacitance of the network shown below between the points A nd 'B', Given: C1 = C2 = 12uF.C3 = 7uF, CA = C5 = C6 =151F C6 =15uF

Answers

As No diagram attached I am taking all are connected in series

We know

[tex]\boxed{\sf C_{eq}=C_1+C_2\dots}[/tex]

[tex]\\ \sf \longmapsto C_{eq}=12+12+7+15+15+15[/tex]

[tex]\\ \sf \longmapsto C_{eq}=24+7+45[/tex]

[tex]\\ \sf \longmapsto C_{eq}=76\mu F[/tex]

If you jump off a 5 m diving platform how long will take you hit the water

Answers

Answer:

t = 1.0s

Explanation:

^d = v_0*t + (1/2)*a*t²

(5m-0m) = 0m/s*t + (.5)(9.81m/s²)*(t)²

5m = (4.905m/s²)*t²

t² = 1.01937s²

t = √1.01937s²

t = 1.0s

Why does cold water kept in an open container become warm on a hot summer afternoon?

Answers

Cold water kept in an open container acquires heat from the warmer surrounding becomes warm like the air around it due to the transfer of thermal energy

Pls mark as brainliest

Someone help me with these questions please!

Answers

Answer:

a 25 and b 25

2. 26

60n

Open the sash half way up, take the beaker containing the dry ice / water out of the hood, and slowly move it from right in front of the hood all the way down to the floor. At what point do the fumes stop getting sucked up by the fume hood?

Answers

Answer:

The fumes stop getting sucked up by the fume hood once the beaker is pulled out of the hood.

We do not use water instead of mercury in a barometer​

Answers

Answer:

Because

1)Water is relatively less dense. Mercury is 13.6 times more dense than water. SO, If you use water, you have to have the length of barometer of length (or height) 13.534 times the length of mercury barometer, which may be more than 11 meter in length.

2)Also mercury as compared to water, has comparatively less specific heat and good conductor of heat, could come to the same temperature of the atmosphere more quickly.

Answer:

The atmospheric pressure at sea level 76 cm of Hg=1.013× 10⁵ pascal .

Explanation:

That is if water is used in barometer tube instead of mercury the length of the tube must be greater than 10.326 cm.so we cannot replace mercury by water in the barometer.

Which of the units of the following physical quantities are derived

Answers

Answer:

You have not provided options but so long as the option is none of these, it's the right answer:

Electric current, Thermodynamic temperature,mass,time amount of substance,length, luminous intensity

Two resistors connected in series have an equivalent resistance of 690 Ohms. When they are connected in parallel, their equivalent resistance is 118 Ohms. Find the resistance of each resistor.

Answers

Explanation:

Let [tex]R_1[/tex] and [tex]R_2[/tex] be the the resistances of the resistors. We are given that

[tex]R_1 + R_2 = 690\:Ω\:\:\:\:\:\:\:(1)[/tex]

and

[tex]\dfrac{1}{R_1} + \dfrac{1}{R_2} = \dfrac{1}{118\:Ω}\:\:\:\:\:(2)[/tex]

From Eqn(1), we can write

[tex]R_2 = 690\:Ω - R_1[/tex]

and then plug this into Eqn(2):

[tex]\dfrac{1}{R_1} + \dfrac{1}{690\:Ω - R_1} = \dfrac{1}{118\:Ω}[/tex]

or

[tex]\dfrac{690\:Ω}{(690\:Ω)R_1 - R_1^2}= \dfrac{1}{118\:Ω}[/tex]

[tex]\Rightarrow R_1^2 - (690\:Ω)R_1 + (690\:Ω)(118\:Ω)= 0[/tex]

or

[tex]R_1^2 - 690R_1 + 81420 = 0[/tex]

Using the quadratic formula, we find that the above equation has two roots:

[tex]R_1 = 151.1\:Ω,\:\:538.9\:Ω[/tex]

This means that if you choose one root value for [tex]R_1[/tex], the other root will be the value for [tex]R_2[/tex].

Light of wavelength 600 nm illuminates a diffraction grating. The second-order maximum is at angle 39.2. How many lines per millimeter does this grating have?

Answers

Answer:

Diffraction equation applies in this case:

d*Sin x = m*wavelength, where d = spacing of lines, x = angle = 39.5°, m = order of maximum = 2

Substituting;

d* Sin 39.5 = 2*600*10^-9

d = (2*600*10^-9)/Sin 39.5 = 1.88656*10^-6 m

In 1 mm (or 0.001 m), the number of lines is given as;

Number of lines = 0.001/d = 0.001/(1.88656*10^-6) = 530.065 ≈ 530 lines



5. An electron is moving north in a region where

the magnetic field is south. The magnetic force

exerted on the electron is:

A.Zero

B. up

C. down

D. east

E. west

Answers

Answer:

eastlove india

Two forces are acting on a body. One acts east, the other at 35° north of east. If the
two forces are equal in magnitude of 50 N, find the resultant using the Law of Sines
and the Law of Cosines. Please answer with full solution. Thanks

Answers

A=B=50NAngle=theta=35°

We know

[tex]\boxed{\sf R=\sqrt{A^2+B^2+2ABcos\Theta}}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{50^2+50^2+2(50)(50)cos35}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{2500+2500+2(2500)\times (-0.9)}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{5000+5000(-0.9)}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{5000+(-4500)}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{5000-4500}[/tex]

[tex]\\ \sf\longmapsto R=\sqrt{-500}[/tex]

[tex]\\ \sf\longmapsto R=22.4i[/tex]

Resultant using the Law of Sines and the Law of Cosines will be R=95 N

What is force?

Force is an external agent applied on any object to displace it from its position. Force is a vector quantity, so with magnitude it also requires direction. Direction is necessary to examine the effect of the force and to find the equilibrium of the force.

The Magnitude of two forces =50 N

Angle between the forces = 35

By using the resultant formula

[tex]\rm R=\sqrt{A^2+B^2+2ABCos\theta}[/tex]

[tex]\rm R=\sqrt{50^2+50^2+2(50)(50)Cos35}[/tex]

[tex]\rm R=\sqrt{5000+5000(0.81)}[/tex]

[tex]\rm R=\sqrt{5000+4500}[/tex]

[tex]\rm R=95\ N[/tex]

Hence the Resultant using the Law of Sines and the Law of Cosines will be R=95 N

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A roller coaster has a total track length of 500 yards. A complete ride on the roller coaster is considered two times around the track. The start and stop places for the ride are virtually the same. What are the distance and displacement for a ride on the roller coaster? Explain your answers.

Answers

Answer:

Explanation:

its 1000 yards if its going around the track 2 times and that if one whole  around the track is 500 its 500 x 2

Which of the units of the following physical quantities are derived

Answers

Answer:

where is the attachment

Explanation:

Determine the point of contraflexure

Answers

Answer:

The point of contraflexure (PoC) occurs where bending is zero and at the point of change between positive and negative (or between compression and tension). In a beam that is flexing (or bending), the point where there is zero bending moment is called the point of contraflexure.

a dentist used a light have wavelength 450nm what is the energy of the light

Answers

Answer:

≈ 4.41 x 10^-19

Explanation:

The formula for the energy of light is...

E = hc / λ

where 'h' is Planck's constant: 6.626 x 10^-34 Js

           'c' is the speed of light: 2.998 x 10^8 ms

       &  'λ' is the wavelength (in this case): 450 nm

1 nanometer (nm) = 1 x 10^-9m

E = (6.626 x 10^-34 Js)(2.998 x 10^8 ms) / (450nm)(1 m / 10^-9 nm)

E ≈ 4.41 x 10^-19 J

I think that's the answer and I hope it helps!

a bullet is dropped from the same height when another bullet is fired horizontally. they will hit the ground

Answers

Answer:

it will drop simultaneously

which sources of associated with the line emission spectrum?
1) electric fire
2) neon street sign
3) red traffic light
4) sun​

Answers

Answer:

Answer if this question neon street sign

Explanation:

may this answer is helpful for you

how is the area of a circle measured​

Answers

Answer:

Area of circle is measured using formula πr² which means π×radius×radius and π could be 22/7 or 3.14

Explanation:

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Answers

Give me points I will help you

The source of sound moves away from the listener.The listener has the impression that the source is lower in pitch. Why?

Answers

When the source is moving away from the observer the velocity of the source is added to the speed of light. This increases the value of the denominator, decreasing the value of the observed frequency. Frequency corresponds to pitch or tone; a lower observed frequency will result in a lower observed pitch.

Two long straight wires are suspended vertically. The wires are connected in series, and a current from a battery is maintained in them. What happens to the wires? What happens if the battery is replaced by an a-c source?

Answers

Answer:

(i) When a battery is connected inseries to two long parallel wires, the currents in the two wires will be in opposite directions. Due to which a force of repulsion will be acting between them and they are moving further apart.

(ii) When a battery is connected in parallel to two long parallel wires, the currents in the two wires will be in same direction. Due to it, a force of attraction will be acting between them and they are coming closer to each other.

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Explanation:

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A magnifying glass produces a maximum angular magnification of 5.4 when used by a young person with a near point of 20 cm. What is the maximum angular magnification obtained by an older person with a near point of 65 cm

Answers

67 points to the 55th power add it then you get exactly 1500

A train moving west with an initial velocity of 20 m/s accelerates at 4 m/s2 for 10 seconds. During this tim
moves a distance of
meters.

Answers

Answer:

400m

Explanation:

[tex]x = v_{0}t + \frac{at^{2} }{2} \\x = 20*10+\frac{4*10x^{2} }{2} = 400m[/tex]
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