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Determine the velocity of the pebble as it passes over the top of the tree.​

Answer:

a)density = mass /volume

b)to find volume put water into a container .measure the level of water , put the coins into the beaker containing water , measure the level of water again, subtract the new volume withe the first one . the result is the volume of coins

Answer:

hi

Explanation:

your answer is

The energy in the wave is proportional to the product of the electric and magnetic fields.

Answer:

40g

Explanation:

20g range > 1.0cm

Therefore,

40g range > 2.0cm

Answer:

chk picture for eqn

Explanation:

[tex]3.20×10^7\:\text{m/s}[/tex]

Explanation:

Let

[tex]L = 28.2\:\text{m}[/tex]

[tex]L' = 28.2\:\text{m} - 0.161\:\text{m} = 28.039\:\text{m}[/tex]

The Lorentz length contraction formula is given by

[tex]L' = L\sqrt {1 - \left(\dfrac{v^2}{c^2}\right)}[/tex]

where L is the length measured by the moving observer and L' is the length measured by the stationary Earth-based observer. We can rewrite the above equation as

[tex]\sqrt {1 - \left(\dfrac{v^2}{c^2}\right)} = \dfrac{L'}{L}[/tex]

Taking the square of the equation, we get

[tex]1 - \left(\dfrac{v^2}{c^2}\right) = \left(\dfrac{L'}{L}\right)^2[/tex]

or

[tex]1 - \left(\dfrac{L'}{L}\right)^2 = \left(\dfrac{v}{c}\right)^2[/tex]

Solving for v, we get

[tex]v = c\sqrt{1 - \left(\dfrac{L'}{L}\right)^2}[/tex]

[tex]\:\:\:\:=(3×10^8\:\text{m/s})\sqrt{1 - \left(\dfrac{28.039\:\text{m}}{28.2\:\text{m}}\right)^2}[/tex]

[tex]\:\:\:\:=3.20×10^7\:\text{m/s} = 0.107c[/tex]

Explanation:

local units doesn't give accurate measurement

but standard units give accurate measurement

Answer:

3201.304 J

Explanation:

Use ideal gas equation to initial stage:

PV=nRT

P * 0.034 = 1.8 * 8.314 * 250

P = 110038.2353 Pa

Use ideal gas equation to final stage:

PV=nRT

P * 0.08 = 1.8 * 8.314 * 250

P = 46766.25 Pa

Process is isothermal (constant temperature )

Therefore,

Work= C ln (V2/V1)

(P1V1=P2V2=C)

(Above equation is taken by integration of P.dv)

Work = P1V1 ln (V2/V1) = P2V2 ln (V2/V1)

By substituting above data to the equation:

Work = (110038.2353 * 0.034) * ln (0.08/0.034)

Work = 3201.304 J

Answer:

Simple harmonic motion is a special type of periodic motion or oscillation motion where the restoring force is directly proportional to the displacement and acts in the direction opposite to that of displacemen

Answer

Irma

Explanation:

You should invite Irma to the meeting because she is in Charlotte and she also visited after 10/24/20

The length of the brass at a temperature rise of 100 K is 2.0036 m

From the question given above, the following data were obtained:

Original length (L₁) = 2 m

Temperature rise (ΔT) = 100 K

Coefficient of linear expansion (α) = 18×10¯⁶ K¯¹

The final length of the brass can be obtained as follow:

α = L₂ – L₁ / L₁ΔT

18×10¯⁶ = L₂ – 2 / (2 × 100)

18×10¯⁶ = L₂ – 2 / 200

Cross multiply

L₂ – 2 = 18×10¯⁶ × 200

L₂ – 2 = 0.0036

Collect like terms

L₂ = 0.0036 + 2

L₂ = 2.0036 m

Thus, the length of the brass at a temperature rise of 100 K is 2.0036 m

Learn more: https://brainly.com/question/21983527

Answer:

The universal law of gravitation.

PE = m * G M / R^2  potential energy of mass m due to attractive forces

If the kinetic energy of mass m is greater than the energy due to the attractive masses then then mass m can continue indefinitely away from the attracting masses.

Answer:

When a stone is going around a circular path, the instantaneous velocity of stone is acting as tangent to the circle. When the string breaks, the centripetal force stops to act. Due to inertia, the stone continues to move along the tangent to circular path. So, the stone flies off tangentially to the circular path

Answer:

when the string's rotation is broken, there will be no centripetal force to keep the stone stationary. Thus, the stone will flung away when the rotation is stopped

The “rainbow” surface of a CD or DVD being the result of a transmission grating is False.

This happens when white light reflects on a metal to give rainbow colors and interesting patterns.

This is seen on the surface of a CD which is why transmission grating being the cause is false.

Read more about Reflection here https://brainly.com/question/26494295

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Answer:

The tension in the cord provides by centripetal force

T = Fc

= mv^2/r

= 2kg ( 6)^2/2

=36 N

The SI unit of pressure is the pascal: 1Pa=1N/m2 1 Pa = 1 N/m 2 . Pressure due to the weight of a liquid of constant density is given by p=ρgh p = ρ g h , where p is the pressure, h is the depth of the liquid, ρ is the density of the liquid, and g is the acceleration due to gravity.

Answer:

The first law of motion describes the principle of law of inertia.

Answer:

Following are the solution to the given question:

Explanation:

Applying the Snell Law:

when is the liquid's refractive index, is the air's refractive index.  

the liquid's refractive index,   the air's index of refraction.

It is the limiting case when , Inside the interphase of two mediums, light is scattered. Thus,

[tex]n_l \sin \theta_l = n_a \sin 90^\circ = n_a[/tex]

[tex]\theta_l = \arcsin \dfrac{n_a}{n_l} =\arcsin \dfrac{1}{1.38} = 46.4^\circ[/tex]

From  the incident angles [tex]\theta_l[/tex] is greater than 46.4°, that is the light reflected back into the liquid.

Answer:

a) 70,560 J

b) 88.2 N/m

Explanation:

The spring potential will equal the change in gravity potential

PS = PE = mgh = 80(9.8)(100 - 10) = 70,560 J

PS = ½kx²

k = 2PS/x² = 2(70560)/(100 - 50 - 10)² = 88.2 N/m

Since the frequencies are unrelated, and there are a large number of them, I'll say this represents an example of noise.

Explanation:

We will assume that the rim of the wheel is also very thin, like the spokes. The distance s between the spokes along the rim is

[tex]s = \frac{1}{8}C = \frac{1}{8}(2\pi)(0.25\:\text{m}) = 0.196\:\text{m}[/tex]

The 20-cm arrow, traveling at 6 m/s, will travel its length in

[tex]t = \dfrac{0.2\:\text{m}}{6\:\text{m/s}} = \dfrac{1}{30}\:\text{s}[/tex]

The fastest speed that the wheel can spin without clipping the arrow is

[tex]v = \dfrac{s}{t} = \dfrac{0.196\:\text{m}}{\left(\dfrac{1}{30\:\text{s}}\right)} = 5.9\:\text{m/s}[/tex]

The angular velocity [tex]\omega[/tex] of the wheel is given by

[tex]\omega = \dfrac{v}{r} = \dfrac{5.9\:\text{m/s}}{0.25\:\text{m}} = 23.6\:\text{rad/s}[/tex]

In terms of rev/s, we can convert the answer above as follows:

[tex]23.6\:\dfrac{\text{rad}}{\text{s}}×\dfrac{1\:\text{rev}}{2\pi\:\text{rad}} = 3.8\:\text{rev/s}[/tex]

As you probably noticed, I did the calculations based on the assumption that I'm aiming for the edge of the wheel because this is the part of the wheel where a point travels a longer linear distance compared to ones closer to the axle, thus giving the arrow a better chance to pass through the wheel without getting clipped by the spokes. If you aim closer to the axle, then the wheel needs to spin slower to allow the arrow to get through without hitting the spokes.

Answer:omega=23.56... rad/s

Explanation:for the arrow to pass without hitting the 8 spokes

taking the spokes thickness to be a point along the spokes linear motion path

lets calculate the time athe arrow pass point length of the wire 0.25m and it's speed(6m/s)

t=0.25m÷6m/s=0.0333...s

so every spoke around the wheel must move replacing each other's position so distribution of eight spokes=2π÷8=0.78... rad so using as angular displacement and t=0.033s then omega=∅/t=0.78/0.033=23.56rad/s

*yes

*space between spokes

Answer:

It is to produce sunlight in the forest plants

[tex]\boxed{\sf 1°C=273K}[/tex]

Sol:-1

[tex]\\ \sf\longmapsto 30°C[/tex]

[tex]\\ \sf\longmapsto 273+30[/tex]

[tex]\\ \sf\longmapsto 303K[/tex]

Sol:-2

[tex]\\ \sf\longmapsto 50°C[/tex]

[tex]\\ \sf\longmapsto 50+273[/tex]

[tex]\\ \sf\longmapsto 323K[/tex]

Answer:

A circuit with two 10 ohm resistors connected in series.

Explanation:

The formula for the equivalent resistance for resistors in parallel is

[tex]\frac{1}{Rt} = \frac{1}{R1} + \frac{1}{R2}[/tex]   So if R1=R2= 10  [tex]\frac{1}{Rt} = \frac{1}{10} + \frac{1}{10} = \frac{2}{10} <=> Rt =\frac{10}{2} =5 ohm[/tex]

The formula for the equivalent resistance for resistors in series is

Rt = R1 + R2  So Rt= 10 + 10 = 20

Answer:

Req = 564 Ω

Explanation:

The equivalent resistance between R1 and R2:

1/R =1/R1 + 1/R2

1/R =1/960 + 1/640

1/R = 1/384

R = 384

Now, the equivalent resistance between R and R3:

Req = 384 + 180

Req = 564 Ω

Answer:

Electric generator is the device that converts mechanical energy into electrical energy

Answer:

prove that Sin^6 ϴ-cos^6ϴ=(2Sin^2ϴ-1)(cos^2ϴ+sin^4ϴ)

please sove step by step with language it is opt maths question

Answer:

Hey,. its a simple question. hope you learn from the solution. check attached picture

Explanation:

Answer:

[tex]f=9.55Hz[/tex]

Explanation:

From the question we are told that:

Number of Turns [tex]N=200[/tex]

Length [tex]l=5cm to 10cm[/tex]

Voltage [tex]V=18V[/tex]

Magnetic field [tex]B=300mT[/tex]

Generally, the equation for Frequncy of an amarture is mathematically given by

[tex]f =\frac{ V}{(N B A * 2 pi )}[/tex]

[tex]f =\frac{ 18}{(200 300*10^{-3} (10*10^-2)(5*10^{-2}) * 2 *3.142 )}[/tex]

[tex]f=9.55Hz[/tex]

Answer:

The dimensions of Young's Modulus, as well as material stress, are the same as pressure because stress is like pressure in a solid, except with some key differences that warrant the use of different terminology.