Answer:
allows us to accept the null hypothesis
Explanation:
The z test(in a normal distribution) score for the critical region determines whether we reject the null hypothesis(H0) or accept the null hypothesis(reject or fail to reject the null hypothesis). If we fail to reject the null hypothesis, then we have accepted the alternative hypothesis (H1). The critical region rejection for z test is calculated using alpha and z score, if z score is greater or less than alpha(positive or negative), we reject the null hypothesis.
-12x + 12 = 4 - 15x + 9
Answer:
x = 1/3
Step-by-step explanation:
-12x + 12 = 4 - 15x + 9
Combine like terms
-12x +12 = -15x+13
Add 15x to each side
-12x+12 +15x = -15x+15x+13
3x+12 = 13
Subtract 12 from each side
3x+12-12 = 13-12
3x = 1
Divide by 3
3x/3 = 1/3
x = 1/3
take away 4/5 from 6 1/2
Answer:
3-4/5=2.2
hope it helps
Hi there!
»»————- ★ ————-««
I believe your answer is:
[tex]5\frac{7}{10}[/tex]
»»————- ★ ————-««
Here’s why:
⸻⸻⸻⸻
[tex]\boxed{\text{Calculating the answer...}}\\\\6\frac{1}{2}-\frac{4}{5} \\-------------\\6\frac{1}{2} = \frac{13}{2} \\\\\frac{13}{2} - \frac{4}{5}\\\\LCM(2,5): 10\\\\\frac{13}{2} =\frac{13*5}{2*5} =\frac{65}{10}\\\\\frac{4}{5}=\frac{4*2}{5*2}=\frac{8}{10}\\\\\frac{65}{10}-\frac{8}{10}\\\\ \frac{57}{10}\\\\\frac{57}{10}\rightarrow\boxed{5\frac{7}{10}}[/tex]
»»————- ★ ————-««
Hope this helps you. I apologize if it’s incorrect.
HURRY PLEASE!!!!!!
Line AB has a slop of 1/2
What would the slope of line CD have to be if we knew CD was perpendicular to AB?
2
-2
1/2
-1/2
Answer:
-2
Step-by-step explanation:
Perpendicular lines have slopes that are negative reciprocals
Take the slope of AB = 1/2
-1/(1/2)
-1 * 2/1
-2
The slope of a line perpendicular is -2
I need help completing this problem ASAP
4/(√x - √(x - 2)) × (√x + √(x - 2))/(√x + √(x - 2))
= 4 (√x + √(x - 2)) / ((√x)² - (√(x - 2))²)
= 4 (√x + √(x - 2)) / (x - (x - 2))
= 4 (√x + √(x - 2)) / (x - x + 2)
= 4 (√x + √(x - 2)) / 2
= 2 (√x + √(x - 2))
Please help me with this on the picture
Answer:
this is the chapter of linear equations in one variable?
The football coach randomly selected 10 players and timed how long each player took to perform a certain drill. The result has a sample mean of 9.48 minutes and sample standard deviation of 2.14 minutes. Round answers to two decimals. The 95% confidence interval for the mean time for all players is : __________
Answer:
The 95% confidence interval for the mean time for all players, in minutes, is: (7.95, 11.01).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom,which is the sample size subtracted by 1. So
df = 10 - 1 = 9
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 9 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.95}{2} = 0.975[/tex]. So we have T = 2.2622.
The margin of error is:
[tex]M = T\frac{s}{\sqrt{n}} = 2.2622\frac{2.14}{\sqrt{10}} = 1.53[/tex]
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 9.48 - 1.53 = 7.95 minutes.
The upper end of the interval is the sample mean added to M. So it is 9.48 + 1.53 = 11.01 minutes.
The 95% confidence interval for the mean time for all players, in minutes, is: (7.95, 11.01).
Sketch the region of integration and convert the polar integral to a Cartesian integral or sum of integrals. Do not evaluate the integral.
∫ ^π∫^2 r^3 sinθcosθdrd()
π/2 0
It looks like the integral in polar coordinates is given to be
[tex]\displaystyle\int_{\pi/2}^\pi \int_0^2 r^3\sin(\theta)\cos(\theta)\,\mathrm dr\,\mathrm d\theta[/tex]
Converting back to Cartesian, we take
x = r cos(θ)
y = r sin(θ)
dx dy = r dr dθ
so we can easily recover the integrand in Cartesian:
[tex]r^3\sin(\theta)\cos(\theta)\,\mathrm dr\,\mathrm d\theta = (r\sin(\theta))(r\cos(\theta))(r\,\mathrm dr\,\mathrm d\theta) = xy\,\mathrm dx\,\mathrm dy[/tex]
This leaves us with the limits:
• π/2 ≤ θ ≤ π corresponds to the second quadrant of the (x, y)-plane (that is, where x < 0 and y > 0)
• 0 ≤ r ≤ 2 correspond to the disk of radius 2 centered at the origin
Taken together, we see the region of integration is a quarter-disk of radius 2 in the second quadrant, which we can capture by the set
{(x, y) : -√2 ≤ x ≤ 0 and 0 ≤ y ≤ √(2 - x ²)}
So, in Cartesian coordinates, the integral would be
[tex]\displaystyle \boxed{\int_{-\sqrt2}^0 \int_0^{\sqrt{2-x^2}} xy\,\mathrm dy\,\mathrm dx}[/tex]
Type the correct answer In each box. Use numerals instead of words. What is the equation of the quadratic function that has a minimum at (7,-3) and goes through (9.9)
Answer:
Step-by-step explanation:
This semester, the tuition fee increased to $5,871. If this represents an increase by 14%, what was the original fee?
Of the respondents, 502 replied that America is doing about the right amount. What is the 95 % confidence interval for the proportion of all American adults who feel that America is doing about the right amount to protect the environment?
Answer:
The 95 % confidence interval for the proportion of all American adults who feel that America is doing about the right amount to protect the environment is (0.461, 0.543), considering [tex]n = 1000[/tex]
Step-by-step explanation:
Incomplete question, so i will suppose this is a sample of 1000.
In a sample with a number n of people surveyed with a probability of a success of [tex]\pi[/tex], and a confidence level of [tex]1-\alpha[/tex], we have the following confidence interval of proportions.
[tex]\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}[/tex]
In which
z is the z-score that has a p-value of [tex]1 - \frac{\alpha}{2}[/tex].
Of the n respondents, 502 replied that America is doing about the right amount.
Supposing [tex]n = 1000[/tex], so [tex]\pi = \frac{502}{1000} = 0.502[/tex]
95% confidence level
So [tex]\alpha = 0.05[/tex], z is the value of Z that has a p-value of [tex]1 - \frac{0.05}{2} = 0.975[/tex], so [tex]Z = 1.96[/tex].
The lower limit of this interval is:
[tex]\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.502 - 2.575\sqrt{\frac{0.502*0.498}{1000}} = 0.461[/tex]
The upper limit of this interval is:
[tex]\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.502 + 2.575\sqrt{\frac{0.502*0.498}{1000}} = 0.543[/tex]
The 95 % confidence interval for the proportion of all American adults who feel that America is doing about the right amount to protect the environment is (0.461, 0.543), considering [tex]n = 1000[/tex]
Write a quadratic equation having the given numbers as solutions. -7 and -5
The quadratic equation is ___ =0.
Answer:
x²+12x+35
Step-by-step explanation:
in factored form it would just be
(x+7)(x+5)=0
expand this
x²+12x+35=0
find the equation of the line
The slope of the line containing the points (-5, 3) and (-2, 1) is ________.
Answer:
-2/3
Step-by-step explanation:
We can use the slope formula
m = ( y2-y1)/(x2-x1)
= ( 1-3)/(-2 - -5)
= (1-3)/(-2+5)
= -2/3
si 40/a = 35/7 entonces cual es el valor de a
Respuesta:
a = 8
Explicación paso a paso:
Para obtener el valor de a en la ecuación:
40 / a = 35/7
Cruzamos multiplicamos:
40 / a = 35/7
40 * 7 = 35 * a
280 = 35a
Dividir ambos lados por 35
280/35 = 35a / 35
8 = a
a = 8
Use the graph to determine the input values that correspond with f(x) = 1.
Answer:
[tex]x = -7[/tex] and [tex]x = 2[/tex]
Step-by-step explanation:
Given
See attachment for graph
Required
Find x, for [tex]f(x)= 1[/tex]
From the graph, we have the following readings
[tex]f(x)= 1[/tex] when:
[tex]x = 2[/tex] and [tex]x = -7[/tex]
Hence, (d) is correct
The formula for converting from kelvins (K) to degrees Celsius (°C) is:
°C = K - 273
Using this formula, convert 400 K to degrees Celsius.
O A. 127°C
O B. 673°C
O C. -673°C
O D. -127°C
Answer:
answer is A. 127°C
hopes this helps you
Which expression is equivalent to (b^n)m?
Step-by-step explanation:
By the law of exponent :
(a^n)^m=a^n×m
Option C
b^n×m is the correct answer...
hope it helps
The amount of soda a dispensing machine pours into a 12 ounce can of soda follows a normal distribution with a standard deviation of 0.08 ounce. Every car that has more than 12.20 ounces of soda poured into it causes a spill and the can needs to go through a special cleaning process before it can be sold. What is the mean amount of soda the machine should dispense if the company wants to limit the percentage that need to be cleaned because of spillage to 3%
Answer:
x = 12.15 oz
Step-by-step explanation:
z = 1.8808
1.8808 = (x - 12)/.08
g A control group of 14 vehicles using regular gasoline showed mean CO2 emissions of 679 pounds per 1000 miles with a standard deviation of 15 pounds. At α = 0.05, in a left-tailed test (assuming equal variances) the test statistic is: Group of answer choices
Answer:
0.236
Step-by-step explanation:
Given :
x1 = 667 ; n1 = 10 s1 = 20
x2 = 679 ; n2 = 14 s2 = 15
Test statistic :
(x1 - x2) / √[Sp² (1/n1 + 1/n2)]
The pooled Variance, Sp² :
Sp² = [(n1 - 1)s1² + (n2 - 1)s2²] / (n1 + n2 - 2)
Sp² = [(9*20²) + (13*15²)] / (10+14-2)
Sp² = 6525 / 22 = 296.59
T = (667 - 679) / √(296.59*(1/10 + 1/14)
T = -12 / 50.844
T = 0.236
Test statistic = 0.236
КУ
11
10
A
9
8
7 구
6
5
4
A А
C
3
B'
2
1
B
C с
-6 -5 -4 -3 -2 -1
1 2 3 4 5 6
A ABC is dilated about the origin./
What scale factor was used to make the image A A'B'C?
Answer:
3
Step-by-step explanation:
The dilation factor is 3
A perfect correlation is denoted by:
A. +1.0 and -1.0
B. +1.00
C. -1.00
D. .50
A perfect correlation is denoted by:
A. +1.0 and -1.0
Tìm vi phân toàn phần của các hàm số sau:
ln(x+√(x^2+y^2 ) ) ln(sin(y/x))
Let f = ln(x + √(x ² + y ²)) ln(sin(y/x)).
Then the total differential is
[tex]\mathrm df = \dfrac{\mathrm d\left(x+\sqrt{x^2+y^2}\right)}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\mathrm d\left(\sin\left(\frac yx\right)\right)}{\sin\left(\frac yx\right)}[/tex]
[tex]\mathrm df = \dfrac{\mathrm dx + \frac{\mathrm d(x^2+y^2)}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}}\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}\right)\dfrac{\cos\left(\frac yx\right)\,\mathrm d\left(\frac yx\right)}{\sin\left(\frac yx\right)}[/tex]
[tex]\mathrm df = \dfrac{\mathrm dx + \frac{2x\,\mathrm dx+2y\,\mathrm dy}{\sqrt{x^2+y^2}}}{x+\sqrt{x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) + \ln\left(x+\sqrt{x^2+y^2}}\right)\dfrac{\cos\left(\frac yx\right)\frac{x\,\mathrm dy-y\,\mathrm dx}{x^2}}{\sin\left(\frac yx\right)}[/tex]
[tex]\mathrm df = \dfrac{\left(2x+\sqrt{x^2+y^2}\right)\,\mathrm dx +2y\,\mathrm dy}{x\sqrt{x^2+y^2}+x^2+y^2\right)\ln\left(\sin\left(\dfrac yx\right)\right) \\\\ \indent + \dfrac1{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}}\right)(x\,\mathrm dy-y\,\mathrm dx)[/tex]
[tex]\mathrm df = \left(\left(\dfrac{2x+\sqrt{x^2+y^2}}{x\sqrt{x^2+y^2}+x^2+y^2}\right)\ln\left(\sin\left(\dfrac yx\right)\right) - \dfrac y{x^2}\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dx \\\\ \indent + \left(\dfrac{2y}{x\sqrt{x^2+y^2}+x^2+y^2}\ln\left(\sin\left(\dfrac yx\right)\right)+\dfrac1x\cot\left(\dfrac yx\right)\ln\left(x+\sqrt{x^2+y^2}\right)\right)\,\mathrm dy[/tex]
Which type of triangle has altitudes that form outside the triangle itself?
Select one:
a. acute
b. equiangular
c. obtuse
d. right
9514 1404 393
Answer:
c. obtuse
Step-by-step explanation:
For an obtuse triangle, the altitudes from the vertices on either side of the obtuse angle will be drawn outside the triangle.
2cos2+cos2(2)−2cos2cos2=1
How many
Assume that the mean hecaht of soldiers is 166cm
with a standard deration of 8. cm.
soldeers in a regiment of 1000 would you expect to
be over 177 cm tall.
Answer:
85
Step-by-step explanation:
Given that :
Mean height , μ = 166
Standard deviation, σ = 8
Sample size, n = 1000
Using the Zscore formula :
Zscore = (x - μ) / σ
x = 177
Z = (177 - 166) / 8
Z = 1.375
P(Z > 1.375) = 0.084566(Area to the right of Z)
P(Z > 1.375) * n
0.084566 * 1000 = 84.566 = 85 soldiers
Surface Area of cones
Instructions: Find the surface area of each figure. Round your answers to the nearest tenth, if necessary.
9514 1404 393
Answer:
64.1 ft²
Step-by-step explanation:
The area of the cone is given by ...
A = πr(r +h) . . . . for radius r and slant height h
A = π(2 ft)(2 ft +8.2 ft) ≈ 64.1 ft²
A package contains 12 resistors, 3 of which are defective. If 4 are selected, find the probability of getting
Answer:
Incomplete question, but I gave a primer on the hypergeometric distribution, which is used to solve this question, so just the formula has to be applied to find the desired probabilities.
Step-by-step explanation:
The resistors are chosen without replacement, which means that the hypergeometric distribution is used to solve this question.
Hypergeometric distribution:
The probability of x successes is given by the following formula:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
In which:
x is the number of successes.
N is the size of the population.
n is the size of the sample.
k is the total number of desired outcomes.
Combinations formula:
[tex]C_{n,x}[/tex] is the number of different combinations of x objects from a set of n elements, given by the following formula.
[tex]C_{n,x} = \frac{n!}{x!(n-x)!}[/tex]
In this question:
12 resistors, which means that [tex]N = 12[/tex]
3 defective, which means that [tex]k = 3[/tex]
4 are selected, which means that [tex]n = 4[/tex]
To find an specific probability, that is, of x defectives:
[tex]P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}[/tex]
[tex]P(X = x) = h(x,12,4,3) = \frac{C_{3,x}*C_{9,4-x}}{C_{12,4}}[/tex]
Listed below are the overhead widths (in cm) of seals measured from photographs and the weights (in kg) of the seals. Construct a scatterplot, find the value of the linear correlation coefficient r, and find the critical values of r using α=0.01. Is there sufficient evidence to conclude that there is a linear correlation between overhead widths of seals from photographs and the weights of the seals?
Answer:
1.) scatter plot is attached below.
There is no sufficient evidence to support the claim that there is a linear correlation between overhead widths of seals from photographs and the weights of the seals.
Step-by-step explanation:
Given the data :
Overhead width : 7.2 7.5 9.7 9.3 8.7 8.2
Weight : 119 156 243 200 199 188
The linear correlation Coefficient, R = 0.946
Using the Pvalue calculator for R score ;
Pvalue = 0.0149
Since, Pvalue > Α ; WE fail to reject the Null and conclude that there is no sufficient evidence to support the claim that there is a linear correlation between overhead widths of seals from photographs and the weights of the seals.
How many 4-digit passcodes can be created if each digit can be any number, 0-9?
6,561
10,000
40
5,040
Answer:
6,561
that's a good number
0 thru 9 is 10 numbers.
Each digit can be 1 of 10 numbers:
Total combinations = 10 x 10 x 10 x 10 = 10,000
Answer: 10,000
Evaluate 2w^2-3w+7 when w=-2
Hey there!
2w^2 - 3w + 7
= 2(-2)^2 - 3(-2) + 7
(-2)^2
= (-2)(-2)
= 4
= 2(4) - 3(-2) + 7
2(4) = 8
3(-2) = -6
= 8 - (-6) + 7
= 8 + 6 + 7
8 + 6 = 14
14 + 7
= 21
Answer: 21
Good luck on your assignment and enjoy your day!
~Amphitrite1040:)
