For each of the indicates values given for x and y, determine which expression has a greater value (x+y)^2 or (x-y)^2

Answer:

f(x)=5cos(1/3x) this is an equation

The 15 percent-off $123 or 15 percent discount for a item in which the original price is $123 is: $18.45

Using this formula

Amount = Original Price x Discount

Let plug in the formula

Amount= 123 x 15 / 100

Amount = 1845 / 100

Amount = $18.45

Inconclusion the 15 percent-off $123 is $18.45.

Learn more about 15 percent-off $123 here:https://brainly.com/question/23192029

Answer:

C

Step-by-step explanation:

The expression is x>55 and 55 isn't included

Answer:

c

Step-by-step explanation:

Answer:

nfngkfngmnfjf jvfjkfntfknddjhdhdbdbdb

Answer:

2/5

Step-by-step explanation:

P(black)=10/25=2/5

Given Equations

Let it has solution (x,y)

Add both

[tex]\\ \sf\longmapsto 5x+4x+3y+7y=8+34[/tex]

[tex]\\ \sf\longmapsto 9x+10y=42[/tex]

It will also have same solution (x,y)

The solution of the equations is (-2, 6) which satisfies the equation 9x + 10y = 42.

The allocation of weights to the important variables that produce the calculation's optimum is referred to as a direct consequence.

The system of linear equations is given below.

5x + 3y = 8               ...1

4x + 7y = 34            ...2

From equation 1, then we have

5x + 3y = 8

y = 8/3 - (5/3)x

Put in equation 2, then we have

4x + 7[8/3 - (5/3)x] = 34

12x + 56 - 35x = 102

-23x = 46

x = - 2

Then the value of y is calculated as,

y = 8/3 - (5/3)(-2)

y = 8/3 + 10/3

y = 18 / 3

y = 6

Let's check whether (-2, 6) satisfy the equation 9x + 10y = 42 or not. Then we have

9(-2) + 10(6) = 42

- 18 + 60 = 42

42 = 42

The solution of the equations is (-2, 6) which satisfies the equation 9x + 10y = 42.

More about the solution of the equation link is given below.

https://brainly.com/question/545403

#SPJ2

Step-by-step explanation:

Recall that [tex]\sin^2x + \cos^2x = 1[/tex]

[tex](\sin x \sin y - \cos x \cos y)(\sin x \sin y + \cos x \cos y)[/tex]

[tex]= \sin^2 x \sin^2 y - \cos^2 x \cos^2 y[/tex]

[tex]= \sin^2 x (1 - \cos^2 y) - \cos^2 x \cos^2 y[/tex]

[tex]= \sin^2 x - \sin^2 x \cos^2y - \cos^2x \cos^2y[/tex]

[tex]= \sin^2x - (\sin^2x + \cos^2x)\cos^2y[/tex]

[tex]= \sin^2x - \cos^2y[/tex]

Answer:

90

Step-by-step explanation:

Angle Formed by Two Chords= 1/2(SUM of Intercepted Arcs)

105 = 1/2 (120+x)

210 = 120+x

Subtract 120 from each side

210-120 = x

90 =x

The value of  Intercepted Arcs x will be 90. so option C is correct.

If the considered circle has center O and chord AB, then if there is perpendicular from O to AB at point C, then that point C is bisecting(dividing in two equal parts) the line segment AB.

Or

|AC| = |CB|

Angle Formed by Two Chords= 1/2 (Sum of Intercepted Arcs)

105 = 1/2 (120+x)

210 = 120+x

Subtract 120 from each side;

210-120 = x

90 =x

Hence, the value of  Intercepted Arcs x will be 90. so option C is correct.

Learn more about chord of a circle here:

https://brainly.com/question/27455535

#SPJ5

Answer: ME

Step-by-step explanation:

Answer:

166

Step-by-step explanation:

Since the lines are parallel, A=B. 7x+40=3x+112, 4x=72, x=18. A=166

Answer:

w = -46/5

Step-by-step explanation:

Answer:

w=-9.2

Step-by-step explanation:

7(w+8)=2w+10

7w+56=2w+10

7w-2w=10-56

5w=-46

w=-9.2

Answer:

-3(z-x) = y

Step-by-step explanation:

Z=x-y/3

Solve for y

Subtract x from each side

z-x = x- y/3 -x

z-x = -y/3

Multiply each side by -3

-3(z-x) = -y/3 * -3

-3(z-x) = y

9514 1404 393

Answer:

  16.9 m

Step-by-step explanation:

Angle BMT in the attached diagram is the complement of the angle of depression, so is 90° -56° = 34°. The distance BT is the side of the triangle opposite this angle, and the given tree height TM = 25 is the side of the triangle adjacent to the angle. Then the relevant trig relation is ...

  Tan = Opposite/Adjacent

  Opposite = Adjacent × Tan

  BT = (25 m)·tan(34°) ≈ 16.863 m

The banana is about 16.9 meters from the tree.

Answer:

-Hello Fatema!

[tex] \boxed{ \large{ \tt{✺ \: AREA \: OF \: A \: CIRCLE = \pi \: d }}}[/tex]

[tex] \large{ \tt{⟶ \: 153.86 = 3.14 \: d}}[/tex]

[tex] \large{ \tt{⟶ \: d = \frac{153.86}{3.14} }}[/tex]

[tex] \large{ \tt{⟶d = 49 \: m}}[/tex]

[tex] \large{ \boxed{ \boxed{ \tt{⤿ \: OUR \: FINAL \: ANSWER : \: 49 \: m}}}}[/tex]

I hope this helps :]

63x2−164x+96

Answer:

63x² - 164x + 96

Step-by-step explanation:

Use the FOIL method:

7x · 9x = 63x²

7x · -8 = -56x

9x · -12 = -108x

-12 · -8 = 96

63x² - 56x - 108x + 96

63x² - 164x + 96

Answer:

Step-by-step explanation:

Answer:

4y+x-3=0

Step-by-step explanation:

The equation is y=mx+b

1) Use the coordinates from the first point

(-1,1)

1= -m+b

2) Use the coordinates frm the second point

(-5,2) (y=mx+b, use x=-5, y=2)

2=-5m+b

You have the system of equations

1=-m+b (multiply by -1)  -1= m-b

2=-5m+b

Add the first equation (multiplied by -1) and the second one

-1+2= m-b-5m+b

1= -4m

m=-0.25

2=1.25+b

b=0.75

y=-0.25x+0.75

4y= -x+3

4y+x-3=0

Answer:

√245

Step-by-step explanation:

altitude on hypotenuse theorem:

m^2=7*35

m^2=245

m=√245

Answer:

25

Step-by-step explanation:

Let x represent the number of $50 jackets that were sold, and let y represent how many $30 jackets were sold.

50x + 30y = 2360

y = x + 12

Solve by substitution by substituting the second equation into the first one. Then, solve for x:

50x + 30y = 2360

50x + 30(x + 12) = 2360

50x + 30x + 360 = 2360

80x + 360 = 2360

80x = 2000

x = 25

So, 25 $50 jackets were sold.

Answer:

348 m^2

Step-by-step explanation:

The figure is made up of a rectangle 24 m by 12 m, and a triangle with a 24 m base and a 5 m height.

A = LW + bh/2

A = 24 m * 12 m + (24 m)(5 m)/2

A = 288 m^2 + 60 m^2

A = 348 m^2

howdy!!

yr answer is the third graph!

Answer:

The value of the test statistic is 59.75.

Step-by-step explanation:

The test statistic for the population standard deviation is:

[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]

In which n is the sample size, [tex]\sigma_0[/tex] is the value tested and s is the sample standard deviation.

A sample of 45 bottles of soft drink showed a variance of 1.1 in their contents.

This means that [tex]n = 45, s^2 = 1.1[/tex]

The process engineer wants to determine whether or not the standard deviation of the population is significantly different from 0.9 ounces.

0.9 is the value tested, so [tex]\sigma_0 = 0.9, \sigma_0^2 = 0.81[/tex]

What is the value of the test statistic

[tex]\chi^2 = \frac{n-1}{\sigma_0^2}s^2[/tex]

[tex]\chi^2 = \frac{44}{0.81}1.1 = 59.75[/tex]

The value of the test statistic is 59.75.

Answer:

R12

Step-by-step explanation:

Answer: R12

Explanation:

Cost of 1 loaf = R6

Cost of 4 halves = 6/2×4

= 6 × 2

= R12

Please click thanks and mark brainliest if you like

Answer:

Step-by-step explanation:

2|x-1|+5 < 13

2|x-1| < 8

|x-1| < 4

-4 < x-1 < 4

-3 < x < 5

Answer:

$54.32

Step-by-step explanation:

19=$36.48/19 =1.94

1=$1.94 * 28= 54.32

28=54.32

Answer:

4x+8 +3x - 6 + 3x

10x + 8 - 6

10x + 2

Answer:

3x-2+2x+1+X

3x+2x+x-2+1

6x-1

Step-by-step explanation:

a) The volume of the prism is

[tex]V = (n^2 - 1)×(n^2 - 1)×(5n)[/tex]

[tex]\:\:\:\:= (n^4 - 2n^2 + 1)(5n)[/tex]

[tex]\:\:\:\:=5n^5 - 10n^3 + 5n[/tex]

b) If the dimensions L of the prism are tripled, the new volume will be

[tex]V' = (3L)^3 = 27L^3 = 27V[/tex]

so it will increase by a factor of 27.

Answer:

640

Step-by-step explanation:

muntiply all the number length width height

Hey there!

[tex]\mathsf{x^{-2}}[/tex]

[tex]\mathsf{= -3^{-2}}[/tex]

[tex]\mathsf{= -1 \times 3^{-2}}[/tex]

[tex]\mathsf{3^{-2}}[/tex]

[tex]\mathsf{= \dfrac{1}{3\times3}}[/tex]

[tex]\mathsf{= -1 \times \dfrac{1}{3\times3}}[/tex]

[tex]\mathsf{= -\dfrac{1}{3\times3}}[/tex]

[tex]\mathsf{3\times 3}[/tex]

[tex]\mathsf{= 3^2}[/tex]

[tex]\mathsf{= - \dfrac{1}{3^2}}[/tex]

[tex]\mathsf{3^2}[/tex]

[tex]\mathsf{= 3 \times 3}[/tex]

[tex]\mathsf{= \bf 9}[/tex]

[tex]\mathsf{-\bf \dfrac{1}{9}}[/tex]

[tex]\boxed{\boxed{\huge\text{Answer: }\boxed{\bf - \dfrac{1}{9}}}}}\huge\checkmark[/tex]

[tex]\huge\text{Good luck on your assignment \& enjoy your day!}[/tex]

~[tex]\frak{Amphitrite1040:)}[/tex]