Answer:
[tex]C. \ \ \ 86[/tex]°
Step-by-step explanation:
1. Approach
In order to solve this problem, one must first find a relationship between arc (a) and arc (c). This can be done using the congruent arcs cut congruent segments theorem. After doing so, one can then use the secants interior angle to find the precise measurement of arc (a).
2. Arc (a) and arc (c)
A secant is a line or line segment that intersects a circle in two places. The congruent segments cut congruent arcs theorem states that when two secants are congruent, meaning the part of the secant that is within the circle is congruent to another part of a secant that is within that same circle, the arcs surrounding the congruent secants are congruent. Applying this theorem to the given situation, one can state the following:
[tex]a = c[/tex]
3. Finding the degree measure of arc (a),
The secants interior angle theorem states that when two secants intersect inside of a circle, the measure of any of the angles formed is equal to half of the sum of the arcs surrounding the angles. One can apply this here by stating the following:
[tex]86=\frac{a+c}{2}[/tex]
Substitute,
[tex]86=\frac{a+c}{2}[/tex]
[tex]86=\frac{a+a}{2}[/tex]
Simplify,
[tex]86=\frac{a+a}{2}[/tex]
[tex]86=\frac{2a}{2}[/tex]
[tex]86=a[/tex]
The probability that a graduate of the Faculty of Finance will defend the diploma “excellent” is 0.6. The probability that he will defend his diploma “perfectly” and receive an invitation to work at the bank is 0.4. Suppose a student defends a diploma. Find the probability that he will receive an invitation to work in a bank?
The probability that he receives an invitation to work in a bank given that he defends his diploma excellently is [tex]\mathbf{0. \overline 6}[/tex]
The reason for the above probability value is as follows;
The known parameters are;
The probability that a graduate of the Faculty of Finance will defend the diploma excellently, P(A) = 0.6
The probability that he will defend perfectly and receive an invitation to work at a bank, P(A∩B) = 0.4
The unknown parameter is;
The probability that the student will receive an invitation from the bank given that the student defend the diploma excellent, [tex]\mathbf {P(B \ | \ A)}[/tex]
The process;
[tex]\mathbf{ P(B \ | \ A)}[/tex] is found using the conditional probability formula as follows;
[tex]\mathbf {P(B \ | \ A) = \dfrac{P(A \cap B) }{P(A)}}[/tex]
Plugging in the values, we get;
[tex]P(B \ | \ A) = \dfrac{0.4 }{0.6} = \dfrac{2}{3} = 0. \overline 6[/tex]
The probability that the student will receive an invitation from the bank given that the student defend the diploma excellent, [tex]P(B \ | \ A)[/tex] = [tex]\mathbf {0. \overline 6}[/tex]
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construct a rectangle PQRS, In which AB= 8cm and diagonal AC= 10cm
A rectangle can be constructed using a straightedge, and a setsquare or compass
Please find attached the drawing of rectangle ABCD
The steps to construct the rectangle ABCD are as follows:
Question:
The missing part of the question is the name of the rectangle = ABCD
The given parameters are;
The length of the side AB = 8 cm
The length of the diagonal of the rectangle ABCD = AC = 10 cm
The steps to construct a rectangle are;
Draw the segment [tex]\overline{AB}[/tex] = 8 cm on a planeDraw perpendicular lines at points A and B with length h given by Pythagoras's theorem as followsh² = [tex]\overline{AC}[/tex]² - [tex]\overline{AB}[/tex]²
∴ h² = 10² - 8² = 36
h = √36 = 6
h = 6 cm = The length of the sides [tex]\mathbf{\overline{AD}}[/tex] and [tex]\mathbf{\overline{CB}}[/tex]
Draw arcs with radius 6 cm from points A and B to intersect the perpendicular lines drawn from points A and B on the same side of the line [tex]\overline{AB}[/tex] at points D and CJoint point C to D with a straight line which is segment [tex]\overline{CD}[/tex] and which completes the rectangle ABCDLearn more about the construction of basic shapes here;
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evaluate -7x^2 -5 + y^2- forx = -2, y=4
Answer:
The (y^2 ) or (y^–2) It is not clear, I solved it in both ways (y^2) and (y^-2) .^_^
[tex] - 7 {x }^{2} - 5 + {y}^{2} \\ - 7( { - 2}^{2} ) - 5 + {4}^{2} \\ - 7( - 4) - 5 + 16 \\ 28 - 5 + 16 \\ = 39[/tex]
_______o_____o_______
[tex] - 7 {x }^{2} - 5 + {y}^{ - 2} \\ - 7( { - 2}^{2} ) - 5 + {4}^{ - 2} \\ - 7( - 4) - 5 + \frac{1}{16} \\ 28 - 5 + \frac{1}{16} \\ = 23.06[/tex]
I hope I helped you^_^
Select all the correct answers.
Consider functions fand g.
f(x) = 4(x – 3)2 + 6
g(x) = -2(x + 1)2 + 4
Which statements are true about the relationship between the functions?
The vertex of function gis 4 units to the left of the vertex of function f.
The vertex of function gis 2 units below the vertex of function f.
Function gopens in the same direction as function f.
Function gopens in the opposite direction of function f.
The vertex of function gis 2 units above the vertex of function fi
vertex of function gis 4 units to the right of the vertex of function f.
Answer:
Step-by-step explanation:
f(x) = 4(x-3)² + 6
Up-opening parabola with vertex (3, 6)
g(x) = -2(x+1)² + 4
Down-opening parabola with vertex (-1,4)
A. True
B. True
C. False
D. True
E. False
F. False
The correct statements are:
"The vertex of function g is 4 units to the left of the vertex of function f.""The vertex of function g is 2 units below the vertex of function f.""Function gopens in the opposite direction of function f."Which statements are true about te functions?Here we have the two quadratic functions:
f(x) = 4*(x - 3)^2 + 6g(x) = -2*(x + 1)^2 + 4The x-value of the vertex is the value of x such that the first term becomes equal to zero, so for f(x) the vertex is at x = 3, and the y-value of the vertex is:
f(3) = 0 + 6 = 6
So the vertex is (3, 6)
For g(x) we can see that the vertex is at x = -1, and:
g(-1) = 0 + 4
So the vertex is at (-1, 4)
Also, you can see that for g(x) and f(x) the leading coefficients are of different sign. Meaning that f(x) opens upwards and g(x) opens downwards.
Now that we know the two vertices, we can see that the correct options are:
"The vertex of function g is 4 units to the left of the vertex of function f."
"The vertex of function gis 2 units below the vertex of function f."
"Function gopens in the opposite direction of function f."
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What is log10^6, considering log10^2=a and log10^3=b?
The answer is simply just a+b.
Solution:
log10^6=log10^2+log10^3
Since log10^2=a and log10^3=b,
The answer is a+b.
I think that the answer is a+b.
Click on the picture for the answer
Answer:
the answer is 1/14
hope this helps you
9514 1404 393
Answer:
(a) 1/14
Step-by-step explanation:
Fractions are multiplied by multiplying numerators and denominators. They are reduced by cancelling common factors. When a product has an even number of minus signs, it is positive.
[tex]\left(-\dfrac{3}{7}\right)\cdot\left(-\dfrac{1}{6}\right)=\dfrac{(-3)(-1)}{7\cdot6}=\dfrac{3}{7\cdot2\cdot3}=\dfrac{1}{7\cdot2}=\boxed{\dfrac{1}{14}}[/tex]
Read image for instructions
The last part answers the first part for you, just look at the y-values.
In other words:
A' (-8, 2)
B' (-4, 3)
C' (-2, 8)
D' (-10, 6)
Explanation:
When you reflect any point over the x-axis, the y-value of the ordered pair is going to change.
This makes sense especially considering that the x-axis is horizontal, so the only way you could cross is to move up or down. If you were to move left or right, you'd only be able to cross the y-axis, since it's vertical.
Now for the last part, as I mentioned above, if you are reflecting across the y-axis, the x-values of the ordered pair is going to change.
A'' (8, 2)
B'' (4, 3)
C'' (2, 8)
D'' (10, 6)
Take note that the only thing that changes for the respective value is its sign, while the number itself stays the same.
Assume the population of regulation basketball weights are normally distributed with a mean of 22 and a standard deviation of 1 ounce. If a sample of 100 regulation basketballs is taken, what is the probability that its sample mean will be greater than 22.2 ounces
Answer: 0.0228
Step-by-step explanation:
please check photo explanation
The probability that the sample mean will be greater than 22.2 ounces will be equal to 0.0228
What is probability?Probability is calculated as the proportion of favorable events to all potential scenarios of an event. The proportion of positive results, or x, for an experiment with 'n' outcomes can be expressed.
As per the given values in the question,
[tex]\mu_x[/tex] = 22
σ(x) = σ/√n
= 1/√100
σ(x) = 0.1
P(x>22.2) = 1- P(x<22.2)
= 1- P(x × μ(x))/ σ(x) < (22.2 - 22)/0.1
1 - P (z < 2.00)
1- 0.9772
= 0.0228
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I will mark as brainliest:)
Answer:
Cube C
Step-by-step explanation:
[tex]{ \sf{because \: it \: is \: identical}}[/tex]
what is the inverse of y=3x+3?
Answer:
The inverse is x/3 -1
Step-by-step explanation:
y = 3x+3
To find the inverse, exchange x and y
x = 3y+3
Solve for y
x-3 =3y+3-3
x-3 = 3y
Divide by 3
x/3 - 3/3 = 3y/3
x/3 -1 = y
The inverse is x/3 -1
0.18 divided by 0.04
9(5x + 1) ÷ 3y
From the expression above, provide an example of each of the following: sum, term, product, factor, quotient, and coefficient. If any are not present, write "not present." (ill give brainiest and if there is any troll answers I will report and take this down )
Answer
3y(5x+1)
Step-by-step explanation:
9*(5x+1)/3y
3(5x+1)y
Answer:
Step-by-step explanation:
sum: 5x + 1
factor: 3 which divides into 9 evenly
quotient: the answer to division: 9(5x + 1)/(3y) = 3(5x +1)/y
coefficent: this depends on what you have been told. In my day, there were two kinds of coefficents
numerical: 5 and 3
literal: x and y
Convert 4.206 m into mm
Answer:
4206 is the answer of this question
Answer:
I think it will help you a lot.
Find f(-1) given f(x) = –2x^3 + 3x^2 – 22
[tex]\\ \sf\longmapsto f(-1)[/tex]
[tex]\\ \sf\longmapsto -2x^3+3x^2-22[/tex]
[tex]\\ \sf\longmapsto -2(-1)^3+3(-1)^2-22[/tex]
[tex]\\ \sf\longmapsto -2(-1)+3(1)-22[/tex]
[tex]\\ \sf\longmapsto 2+3-22[/tex]
[tex]\\ \sf\longmapsto 5-22[/tex]
[tex]\\ \sf\longmapsto -17[/tex]
A(3, 7), B(5, 7), C(3-7), D(5, -7)
what is the area ?
Answer:
28 square units.
Step-by-step explanation:
This is a rectangle with sides (7 - (-7) and (5 - 3)
= 14 by 2
= 28 unit^2.
Taylor wants to find the perimeter of a rectangular playground. The lenght of the playground measures (3x-20) metres. The width of the playground measures (2x+4) metres. What is the perimeter of the playground?
Answer:
Step-by-step explanation:
P = 2(3x-20) + 2(2x+4) = (6x-40) + (4x+8) = 10x-32
The required perimeter of the playground is 10x-32.
The length of the playground measures (3x-20) metres.
The width of the playground measures (2x+4) metres.
What is the perimeter?
Perimeter, is the measure of the figure on its circumference.
The Required perimeter is for the playground is given by
= 2(3x-20) + 2(2x+4)
= 10x-32
Thus the required perimeter of the playground is 10x-32.
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Business/multivariable calc question
help needed asap!!!!
Answer:
There is a min value of 376 located at (x,y) = (9,7)
============================================================
Explanation:
Solve the second equation for y
x+y = 16
y = 16-x
Then plug it into the first equation
f(x,y) = 3x^2+4y^2 - xy
g(x) = 3x^2+4(16-x)^2 - x(16-x)
g(x) = 3x^2+4(256 - 32x + x^2) - 16x + x^2
g(x) = 3x^2+1024 - 128x + 4x^2 - 16x + x^2
g(x) = 8x^2-144x+1024
The positive leading coefficient 8 tells us we have a parabola that opens upward, and produces a minimum value (aka lowest point) at the vertex.
Let's compute the derivative and set it equal to zero to solve for x.
g(x) = 8x^2-144x+1024
g ' (x) = 16x-144
16x-144 = 0
16x = 144
x = 144/16
x = 9
The min value occurs when x = 9. Let's find its paired y value.
y = 16-x
y = 16-9
y = 7
The min value occurs at (x,y) = (9,7)
Lastly, let's find the actual min value of f(x,y).
f(x,y) = 3x^2+4y^2 - xy
f(9,7) = 3(9)^2+4(7)^2 - 9*7
f(9,7) = 376
The smallest f(x,y) value is 376.
determine whether the lines are parallel or not with proper reasons.
Answer:
Parallel
Step-by-step explanation:
Because of interior alternate angles
Angle ARS and Angle BRS are Interior alternate angles in this case ..
Suppose that the manufacturer of a gas clothes dryer has found that, when the unit price is p dollars, the revenue R (in dollars) is R(P) = - 8p^2 + 24,000p. What unit
price should be established for the dryer to maximize revenue? What is the maximum revenue?
The unit price that should be established to maximize revenue is $|
(Simplify your answer.)
Here we have a problem of maximization and quadratic equations.
The unit prize that maximizes the revenue is $1,500, and the maximum revenue is $18,000.
We know that the revenue equation is:
R(P) = - 8p^2 + 24,000p
Where the variable p is the price.
Now we want to find the value of p that maximizes the revenue.
To do it, we can see that the revenue equation is a quadratic equation with a negative leading coefficient.
This means that the arms of the graph will go downwards, then the maximum point of the graph will be at the vertex.
Remember that for an equation like:
y = a*x^2 + b*x+ c
The x-value of the vertex is at:
x = -b/(2*a)
Then for the equation:
R(P) = - 8p^2 + 24,000p
The vertex is at:
p = -(24,000)/(2*-8) = 1,500
The value of p that maximizes the revenue is p = $1,500
To get the maximum revenue, we need to evaluate the revenue equation in that p value.
R(1,500) = - 8*(1,500)^2 + 24,000*1,500 = 18,000
And the revenue equation is in dollars, then the maximum revenue is 18,000 dollars.
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p = 1500 $ the unit price
R(p) = 18000000 $ maximum revenue
We will use two different procedures to calculate the maximum revenue.
That is equivalent to solve the problem and after that to test the solution
The first one is:
R(p) = - 8*p² + 24000*p
we realize that R(p) is a quadratic function ( a parabola) of the form:
y = a*x² + b*x + c ( c = 0 in this case)
We also know that as the coefficient of p² is negative the parabola opens downwards then the vertex is a maximum value for R(p), and the x coordinate of p is:
x = p = - b/2*a then by substitution
p = - ( 24000)/ 2 ( - 8)
p = 1500 $ and for that value of p
R(p) = - 8 ( 1500)² + 24000* (1500) = - 18000000 + 36000000
R(p) = 18000000 $
The second procedure is solving with the help of derivatives.
R(p) = - 8*p² + 24000*p
Tacking derivatives on both sides of the equation we get:
R´(p) = -16p + 24000
If R´(p) = 0 then -16p + 24000 = 0
p = 24000/ 16 p = 1500
if we check for the second derivative
R´´(p) = -16 -16 < 0 therefore there is a maximum value for R(p) when p = 1500, and that value is:
By substitution in R(p)
R(p) = -8 *(1500)² + 24000* 1500
R(p) = - 18000000 + 36000000
R(p) = 18000000 $
give ABCD is a trapizod , Ab = 13, CD= 14, BC = 15, and AD = 20 what is the area
Step-by-step explanation:
A=140sq. units
Step-by-step explanation:
ABCD
A=13
B=15
C=14
D=20
C=14×14
=196sqr.units
the mode of 3,5,1,2,4,6,0,2,2,3 is
giving out brainliest
find coordinate of a point on x axis which is at a distance of 5 units from (5,4)
Step-by-step explanation:
Hi there!
Please see attached picture for your answer.
Hope it helps!
May I get some help with this question?
Find the slope of the line containing the points (7,5) and (2, 4).
Answer:
1/5
Step-by-step explanation:
the two points are(7,5) and (2,4)
let,(x1,y1)=(7,5) and (x2,y2)=(2,4)
slope (m)=y2-y1/x2-x1
=4-5/2-7
=-1/-5
=1/5(minus ,minus are cut)
13.) Jessica earns 5 points for every assignment she completes, plus 15 points just for being in class on a given day. How many assignments does she need to complete to earn 65 points? First, write the equation that fits this model. Let z be the amount of assignments completed. *
Answer:
10
5z+15=65
Step-by-step explanation:
5z+15=65
5(10)+15=65
Complete the square to evaluate the definite integral
∫dx/x^2-2x+5
Bounds:1-3
[tex]\displaystyle \int_1^3 \frac{\mathrm dx}{x^2-2x+5}[/tex]
Follow the instruction and complete the square in the denominator:
x ² - 2x + 5 = (x ² - 2x + 1) + 4 = (x - 1)² + 4
Then the integral is
[tex]\displaystyle \int_{x=1}^{x=3} \frac{\mathrm dx}{(x-1)^2+4}[/tex]
Substitute y = x - 1 and dy = dx :
[tex]\displaystyle \int_{y+1=1}^{y+1=3} \frac{\mathrm dy}{y^2+4} = \int_{y=0}^{y=2}\frac{\mathrm dy}{y^2+4}[/tex]
Substitute y = 2 tan(z) and dy = 2 sec²(z) dz :
[tex]\displaystyle \int_{2\tan(z)=0}^{2\tan(z)=2}\frac{2\sec^2(z)}{(2\tan(z))^2+4}\,\mathrm dz = \frac12 \int_{z=0}^{z=\pi/4} \frac{\sec^2(z)}{\tan^2(z)+1}\,\mathrm dz \\\\ = \frac12 \int_{z=0}^{z=\pi/4} \frac{\sec^2(z)}{\sec^2(z)}\,\mathrm dz \\\\ = \frac12 \int_{z=0}^{z=\pi/4} \mathrm dz = \frac12 z\bigg|_{z=0}^{z=\pi/4} = \frac12 \left(\frac\pi4-0\right) = \boxed{\frac\pi8}[/tex]
Armando's carpet has an area of 220 square feet. He hires the Carpet Pro carpet cleaning service, which is able to clean 9 square feet of his carpet every minute. Therefore, in the first minute, CarpetPro is able to clean 9 square feet of Armando's carpet (leaving 211 square feet remaining to be cleaned). In the second minute, the cleaner is again able to clean 9 square feet of carpet (leaving 202 square feet to be cleaned), etc. Which of the following functions expresses the number of square feet that still remain to be cleaned after t minutes from the time that the carpet cleaner began cleaning this carpet.
a. A(t) = 220 - 9
b. A(t) = 220 - 0.1
c. A(t) = 220(0.1)
d. A(t) = 220(0.96)
e. A(t) 220 - 0.96
Answer:
The answer is A
Step-by-step explanation:
The answer needs to be in slope-intercept form or y=mx+b because the amount of carpet being cleaned every minute is a constant decrease of 9 square feet.
So our b value (or how much carpet cleaned at 0 minutes) is 220
And our m value (or slope or how much carpet is being cleaned every minute) is 9
So if we plug the variables with the tangible numbers we get A(t) = -9x+220 or A(t) = 220-9x.
provided by gauth math
I need to find the distance B in the special counter sink shown
Answer:
Step-by-step explanation:
87°32' = 86°92'
(86°92')/2 = 43°46'
B = 13/(16cos(43°46')) = 1.125
Answer:
Step-by-step explanation:
Simplify i^38 ????????
Answer:
i is defined as the square root of -1.
i^2 = -1
i^3 = -i
i^4 = 1
Following the pattern, we see that i^40 = 1, so i^38 is two above, or equal to -1.
So, i^38 = -1.
Let me know if this helps!
Dividing integers
7. (-154) ➗ (-14) =
11. (-40) ➗10=
15. 90 ➗ (-15)=
16. 108 ➗ (-9)=
17. (-48) ➗ (-6)=
18. (-105) ➗ 7=
first we shall learn the rules.when numbers with same sign are divided it gives pisitive sign but, when numbers of different signs are divided it gives negetive sign.
here,
7. (-154) ➗ (-14) =11
11. (-40) ➗10=-4
15. 90 ➗ (-15)=-6
16. 108 ➗ (-9)=-12
17. (-48) ➗ (-6)=8
18. (-105) ➗ 7=-15
hope it helps you..........