Find the transpose of AB​

Step-by-step explanation:

Let the price of CD, tshirt and jeans be x,y and z respectively.

given:

x+2y+2z=133......(i)

y=x+13.......(ii)

2z=y+30....(iii)

in eqn (iii) ,

2z=y+30

or, 2z=x+13+30

or, z=(x+43)/2....(iv)

now in eqn (i),

x+2y+2z=133

or, x+2(x+13)+2((x+43)/2) =133

or, x+2x+26+x+43=133

or, 4x=133-69

or, x= 64/4

•°• x=$16

Answer:

Step-by-step explanation:

Charlotte starts at 19 years old.

Rachel starts at 24 years old.

Then two years later, Rachel is 26 and Charlotte is 21. This is not 3 times Charlotte's age.

Do you have all the right info?

Answer:

Regular Polygons are never concave by definition.

Step-by-step explanation:

Answer:

g − 1 ( x ) =  x/ 5 +  2

Step-by-step explanation:

See the pic for solutions :)

Answer:

Step-by-step explanation:

First number is 1/10

Last letter is 1/26

The second digit is 1/9

The first letter is 1/25

1/10 * 1/26 * 1/9 * 1/25

0.00001709

This assumes no duplication is allowed,

If there are duplications

then 1/10 * 1/10 * 1/26 * 1/26

0.000014782

Answer:

The sample size must be of 47,059,600.

Step-by-step explanation:

We have to find our [tex]\alpha[/tex] level, that is the subtraction of 1 by the confidence interval divided by 2. So:

[tex]\alpha = \frac{1 - 0.95}{2} = 0.025[/tex]

Now, we have to find z in the Z-table as such z has a p-value of [tex]1 - \alpha[/tex].

That is z with a p-value of [tex]1 - 0.025 = 0.975[/tex], so Z = 1.96.

Now, find the margin of error M as such

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

In which [tex]\sigma[/tex] is the standard deviation of the population and n is the size of the sample.

Standard deviation:

[tex]\sigma = 3.5[/tex]

If you want the error bound E of a 95% confidence interval to be less than 0.001, how large must the sample size n be?

This is n for which M = 0.001. So

[tex]M = z\frac{\sigma}{\sqrt{n}}[/tex]

[tex]0.001 = 1.96\frac{3.5}{\sqrt{n}}[/tex]

[tex]0.001\sqrt{n} = 1.96*3.5[/tex]

[tex]\sqrt{n} = \frac{1.96*3.5}{0.001}[/tex]

[tex](\sqrt{n})^2 = (\frac{1.96*3.5}{0.001})^2[/tex]

[tex]n = 47059600[/tex]

The sample size must be of 47,059,600.

Answer:

[tex](a)\ V = \{(N,30),(R,37),(S,17)\}[/tex]

[tex](b)[/tex]

[tex]Domain = \{N,R,S\}[/tex]

[tex]Range = \{37,30,17\}[/tex]

Step-by-step explanation:

Given

[tex]V(R) = 37,\ V(N) = 30,\ V(S) = 17[/tex]

Solving (a): Set of ordered pair

A function y = f(x) is represented as (x,y)

So, the ordered pair of V is:

[tex]V = \{(R,37),(N,30),(S,17)\}[/tex]

Order the alphabets in increasing order

[tex]V = \{(N,30),(R,37),(S,17)\}[/tex]

Solving (b): The domain and the range

In a function [tex]\{(x_1,y_1),...,(x_n,y_n)\}[/tex]

The domain and the range are represented as:

[tex]Domain = \{x_1,x_2....x_n\}[/tex]

[tex]Range = \{y_1,y_2....y_n\}[/tex]

So, we have:

[tex]Domain = \{N,R,S\}[/tex]

[tex]Range = \{37,30,17\}[/tex]

Answer: I think the answer is A

Step-by-step explanation:

9514 1404 393

Answer:

  B. (0, –2)

Step-by-step explanation:

Put the (x, y) values into the given formula.

  (x, y) ⇒ (x +5, y -2)

  B(-5, 0) ⇒ B'(-5+5, 0-2) = B'(0, -2)

Answer:

$9

Step-by-step explanation:

30*(100%-70%)=9

Answer:

9

Step-by-step explanation:

Take the original price

Multiply by the discount percent

30 *70%

30 *.70

21

The discount is 21 percent

Subtract this from the original amount

30-21

9

The PERCENTAGE ANNUAL RATE is 9.0% to the nearest tenth using the SIMPLE INTEREST FORMULA

The question is related to a SIMPLE INTEREST problem:

Loan period = 60 days

using 365 days a year ;

converting to years , 60 days = (60 / 365) years

interest on loan = 73.97

principal = 5000

Using the formula:

interest = (principal * rate * time)

73.79 = (5000 * rate * (60/365)

Rate = 73.79/(5000 * (60/365)) =8.977%

rate = 9%

Therefore, PERCENTAGE ANNUAL RATE is 9.0%

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Answer:

It's a negative.

Step-by-step explanation:

The value of a positive number is still a positive number.

Answer:

[tex](f-g)(4) = -59[/tex]

Step-by-step explanation:

We are given the two functions:

[tex]f(x)=4x-3\text{ and } g(x) = x^3 +2x[/tex]

And we want to find the value of:

[tex](f-g)(4)[/tex]

Recall that this is equivalent to:

[tex](f-g)(4) = f(4) - g(4)[/tex]

Find f(4):

[tex]f(4) = 4(4)-3 = 13[/tex]

And find g(4):

[tex]g(4) = (4)^3 + 2(4) =72[/tex]

Substitute:

[tex](f-g)(4) = (13)-(72)[/tex]

And subtract. Hence:

[tex](f-g)(4) = -59[/tex]

Step-by-step explanation:

I love this question!

So there are a couple different ways of solving this. You feel free to ignore whichever one makes less sense.

Subtracting First

The first option is taking f(x) and g(x) and subtracting them, then introducing the number.

The calculation:

f(x) - g(x)

Substitute.

4x - 3 - (x^3 + 2x)

Multiply out the negative.

4x - 3 - x^3 - 2x

Rewrite.

-x^3 + 4x - 2x - 3

Simplify.

-x^3 + 2x - 3

Then, replace x with 4.

-(4)^3 + 2(4) - 3

Simplify.

-64 + 8 - 3

Add.

-59

Making x = 4 first

Here, we'll do what's on the tin. Find f(4) and g(4), then subtract them.

f(x) = 4x - 3

f(4) = 4(4) - 3

f(4) = 16 - 3

f(4) = 13

Then find g(4):

g(x) = x^3 + 2x

g(4) = (4)^3 + 2(4)

g(4) = 64 + 8

g(4) = 72

Then, subtract these two:

f(4) - g(4) = 13 - 72

f(4) - g(4) = -59

Answer:

Either way, the answer is -59

Answer:

6

Step-by-step explanation:

21-20 = 1

20-18 =2

18 -15 = 3

15-11 = 4

We are subtracting 1 more each time

11-5 = 6

Answer:

384 cubic inches

Step-by-step explanation:

first find the volume of the fish tank by multipying the length, width, and height.

v=lwh

 =(16in)(4in)(12in)

 = 768 cubic inches (This answer is equal to the volume of the entire fish tank, however we need to find how much water half the tank can hold. To figure this out, we need to divide 768 by 2. And you should get 384 cubic inches)

Answer:

384

Step-by-step explanation:

took the quiz

a-7=3(b+2)

1. Simplify/Combine like terms

a-7=3b+6

2. Remove a variable

a-7-a=3b+6-a

7=2b+6

3. Isolate the variable

7-6=2b-6

1=2b

4. Divide

1/2=2b/2

b=1/2

1/2g?

Answer:

[tex]Pr= \frac{1}{21}[/tex]

Step-by-step explanation:

Given

[tex]n(S) = 7[/tex] --- number of games

Required

Probability of bike and movie in consecutive order

This probability is represented as:

[tex]Pr = P(Bike\ and\ Movie) \ or\ P(Movie\ or\ Bike)[/tex]

So, we have:

[tex]Pr = P(Bike\ and\ Movie) \ +\ P(Movie\ or\ Bike)[/tex]

The probability is an illustration of selection without replacement;

So, we have:

[tex]P(Bike\ and\ Movie) = P(Bike) * P(Movie)[/tex]

[tex]P(Bike\ and\ Movie) = \frac{n(Bike)}{n(S)} * \frac{n(Movie)}{n(S) - 1}[/tex] ---- without replacement

Bike and Movie appear in the game list 1 time.

So, the equation becomes

[tex]P(Bike\ and\ Movie) = \frac{1}{7} * \frac{1}{7 - 1}[/tex]

[tex]P(Bike\ and\ Movie) = \frac{1}{7} * \frac{1}{6}[/tex]

[tex]P(Bike\ and\ Movie) = \frac{1}{42}[/tex]

Similarly,

[tex]P(Movie\ and\ Bike) = \frac{1}{42}[/tex]

So, we have:

[tex]Pr = P(Bike\ and\ Movie) \ +\ P(Movie\ or\ Bike)[/tex]

[tex]Pr= \frac{1}{42}+\frac{1}{42}[/tex]

Take LCM

[tex]Pr= \frac{1+1}{42}[/tex]

[tex]Pr= \frac{2}{42}[/tex]

[tex]Pr= \frac{1}{21}[/tex]

Answer:

5≤x≤7

Step-by-step explanation:

For a given function f(x), the average rate of change in a given interval:

a ≤ x ≤ b

is given by:

[tex]r = \frac{f(b) - f(a)}{b - a}[/tex]

Here we have:

f(x) = 4*log(x + 2)

And we want to see which interval has the smallest average rate of change, so we just need fo find the average rate of change for these 4 intervals.

1)  1≤x≤3

here we have:

[tex]r = \frac{f(3) - f(1)}{3 - 1} = \frac{4*log(3 + 2) - 4*log(1 + 2)}{2} = 0.44[/tex]

2)  5≤x≤7

[tex]r = \frac{f(7) - f(5)}{7 - 5} = \frac{4*log(7 + 2) - 4*log(5 + 2)}{2} = 0.22[/tex]

3) 3≤x≤5

[tex]r = \frac{f(5) - f(3)}{5 - 3} = \frac{4*log(5 + 2) - 4*log(3 + 2)}{2} = 0.29[/tex]

4) −1≤x≤1

[tex]r = \frac{f(1) - f(-1)}{1 - (-1)} = \frac{4*log(1 + 2) - 4*log(-1 + 2)}{2} = 0.95[/tex]

So we can see that the smalles average rate of change is in 5≤x≤7

There will be about 6.25 sheep on each acre.  

250/40 = 6.25

Answer:

The first droplet will hit the ground after about 1.54 seconds.

The second droplet will hit the ground after about 1.6 seconds.

Thus, the first hits the ground first.

Step-by-step explanation:

We are given the function:

[tex]y=-16r^2 + 38[/tex]

Which represents the height y in feet of a water droplet t seconds after falling from an icicle.

Part A)

We want to find the time it took for the water droplet to hit the ground.

When it hit the ground, its height y above ground will be zero. Therefore, we can let y = 0 and solve for r:

[tex]0=-16r^2+38[/tex]

Subtract 38 from both sides:

[tex]-38 = -16 r^2[/tex]

Divide:

[tex]\displaystyle r^2 = \frac{38}{16} = \frac{19}{8}[/tex]

And take the principal square root of both sides:

[tex]\displaystyle r= \sqrt{\frac{19}{8}} = \frac{\sqrt{38}}{4} \approx1.54\text{ seconds}[/tex]

So, the first water droplet hits the ground after about 1.54 seconds.

Part B)

We want to determine how long it will take for a water droplet to hit the ground from a height of 41 feet.

From the original equation, if r = 0, then y = 38. So, the initial height was 38 feet.

Then we can modify the function into:

[tex]y= -16r^2 + 41[/tex]

In this case, when r = 0, the starting height y is 41 feet.

Again, let y = 0 and solve for r:

[tex]0 = -16r^2 + 41[/tex]

Isolate:

[tex]\displaystyle r^2 = \frac{41}{16}[/tex]

And take the principal square root of both sides:

[tex]\displaystyle r = \sqrt{\frac{41}{16}} = \frac{\sqrt{41}}{4} \approx 1.6\text{ seconds}[/tex]

So, the second drop will hit the ground after approximately 1.6 seconds.

And in conclusion, the first drop will hit the ground sooner (as expected).

Answer:

The number of flowers on the plant

Step-by-step explanation:

Answer:

C: Number of flowers on the plant

Step-by-step explanation:

i got it right on my test

this the answer of queastions

Step-by-step explanation:

67.18,68.82

Let mu be the true population mean of statistics exam scores. We have a large random samples of n=36 scores with a sample mean of 68.we know that the population standard deviation is sigma=3.A pivotal quantity is 3^sqrt(36)=(3/6)=68(1/2) which is approximately normally distributed. Therefore the 85%confidence interval is 68-(1/2)(1.6449), 68+(1/2)(1.6449) i.e (67.18,68.82)

Answer:

15km

Step-by-step explanation:

hope it is well understood?

Answer:

5 times.

Step-by-step explanation:

First, look at the values of each line at the 1-hour mark.

For line A (the bicyclist), the distance is about 25 km.

For line B (the pedestrian), the distance is about 5 km.

To determine how many times greater the bicyclist distance is than the pedestrian, divide the values:

[tex]\frac{25\text{km}}{5\text{km}}=5[/tex]

Therefore, the distance covered by the bicyclist for 1 hour is 5 times greater than the distance covered by the pedestrian for the same amount of time.

Answer:

3rd option

Step-by-step explanation:

(1/2)^-2t

= (2^-1)^-2t

= 2^2t

= (2^2)^t

Answered by GAUTHMATH

Answer: 10m, 33m, and 29m

Step-by-step explanation:

n + 3n+3 + 3n-1 = 72m

7n+2=72m

7n = 72-2

n = 70/7

n = 10

Answer:

1/2

Step-by-step explanation:

Number of bags = 3

number of bags with $10 bill initially = 2

number of bags with $5 bill initially = 1

assume :

event you pick a $5 bill at first draw = A

event you pick a $5 bill at second draw = B

hence : P ( A n B ) = 1/3 * 1 = 1/3

P( A ) = ( 1/3 * 1 ) + ( 1/3 * 1/2 + 1/3 * 1/2 )  = 2/3

therefore P( that the second drawn bill is $5 )

P( B | A ) = P(A n B ) / P ( A )

              = (1/3) / (2/3) = 1/2

The probability that it, too, is a $ 5 bill is 33.33%.

Since you have 3 bags, and two of them contain a single $ 10 bill, and the third contains a single $ 5 bill, supposing you pick one of these bags uniformly at random and you then add a $ 5 bill to the bag, so it now contains two bills, and the bag is shaken, and you randomly draw a bill from the bag without looking into the bag, supposing it turns out to be a $ 5 bill, if a you draw the remaining bill from the bag, to determine what is the probability that it, too, is a $ 5 bill, the following calculation must be performed:

Therefore, the probability that it, too, is a $ 5 bill is 33.33%.

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