Find the distance between points (a,b) and Q -a,-b)​

Answers

Answer 1

Answer:

d = 2* sqrt(a^2 + b^2)

Step-by-step explanation:

Interesting question. You should begin by noting that 0 is not the answer although it looks like it should be.

P = (a,b)

Q= (-a,-b)

x1 = a

x2 = - a

y1 = b

y2 = - b

d = sqrt( (x2 - x1)^2 + (y2 - y1)^2 )

d = sqrt( (-a - a)^2 + (-b - b)^2  )

d = sqrt ( -2a)^2 + - (2b)^2 )

d = sqrt(4a^2 + 4b^3)

d = 2* sqrt(a^2 + b^2)


Related Questions

find the missing side of the triangle.​

Answers

Answer:

34

Step-by-step explanation:

x² = 30² + 16²

(pythagoras theorem)

x = Square root 30² + 16²

x = 34

Pythagorean theorem
A^2 + B^2 = C^2
30^2 + 16^2 = C^2
1156 = c^2
Square root of 1156 = c
C = 34
Therefore x = 34

A jar contains 5 blue marbles, 2 black marbles, and 7 brown marbles.

Answers

Answer:

5/13

five blue marbles, but one blue removed  thus 5/13

Step-by-step explanation:

Answer:

C 5/13

Step-by-step explanation:

Can you help me out plz

Answers

Answer:

An isometry preserves all the following except orientation .

please help, i will give brainliest!

Answers

Answer:

yes please, ask the question

PLEASE HELP. In the triangles below, DF MN, DG MP, D P. Can you prove that DFG MNP? Explain your answer. (15 points)

Answers

Complete question is;

In the triangles attached , DF is congruent to MN,DG is congruent to MP, angle D is congruent to angle P. Can you prove that triangle DFG is congruent to MNP.

Answer:

Proved below

Step-by-step explanation:

From the attached triangles, we can see that;

∠D corresponds to ∠M

∠F corresponds to ∠N

∠G corresponds to ∠P

But we are told that ∠D is congruent to ∠P. Thus, since we have 2 other congruent sides in the triangles, we can conclude that Side-Angle-Side Postulate (SAS) congruency theorem that triangle DFG is congruent to MNP.

Nishi invests £3400 at 5% interest per year. Work out how much she will have altogether after: 3 years​

Answers

Answer:

£510

Step-by-step explanation:

5% of 3400 is 170. SInce she gets that much money every year, after 3 years she'll have 3*170 = £510.

Answer: Simple Interest = PRT

P= 3400

R = 5% = 5/100

T = 3

=> 3400 × 5/100 × 3 = 510

=》3400 + 510 = 3910

Step-by-step explanation:

Two cars leave the park at the same time opposite directions one goes 3 times faster after 6 hours they travel 140miles how fast did theyg go

Answers

Answer:

Their speeds are;

5.83 mph and 17.49 mph

Step-by-step explanation:

We are told that they leave the park the same time.

Let the speed one car traveled be v

Since the other car is 3 times faster, then it means that, it's speed is 3v.

Now, after 6 hours they travel 140 miles.

We know that;

Speed = distance/time.

Thus;

(v + 3v) = 140/6

4v = 140/6

v = 140/24

v = 5.83 mph

Thus, second car's speed = 3v = 3 × 5.83 = 17.49 mph

Which of the following describes an air mass with the symbol CT? a. it is a cold air mass over an ocean c. it is a warm air mass over an ocean b. it is a warm air mass over a continent d. it is a cold air mass over a continent Please select the best answer from the choices provided

Answers

CT means continental tropical. meaning warm land. so the answer is B :) and this should be in the science section not math btw! good luck

Answer:

B is correct_

On the first day of travel, a driver was going at a speed of 40 mph. The next day, he increased the speed to 60 mph. If he drove 2 more hours on the first day and traveled 20 more miles, find the total distance traveled in the two days.

Answers

Answer:

380

Step-by-step explanation:

This is a bit nasty. It depends on how you read the 20 miles more and what you do with it. The best and most careful way to do it is do it a long way setting up the two equations carefully.

Second day

Let the time travelled = t

Let the speed travelled = 60 mph

d2 = 60*t

First Day

40*(t + 2) = d1

but d1 = d2 + 20 because he travelled 20 miles further on d1

40 * (t + 2) = d2 + 20

d2 however = 60*t

40*(t+2 ) = 60*t + 20          Remove the brackets

40t + 80 = 60t + 20           Subtract 20 from both sides

40t + 60 = 60t                   Subtract 40t from both sides

60 = 20*t                           Divide by 20

t = 60/20

t = 3 hours.

Day 2 = 60 + t = 180

Day 1 = 40*5  = 200

Total distance = 380

Where did that 20 miles go? It was just an observation about the difference in distance travelled between the 2 days.

The total distance the driver traveled in the two days is 260 miles

From the question, on the first day, the driver was going as a speed of 40 mph.

Let s be speed

∴ [tex]s_{1}= 40mph[/tex]

On the second day, he increased the speed to 60 mph

∴ [tex]s_{2}= 60mph[/tex]

From the statement- If he drove 2 more hours on the first day

Let time be t

Then

[tex]t_{1}= t_{2} + 2[/tex] hrs

and traveled 20 more miles

Let d be distance  

Then,

[tex]d_{1}= d_{2} + 20[/tex] miles

From the formula

Distance = Speed × Time

Then,

[tex]d = s \times t[/tex]

∴ [tex]d_{1} = s_{1} \times t_{1}[/tex]

From above,

[tex]d_{1}= d_{2}+20[/tex] miles

[tex]s_{1}= 40mph[/tex]

[tex]t_{1}= t_{2} + 2[/tex] hrs

Putting these into

[tex]d_{1} = s_{1} \times t_{1}[/tex]

[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex] ...... (1)

But,

[tex]Time = \frac{Distance}{Speed}[/tex]

∴ [tex]t_{2}= \frac{d_{2} }{s_{2} }[/tex]

From above, [tex]s_{2}= 60mph[/tex]

∴ [tex]t_{2}= \frac{d_{2} }{60}[/tex]

Put this into equation (1)

[tex]d_{2} + 20 = 40\times (t_{2}+2)[/tex]

[tex]d_{2} + 20 = 40\times (\frac{d_{2}}{60} +2)[/tex]

[tex]d_{2} + 20 = \frac{2}{3}d_{2} +80\\d_{2} = \frac{2}{3}d_{2} +80-20\\d_{2} = \frac{2}{3}d_{2} +60[/tex]

Multiply through by 3

[tex]3\times d_{2} = 3\times \frac{2}{3}d_{2} +3 \times 60\\3d_{2} = 2d_{2} + 120\\3d_{2} -2d_{2} = 120[/tex]

∴ [tex]d_{2} = 120[/tex] miles

∴The distance traveled on the second day is 120 miles

For the distance traveled on the first day,

Substitute [tex]d_{2}[/tex] into the equation

[tex]d_{1}= d_{2}+20[/tex] miles

∴ [tex]d_{1}= 120+20[/tex]

[tex]d_{1}= 140[/tex] miles

∴ The distance traveled on the first day is 140 miles

The total distance traveled in the two days = [tex]d_{1} + d_{2}[/tex]

The total distance traveled in the two days = 120 miles + 140 miles

The total distance traveled in the two days = 260 miles

Hence, the total distance the driver traveled in the two days is 260 miles

Learn more here: https://brainly.com/question/23531710

I NEEDDDD HELPPPP ITSSS URGENTTTT!!!!!

Answers

Answer: 380.1

Step-by-step explanation:

The area of a circle is pi*r^2. So 11 times 11 is 121. Then multiply by pi. When multiplies by pi you get 380.132711084. rounded to the nearest tenth is 380.1.

Instructions: Find the measure of the indicated angle to the nearest
degree.
19
?
8
=

Answers

Answer:

? ≈ 65°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cos? = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{8}{19}[/tex] , then

? = [tex]cos^{-1}[/tex] ([tex]\frac{8}{19}[/tex] ) ≈ 65° ( to the nearest degree )

Factor completely, show work.

x² - 49

Answers

You want to pull out the square roots of each term since they are both perfect squares.

Factor using the difference of squares formula: a2-b2=(a+b)(a-b)

This formula allows the middle term to cancel out.

=x2 - 49

=(x + 7)(x - 7)

ANSWER: (x + 7)(x - 7)

Hope this helps! :)

Find the pressure exerted by a force of 240 N on an area of 30 cm2. Find the answer in SI unit​

Answers

Answer:

Pressure is 80,000 pascals.

Step-by-step explanation:

Area:

[tex] = { \bf{ 30 \times {10}^{ - 4} \: {m}^{2} }}[/tex]

Pressure:

[tex]{ \bf{pressure = \frac{force}{area} }} \\ \\ { \tt{ = \frac{240}{30 \times {10}^{ - 4} } }} \\ = { \tt{80000 \: pascals}}[/tex]

You want to put a 3 inch thick layer of topsoil for a new 15 ft by 26 ft garden. The dirt store sells by the cubic yards. How many cubic yards will you need to order? The store only sells in increments of 1/4 cubic yards.

Answers

Answer:

You will need to order 3.75 cubic yards of topsoil.

Step-by-step explanation:

Since you want to put a 3 inch thick layer of topsoil for a new 15 ft by 26 ft garden, and the dirt store sells by the cubic yards, to determine how many cubic yards will you need to order given that the store only sells in increments of 1/4 cubic yards, the following calculation should be performed:

3 inches = 0.25 feet

15 x 26 = 390 x 0.25 = 97.5

1 cubic yard = 27 cubic feet

97.5 cubic feet = 3.61 cubic yards

3.75 = 1/4 x 15

Therefore, you will need to order 3.75 cubic yards of topsoil.

A shopkeeper fixed the marked price of his radio to make a profit of 30 %. Allowing 15 % discount on the marked price, the radio was sold. What percent profit did he make? ​

Answers

Answer:

10.5 %

Step-by-step explanation:

Here .

let the Cost Price be 'x'

the..

by the question..

the marked price was fixed to make 30% profit

then..

the marked price will be

x+ 30% of x

= x + 30/100 × x

=x+ 0.3x

=1.3x

soo .. the marked price is 1.3x

now.. after allowing 15% discount..

the selling price will be

1.3x - 15% of 1.3x

= 1.3x - 0.195x

= 1.105x

thank you...

plzz mark me brainliest now

now..

profit made = 1.105x-x

= 0.105x

soo .

in percentage..

profit percent = profit/cp × 100%

= 0.105x/x × 100%

= 10.5 %

757divide 100=to in hours and minutes

Answers

Answer:

Step-by-step explanation:

757 minutes = 12 hours 37 minutes

Venus has 80 ounces of sports drink. If she drinks 60% of it, how much sports drink will she have left?

Answers

Answer:

32 ounces

Step-by-step explanation:

It would be 32 ounces that Venus has left in her sports drink.


Use the figure to find the Total Area.

Answers

Answer:

60

Step-by-step explanation:

Multiply length times width times height

Answer:

C or 104

Step-by-step explanation:

I assume this is surface area, and I don't know what kinda sadist person would make everyone learn in "Total Area," but it is what it is.

So, to find total area, we need to literally multiply every different number with the other.

(You should not do it the way I did, as I did it in the easiest and simpliest way to understand possible.)

Actually, you get the length, width, and height of a figure and do what is below pretty much.

You multiply the length by the width, the length by the height, and the width by the height (doesn't have to be in this order, this is just to make it easy to remember which ones you did.)

We multiply the

5 * 6

5 * 2

and then the

6 * 2

This accounts for every possible case, as multiplying 2 * 5 gives the same thing as the second expression anyways.

So we then solve these three expressions.

5 * 6 = 30

5 * 2 = 10

and then the

6 * 2 = 12

And we add them to get

30 + 10 + 12

= 52.

Then we multiply by 2, because there are two cases of each face of the shape.

You need to remember that there is 3 other faces on the shape you are looking at, it's just that the shape/figure is facing you in a way that you can't see them.

After multiplying by 2, we get

52 * 2

= 104, which is C.

TAKE A SCREENSHOT NOT A PICTURE AS WE DON'T NEED TO SEE SOME 420P MONITOR FROM 1987 THAT SHOWS EVERY PIXEL PLEASE AND THANK YOU :D

is (the number in the photo) rational or irrational?

Answers

Answer:

irrational

Step-by-step explanation:

1. Which of the following is an algebraic expression?
a. X+5= 7
b. 5-2x = 3
C. 5x +4- 2x
d. -2 = 3x + 1

Answers

1.

C. 5x + 4 - 2x is an algebraic expression

Sally spent half of her allowance going to the movies. She washed the family
car and earned 6 dollars. What is her weekly allowance if she ended with
17 dollars ?

Answers

does it give the answer choice or is it a blank space?

given: ray FEH bisects

Answers

hhhahahshhehrhhehrhrhrhrh

4. a) x2 + xy2 + y 4

Answers

Answer:

x2 + xy2 + y 4=(x+y^2)^2-xy^2

Step-by-step explanation:

1. 9+x-7
2. 8-2x+5x
3. -x-9+3x
4. 4x-6-4x

Answers

Answer:

1)9-7+x

2+x

2)8-2x+5x

8+3x

3)-x+3x-9

2x-9

4)4x-4x-6

-6

you have to group the like terms

I hope this helps and sorry if they are wrong

Find the multiples of 7 which is greater than 56 but less than 77

Answers

Answer:

63,70

Step-by-step explanation:

7 x 8 = 56

7 x 11 = 77

multiples of 7 and 9, 7 x 10

63 and 70

7×9 = 63

7×10 = 70

Answered by Gauthmath must click thanks and mark brainliest

7.


For which discriminant is the graph possible?



A. b2 – 4ac = 0


B. b2 – 4ac = –1


C. b2 – 4ac = 4

Answers

Answer:

C. b2 – 4ac = 4

Step-by-step explanation:

Answer:

The graph is possible for  

Step-by-step explanation:

we know that

The discriminant of a quadratic equation of the form

is equal to

If D=0 the quadratic equation has only one real solution

If D>0 the quadratic equation has two real solutions

If D<0 the quadratic equation has no real solution (complex solutions)

In this problem , looking at the graph, the quadratic equation has two real solutions (the solutions are the x-intercepts)

so

therefore

The graph is possible for

...............................................................................................................................................

Answer:

b^2 – 4ac = 4

...............................................................................................................................................

(PICTURE) 15 Points and marking Brainliest could someone please answer/explain this for me

Answers

Answer:

9. Hypotenuse = √(19.1²+11.3²) = √492.5 = 22.2 m²

10. Area = (34×40)/2 + (17²×π/2)

= 680 + 453.96

= 1133.96 cm²

Answered by GAUTHMATH

EVALUATE: 10x – 2y3 (if x = 5 and y = 2)​

Answers

Answer:

10*(5) - 2*(2)^3

= 50 - 2*8

= 50 - 16

=34

Answer:

Step-by-step explanation:

với x=5 và y=2

phương trinh trở th a

10*  5 - 2 * 2^ 3

=50 -  2*8

=50 - 16

=34

can someone help me with this

Answers

Answer:

Infenitely many solutions

helpppp please.......​

Answers

The equation your teacher has given you is an identity. We can prove this by transforming one side into the other. I'll transform the right hand side (RHS) into the left hand side (LHS).

This means I'll keep the LHS the same for each line. I'll only change the RHS. The goal is to get the same thing on both sides (I could go the other way around but I find this pathway is easier).

[tex]\tan^4(\theta)+\sec^2(\theta) = \sec^4(\theta)-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\sec^2(\theta)\right)^2-\tan^2(\theta)\\\\\tan^4(\theta)+\sec^2(\theta) = \left(\tan^2(\theta)+1\right)^2-\tan^2(\theta) \ \text{ ... see note 1}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+2\tan^2(\theta)+1-\tan^2(\theta)\\\\[/tex]

[tex]\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\tan^2(\theta)+1\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta)-1+1 \ \text{ ... see note 2}\\\\\tan^4(\theta)+\sec^2(\theta) = \tan^4(\theta)+\sec^2(\theta) \ \ \Large \checkmark\\\\[/tex]

note1: I use the identity [tex]\tan^2(\theta)+1 = \sec^2(\theta)[/tex] which is derived from the pythagorean trig identity [tex]\sin^2(\theta)+\cos^2(\theta) = 1[/tex]note2: based on the previous note, we can say [tex]\tan^2(\theta) = \sec^2(\theta)-1[/tex]

So because we've arrived at the same thing on both sides, the original equation is an identity. It always true no matter what theta value you plug in, as long as theta is in the domain. So something like theta = pi/2 won't work because tan(pi/2) = undefined and sec(pi/2) = undefined. It's based on how cos(pi/2) = 0 and this value is in the denominator. Dividing by zero is undefined.

Consequently, this means all solutions to cos(theta) = 0 will be excluded from the domain. Everything else works.

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