Find the distance between (6,6) & (-6,2)
Round your answer to the nearest 100th

The answer is prime! I hope this helps you out!

Answer:

23 is a prime number. Reason: Prime number are those numbers which are divisible by 1 and itself. Example: 5 is divisible by 1 and 5 only.

Answer:

y=(3/7)*x+52/7

Step-by-step explanation:

The slope of the line will be (3/7). The equation of line will be y=(3/7)*x+52/7

Answer:

1080

Step-by-step explanation:

PEMDAS says multiply and divide from left to right

9*5*6*3÷3*4*6÷6

45*6*3÷3*4*6÷6

270*3÷3*4*6÷6

810÷3*4*6÷6

270*4*6÷6

1080*6÷6

6480÷6

1080

Answer:

[tex]cos49 = \frac{26}{x} \\ x = 39.6305[/tex]

Answer:

35 full bags

Step-by-step explanation:

$305-$35.75=$269.25

$269.25 divided by $7.50=35.9 bags (round off to lowest for number of full                                            bags)

Answer:

y=-2x-1

Step-by-step explanation:

The slope is - 2. The equation is y=-2x-1

It will take Fred 42 minutes to type and spell check 60 pages.

Given the following data;

To find how long it takes him to type and spell check 60 pages;

We would use direct proportion to express the work described and solve for the unknown variable (time).

[tex]9 \;minutes : 13 \;pages\\\\X \;minutes : 60 \;pages[/tex]

Cross-multiplying, we have;

[tex]9[/tex] × [tex]60[/tex] [tex]= 13[/tex] × [tex]X[/tex]

[tex]540 = 13X\\\\X = \frac{540}{13}[/tex]

X = 41.54 ≈ 42 minutes

Therefore, it will take Fred 42 minutes to type and spell check 60 pages.

Find more information: https://brainly.com/question/89674

Answer:

1051.9 minutes

Step-by-step explanation:

16 games at 58.35 minutes =

16* 58.35 =933.6 minutes

2 playoffs at 59.15

2 * 59.15 = 118.3 minutes

Add them together

933.6+118.3 =1051.9 minutes

Answer:

the answer is 1051.9 minutes

Step-by-step explanation:

[tex]\sf{}[/tex]

♛┈⛧┈┈•༶♛┈⛧┈┈•༶

Answer:

Hello,

Answer C

Step-by-step explanation:

Since ln(1)=0

if x=1 then y=4 ==> y=ln(x)+4

y=ln(x) is translated up for 4 units.

Answer:

[tex]\sqrt{280}[/tex] = 2[tex]\sqrt{70}[/tex]

37^2 = 1369

33^2 =1089

1369-1089 = 280

Step-by-step explanation:

9514 1404 393

Answer:

  π = 2A/r²

Step-by-step explanation:

Multiply by the inverse of the coefficient of π.

  A = π(r²/2)

  π = 2A/r²

Answer:

4 i believe that's the answer

No piece of information is supplied to choose from ; However, the requirements for the test statistic of the hypothesis in question is given below.

Answer:

Kindly check explanation

Step-by-step explanation:

The hypothesis in the question above which is to be tested is a one sample proportion test ;

The test statistic formula for a one sample proportion test is given as :

Test statistic = (Phat - P) / √[P(1 - P) / n] ;

Where;

Phat = sample proportion

P = population proportion

n = sample size

Sample proportion = x / n ;

Therefore, once the parameters (Sample proportion, population proportion and sample size are given) then obtaining the test statistic is possible.

Answer:

10.2

Step-by-step explanation:

Length of arc=(2*pi*r)*(theta/360)

Length of arc=(2*pi*3)*(195/360)=10.2

.・。.・゜✭・Srry but which language is this!?

Step-by-step explanation:

9) let number=x

Four times a number=4x

Condition:

4x+5=32

10) square of number=x²

Condition:

x²-4=12

11)

Condition:

3(x+4)=20

Note:if you need to know any question please let me know.

The equivalent resistance of the network shown is: [tex]R_{eq}=16.463\Ohm[/tex]

So, first of all, we can start by determining what each of the resistances is equal to. In this case we can start by saying that [tex]R_{1}=11R_{11}[/tex] This means that:

[tex]R_{1}=11(3\Ohm)[/tex]

Therefore:

[tex]R_{1}=33\Ohm[/tex]

We can now use this value to find the value of the other resistances. The given condition for the resistances can be represented with the following formula:

[tex]R_{n}=\frac{R_{1}}{n}[/tex]

so:

[tex]R_{2}=\frac{R_{1}}{2}=\frac{33}{2}\Ohm[/tex]

[tex]R_{3}=\frac{R_{1}}{3}=\frac{33}{3}\Ohm=11 \Ohm[/tex]

[tex]R_{4}=\frac{R_{1}}{4}=\frac{33}{4}\Ohm[/tex]

[tex]R_{5}=\frac{R_{1}}{5}=\frac{33}{5}\Ohm[/tex]

[tex]R_{6}=\frac{R_{1}}{6}=\frac{33}{6}\Ohm=\frac{11}{2}\Ohm[/tex]

[tex]R_{7}=\frac{R_{1}}{7}=\frac{33}{7}\Ohm[/tex]

[tex]R_{8}=\frac{R_{1}}{8}=\frac{33}{8}\Ohm[/tex]

[tex]R_{9}=\frac{R_{1}}{9}=\frac{33}{9}\Ohm=\frac{11}{3}\Ohm[/tex]

[tex]R_{10}=\frac{R_{1}}{10}=\frac{33}{10}\Ohm[/tex]

[tex]R_{11}=3\Ohm[/tex]

So now that we know what each resistance is equal to, we can go ahead and analyze the circuit.

In this case we can see that [tex]R_{10}[/tex] and [tex]R_{11}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{1011}=\frac{R_{10}R_{11}}{R_{10}+R_{11}}[/tex]

Which yields:

[tex]R_{1011}=\frac{(\frac{33}{10}\Ohm)(3\Ohm)}{\frac{33}{10}\Ohm+3\Ohm}[/tex]

[tex]R_{1011}=\frac{11}{7}\Ohm[/tex]

Now, [tex]R_{8}[/tex], [tex]R_{9}[/tex] and [tex]R_{1011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:

[tex]R_{891011}=R_{8}+R_{9}+R_{1011}[/tex]

[tex]R_{891011}=\frac{33}{8}+\frac{11}{3}+\frac{11}{7}[/tex]

[tex]R_{891011}=\frac{1573}{168}\Ohm[/tex]

Now,  we can see that [tex]R_{7}[/tex] and [tex]R_{891011}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{7891011}=\frac{R_{7}R_{891011}}{R_{7}+R_{891011}}[/tex]

Which yields:

[tex]R_{7891011}=\frac{(\frac{33}{7}\Ohm)(\frac{1573}{168})}{\frac{33}{7}\Ohm+\frac{1573}{168}\Ohm}[/tex]

[tex]R_{7891011}=\frac{4719}{1505}\Ohm[/tex]

Now, [tex]R_{5}[/tex], [tex]R_{6}[/tex] and [tex]R_{7891011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:

[tex]R_{567891011}=R_{5}+R_{6}+R_{7891011}[/tex]

[tex]R_{567891011}=\frac{33}{5}\Ohm+\frac{11}{2}\Ohm+\frac{4719}{1505}\Ohm[/tex]

[tex]R_{567891011}=15.236\Ohm[/tex]

Next,  we can see that [tex]R_{4}[/tex] and [tex]R_{567891011}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{4567891011}=\frac{R_{4}R_{567891011}}{R_{4}+R_{567891011}}[/tex]

Which yields:

[tex]R_{4567891011}=\frac{(\frac{33}{4}\Ohm)(15.236\Ohm)}{\frac{33}{4}\Ohm+15.236\Ohm}[/tex]

[tex]R_{4567891011}=5.352\Ohm[/tex]

Now, [tex]R_{2}[/tex], [tex]R_{3}[/tex] and [tex]R_{4567891011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:

[tex]R_{234567891011}=R_{2}+R_{3}+R_{4567891011}[/tex]

[tex]R_{234567891011}=\frac{33}{2}\Ohm+11\Ohm+5.352\Ohm[/tex]

[tex]R_{234567891011}=32.852\Ohm[/tex]

Finally, we can see that [tex]R_{1}[/tex] and [tex]R_{234567891011}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{eq}=\frac{R_{1}R_{234567891011}}{R_{1}+R_{234567891011}}[/tex]

Which yields:

[tex]R_{eq}=\frac{(33\Ohm)(32.852\Ohm)}{33\Ohm+32.852\Ohm}[/tex]

[tex]R_{eq}=16.463\Ohm[/tex]

See attached picture for images on how to reduce the circuit.

You can find further information in the following link.

https://brainly.com/question/21538325?referrer=searchResults

Answer:

70.908 is greater than 7.908 .

I hope your day goes nice

Answer:

both are different because of different placement of point.

Answer:

Step-by-step explanation:

Temperature is a function of the time of day. There can be only one temperature at any particular time.

In contrast, a particular temperature can occur more than one time in a day, so time is not a function of temperature.

Answer:

x = -1/4

Step-by-step explanation:

[tex]81^{x}[/tex] = 1/3

[tex]3^{4}^{x}[/tex] = [tex]3^{-1}[/tex]

4x = -1

x = -1/4

Answer:

x = - [tex]\frac{1}{4}[/tex]

Step-by-step explanation:

Using the rules of exponents

[tex](a^m)^{n}[/tex] = [tex]a^{mn}[/tex] , [tex]a^{-m}[/tex] = [tex]\frac{1}{a^{m} }[/tex]

Given

[tex]81^{x}[/tex] = [tex]\frac{1}{3}[/tex] [ note that 81 = [tex]3^{4}[/tex] ] , then

[tex](3^4)^{x}[/tex] = [tex]3^{-1}[/tex] , that is

[tex]3^{4x}[/tex] = [tex]3^{-1}[/tex]

Since the bases on both sides are equal, both 3, then equate exponents

4x = - 1 ( divide both sides by 4 )

x = - [tex]\frac{1}{4}[/tex]

[tex]\\ \sf\longmapsto 2(3x-7)+4(3x+2)=6(5x+9)+3[/tex]

[tex]\\ \sf\longmapsto 6x-14+12x+8=30x+54+3[/tex]

[tex]\\ \sf\longmapsto 6x+12x-14+8=30x+57[/tex]

[tex]\\ \sf\longmapsto 18x+6=30x+57[/tex]

[tex]\\ \sf\longmapsto 30x-18x=6-57[/tex]

[tex]\\ \sf\longmapsto 12x=51[/tex]

[tex]\\ \sf\longmapsto x=\dfrac{51}{12}[/tex]

Answer:

the cost of filling the pool is $386.3

Step-by-step explanation:

Given;

dimension of the rectangular pool, = 25 yd by 30 yd by 5.1 ft

covert the given dimensions to feet;

1 yd = 3 ft

25 yd = 25 x 3 ft = 75 ft

30 yd = 30 x 3 ft = 90 ft

The volume of the rectangular pool in cubic feet (ft³);

Volume = 75 ft  x 90 ft  x 5.1 ft

Volume = 34,425 ft³

Convert the volume to gallons;

1 ft³ = 7.481 gallons

10,125 ft³ = 34,425 x 7.481 gallons

               = 257,533.425 gallons

The cost per a 1000 gallons is $1.50, then cost of the 257,533.425 gallons is calculated as;

[tex]cost = \frac{\$ 1.50}{1000 \ gallons} \times 257,533.425 \ gallons = \$ 386.3[/tex]

Therefore, the cost of filling the pool is $386.3

Answer:

0

2

-1

Step-by-step explanation:

from f(0) we find that

y = mx - 1

from f(-1) we find that the equation is

y = -3x - 1

1)

inverse f(x) :

x = -3y - 1

y = -(x + 1) / 3           x = -1

y = -(-1 + 1) / 3

y = 0

2)

y also equal to 0 since x = -1

3)

f^-1(2) = -(2+1) / 3

          = -3/3

          = -1

f(-1) =  2

Answer:

[tex]{ \sf{ \underline{ {x}^{2} + 5x - 6 }}}[/tex]

Step-by-step explanation:

[tex](x + 6)(x - 1) \\ = {x}^{2} - x + 6x - 6 \\ = {x}^{2} + 5x - 6[/tex]