Determine the mass of CaCl2·2H2O(MW 147.02g/mole) to weigh out using a four-place analytical balance to prepare 100mL of a 0.1005M solution of Ca2+.

Answers

Answer 1

Answer:

1.4776 g

Explanation:

First, let us determine the number of moles present in  100 mL of 0.1005 M solution of Ca2+.

mole = molarity x volume in Liter

mole of Ca2+ = 0.1005 x 0.1 = 0.01005

Also,

mole = mass/molar mass

mass of 0.01005 mole Ca2+ = mole x molar mass

                 = 0.01005 x 147.02 = 1.4776 g

Since 1 mole of Ca2+ is present is 1 mole of CaCl2·2H2O, 1.4776 g of CaCl2·2H2O would be weighed out in order to prepare 00mL of a 0.1005M solution of Ca2+.

Answer 2

To prepare a 100 mL solution of 0.1005 M [tex]Ca^2^+[/tex], we would need to weigh out approximately 14.737 grams of [tex]CaCl_2.2H_2O[/tex].

We must use the molar mass and molarity formula to calculate the mass of [tex]CaCl_2.2H_2O[/tex] needed to make a 0.1005 M solution of [tex]Ca^2^+[/tex].

Let's start by figuring out how many moles of [tex]Ca^2^+[/tex]are needed for the solution:

Molarity (M) = moles/volume (L)

0.1005 M = x moles/0.1 L (100 mL converted to liters)

x = 0.1005 moles of [tex]Ca^2^+[/tex]

So, the molar mass of [tex]CaCl_2.2H_2O[/tex]:

Ca (40.08 g/mol) + 2Cl (35.45 g/mol) + 2([tex]H_2O[/tex]) (2 * 18.02 g/mol) = 147.02 g/mol

Then, we calculate the mass

Mass = moles * molar mass

Mass = 0.1005 moles * 147.02 g/mol

Mass = 14.737 grams

Therefore, to prepare a 100 mL solution of 0.1005 M [tex]Ca^2^+[/tex], we would need to weigh out approximately 14.737 grams of [tex]CaCl_2.2H_2O[/tex].

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The pH of a solution of 3-hydroxypropanoic acid is measured to be . Calculate the acid dissociation constant of 3-hydroxypropanoic acid. Be sure your answer has the correct number of significant digits.

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The pH of a 0.53 M solution of 3-hydroxypropanoic acid (HC₃H₅O₃) is measured to be 2.39. Calculate the acid dissociation constant of 3-hydroxypropanoic acid. Be sure your answer has the correct number of significant digits.

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Step 2: Write the acid dissociation reaction

3-hydroxypropanoic acid is a weak acid that dissociates according to the following equation.

HC₃H₅O₃(aq) ⇄ C₃H₅O₃⁻(aq) + H⁺(aq)

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Step 4: Calculate the acid dissociation constant (Ka) of 3-hydroxypropanoic acid

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Answers

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Answers

Answer:

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Option d) 1.12 is the correct answer

Explanation:

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Hello!

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