Convierta 164 decimetros a hectometros

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Answer 1

Answer:

sinco

Explanation:


Related Questions

a coach is travelling east wards at 12.6 m/s after 12 second its velocity is 9.5 m/s in the same direction. what is the acceleration and direction of its acceleration?

pls do it with the formula
thx mates :)​

Answers

Initial velocity=u=12.6m/sFinal velocity=9.5m/sTime=t=12sAcceleration be a

[tex]\\ \rm\longmapsto a=\dfrac{v-u}{t}[/tex]

[tex]\\ \rm\longmapsto a=\dfrac{12.6-9.5}{12}[/tex]

[tex]\\ \rm\longmapsto a=\dfrac{3.1}{12}[/tex]

[tex]\\ \rm\longmapsto \overrightarrow{a}=0.25m/s^2[/tex]

Consider the nearly circular orbit of Earth around the Sun as seen by a distant observer standing in the plane of the orbit. What is the effective "spring constant" of this simple harmonic motion?
Express your answer to three significant digits and include the appropriate units.

Answers

We have that the spring constant is mathematically given as

[tex]k=2.37*10^{11}N/m[/tex]

Generally, the equation for angular velocity is mathematically given by

[tex]\omega=\sqrt{k}{m}[/tex]

Where

k=spring constant

And

[tex]\omega =\frac{2\pi}{T}[/tex]

Therefore

[tex]\frac{2\pi}{T}=\sqrt{k}{n}[/tex]

Hence giving spring constant k

[tex]k=m((\frac{2 \pi}{T})^2[/tex]

Generally

Mass of earth [tex]m=5.97*10^{24}[/tex]

Period for on complete resolution of Earth around the Sun

[tex]T=365 days[/tex]

[tex]T=365*24*3600[/tex]

Therefore

[tex]k=(5.97*10^{24})((\frac{2 \pi}{365*24*3600})^2[/tex]

[tex]k=2.37*10^{11}N/m[/tex]

In conclusion

The effective spring constant of this simple harmonic motion is

[tex]k=2.37*10^{11}N/m[/tex]

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The ratio of RMS of velocity , Probable Velocity and Average velocity is ??​

Answers

Answer:

2 :π8 :3

The ratio between the most probable velocity,mean velocity and root mean square velocity is 2 :π8 :3. Vrms=M3RT.

Explanation:

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Please help! Can give brainliest too.

Answers

Explanation:

[tex]v = \sqrt{2ax}[/tex]

Take the square of both sides:

[tex]v^2 = \left(\sqrt{2ax}\right)^2 = 2ax[/tex]

Divide both sides by 2a and you will get

[tex]x = \dfrac{v^2}{2a}[/tex]

How do you know that a liquid exerts pressure?​

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Answer:

The pressure of water progressively increases as the depth of the water increases. The pressure increases as the depth of a point in a liquid increases. The walls of the vessel in which liquids are held are likewise subjected to pressure. The sideways pressure exerted by liquids increases as the liquid depth increases.

calculate horizontal distance travelled by a ball travelling with a speed of 20root2 mper sec without hitting ceiling of height 20 m per sec​

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Calculate the horizontal distance travelled by a ball throw with a velcoity 20 sqrt 2 ms^(-1) without hitting the ceiling of an anditorium of heith 20 m. Use g= 10 ms^(-2). =(20√2)2sin2×45∘10=9800×1)10=80m .

HOPE SO IT HELPS YOU

What is the momentum of a 36.9 N bowling ball with a velocity of 7.56 m/s?

Answers

Answer:

momentum (m)=36.9N

velocity (v)=7.56m/s

now,

momentum (m)=m×v

36.9=m×7.56

36.9÷7.56=m

m=4.89kg

a standard bathroom scale is placed on an elevator. A 34 kg boy enters the elevator on the first floor and steps on the scale. What will the scale read (in newtons) when the elevator begins to accelerate upward at 0.4 m/s2

Answers

Answer:F = 255 N

Explanation:

It is given that,

Mass of the boy, m = 25 kg

Acceleration of the elevator,  

The elevator is accelerating in upward direction. The net force acting on the boy is given by :

g is the acceleration due to gravity

F = 255 N

The scale reading is 255 N as it begins to accelerate upward. hence, this is the required solution.

An electric motor and a generator are similar in that both

A. Produce mechanical energy.
B. Use electricity.
C. Transform energy into a different form.
D. Create energy.

Answers

C. transform energy into a different from.

I hope this helps

A linear accelerator can be used to accelerate which of the following?
Question 3 options:

protons and electrons

protons and neutrons

protons only

protons, electrons, and neutrons

Answers

Answer: protons and electrons

who was the youngest female to give birth​

Answers

Answer:

5 years old 7 months and 21 days

Explanation:

Answer:

lina marcela medina de jurado

The speed of a horse is 134 meters per second how long does it takes to travel a distance of 19,311?

Answers

Answer:

just need some focus

Explanation:

tan 13. The speed of a horse is 134 meters per second how long does it take to travel a distance of 19,311m? M+ tud V 134 14. You are walking down the block and see your neighbor's pitbull 30 meters away, out of the fence, starring at you. Suddenly, he starts running towards you at 20m/s. How long will it be before you're the pitbull's lunch?  V 15. A pendulum has a frequency of 2 Hz what is it's period. T = 1/2 16. You have just finished a 1600 mile trip, and it took you 16 hours. What was your average speed V = Ad At 17. You are flying from New York, NY to SanFrancisco California, a distance of 2582 miles, it takes 6.33hrs to complete the flight what was your average speed? give answer in m/s. V = Ad = At 3 of 6

Electrons are emitted from a surface when light of wavelength 500 nm is shone on the surface but electrons are not emitted for longer wavelengths of light. The work function of the surface is

Answers

Explanation:

Given: [tex]\lambda = 500\:\text{nm} = 5×10^{-7}\:\text{m}[/tex]

[tex]\nu = \dfrac{c}{\lambda} = \dfrac{3×10^8\:\text{m/s}}{5×10^{-7}\:\text{m}}[/tex]

[tex]\:\:\:\:\:= 6×10^{14}\:\text{Hz}[/tex]

The work function [tex]\phi[/tex] is then

[tex]\phi = h\nu = (6.626×10^{-34}\:\text{J-s})(6×10^{14}\:\text{Hz})[/tex]

[tex]\:\:\:\:\:\:\:= 3.98×10^{-19}\:\text{J}[/tex]

The work function of the surface is equal to 3.98 × 10⁻¹⁹J.

What are frequency and wavelength?

The frequency can be explained as the number of oscillations of a wave in one second. The frequency has S.I. units of hertz.

The wavelength can be explained as the distance between the two adjacent points such as two crests or troughs on a wave.

The expression between wavelength (λ), frequency, and speed of light (c) is:

c = νλ

Given, the wavelength of the light, ν = 500 nm

The frequency of the light can determine from the above-mentioned relationship:

ν = c/λ= 3 × 10⁸/500 × 10⁻⁹ = 6 × 10¹⁴ Hz

The work function = h ν =  6 × 10¹⁴ × 6.626 × 10⁻³⁴

φ = 3.98 × 10⁻¹⁹J

Therefore, the work function of the surface is 3.98 × 10⁻¹⁹J.

Learn more about wavelength and frequency, here:

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. Two charges, Q1 and Q2 , are separated by a certain distance R. If the magnitudes of the charges are halved, and their separation is also halved, then what happens to the electrical force between these charges

Answers

Answer: Magnitude of electrical force stays the same.

Explanation:

Equation:

[tex]F_{e} =k\frac{Q_{1}Qx_{2} }{r^{2} }[/tex]

Since the magnitude of each charge is halved.

and

the separation is halved.

[tex]F_{e} =k\frac{(.5Q_{1}*.5Q_{2} }{(.5r)^{2} }[/tex]

[tex]F_{e} =k\frac{.25*Q_{1}Qx_{2} }{.25*r^{2} }[/tex]

Cancel out .25 on the numerator and denominator. Leaving the original equation.

PleasePlease help me solve these articles with me

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Ngl I lost brain cells tryna figure out what ur doing

How many different ingredients will you need…

Answers

Answer:

11

Explanation:

hope this helps!!!!!

Two point charges of equal magnitude are 7.5cm apart. At the midpoint of the line connecting them, their combined electric field has a magnitude of 49N/CFind the magnitude of the charges (pC)

Answers

Answer:

q 1 = q 2 = Q

E = k * Q / r²

The combined electric field:

E = 2 * k * Q / r²

k = 9 · 10^9 Nm²/C²

r = 0.075 : 2 = 0.0375 m

45 N/C = 2 · 9 · 10^9 · Q / 0.0375²

45 = 18 · 10 ^9 Q / 0.0014062

Q = 45 · 0.0014062 / 18 · 10^9

Q = 0.003515 · 10^(-9) C

Q = 3.5155 · 10 ^ (-12) C = 3.5155 pC

if you jog at a speed of 1.5m/s for 20 seconds how far di you travel

Answers

Answer: 30m

Explanation:

Given:

Speed: 1.5m/s

Time: 20 seconds

Distance = speed × time

Distance = 1.5 × 20

= 30m

Therefore you will travel 30m

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Please help me. Im not good at physics​

Answers

Answer:

The answer is frictional force !

Answer:

4th option Friction

Explanation:

Friction always is there when an object is incline (sloping)

and here you can see the box is slopping down so frictional force is applied here

Where does a body have more weight the poor at the eqator of the earth.​

Answers

At the North Pole or South Pole but ur body itself doesn’t not change it is the force of gravity that changes as u approach the pole

Answer:

Explanation:

Your body weighs more at the pole for two important reasons. Both have to do to the spin of the earth on its axis.

Because of its spin the earth is thicker around the equator than it is through the poles. This means that when you stand on the equator, you are farther away from the center of earth than you would be at the poles. As gravity decreases with the inverse of the square of distance, gravity will be weaker at the equator.

As you are also spinning with the earth, you will have a required centripetal acceleration and force to keep you attached to the ground, This force decreases the effect of gravity so again, you would weigh less at the equator.

An equation for the period of a planet is 4 pie² r³/Gm where T is in secs, r is in meters, G is in m³/kgs² m is in kg, show that the equation is dimensionally correct.​

Answers

Answer:

[tex]\displaystyle T = \sqrt{\frac{4\, \pi^{2} \, r^{3}}{G \cdot m}}[/tex].

The unit of both sides of this equation are [tex]\rm s[/tex].

Explanation:

The unit of the left-hand side is [tex]\rm s[/tex], same as the unit of [tex]T[/tex].

The following makes use of the fact that for any non-zero value [tex]x[/tex], the power [tex]x^{-1}[/tex] is equivalent to [tex]\displaystyle \frac{1}{x}[/tex].

On the right-hand side of this equation:

[tex]\pi[/tex] has no unit.The unit of [tex]r[/tex] is [tex]\rm m[/tex].The unit of [tex]G[/tex] is [tex]\displaystyle \rm \frac{m^{3}}{kg \cdot s^{2}}[/tex], which is equivalent to [tex]\rm m^{3} \cdot kg^{-1} \cdot s^{-2}[/tex].The unit of [tex]m[/tex] is [tex]\rm kg[/tex].

[tex]\begin{aligned}& \rm \sqrt{\frac{(m)^{3}}{(m^{3} \cdot kg^{-1} \cdot s^{-2}) \cdot (kg)}} \\ &= \rm \sqrt{\frac{m^{3}}{m^{3} \cdot s^{-2}}} = \sqrt{s^{2}} = s\end{aligned}[/tex].

Hence, the unit on the right-hand side of this equation is also [tex]\rm s[/tex].

May someone help...please. Pretty please...

If a person is 18 % shorter than average, what is the ratio of his walking pace (that is, the frequency 'f' of his motion) to the walking pace of a person of average height? Assume that a person's leg swings like a pendulum and that the angular amplitude of everybody's stride is about the same.
f(short)/f(avg)=?

Answers

We have that  the ratio of his walking pace  to the walking pace of a person of average height is

[tex]\frac{V_2}{V_1}=1.10[/tex]

given the assumption and the calculation given below

From the question we are told that:

Consider a person 18\% shorter than average

Let average height of a person be [tex]10m[/tex]

Therefore

The height of an [tex]18\%[/tex] shorter man is mathematically given as

H=10*0.18

H=8.2m

Generally, the equation for velocity is mathematically given by

[tex]v=\frac{1}{2\pi} \sqrt{{g}{l}}[/tex]

Where we have the  Assumption that a person's leg swings like a pendulum and that the angular amplitude of everybody's stride is about the same

Therefore

[tex]\frac{V_1}{V_2}=\frac{l_1}{l_2}[/tex]

[tex]\frac{V_1}{V_2}={82}{100}[/tex]

[tex]\frac{V_2}{V_1}=1.10[/tex]

In conclusion

The ratio of his walking pace (that is, the frequency 'f' of his motion) to the walking pace of a person of average height is

[tex]\frac{V_2}{V_1}=1.10[/tex]

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Under normal circumstances: _________
a. Fetal Hb binds to oxygen more tightly than Mb binds.
b. Fetal Hb binds oxygen more tightly in the absence of 2,3-BPG.
c. Fetal Hb does not bind to oxygen.
d. Adult Hb has the lowest affinity for oxygen of the 3.
e. More than one of these statements is correct.

Answers

Answer:

Fetal Hb binds oxygen more tightly than adult Hb (not option a)

(a) Joseph was pushing a car.On his observation found that it was easier to keep the car in moti with a smaller force than to start its motion. Explain why?​

Answers

Answer:

Newton's laws states that 'what is in motion, stays in motion until a external force is applied', when a car is already moving, it's in motion already but to start a car, you need to apply some force to get it going, that force isn't required for a moving car.

A race car goes from a complete stop at the start line to 150 miles per hour in 5 seconds. What is its acceleration? Show your work.

Answers

Answer:

Explanation:

150/5  = 30

30mph per 1 second

what does displacement consists of

Answers

Answer:

The displacement of a body has two components: rigid-body displacement and deformation. A rigid-body displacement consists of a simultaneous translation and rotation of the body without changing its shape or size.

Explanation:

what happens to the weight of the body when it is falling freely under the action of gravity​

Answers

Answer:

A freely falling object has weight W=mg, where W-weight, m-mass of the object and g-acceleration produced due to the earth's gravity. ... This happens because the normal reaction force exerted on the object in the lift is equal to zero, and normal force equals to mg, which in turn equals the weight of the object

Explanation:

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Answer:

Gradually increases until the maximum weight reaches the surface of the earth

Explanation:

What is the author's MAIN purpose for including information about viruses? D to suggest that it could be dangerous for explorers to bring home life from other planets B to provide an example that illustrates the difficulty of defining life in some cases on Earth С to demonstrate the need for extra protective gear when explorers go into space D to highlight the differences between natural life and artificial life mixed in a lab Back Submit​

Answers

Answer:

B

Explanation:


Which units are being recalled?

—-

Answers

Answer:

a c e f

Explanation:

Start with the last year then the month. to eliminate wrong choices

8. A mass of 10 Kg is accelerating at 3 m/s2. What is the applied net force?

Answers

Answer:

Explanation:

F = ma

F = (10)(3)

F = 30 N

Answer:

[tex]\boxed {\boxed {\sf 30 \ Newtons}}[/tex]

Explanation:

We are asked to find the applied net force. According to Newton's Second of Law, force is the product of mass and acceleration.

[tex]F= m \times a[/tex]

The object has a mass of 10 kilograms and it is accelerating at 3 meters per second squared.

m= 10 kg a= 3 m/s²

Substitute the known values into the formula.

[tex]F= 10 \ kg \times 3 \ m/s ^2[/tex]

Multiply.

[tex]F= 30 \ kg \times m/s^2[/tex]

1 kilogram meter per second squared is equal to 1 Newton, so our answer of 30 kg × m/s² is equal to 30 N.

[tex]F= 30 \ N[/tex]

The applied net force is 30 Newtons.

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