Consider the line y = 4x + 9. If a second line is perpendicular to this one, what is its slope?

Answer:

Line that passes through the points (-6,5) and (-2,7) is,

y=x/2+8, slope is 1/2

line that passes through the points (4,2) and (6,6) is,

y=2x-6, slope is 2

so, there is no relationship between those two lines,

intersection point is (28/3,38/3)

Answer:

D) 1

Step-by-step explanation:

using the distributive property we have ax+a+bx-b-2=0. because the equation is true for all real x, ax=-bx. this means a-b-2=0 and a=-b. a-b-2=0 becomes a=b+2. then we substitute a for -b and get -b=b+2 which becomes 2b=-2 so b=-1. since a=-b, a=1

Answer:

[tex] 16 {x}^{4} {y}^{6} [/tex]

Step-by-step explanation:

[tex](4 {x}^{2} {y}^{3} {)}^{2} [/tex]

➡️ [tex] {4}^{2} \times ( {x}^{2} {)}^{2} \times ( {y}^{3} {)}^{2} [/tex]

➡️ [tex] = 16 {x}^{4} {y}^{6} [/tex] ✅

Answer:

Line A does not intersect line B.

Step-by-step explanation:

line A comes close, but does not touch, intersect, or overlap line A. hope this helps, please correct me if i am wrong.

Answer:

B is correct .trust me

Step-by-step explanation:

Answer:

554.7

Step-by-step explanation:

The pay=25.8*14+(25.8)*5*1.5=554.7

9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

  (iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

  x = 70

The angle marked y° is the supplement to the one marked 160°.

  y = 20

__

(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

  tan(∠BAC) = BC/BA = 120/100 = 1.2

  ∠BAC = arctan(1.2) ≈ 50.2°

__

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

  bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

__

(iv) The bearing of A from C is 180 added to the bearing of C from A:

  120 +180 = 300

The three-digit bearing of A from C is 300.

Answer:

65 m

Step-by-step explanation:

u = 6 m/s

v = 20 m/s

t = 5 s

[tex]s=\frac{1}{2} (6+20)5[/tex]

[tex]s=\frac{1}{2} (26)5[/tex]

[tex]s=(13)5[/tex]

[tex]s=65[/tex]

Hey there!

1/2(6 + 20)(5)

= 1/2 (26)(5)

1/2(26) = 13

= 13(5)

= 65

Therefore, your answer is most likely: 65m

Good luck on your assignment and enjoy your day!

~Amphitrite1040:)

Answer:

y=2

Step-by-step explanation:

A horizontal line has a slope of zero so the x term is zero

y = mx+b

y = b

y must equal a constant

Answer:

Step-by-step explanation:

Mean: sum of terms/ number of terms

4 + 2 + 3 + 1 + 1 + 5  = 16

Numbr of terms = 6

16/6 = 2.66

Answered by g a u t h m a th

Answer:

2 2/3

Step-by-step explanation:

The mean is the average of the values

The values on the graph are 4, 2, 3, 1, 1, and 5

Average is sum/number of values

4+2+3+1+1+5=16

16/6=2 2/3

Answer:

8 of the 11

Step-by-step explanation:

4+4=8 of the 11

Part of oranges usef from the orange packet used on 1st day = 4/11

Part of oranges used from the orange packet used on 2nd day = 4/11

Total part of oranges used from the orange packet

= (4/11) + (4/11)

= 8/11

So, Sipho's dad used 8 elevenths of the oranges.

The value of g across from angle G is 5feet

According to sine rule

[tex]\frac{e}{sinE}=\frac{f}{sinF}=\frac{g}{sinG}[/tex]

Given the following

∠G = 45°

∠F = 82°

f = 7feet

Required

side g

Substitute the given values into the formula

[tex]\frac{f}{sinF}=\frac{g}{sinG}\\ \frac{7}{sin82}=\frac{g}{sin45}\\\frac{7}{0.9903}=\frac{g}{0.7071}\\7.0686=\frac{g}{0.7071}\\g=7.0686*0.7071\\g=4.998\\g\approx5ft[/tex]

Hence the value of g across from angle G is 5feet

Learn more here: https://brainly.com/question/15018190

The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.

Let be [tex]EFG[/tex] a Triangle, whose expression derived from the Law of Sines is described below:

[tex]\frac{e}{\sin E} = \frac{f}{\sin F} = \frac{g}{\sin G}[/tex] (1)

Where:

[tex]e[/tex] - Measure of the line segment FG, in feet.

[tex]f[/tex] - Measure of the line segment EG, in feet.

[tex]g[/tex] - Measure of the line segment EF, in feet.

[tex]E[/tex] - Angle at vertex E, in sexagesimal degrees.

[tex]F[/tex] - Angle at vertex F, in sexagesimal degrees.

[tex]G[/tex] - Angle at vertex G, in sexagesimal degrees.

We can determine a missing length, by knowing the length of a neighboring side and two consecutive angles. If we know that [tex]f = 7\,ft[/tex], [tex]G = 45^{\circ}[/tex] and [tex]F = 82^{\circ}[/tex], then the measure of the line segment EF is:

[tex]g = f\cdot \left(\frac{\sin G}{\sin F} \right)[/tex] (2)

[tex]g = (7\,ft)\cdot \left(\frac{\sin 45^{\circ}}{\sin 82^{\circ}} \right)[/tex]

[tex]g\approx 4.998\,ft[/tex]

[tex]g \approx 5\,ft[/tex]

The length of the line segment EF ([tex]g[/tex]) is approximately 5 feet.

Answer:

Step-by-step explanation:

Any alteration to the x value means that the function will move right. There are no exceptions to this that  I can think of.

Answer:

56

Step-by-step explanation:

A=(3*4)+(4*(4+3+4))=56

Find the intersection of the two planes. Do this by solving for z in terms of x and y ; then solve for y in terms of x ; then again for z but only in terms of x.

-4x + 2y - z = 1   ==>   z = -4x + 2y - 1

3x - 2y + 2z = 1   ==>   z = (1 - 3x + 2y)/2

==>   -4x + 2y - 1 = (1 - 3x + 2y)/2

==>   -8x + 4y - 2 = 1 - 3x + 2y

==>   -5x + 2y = 3

==>   y = (3 + 5x)/2

==>   z = -4x + 2 (3 + 5x)/2 - 1 = x + 2

So if we take x = t, the line of intersection is parameterized by

r(t) = ⟨t, (3 + 5t )/2, 2 + t⟩

Just to not have to work with fractions, scale this by a factor of 2, so that

r(t) = ⟨2t, 3 + 5t, 4 + 2t⟩

(a) The tangent vector to r(t) is parallel to this line, so you can use

v = dr/dt = d/dt ⟨2t, 3 + 5t, 4 + 2t⟩ = ⟨2, 5, 2⟩

or any scalar multiple of this.

(b) (-1, -1, 1) indeed lies in both planes. Plug in x = -1, y = 1, and z = 1 to both plane equations to see this for yourself. We already found the parameterization for the intersection,

r(t) = ⟨2t, 3 + 5t, 4 + 2t⟩

Answer: sqrt 3V/pih = r

Step-by-step explanation:

3V = (pi r^2h)3

3V = pi r^2 h

3V/pih = r^2

Sqrt (3V/pi h) = r

Answer:

Hello,

Are you still alive ?

Step-by-step explanation:

a)

c=k*b (c varies directly as b)

6=k*2 ==> k=3 ( c = 6 when b = 2.)

[tex]\boxed{c=3*b }\\[/tex]

b)

b=14 ==> c=3*14=42

c)

c=39

[tex]b=\dfrac{c}{3} =\dfrac{39}{3} =13\\[/tex]

Answer:

Step-by-step explanation:

Answer:

11 weeks.

Step-by-step explanation:

227-106=121

121 divided by 11 = no. of weeks

Therefore it takes her 11 weeks.

Answer:

It will take 11 weeks

Step-by-step explanation:

11 times 11 is 121.

121 plus 106 is 227

which is the exact number the bike costs

Answer:

B = A/5h - b; You could use

B = (A - 5hb)/5h  This just puts everything over a common denominator.

Step-by-step explanation:

A = 5h (B + b)          Divide both sides by 5h

A/5h = B + b             Subtract b from both sides.

A/5h - b = B

Step-by-step explanation:

x=72

63+45+x=180

[tex]108 + x = 180[/tex]

[tex]x = 72[/tex]

Answer:

y=4x+3

m=4

b=3

Step-by-step explanation:

Since the equation is already solved for y, we don't have to do that. The equation is actually in slope-intercept form, where y=mx+b. m represents the slope, and b represents y-intercept.

Therefore, we can tell m=4 and b=3.

I have also included a picture of what the graph should look like.

Answer:

A. [tex]\frac{5}{13}[/tex]

Step-by-step explanation:

Hi there!

We are given right triangle PQR, with PR=5, RQ=12, and PQ=13

We want to find the value of sin(Q)

Let's first recall that sine is [tex]\frac{opposite}{hypotenuse}[/tex]

In reference to angle Q, PR is the opposite side, RQ is the adjacent side, and PQ is the hypotenuse

So that means that sin(Q) would be [tex]\frac{PR}{PQ}[/tex]

Substituting the values of PR and PQ gives sin(Q) as [tex]\frac{5}{13}[/tex], which is A

Hope this helps!

Answer:

Not a subspace

Step-by-step explanation:

(4,0,0) and (0,4,0) are vectors in R3 with zero or one entries being nonzero, but their sum, (4,4,0) has two nonzero entries.

Answer:

167.64 cm

Step-by-step explanation:

I dont kno how to work it out

[tex] \begin{cases} \\ \large\bf{\green{ \implies}} \tt \: - \: \frac{1}{2} \: m \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - \frac{1 \: m}{2} \: = \: - 9 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 9 \: \times \: 2 \\ \\ \large\bf{\green{ \implies}} \tt \: - 1m \: = \: - 18 \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{ \cancel- 18}{ \cancel - 1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: \frac{18}{1} \\ \\ \large\bf{\green{ \implies}} \tt \: m \: = \: 18 \: \\ \end{cases}[/tex]

Answer:

The AP is 1, 11/2, 10, 29/2, 19, ....

Step-by-step explanation:

Let the first term be a and d be the common difference of the arithmetic progression.

ATQ, a+2d+a+6d=38, 2a+8d=38 and a+8d=37. Solving this, we will get a=1 and d=9/2. The AP is 1, 11/2, 10, 29/2, 19, ....

Answer:

= 4

Step-by-step explanation:

first lets find the value of x in 3x+2=5/9

3x+2=5/9

3x = [tex]\frac{5}{9}[/tex] -2

3x = [tex]\frac{3}{9}[/tex]

3x = [tex]\frac{1}{2}[/tex]

x = [tex]\frac{1}{2 * 3\\ }[/tex]

x = [tex]\frac{1}{6}[/tex]

[tex]\frac{1}{6}[/tex] can also be written as [tex]6^{-1}[/tex]

−3x+8

-3 ([tex]\frac{1}{6}[/tex]) +8

[tex]\frac{-3}{6}[/tex] +8

= 4