Công thức xác định tuổi thọ KL
Which one is it------------------
Answer:
you're right
Step-by-step explanation:
As the number of copies increases, the dimensions of the images continue to decrease but never reach 0. Option A is correct.
As of the given statement,
Both copy machines reduce the dimensions of images that run through the machines. which statment is true is to be justified.
In mathematics, dimensions are the measurements of the size or distance of an item, region, or space in one direction. In layman's words, it is the measurement of something's length, width, and height. Length is the most commonly used dimension.
here,
Both copy machines diminish the size of images that pass through them. Which statement is correct must be justified. So, As the number of copies increases, the image dimensions drop but never reach zero.
Thus, the image dimensions decrease as the number of copies grows, but never reaches zero.
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a motercycle can travel 60 miles per gallon. approximently how many gallons of fuel will the motercycle need to travel 40 km
[1 mile = 1.6km]
Answer:
Step-by-step ex0.72
For the same random sample of adult women, with a sample mean height of x¯=64.3 inches and sample standard deviation of s=2.4 inches, use the Empirical Rule to determine the approximate percent of heights that lie between 59.5 inches and 69.1 inches.
Round your answer to the nearest whole number (percent).
Answer:
95%
Step-by-step explanation:
Mean , xbar = 64.3; standard deviation, s= 2.4
Using the empirical formula where ;
68% of the distribution is within 1 standard deviation from the mean ;
95% of the distribution is within 2 standard deviation from the mean
percent of heights that lie between 59.5 inches and 69.1 inches.
Number of standard deviations from the mean /
Z = (x - μ) / σ
(x - μ) / σ < Z < (x - μ) / σ
(59.5 - 64.3) / 2.4 < Z < (69.1 - 64.3) / 2.4
-2 < Z < 2
Thia is within 2 standard deviations of the means :
2 standard deviation form the mean = 95% according to the empirical rule.
A car is traveling at a rate of 80 miles per hour. Assume that 1 mile is equal to 1.6km.
what is the rate:. km/h
distance traveled in 3 hours: km
I think that car travelled 128 km in one hour and 384km in 3 hours
Answer: 384 km
Step-by-step explanation:
Convert m/ph to k/ph by multiplying the equivalent of 1 mile in kilometers
(1m = about 1.6km) by the total number of miles.
80 x 1.6 = 128
You now have the distance traveled per hour in m/ph converted to k/ph.
All you do now is multiply it by the time traveled:
(128 kilometers per one hour for 3 hours)
128 kph x 3 = 384km
PLS HELP!!!
Solve x^2 – 4 = 5 by graphing the related function.
A) There are two solutions: 3 and –3.
B) There are two solutions: ±1.
C) There is one solution: 1
D) There are no real number solutions.
Answer:
A
Step-by-step explanation:
Because we can rearrange the equation and get:
x²=5+4
x²=9
[tex]x = \sqrt{9} [/tex]
[tex]x = + 3 \: \: or \: \: - 3[/tex]
PLZ ANSWER QUESTION IN PICTURE
Answer: [tex](\frac{2}{5},0) ; (0,2)[/tex]
Step-by-step explanation:
(to find the x-intercept, plug in 0 for y)
(to find the y-intercept, plug in 0 for x)
[tex]0=-5x+2\\5x=2\\x=\frac{2}{5}\\(\frac{2}{5},0)\\y=-5(0)+2\\y=2 \\(0,2)[/tex]
Determine whether or not the given procedure results in a binomial distribution. If not, identify which condition is not met. Spinning an American roulette wheel 8282 times and recording the number the ball lands on.
Answer:
No, binomial distribution cannot be applied.
Step-by-step explanation:
We known that a Binomial Distribution depends on provided experiment , a binomial distribution have only 2 outcomes. For example, when we flip a coin in the air, then the possible outcomes are Head and Tail.
But in the context, an American roulette wheel has [tex]37[/tex] outcomes. It means when we spin the American Roulette wheel, ball may lend on any of the numbers between 0 to 36. So there are more than [tex]2[/tex] outcomes.
Therefore, binomial distribution can not be applied here.
The coordinates of the preimage are:
A(−8,−2)
B(−4,−3)
C(−2,−8)
D(−10,−6)
Now let’s find the coordinates after the reflection over the x-axis.
A′(−8,
)
B′(−4,
)
C′(−2,
)
D′(−10,
)
And now find the coordinates after the reflection over the y-axis.
A′′(
,2)
B′′(
,3)
C′′(
,8)
D′′(
,6)
This is also the same as a rotation of 180∘.
9514 1404 393
Answer:
A'(-8, 2) ⇒ A"(8, 2)B'(-4, 3) ⇒ B"(4, 3)C'(-2, 8) ⇒ C"(2, 8)D'(-10, 6) ⇒ D"(10, 6)Step-by-step explanation:
Reflection over the x-axis changes the sign of the y-coordinate. Reflection over the y-axis changes the sign of the x-coordinate. We can summarize the transformations as ...
preimage point ⇒ reflection over x ⇒ reflection over y
A(−8,−2) ⇒ A'(-8, 2) ⇒ A"(8, 2)
B(−4,−3) ⇒ B'(-4, 3) ⇒ B"(4, 3)
C(−2,−8) ⇒ C'(-2, 8) ⇒ C"(2, 8)
D(−10,−6) ⇒ D'(-10, 6) ⇒ D"(10, 6)
which of the rolling equations have exactly one solutions ?
ps: (click the picture to see answer choices)
Answer:
All have exactly one solution
Step-by-step explanation:
a) -13x + 12 = 13x - 13
+13x +13x
-------------------------------
12 = 26x - 13
+13 +13
-------------------
25 = 26x
----- ------
26 26
25/26 = x
b) 12x + 12 = 13x - 12
-12x -12x
-----------------------
12 = x - 12
+12 +12
-----------------
24 = x
c) 12x + 12 = 13x + 12
-12x -12x
-----------------------------
12 = x + 12
0 = x
d) -13x + 12 = 13x + 13
+13x +13x
-----------------------------
12 = 26x + 13
-13 -13
-----------------------
-1 = 26x
--- -----
26 26
-1/26 = x
forty-five percent of the students in a dorm are business majors and fifty-five percent are non-business majors. business majors are twice as likely to do their studying at the library as non-business majors are. half of the business majors study at the library. if a randomly slected student from the dorm studies at the library, what is the probability the student is a business major
Solution :
Defining the following events as :
B : Being a Business major
α : Studying at the library
∴ Given that :
[tex]$P(B) = \frac{45}{100}$[/tex]
= 0.45
Again, P [ Studying at the library | Being a Business major ] = 2 P [ Studying at the library | Being a non business major ]
[tex]$P[ \alpha | B] = 2 P[\alpha | B^C]$[/tex] .......(1)
Again,
[tex]$P[\text{Studying at the library } | \text{ Being a business major}] = \frac{1}{2} = 0.50$[/tex]
[tex]$P(\alpha | B) = 0.50$[/tex]
From (1), we get
[tex]$P(\alpha | B^C) = \frac{1}{2} . P(\alpha | B)$[/tex]
[tex]$=\frac{1}{2} \times 0.50$[/tex]
= 0.25
Therefore, we need,
= P[ The students is a Business major | The student studies at the library ]
[tex]$=P(B | \alpha)$[/tex]
By Bayes theorem
[tex]$=\frac{P(B). P(\alpha | B)}{P(B).P(\alpha | B) + P(B^C). P(\alpha | B^C)}$[/tex]
[tex]$=\frac{0.45 \times 0.50}{0.45 \times 0.50 + 0.55 \times 0.25}$[/tex]
= 0.6207
if a/b = 3 and a + b = 2, what is a - b
Answer:
1
Step-by-step explanation:
a/b=3------equation 1
a+b=2-----equation 2
from equation 2
b=2-a
substitute b=2-a in equation 1
a/2-a=3
a=3(2-a)
a=6-3a
a+3a=6
a=6/4
a=3/2
substitute a=3/2 in equation 2
3/2+b=2
3+2b=4
2b=1
b=1/2
a-b=3/2-1/2
a-b=(3-1)/2
a-b=2/2
a-b=1
For a standard normal distribution, find:
P(z > c) = 0.058
Find c.
Answer:
1.572
Step-by-step explanation:
For a standard normal distribution,
P(z > c) = 0.058
To obtain C ; we find the Zscore corresponding to the proportion given, which is to the right of the distribution ;
Using technology or table,
Zscore equivalent to P(Z > c) = 0.058 is 1.572
Hence, c = 1.572
Is segment AB tangent to circle O shown in the diagram, for AB = 8, OB = 3.75, and AO = 10.25. Explain your reasoning and show all work in your own words. (The figure is not drawn to scale.)
9514 1404 393
Answer:
not tangent
Step-by-step explanation:
AB will be tangent to circle O if AB ⊥ BO. That can be tested by checking to see if AB, BO, and AO satisfy the Pythagorean theorem.
According to the Pythagorean theorem, the length of the hypotenuse of a right triangle with legs 3.75 and 8 will be ...
hypotenuse = √(3.75² +8²) = √78.0625 ≈ 8.835
The length of AO is somewhat greater than that, so AB cannot be a tangent to the circle.
__
The angle ABO is obtuse.
A one lane highway runs through a tunnel in the shape of one half a sine curve cycle
The sine curve equation, y = 10·sin(x·π/24), that models the entrance of the
tunnel with a cross section that is the shape of half of a sine curve and the
height of the tunnel at the edge of the road, (approximately 7.07 ft.) are
found by applying the following steps
(a) The equation for the sine curve is y = 10·sin(x·π/24)
(b) The height of the tunnel at the edge of the road is approximately 7.07 feet
The reason for the above answers are presented as follows;
(a) From a similar question posted online, the missing part of the question
is, what is the height of the tunnel at the edge of the road
The known parameters;
The shape of the tunnel = One-half sine curve cycle
The height of the road at its highest point = 10 ft.
The opening of the tunnel at road level = 24 ft.
The unknown parameter;
The equation of the sine curve that fits the opening
Method;
Model the sine curve equation of the tunnel using the general equation of a sine curve;
The general equation of a sine curve is y = A·sin(B·(x - C) + D
Where;
y = The height at point x
A = The amplitude = The distance from the centerline of the sine wave to the top of a crest
Therefore;
The amplitude, A = The height of half the sine wave = The height of the tunnel = 10 ft.
D = 0, C = 0 (The origin, (0, 0) is on the left end, which is the central line)
The period is the distance between successive points where the curve passes through the center line while rising to a crest
Therefore
The period, T = 2·π/B = 2 × Opening at the road level = 2 × 24 ft. = 48 ft.
T = 48 ft.
We get;
48 = 2·π/B
B = 2·π/48 = π/24
By plugging in the values for A, B, C, and D, we get;
y = 10·sin((π/24)·(x - 0) + 0 = 10·sin(x·π/24)
The equation of the sine curve that fits the opening is y = 10·sin(x·π/24)
(b) The height of the tunnel at the edge of the road is given by substituting
the value of x at the edge of the road into the equation for the sine curve
as follows;
The width of the shoulders = 6 feet
∴ At the edge of the road, x = 0 + 6ft = 6 ft., and 6 ft. + 12 ft. = 18 ft.
Therefore, we get;
y = 10 × sin(6·π/24) = 10 × sin(π/4) = 5×√2
y = 10 × sin(18·π/24) = 10 × sin(3·π/4) = 5×√2
The height of the, y, tunnel at the edge of the road where, x = 6, and 18 is y = 5·√2 feet ≈ 7.07 ft.
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In the graph above, which vertical line (V) and horizontal line (H) can be used to graph point A?
A)
V: x = 1; H: y = 4
B)
V: x = 4; H: y = 1
C)
V: y = 4; H: x = 1
D)
V: x = 1; H: y = –4
Answer:
V: x = 1; H: y = 4
Step-by-step explanation:
Point A is at x = 1 and y = 4
A vertical line at x=1 and a horizontal line at y = 4
1. Choose the correct decimal for "three tenths."
3
0.03
0.003
0.3
Please hurry, if you do reply thank u, it means alot! <3 :)
Answer:
3 tenths means 3 over ten represented as as 3/10 and 10 has one zero I.e tenth different from hundredths which has 2 zeros so our decimal shld also have one zero which is 0.3...so 0.3 is the answe hope it helps❤
In a survey conducted at a pet store, 150 customers were asked if they owned
birds or fish. The survey data are shown in the relative frequency table.
Answer:
12% percent of fish in own
The % of people surveyed own fish is 12%.
To find the % of people surveyed own fish.
What is relative frequency?Relative frequency refers to the percentage or proportion of times that a given value occurs within a set of numbers, such as in the data recorded for a variable in a survey data set.
Given that:
In a survey conducted at a pet store, 150 customers were asked if they owned birds or fish.
By the data on the table:
Total (own fish) = 0.04 + 0.08 = 0.12
So, own fish = 0.12
=12/100= 12%
So, 12% of the people surveyed own fish.
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Consider the probability that at most 85 out of 136 DVDs will work correctly. Assume the probability that a given DVD will work correctly is 52%. Specify whether the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.
Answer:
Since both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the necessary conditions are satisfied.
0.9945 = 99.45% probability that at most 85 out of 136 DVDs will work correctly.
Step-by-step explanation:
Test if the normal curve can be used as an approximation to the binomial probability by verifying the necessary conditions.
It is needed that:
[tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex]
Binomial probability distribution
Probability of exactly x successes on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].
Assume the probability that a given DVD will work correctly is 52%.
This means that [tex]p = 0.52[/tex]
136 DVDs
This means that [tex]n = 136[/tex]
Test the conditions:
[tex]np = 136*0.52 = 70.72 \geq 10[/tex]
[tex]n(1-p) = 136*0.48 = 65.28 \geq 10[/tex]
Since both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex], the necessary conditions are satisfied.
Mean and standard deviation:
[tex]\mu = E(X) = np = 136*0.52 = 70.72[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{136*0.52*0.48} = 5.83[/tex]
Consider the probability that at most 85 out of 136 DVDs will work correctly.
Using continuity correction, this is [tex]P(X \leq 85 + 0.5) = P(X \leq 85.5)[/tex], which is the p-value of Z when X = 85.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{85.5 - 70.72}{5.83}[/tex]
[tex]Z = 2.54[/tex]
[tex]Z = 2.54[/tex] has a p-value of 0.9945.
0.9945 = 99.45% probability that at most 85 out of 136 DVDs will work correctly.
Sarah has two similar rectangular boxes. The dimensions of Box 1 are four times those of Box 2.
How many times greater is the surface area of Box 1 than the surface area of Box 2?
8
64
4
16
Answer:
16
Step-by-step explanation:
an area is always calculated by multiplying 2 dimensions.
when changing the dimensions, then the change factors for EACH dimension go into the calculation too.
therefore, when both dimensions of an area are enlarged 4 times, then the area is enlarged 4×4 = 16 times.
this just propagates to the whole surface area of an object, as each individual area of the overall surface area is enlarged by the same factor. and so, the sum of all the individual areas (= altogether the surface area of the object) is also enlarged in total by the same factor.
just think
16×a + 16×b + 16×c ... = 16×(a+b+c+...)
and you understand why.
For rehab after an injury a patient walks 200m on the first day each day he will increase the amount walked by 100m. How many total kilometers will the patient have walked after 12 days
Answer:
3.3km
Step-by-step explanation:
200m on first day
Increase 200 by 100 = 300 (200+100)
From 2nd day to 11th day
300×11
3300m
If 1000m = 1km
3300m =?
3300/1000
3.3km
I hope it helps
A student decides she wants to save money to buy a used car, which costs $2600.She comes upwith what she thinks is a very modest savings plan. She decides to save 2 cents the first day anddouble the amount she saves each day thereafter. On the second day she plans to save 4 cents, onthe third day, 8 cents, and so on.
(a)Write an expression that represents the amount savedon dayn;(b)Write an expression that represents the total amount savedby dayn (including day n);(c)Determine how long it will take her to save enough money to buy the car (The answermay surprise you!)
Answer: total cost to be saved is $2600. Her saving pattern is 2, 4, 8,…
a) The pattern of her saving is in geometric sequence. i.e. a=2, r=4/2=2 0r 8/4=2 ( a = First term, r = common ratio) so, expression for amount saved on day (n) = t(n) = ar^(n-1), where: a = first day of saving r = common ration n = number of day
b) Expression that represents the total amount saved by day (n) (including day n) = S = a(r^n-1)/r-1 where: S = sum of amount saved a = first day of saving r = common ration n = number of day
c) To buy the car, she needs at least $2600 which is equal 260000 cents. S = a(r^n-1)/r-1 = 260000 = 2(2^n-1)/r-1 = 260000/2 = 2^n-1/2-1 = 130000 = 2n^-1 = 130000+1 = 2^n = 130001 = 2^n = n = ln(130001)/ln(2) = n = 16.988
So… for n to satisfy the least value of 130001 cents, n should be at least 17 Therefore it will take at least 17 days for her to save enough money to buy a car
Step-by-step explanation:
It will take her about 17 days to buy the car worth 260000 cents
If a student decides she wants to save money to buy a used car that cost $2600 (260,000 cents)
If she saves 2 cents the first day and doubles the amount thereafter, the sequence of savings will be:
2, 4, 8...
This sequence is geometric in nature
In order to determine how long it will take her to save 260,000, we will use the sum of a GP formula expressed as:
[tex]S_n = \frac{a(r^n-1)}{r-1}[/tex]
Given the folowing
a = 2
r = 4/2 = 8/4 = 2
Sn = 260,000
Substitute into the formula the given parameters
[tex]260000= \frac{2(2^n-1)}{2-1}\\260000/2=2^n-1\\130000 = 2^n - 1\\2^n = 130000 + 1\\2^n = 130001\\nlog 2=log130001\\n = \frac{log130001}{log2} \\n \approx 17[/tex]
This shows that it will take her about 17 days to buy the car worth 260000 cents
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Determine whether the following events are mutually exclusive. Choosing a student who is a French major or a chemistry major from a nearby university to participate in a research study. (Assume that each student only has one major.)
A. Mutually Exclusive
B. Not Mutually Exclusive
Answer:
A. Mutually Exclusive
Step-by-step explanation:
Mutually exclusive events:
Two events are mutually exclusive if they cannot happen together, that is, supposing the events are A and B:
[tex]P(A \cap B) = 0[/tex]
Choosing a student who is a French major or a chemistry major
Since each student only has one major, the student cannot be both a French and a Chemistry major, that is, [tex]P(A \cap B) = 0[/tex], so they are mutually exclusive and the correct answer is given by option A.
Algebra two divide plz help
Answer:
- x³ - 2x² + 3 - 1 / x
Step-by-step explanation:
(4x³ - 8x² + 12x - 4) / (-4x)
- x³ - 2x² + 3 - 1 / x
What is the conjugate of
square root 8 - square root 9
Answer:
[tex]\sqrt{8}+\sqrt{9}[/tex]
Step-by-step explanation:
By definition, the conjugate of a binomial is when you switch the operator (either + or -) in between the terms. For example, the conjugate of [tex]a+b\sqrt{c}=a-b\sqrt{c}[/tex] as we are just changing the addition symbol (+) to a subtraction symbol (-).
Therefore, the conjugate of [tex]\sqrt{8}-\sqrt{9}[/tex] occurs when we change the subtraction symbol to an additional symbol, hence the answer is [tex]\boxed{\sqrt{8}+\sqrt{9}}[/tex]
write the first 10 multiplies of 6 and 8 pairs of numbers and find this LCM
↪[tex] \huge\rm{answer: } \: \boxed{ \purple{24 }}[/tex]
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
M(6)= {0, 6, 12, 18, 24, 30, 36, 42, 48, 54, 60 ...}
M(8) = {0, 8, 16, 24, 32, 40, 48, 56, 64, 72, 80...}
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
I hope you understood!✏
➖➖➖➖➖➖➖➖➖➖➖➖➖➖➖
[tex] \huge\boxed{ \boxed{ \rm{Hope \: this \: helps }}}[/tex]
Answer:
6=0,6,12,18,24,30,36,42,48,54,60
8=0,8,16,24,32,40,48,56,64,72,80
HCF=24,48
LCM=0,6,12,18,,30,36,42,48,54,60,8,16,24,32,40,,56,64,72,80
A brewery has a beer dispensing machine that dispenses beer into the company's 12 ounce bottles. The distribution for the amount of beer dispensed by the machine follows a normal distribution with a standard deviation of 0.17 ounce. The company can control the mean amount of beer dispensed by the machine. What value of the mean should the company use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount on the label)
Answer:
The company should use a mean of 12.37 ounces.
Step-by-step explanation:
Normal Probability Distribution
Problems of normal distributions can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.
The distribution for the amount of beer dispensed by the machine follows a normal distribution with a standard deviation of 0.17 ounce.
This means that [tex]\sigma = 0.17[/tex]
The company can control the mean amount of beer dispensed by the machine. What value of the mean should the company use if it wants to guarantee that 98.5% of the bottles contain at least 12 ounces (the amount on the label)?
This is [tex]\mu[/tex], considering that when [tex]X = 12[/tex], Z has a p-value of [tex]1 - 0.985 = 0.015[/tex], so when [tex]X = 12, Z = -2.17[/tex].
Then
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-2.17 = \frac{12 - \mu}{0.17}[/tex]
[tex]12 - \mu = -2.17*0.17[/tex]
[tex]\mu = 12 + 2.17*0.17[/tex]
[tex]\mu = 12.37[/tex]
The company should use a mean of 12.37 ounces.
Does this appear to be a regular polygon? Explain using the definition of a regular polygon.
Answer:
yes it is. a polygon is any closed shape with at least 3 connected lines (eg. triangle, square, pentagon, hexagon, heptagon, octagon, etc)
Step-by-step explanation:
What is (4n + 3n2 + 2) - (n - 6n
+1) simplified?
A -3n2 + 3n-2 C 9n2 + 3 + 2
B 3n2 + 3n + 2 D 9n2 + 3n + 1
C 9n2 + 3n + 2
D 9n2 + 3n + 1
Step-by-step explanation:
4n + 3n2 + 2 + n + 6n – 1 Expand with – 1
3n2 + 4n + n + 6n + 2 – 1 Grouped liked terms
3n2 + 11n – 1
Destiny just received two separate gifts from her great-great-grandmother.
The first gift is a box of 18 chocolate candy bars, and the second gift is a pack of 12 cookies.
Destiny wants to use all of the chocolate candy bars and cookies to make identical snack bags for her cousins.
What is the greatest number of snack bags that Destiny can make?
Answer:
Destiny will be able to create 12 identical snack bags.
Step-by-step explanation:
Given that a snack bag will be 1 chocolate candy bar, and 1 cookie, we have to subtract 1 chocolate for every cookie she has, and that will leave us with 6 chocolate bars left. The equation for this is 18 - 12 = 6.
A rectangular floor is 9 yards long and 3 yards wide. What is the area
