Answer:
The gravitational potential energy of the 8.6 kg mass is 5.38x10⁸ J.
Explanation:
We can find the gravitational potential energy of the mass using the following equation:
[tex] E_{p} = m*g*h [/tex]
Where:
m: is the mass = 8.6 kg
g: is the gravity = 9.81 m/s^{2}
h: is the height = Earth's radius = 6371 km
Hence, we have:
[tex]E_{p} = 8.6 kg*9.81 m/s*6371000 m = 5.38 \cdot 10^{8} J[/tex]
Therefore, the gravitational potential energy of the 8.6 kg mass is 5.38x10⁸ J.
I hope it helps you!
Plz help ASAP I will give brainliest PLZ
The weight of a bucket is 186 N. The bucket is being raised by two ropes. The free-body diagram shows the forces acting on the bucket.
A free body diagram with 3 force vectors. The first vector is pointing downward, labeled F Subscript g Baseline = 186 N. The second vector is pointing up, labeled F Subscript 1 Baseline 105 N. The third vector is pointing upward from the tip of the second using the tail to tip method, labeled F Subscript 2 Baseline = 115 N. The combined two vectors pointing upward are shorter than the one pointing downward.
The acceleration of the bucket, to the nearest tenth, is
m/s2.
Answer:
1.8m/s^2
Explanation:
Since the two ropes are going up, their combined force is 105+115=220N. With a gravitational force of 186N, the force of the two ropes pulling up the will be 220-186=34N.
Now we need the mass of the bucket itself in order to find the acceleration of the bucket (remember that F=ma and m is needed to find a). Since gravitational acceleration is 9.8m/s^2 and F=186N, 186/9.8=18.97959184 kg for the mass of the bucket.
Now that we have the mass of the bucket, we can find the acceleration of the bucket. Since F=34N from earlier, 34N/18.97959184kg=1.791397849m/s^2=1.8m/s^2 is the acceleration of the bucket.
Therefore, 1.8m/s^2 is the correct answer.
Please mark brainliest!
Answer:
1.8
Explanation:
honestly i jus took the test
An 11-kilogram cart is pulled with a horizontal force at a constant velocity of 8.0 meters per second, as shown in the diagram. The force of friction between the cart and the floor is 12 newtons. What is the magnitude of the horizontal force?
The cart is pulled at a constant velocity, so it is in equilibrium. In particular, the net horizontal force is zero, and consists of only the pulling force and friction such that
p - f = 0
where p and f denote the magnitudes of the pulling force and friction.
So we have
p - 12 N = 0
p = 12 N
A man steps off a diving platform lands in the water below. If he were to miss the water and land on the concrete, his change in momentum would be the same as if he landed in the water. Why is the change in momentum the same for both situations?
Answer:
if he were to land on concrete, he would most likely die and stop all momentum and for the water, he'd most likely live/die (mostly live) and slow momentum to a stop and rise up to the surface
Explanation:
that's the explanation now i gotta execute order 66
A syringe has a fine needle with an inside diameter of 109μm. The barrel has a diameter of 2.22cm and is filled with water. Calculate the velocity of water as it squirts horizontally from the needle if you apply a force of 3.24N onto the plunger. (Hint: you may approximate the area of the barrel to be much larger than the area of the needle).
Answer: the velocity of water as it squirts horizontally from the needle is 4.09196 m/s
Explanation:
Given that;
inside diameter = 109μm
barrel diameter = 2.22 cm so r = 1.11 cm = 0.0111 m
force fair = 3.24 N
We know that the inside diameter is neglected; from the Bernoulli's equation
so
P_inside + 1/2pv²_inside + egy_inside = P_outside + 12pv²_outside + egy_outside
p_inside - p_outside = 1/2e_airv²outside = Fair / Abannel
Fair = 1/2painv²outside . Abannel
therefore
3.24 = 1/2(1000) v²outside (πr²)
3.24 = 1/2(1000) v²outside (π × (0.0111)²
3.24 = 0.1935 v²_outlet
v²_outlet = 3.24 / 0.1934
v²_outlet = 16.7441
v_outlet = √16.7441
v_outlet = 4.09196 m/s
Therefore the velocity of water as it squirts horizontally from the needle is 4.09196 m/s
What is the wavelength of an FM radio wave of frequency 90Mhz?
a) 0.033m
b) 0.3m
c) 3.3m
d) 30m
Show calculation
Answer:
3.3m
Explanation:
Given parameters:
Frequency = 90Mhz
Unknown:
Wavelength = ?
Solution:
To find the wavelength, use the expression below;
V = f x wavelength
V is the speed of light = 3 x 10⁸m/s
f is the frequency
Now;
Insert the parameters
3 x 10⁸ = 90 x 10⁶ x wavelength
Wavelength = [tex]\frac{3 x 10^{8} }{9 x 10^{7} }[/tex] = 3.3m
You stand on a merry-go-round which is spinning at f = 0.25 revolutions per
second. You are R = 200 cm from the center.
(a) Find the angular speed ω at which it is spinning.
[3 marks]
(b) Find the centripetal acceleration, ac with which it is spinning. [3 marks]
(c) What is the minimum coefficient of static friction µs between your shoes and
the floor that will keep you from slipping off?
[4 marks]
Answer:
(a) ω = 1.57 rad/s
(b) ac = 4.92 m/s²
(c) μs = 0.5
Explanation:
(a)
The angular speed of the merry go-round can be found as follows:
ω = 2πf
where,
ω = angular speed = ?
f = frequency = 0.25 rev/s
Therefore,
ω = (2π)(0.25 rev/s)
ω = 1.57 rad/s
(b)
The centripetal acceleration can be found as:
ac = v²/R
but,
v = Rω
Therefore,
ac = (Rω)²/R
ac = Rω²
therefore,
ac = (2 m)(1.57 rad/s)²
ac = 4.92 m/s²
(c)
In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:
Centripetal Force = Frictional Force
m*ac = μs*R = μs*W
m*ac = μs*mg
ac = μs*g
μs = ac/g
μs = (4.92 m/s²)/(9.8 m/s²)
μs = 0.5
what is the mass of the 40 kg object on the moon?
Answer:
6.64 Newtons
On the moon that 40 kg child would have a weight of 6.64 Newtons (kg multiplied by gravity) because the moon's gravity is 1/6th of the Earth's gravity. Your mass on any planet on the solar system (Jupiter, Venus, Earth, or anywhere else) is the same because the amount of matter in you does not change.
Explanation:
Find the y-component of this
vector:
Answer:
Dy = 49.01 [m]
Explanation:
The vertical component of the vector can be determined with the sine of the angle.
Dy = 92.5*sin(32)
Dy = 49.01 [m]
Kate is creating two models to describe the effect of thermal energy on the movement of particles in a liquid. She draws the first model of a liquid sample. Her model is shown below.
Explanation:
so sorry
don't know but please mark me as brainliest please
Give one suggestion how to increase the velocity of water rocket?
Answer:
Streamline the body of the rocket to reduce drag
Keep weight to a minimum
Use higher pressures
Use the right amount of water
Nicolas is playing with his toy car. A parachute in the back of the car is released to help slow down the car.
If the forces act on the car as shown in the picture, what is the net force?
Answer:3 N —->
Explanation:
In the case when the forces act on the car as shown in the picture so here the net force should be 3N.
Calculation of the net force:Since
A parachute in the back of the car is released to help slow down the car.
So here the net force should be
= 10 N - 7N
= 3 N
Hence, In the case when the forces act on the car as shown in the picture so here the net force should be 3N.
Learn more about force here: https://brainly.com/question/21422036
To overcome an object's inertia, it must be acted upon by __________. A. gravity B. energy C. force D. acceleration
_________ players per team are allowed to be on the floor at a time during a game.
Group of answer choices
1
5
7
10
Answer:
5
Explanation:
Answer:
5
Explanation:
A projectile is launched straight upward at 50 m/s. Neglecting air resistance its speed upon returning to its starting point is:________.
Answer:
The speed of the projectile upon returning to its starting point is 50 m/s.
Explanation:
Given;
initial velocity of the projectile, u = 50 m/s
The velocity of the projectile is maximum before hitting the ground. As the object moves upward, the velocity reduces as it approaches the maximum height, at the maximum height the velocity becomes zero. Also, as the object moves downward, the velocity starts to increase and becomes maximum before hitting the ground.
Therefore, the speed of the projectile upon returning to its starting point is 50 m/s.
You accidentally drop a watch from the roof of a six-story building. While picking up the watch , you notice that it stopped 2s after it was dropped. How tall is the building?
Answer:
20 m
Explanation:
Area under the speed-time graph = Distance Traveled
Area under Graph 1/2(2)(20)
=20 m
1. A curious physics student drops a book from a high building.
A. What is the VELOCITY of the brick after 3.0s?
B. How FAR(Distance) does the book fall during this time?
2. Suppose a free-fall ride at an amusement park starts at a rest and then drops.
A. What is the VELOCITY of the ride after 2.5s?
B. How FAR do people on the ride fall during the 2.5s time period?
3. You throw a ball downward from a window at a speed of 3.0 m/s.
A. How FAST will it be moving when it hits the sidewalk 2.0m below?
4. If I drop a photo copier off of a 45m tall building and splats on the ground below:
A. Calculate the TIME to hit the ground:
B. Calculate the VELOCITY just before:
Answer:
1.
A. Vf = 29.4 m/s
B. h = 44.1 m
2.
A. Vf = 24.5 m/s
B. h = 30.625 m
3.
A. Vf = 5.5 m/s
4.
A. t = 3.03 s
B. Vf = 29.7 m/s
Explanation:
1.
A.
using 1st equation of motion:
Vf = Vi + gt
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s (since, book starts from rest)
g = 9.8 m/s²
t = time = 3 s
Therefore,
Vf = 0 m/s + (9.8 m/s²)(3 s)
Vf = 29.4 m/s
B.
using 2nd equation of motion:
h = Vi t + (1/2)gt²
h = (0 m/s)(3 s) + (1/2)(9.8 m/s²)(3 s)²
h = 44.1 m
2.
A.
using 1st equation of motion:
Vf = Vi + gt
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 0 m/s (since, book starts from rest)
g = 9.8 m/s²
t = time = 2.5 s
Therefore,
Vf = 0 m/s + (9.8 m/s²)(2.5 s)
Vf = 24.5 m/s
B.
using 2nd equation of motion:
h = Vi t + (1/2)gt²
h = (0 m/s)(2.5 s) + (1/2)(9.8 m/s²)(2.5 s)²
h = 30.625 m
3.
A.
using 3rd equation of motion:
2gh = Vf² - Vi²
where,
Vf = Final Velocity = ?
Vi = Initial Velocity = 3 m/s
g = 9.8 m/s²
h = height = 2 m
Therefore,
2(9.8 m/s²)(2 m) = Vf² - (3 ms)²
Vf² = 39.2 m²/s² - 9 m²/s²
Vf = √30.2 m²/s²
Vf = 5.5 m/s
4.
A.
using 2nd equation of motion:
h = Vi t + (1/2)gt²
where,
h = height = 45 m
Vi = Initial Velocity = 0 m/s (since, photo copier was initially at rest)
t = time = ?
g = 9.8 m/s²
45 m = (0 m/s)(t) + (1/2)(9.8 m/s²)(t)²
t² = 2(45 m)/(9.8 m/s²)
t = √9.18 s²
t = 3.03 s
B.
using 1st equation of motion:
Vf = Vi + gt
Vf = 0 m/s + (9.8 m/s²)(3.03 s)
Vf = 29.7 m/s
How much work is done when you push a table with 300 N of force 5 m across a room?
Help me , what is the properties of fluids ?
The properties of fluids are Density,Viscosity,Temperature, Pressure,Specific Volume,Specific Weight,Specific Gravity.
Which method of heat transfer transmits heat from the lower layers of air to the upper layers of air as the lower layers of air warm up and rise and replace the upper layers of air that cool off and sink down?
Answer:
Convection
Explanation:
The method of heat transfer that allows heat to rise via vertical transport of heated part of a fluid (gas or liquid) and replace the fluid upper layers is called "convection"
Answer:
Convection
Explanation:
Its Convection
Which safety rule is MOST important when smelling the product of a chemical reaction?
Group of answer choices
Keep nose directly above open container.
Hold with tongs
Wear closed -toed shoes.
use a wafting motion.
Answer:
group of answer choices
Explanation:
What is the magnitude of the applied electric field inside an aluminum wire of radius 1.5 mm that carries a 5.5-A current?
Answer:
E = 2.17 x 10⁻² V/m
Explanation:
First we will find out the current density by using the formula:
J = I/A
where.
J = Current Density = ?
I = Current = 5.5 A
A = Cross-Sectional Area = πr² = π(1.5 x 10⁻³ m)² = 7.068 x 10⁻⁶ m²
Therefore,
J = 5.5 A/7.068 x 10⁻⁶ m²
J = 0.778 x 10⁶ A/m²
Now, we calculate the magnitude of applied field:
E = ρJ
where,
E = Magnitude of applied field = ?
ρ = resistivity of Aluminum = 2.8 x 10⁻⁸ Ω.m
Therefore,
E = (2.8 x 10⁻⁸ Ω.m)(0.778 x 10⁶ A/m²)
E = 2.17 x 10⁻² V/m
A 2.00 kg mass is located at (4.00 m, 0.00 m, 0.00 m) and a 4.00 kg mass is located at (0.00 m, 3.00 m, 0.00 m). If this system of masses rotated about the Z-axis perpendicular to the X-Y plane, then the moment of inertia of this system is:_______
Answer:
The moment of inertia of this system is 68 kilogram-square meters.
Explanation:
We have two particles rotating about the z-axis, which is orthogonal to xy plane, the moment of inertia of the system ([tex]I_{z}[/tex]), measured in kilogram-square meters, is determined by the following formula:
[tex]I_{z} = \Sigma \limits_{i=1}^{2}m_{i}\cdot r_{i}[/tex] (1)
Where:
[tex]m_{i}[/tex] - Mass of the i-th particle, measured in kilograms.
[tex]r_{i}[/tex] - Distance of the i-th particle from axis of rotation, measured in meters.
By Pythagorean Theorem we calculate each distance:
[tex](x_{1}, y_{1}, z_{1}) = (4\,m, 0\,m,0\,m)[/tex]
[tex]r_{1}=\sqrt{(4\,m-0\,m)^{2}+(0\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]
[tex]r_{1} = 4\,m[/tex]
[tex](x_{2},y_{2}, z_{2}) = (0\,m, 3\,m, 0\,m)[/tex]
[tex]r_{2} = \sqrt{(0\,m-0\,m)^{2}+(3\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]
[tex]r_{2} = 3\,m[/tex]
If we know that [tex]m_{1} = 2\,kg[/tex], [tex]r_{1} = 4\,m[/tex], [tex]m_{2} = 4\,kg[/tex] and [tex]r_{2} = 3\,m[/tex], then the moment of inertia of the system is:
[tex]I_{z} = m_{1}\cdot r_{1}^{2}+m_{2}\cdot r_{2}^{2}[/tex] (1b)
[tex]I_{z} = (2\,kg)\cdot (4\,m)^{2}+(4\,kg)\cdot (3\,m)^{2}[/tex]
[tex]I_{z} = 68\,kg\cdot m^{2}[/tex]
The moment of inertia of this system is 68 kilogram-square meters.
Net force causes motion.
Answer: If you want me to write them for you here they are
Explanation:
Net force causes change in motion because a net external force causes a change in motion; thus, we see that a net external force causes acceleration.
Not more likely to be Net force motion because if it doesnt say change then its gonna stay the same so Net force does cause change in a motion because take for example if you are going to bounce a basketball its gonna change its position from one place to another thats how Net force causes Change in motion.
Hope this helps :)
help me please answer this
Answer:
that's fusion
Explanation:
Answer:
the answer is fusion for this
A 20kg block slides a cross a horizontal surface. If the coefficient of kinetic friction between the block and the surface is 0.20, what is the force of kinetic friction that acts on the block?
Compute the block's weight:
w = m g = (20 kg) (9.8 m/s²) = 196 N
The net vertical force is 0, so the normal force has the same magnitude:
n + (-w) = 0 → n = 196 N
The frictional force (mag. f ) is proportional to the normal force by a factor of µ = 0.20 such that
f = 0.20 (196 N) = 39.2 N ≈ 39 N
The force of kinetic friction acting on the block of mass 20 Kg having a coefficient of kinetic friction of 0.2 is 39.2 N
We'll begin by calculating the the normal reaction (N). This can be obtained as follow:Mass (m) = 20 Kg
Acceleration due to gravity (g) = 9.8 m/s²
Normal reaction (N) =?N = mg
N = 20 × 9.8
N = 196 NFinally, we shall determine the force of kinetic friction. This can be obtained as follow:Coefficient of kinetic friction (µ) = 0.2
Normal reaction (N) = 196
Force of kinetic friction (F) =?F = µN
F = 0.2 × 196
F = 39.2 NTherefore, the force of kinetic friction acting on the block is 39.2 N
Learn more: https://brainly.com/question/11902512
A radioactive atom has just undergone nuclear decay. Its mass number is now four less than the original atom. Which type of nuclear decay has occurred?
Answer:
Explanation:
mass number is now 4 times less than the original value so alpha decay occur during alpha decay the mass number is decreased 4 times and atomic number decreased 2 times than the original value
Sully is riding a snowmobile on a flat, snow-covered surface with a constant velocity of 10 meters/second. The total mass of the snowmobile, including Sully, is 280 kilograms. If Sully accelerates to a velocity of 16 meters/second over 10 seconds, what’s the force exerted by the snowmobile to accelerate? Use F = ma, where . A. 160 N B. 168 N C. 248 N D. 280 N E. 324 N
Answer:
280.6N
Explanation:
According to Newton's second law;
Force = mass * acceleration
Given
Mass = 280kg
velocity = 10m/s
Time = 10 secs
Acceleration = velocity?/Time
Force = mass * velocity/time
Force = 280 + (16-10/10)
Force = 280 + 0.6
Force = 280.6N
Hence the force exerted by the snowmobile to accelerate is 280.6N
Answer:168 N
Explanation:
How long would it take light to travel round trip to Mars when it is 2x1010m from the Earth?
a) 0.015s
b) 0.03s
c) 66.7s
d) 133s
Show calculation
Answer:
66.7s
Explanation:
Given parameters:
Distance between Mars and Earth = 2 x 10¹⁰m
Unknown:
Time it takes for light to travel = ?
Solution:
The speed of light is given as 3 x 10⁸m/s
Now;
Speed = [tex]\frac{distance}{time}[/tex]
Time = [tex]\frac{distance}{speed}[/tex]
Insert the parameters and solve;
Time = [tex]\frac{2 x 10^{10} }{3 x 10^{8} }[/tex] = 66.7s
A block of mass 500g is pulled from rest on ahorizontal frictionless bench by a steady force F and travels 8m in 2s find the acceleration?
We are Given:
Mass of the block (m) = 500 grams or 0.5 Kg
Initial velocity of the block (u) = 0 m/s
Distance travelled by the block (s) = 8 m
Time taken to cover 8 m (t)= 2 seconds
Acceleration of the block (a) = a m/s²
Solving for the acceleration:
From the seconds equation of motion:
s = ut + 1/2* (at²)
replacing the variables
8 = (0)(2) + 1/2(a)(2)²
8 = 2a
a = 4 m/s²
Therefore, the acceleration of the block is 4 m/s²
An astronaut weighs 626 newtons at Earth's surface. If he were to cut his distance from
Earth's center in half, what would be his new weight, to the nearest newton?
