Calculate the equivalent resistance Req of the network shown in Fig. 3.87 if R1 = 2R2 = 3R3 = 4R4 etc. and R11 = 3

Calculate The Equivalent Resistance Req Of The Network Shown In Fig. 3.87 If R1 = 2R2 = 3R3 = 4R4 Etc.

Answers

Answer 1

The equivalent resistance of the network shown is: [tex]R_{eq}=16.463\Ohm[/tex]

So, first of all, we can start by determining what each of the resistances is equal to. In this case we can start by saying that [tex]R_{1}=11R_{11}[/tex] This means that:

[tex]R_{1}=11(3\Ohm)[/tex]

Therefore:

[tex]R_{1}=33\Ohm[/tex]

We can now use this value to find the value of the other resistances. The given condition for the resistances can be represented with the following formula:

[tex]R_{n}=\frac{R_{1}}{n}[/tex]

so:

[tex]R_{2}=\frac{R_{1}}{2}=\frac{33}{2}\Ohm[/tex]

[tex]R_{3}=\frac{R_{1}}{3}=\frac{33}{3}\Ohm=11 \Ohm[/tex]

[tex]R_{4}=\frac{R_{1}}{4}=\frac{33}{4}\Ohm[/tex]

[tex]R_{5}=\frac{R_{1}}{5}=\frac{33}{5}\Ohm[/tex]

[tex]R_{6}=\frac{R_{1}}{6}=\frac{33}{6}\Ohm=\frac{11}{2}\Ohm[/tex]

[tex]R_{7}=\frac{R_{1}}{7}=\frac{33}{7}\Ohm[/tex]

[tex]R_{8}=\frac{R_{1}}{8}=\frac{33}{8}\Ohm[/tex]

[tex]R_{9}=\frac{R_{1}}{9}=\frac{33}{9}\Ohm=\frac{11}{3}\Ohm[/tex]

[tex]R_{10}=\frac{R_{1}}{10}=\frac{33}{10}\Ohm[/tex]

[tex]R_{11}=3\Ohm[/tex]

So now that we know what each resistance is equal to, we can go ahead and analyze the circuit.

In this case we can see that [tex]R_{10}[/tex] and [tex]R_{11}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{1011}=\frac{R_{10}R_{11}}{R_{10}+R_{11}}[/tex]

Which yields:

[tex]R_{1011}=\frac{(\frac{33}{10}\Ohm)(3\Ohm)}{\frac{33}{10}\Ohm+3\Ohm}[/tex]

[tex]R_{1011}=\frac{11}{7}\Ohm[/tex]

Now, [tex]R_{8}[/tex], [tex]R_{9}[/tex] and [tex]R_{1011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:

[tex]R_{891011}=R_{8}+R_{9}+R_{1011}[/tex]

[tex]R_{891011}=\frac{33}{8}+\frac{11}{3}+\frac{11}{7}[/tex]

[tex]R_{891011}=\frac{1573}{168}\Ohm[/tex]

Now,  we can see that [tex]R_{7}[/tex] and [tex]R_{891011}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{7891011}=\frac{R_{7}R_{891011}}{R_{7}+R_{891011}}[/tex]

Which yields:

[tex]R_{7891011}=\frac{(\frac{33}{7}\Ohm)(\frac{1573}{168})}{\frac{33}{7}\Ohm+\frac{1573}{168}\Ohm}[/tex]

[tex]R_{7891011}=\frac{4719}{1505}\Ohm[/tex]

Now, [tex]R_{5}[/tex], [tex]R_{6}[/tex] and [tex]R_{7891011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:

[tex]R_{567891011}=R_{5}+R_{6}+R_{7891011}[/tex]

[tex]R_{567891011}=\frac{33}{5}\Ohm+\frac{11}{2}\Ohm+\frac{4719}{1505}\Ohm[/tex]

[tex]R_{567891011}=15.236\Ohm[/tex]

Next,  we can see that [tex]R_{4}[/tex] and [tex]R_{567891011}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{4567891011}=\frac{R_{4}R_{567891011}}{R_{4}+R_{567891011}}[/tex]

Which yields:

[tex]R_{4567891011}=\frac{(\frac{33}{4}\Ohm)(15.236\Ohm)}{\frac{33}{4}\Ohm+15.236\Ohm}[/tex]

[tex]R_{4567891011}=5.352\Ohm[/tex]

Now, [tex]R_{2}[/tex], [tex]R_{3}[/tex] and [tex]R_{4567891011}[/tex] are connected in series, so we can calculate their equivalent resistance like this:

[tex]R_{234567891011}=R_{2}+R_{3}+R_{4567891011}[/tex]

[tex]R_{234567891011}=\frac{33}{2}\Ohm+11\Ohm+5.352\Ohm[/tex]

[tex]R_{234567891011}=32.852\Ohm[/tex]

Finally, we can see that [tex]R_{1}[/tex] and [tex]R_{234567891011}[/tex] are parallel, so we can calculate their equivalent resistance.

[tex]R_{eq}=\frac{R_{1}R_{234567891011}}{R_{1}+R_{234567891011}}[/tex]

Which yields:

[tex]R_{eq}=\frac{(33\Ohm)(32.852\Ohm)}{33\Ohm+32.852\Ohm}[/tex]

[tex]R_{eq}=16.463\Ohm[/tex]

See attached picture for images on how to reduce the circuit.

You can find further information in the following link.

https://brainly.com/question/21538325?referrer=searchResults

Calculate The Equivalent Resistance Req Of The Network Shown In Fig. 3.87 If R1 = 2R2 = 3R3 = 4R4 Etc.

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Answers

Answer:

13 23/24

Step-by-step explanation:

9 1/8 + 4 5/6

Step 1. Find the LCD (Least Common Denominator) for both mixed fractions

8: 8, 16, 24,…

6: 6, 12, 18, 24,…

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750 cm^3

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1800 cm^3

Answers

Answer: 600 cm³

Step-by-step explanation:

Volume of square pyramid = (1/3) · b² · h

b = base edge length = 10 cmh = height = 18 cm

Therefore, the volume can be calculated as

[tex]\frac{1}{3} *10^{2}*18=\frac{1}{3}*100*18=\frac{1}{3}*1800=\frac{1800}{3}=600[/tex]

Answer

900

Step-by-step explanation:

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1/2 base x width x height

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Answers

Answer:

x = 2.56, y = -2.63

Step-by-step explanation:

I first multiplied the second equation by two, getting

4x-6y = 26

I then subtracted the equations

 4x+2y = 5

- 4x-6y = 26

--------------------

      8y = -21

y = -2.63

with y solved, I plugged it into the second equation to get x:

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Answer:

Step-by-step explanation:

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Answers

The fence would be the perimeter of the shape.

Perimeter = 17 + 17 + 14 + 14 = 62 meters.

Multiply the price per meter by total meters:

25 x 62 = 1550

For fencing , we have to find the perimeter of rectangle.

[tex] \large\begin{gathered} {\underline{\boxed{ \rm {\red{Formula \: \: Using \: = \: 2 \: ( \: L + B \: )}}}}}\end{gathered}[/tex]

L denotes length of rectangleB denotes breadth of rectangle

L = 17 mB = 14 m

Substuting the values

Perimeter of rectangle = 2 ( L + B )

Perimeter of rectangle = 2 ( 17 m + 14 m )

Perimeter of rectangle = 2 ( 31 m )

Perimeter of rectangle = 62 m.

Hence, the perimeter of rectangle is 62 m.

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Fencing cost = 1,550

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Answers

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Given :

A trinomial [tex]x^2-6x+5[/tex]

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So, the sum of the factors of the trinomial is -6

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Answers

Answer:

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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Answers

Answer:

824

Step-by-step explanation:

Số quạt đã chuyển đi:

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Số quạt còn lại trong kho hàng là:

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Answers

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Answers

The regular polygon that has a rotation of 240 degrees to carry the polygon onto itself is an B. Octagon.

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This refers to an eight-sided polygon that has eight angles and is used in geometry.

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Answers

Answer:

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Step-by-step explanation:

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If I remember correctly, it’s D

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Answers

Answer:

C, y=-2/3x+1

Step-by-step explanation:

using points (0, 1) and (3, -1) obtained from the graph:

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9514 1404 393

Answer:

   10·2^-8 grams

Step-by-step explanation:

The each day, the initial amount for that day is multiplied by 1/2. After 8 days, the initial amount has been multiplied by (1/2)^8, where the exponent of 8 signifies that (1/2) is a factor 8 times in the product.

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Answers

Answer:

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Step-by-step explanation:

(m+n)3

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Answers

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