(c) Read the sentences about the physical properties of metals.
What is the correct sentence?

#All metals have low melting points

#Some metals are gases at room temperature.

#All metals conduct heat.

#All metals are brittle​

We are given:

Volume of gas = 3.8 L

Pressure = 460 mmHg

Temperature = 77°c = (77+273)K = 350K

Converting the pressure to atm:

Pressure(in atm)  = Pressure(in mmHg) / 760

Pressure = 460/760 = 0.6 atm

Finding the number of moles:

using the ideal gas equation:

PV = nRT                                         [where R is the universal gas constant]

replacing the given values in this equation

(0.6)(3.8) = n(0.082)(350)

n = (0.6*3.8)/(0.082*350)

n = 0.08 moles

Answer:

Freezing point of solution = -2.740C

Explanation:

The solution is attached herewith

The normal freezing point of an aqueous solution of C₁₂H₂₂O₁₁ is -1.26°C

The freezing point depression can be calculated using the formula:

ΔTf = i* Kf*m ; where

The molality of the aqueous solution of C₁₂H₂₂O₁₁ is first determined using the formula:

The mass of water is unknown but is determined from the mass of the solute and solution from the formula:

mass of solute = number of moles * molar mass

moles of solute in 1 L solution = 0.7439 moles

molar mass of solute, C₁₂H₂₂O₁₁ = 342.0 g/mol

mass of solute = 0.7439 moles * 342.0 g

mass of solute = 254.41 g

mass of solution = density * volume

volume of solution = 1 L = 1000 mL

mass of solution = 1.35g/ml * 1000 mL

mass of solution = 1350 g

Therefore, mass of solvent (water) = 1350 g - 254.41 g

mass of solvent (water) = 1095.59 g

mass of solvent (water) in kg = 1095.59 g * 1 kg/ 1000 g

mass of solvent (water) in kg = 1.0956Kg

Thus, molality of solution = 0.7439 moles / 1.0956 Kg

molality of solution = 0.679 mol/kg

The freezing point depression, ΔTf, is then determined using the formula: ΔTf = i* Kf*m

Since C₁₂H₂₂O₁₁ is a non-electrolyte; i for C₁₂H₂₂O₁₁ = 1

Kf of water = 1.86 kg/mole

m = 0.679 mol/kg

ΔTf = 1 * 1.86 * 0.679

ΔTf = 1.26 °C

Therefore, freezing point depression, ΔTf = 1.26 °C

normal freezing point of solution = freezing point of water - freezing point depression

normal freezing point of solution = 0.0°C - 1.26°C

normal freezing point of solution = -1.26°C

Therefore, the normal freezing point of an aqueous solution of C₁₂H₂₂O₁₁ is -1.26°C

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Answer:

6.50M

Explanation:

Molarity, M, is an unit of concentration widely used in analytical chemistry. Is defined as the ratio between the moles of solute (In this case, 5.46 moles) and liters of solution. To solve this question we must find the volume of the solution in liters in to find the molarity of the solution, as follows:

Liters solution:

840mL * (1L / 1000mL) = 0.840L

Molarity:

5.46moles / 0.840L

I think that the answer is protons

Answer:

B) Co2 cuz in the diagram I see two similar atoms it might be of (oxygen) and the one atom of (carbon)

Answer:

the food goes to your stomache.

it is held every 4-5 years

Answer:

100 m of KCL

Explanation:

This is because it is a more reactive metal and higher in the electro reactivity series which lead us to believe that it will take a longer time to heat along with the fact that it is lower in the periodic table and is a metal

Answer:

the one that has more power to it

Answer:

1.95 M

Explanation:

Molarity is a measure of the molar concentration of a substance (solution). In relation to the volume, it is calculated using the formula as follows;

C1V1 = C2V2

Where;

C1 = initial concentration (M)

C2 = final concentration (M)

V1 = initial volume (L)

V2 = final volume (L)

According to the provided information in this question;

C1 = 14.38 M

C2 = ?

V1 = 1.28 L

V2 = 9.45 L

Using C1V1 = C2V2

14.38 × 1.28 = C2 × 9.45

18.4064 = 9.45 C2

C2 = 18.4064 ÷ 9.45

C2= 1.95 M

Answer: A

Explanation:

The structure that corresponds to the name. 2, 2, 3-tribromopentane is the first one. option A is correct.

In 2, 2, 3-tribromopentane structure the organic compound consists of 5 charbon chains which all are attached with a single bond to each other and there are 2 bromines attached at the second number of carbon and the last one is attached at the third number of carbon.

Five carbons in the organic compound which all are bounded with a single bond with each other are named pentane and bromine is a functional group attached to the second and third carbon.

This system of the naming of organic compounds was introduced by the international union of pure and applied chemistry. this organic compound is also named based on this system of IUPAC culture.

Therefore, option A is correct.

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Answer:

C Region

Explanation:

C Region contains all the liquids as 0 °C is the freezing point of water (Crystals of water are formed leaving it no more in the liquid state) and 100 °C is the boiling point (The water boils leaving it no more in the liquid state).

Hence, All liquids are contained in the C region.

[tex]\rule[225]{225}{2}[/tex]

Hope this helped!

Answer:

Land-use change: Humans may destroy natural landscapes as they mine resources and urbanize areas. This is detrimental, as it displaces residing species, reducing available habitats and food sources. ... This can negatively effect an ecosystem because the introduced species may outcompete native organisms and displace them.

Explanation:

Answer:

B

Explanation:

Just by looking at the amount of carbons on the straight chain which is four and whom prefix is butane we can see that B is the answers

Answer: Least Common Multiplier of a6m, 0.003 moles 0.01elamos

Steps 6m, 0.003 moles

Compute an expression comprised of Factors that appear either in a6m or 0.003 moles

= 0.018elamos

Explanation:

Taking into account the definition of molarity,  0.005 liters of a 6.0 M solution of acetic acid contain 0.0030 moles​.

Molar concentration or molarity is a measure of the concentration of a solute in a solution and indicates the number of moles of solute that are dissolved in a given volume.

The molarity of a solution is calculated by dividing the moles of solute by the volume of the solution:

[tex]molarity=\frac{number of moles}{volume} [/tex]

Molarity is expressed in units [tex]\frac{moles}{liters} [/tex].

In this case, you have a 6.0 M solution of acetic acid that contain 0.0030 moles​. Replacing in the definition of molarity:

[tex]0.6\frac{moles}{liters} =\frac{0.0030 moles}{volume} [/tex]

Solving:

0.6 [tex]\frac{moles}{liters} [/tex]× volume= 0.0030 moles

volume= 0.0030 moles ÷0.6 [tex]\frac{moles}{liters} [/tex]

volume=0.005 liters

Finally, 0.005 liters of a 6.0 M solution of acetic acid contain 0.0030 moles​.

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Answer:

Explanation:

The balanced chemical equation between

SrO + 2HCl → H2O + SrCl2

When an electrolyte dissolves in water, the resulting solution conducts an electric current.

Answer:

The correct answer is A

Explanation:

Endothermic is a reaction of which heat is provided to break down the reacted molecules

Answer: The new temperature of container is 123 K.

Explanation:

Given: [tex]P_{1}[/tex] = 795 mm Hg,     [tex]T_{1}[/tex] = 273 K

[tex]P_{2}[/tex] = 358 mm Hg,          [tex]T_{2}[/tex] = ?

Formula used to calculate the new temperature is as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}[/tex]

Substitute the values into above formula as follows.

[tex]\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}\\\frac{795 mm Hg}{273 K} = \frac{358 mm Hg}{T_{2}}\\T_{2} = 123 K[/tex]

Thus, we can conclude that the new temperature of container is 123 K.

Answer:

The answer is below

Explanation:

Ketone is a class of organic compounds which has a carbonyl group such that the carbon atom is covalently bonded to an oxygen atom, while the remaining two bonds are to other carbon atoms or hydrocarbon radicals.

Ketones are highly reactive hydrocarbons, they can be gotten from the oxidization of secondary alcohols. Ketone are used for medicinal applications.

The third option is the ketone

it’s the the last 2 choices

Answer:

I think the w/w% of this question is 10.

The w/w% of a solution that contains 10 grams of solute and 100 grams of solvent is 9.09%

Mass percentage is another name of w/w % or weight /weight % .

To determine the weight/weight % of a solution :

we divide the mass of solute by mass of the solution (solute and solvent together) and multiply by 100 to obtain per cent.

[tex]\dfrac{w}{w} \; \%\; =\;\rm\dfrac{mass \;of\; solute}{mass\; of \; solute\;+\;mass\;of\;solvent} \times 100[/tex]

It is given that , mass of solute = 10 grams and mass of solvent = 100 grams

So,

[tex]\dfrac{w}{w} \; \%\; =\;\rm\dfrac{10}{10+100} \times 100[/tex]

[tex]\dfrac{w}{w} \; \%\; =\;\rm\dfrac{10}{110} \times 100\\\\\dfrac{w}{w} \; \%\; =\;\rm\dfrac{100}{11}\\\\\dfrac{w}{w} \; \%\; =\; 9.09 \;\%[/tex]

The w/w% of a solution that contains 10 grams of solute and 100 grams of solvent is 9.09% .

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Answer:

C Condensation of water vapor

Explanation:

One of the components of the atmosphere is water vapour. Water vapour is always present in air.

This water vapour may combine with particles of dust and smoke and condense around them to form clouds.

As more water vapour condenses and coalesces, the clouds become thicker and precipitation eventually follows.

150000 J

Chemistry

Thermodynamics

Specific Heat Formula: q = mcΔT

Math

Pre-Algebra

Order of Operations: BPEMDAS

Step 1: Define

Identify variables

[Given] m = 225 g

[Given] c = 4.184 J/g °C

[Given] ΔT = 133 °C - -26.8 °C = 159.8 °C

[Solve] q

Step 2: Solve for q

Step 3: Check

Follow sig fig rules and round. We are given 3 sig figs.

150436 J ≈ 150000 J

Topic: AP Chemistry

Unit: Thermodynamics

Book: Pearson AP Chemistry

Sodium hydroxide, also known as lye and caustic soda, is an inorganic compound with the formula NaOH. It is a white solid ionic compound consisting of sodium cations Na + and hydroxide anions OH −

Answer:

the correct answer is option C

Answer:

The tectonic style and viability of modern plate tectonics in the early Earth is still debated. Field observations and theoretical arguments both in favor and against the uniformitarian view of plate tectonics back until the Archean continue to accumulate. Here, we present the first numerical modeling results that address for a hotter Earth the viability of subduction, one of the main requirements for plate tectonics. A hotter mantle has mainly two effects: 1) viscosity is lower, and 2) more melt is produced, which in a plate tectonic setting will lead to a thicker oceanic crust and harzburgite layer. Although compositional buoyancy resulting from these thick crust and harzburgite might be a serious limitation for subduction initiation, our modeling results show that eclogitization significantly relaxes this limitation for a developed, ongoing subduction process. Furthermore, the lower viscosity leads to more frequent slab breakoff, and sometimes to crustal separation from the mantle lithosphere. Unlike earlier propositions, not compositional buoyancy considerations, but this lithospheric weakness could be the principle limitation to the viability of plate tectonics in a hotter Earth. These results suggest a new explanation for the absence of ultrahigh-pressure metamorphism (UHPM) and blueschists in most of the Precambrian: early slabs were not too buoyant, but too weak to provide a mechanism for UHPM and exhumation.

Explanation: