Assume that a friend hands you a 10-newton box to hold for her. If you hold the box without moving it at a height of 10 meters above the ground, how much work do you do

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Hydroelectric power, also called hydropower is the electricity produced from generators driven by turbines that convert the potential energy of falling or fast-flowing water into mechanical energy.

Answer:

Hydroelectric power/hydropower -  electricity produced by a hydraulic source, specifically energy generated falling or flowing water

Answer:

If a neutral atom gains electrons, then it will become negatively charged. If a neutral atom loses electrons, then it become positively charged.

Answer:

Modern technology is the advancement of old technology with adjustments.

1. Ghana is still developing economically and modern  infrastructure is not yet well established.

2. Ghana has Environmental- health concerns which contribute to the lack of improvement of technology in Ghana.

3.  Youth unemployment is prevalent therefore contributing to lack of improvement of technology in Ghana.

Explanation:

Ghana is a developing country with rising debt payments which could very well contribute as whole to the lack of improvement of technology in Ghana.

Answer:

b = frequency

Answer:

Can't understand the language

Answer:

 law of conservation of energy states that the total energy of an isolated system remains constant; it is said to be conserved over time.

Answer:

Alpha particles are more massive than beta particles.

Explanation:

The alpha particles are also called double-positive Heilum Nuclei because they have a charge of "+2" and a mass of 4 a.m.u. The properties of the alpha particles are as follows:

1. It possesses high energy due to high velocity. It is 7.7 MeV for most energetic from Rac (i.e: Bismuth-214)

2. It has a very high ionizing power. A 7.7 MeV particle produces about 0.2 x 10⁶ ions.

3. The range of alpha particles is very small. It is about 7 x 10⁻² m and only 4 x 10⁻⁵ m in aluminum for 7.7 MeV alpha-particle.

4. Alpha particles produce fluorescence on striking certain substances, such as zinc sulphide and bariumplatinocynide.

The beta particles are fast-moving electrons, which have a negligible mass.  

Hence, the correct option is:

Alpha particles are more massive than beta particles.

Answer: [tex]-5013.65\ J[/tex]

Explanation:

Given

No of moles [tex]n=3[/tex]

Temperature [tex]T=290\ K[/tex]

Initial volume [tex]V_1=2\ m^3[/tex]

Final volume [tex]V_2=1\ m^3[/tex]

Work done in constant temperature process is

[tex]W=nRT\ln \left(\dfrac{V_2}{V_1}\right)[/tex]

Insert the values

[tex]\Rightarrow W=3\times 8.314\times 290\ln \left (\dfrac{1}{2}\right)\\\\\Rightarrow W=-870\times 8.314\times \ln (2)\\\Rightarrow W=-5013.65\ J[/tex]

Answer:

Serial circuit.   the current is constant.  

            the voltage across a given resistor is half the rating in a one-resistor circuit.

Parallel circuit    the voltage is constant

the current is half the value of the current with a single resistor

Explanation:

To answer exactly this exercise, you need the diagram or the indication of the type of circuit being used, since there are two possibilities, let's consider the results of each one.

Serial circuit.

The two resistance are one after the other.

In this case the current in the resistor sides is the same, that is, the current is constant in the circuit.

The voltage is proportional to the value of each resistor and if the two resistors are equal, the voltage across a given resistor is half the rating in a one-resistor circuit.

Parallel circuit

the two resistance is next to each other.

In this case the voltage is constant, that is, the voltage across the two resistors is the same as in the case of a single resistor.

The current is inversely proportional to the value of the resistance

          i₁ = V / R₁

          i₂ = V / R₂

for a single resistance

           I = V / R

these currents are related

          i = i₁ + i₂

if the two resistors have the same value the current is half the value of the current with a single resistor

The intensity of the electromagnetic wave in terms of the electric field is 0.00298 W/m² and the intensity of the electromagnetic wave in terms of the magnetic field is 1.193x10⁻⁶  W/m².

The intensity of the electromagnetic wave is related to the electric field as well as to the magnetic field.    

a) Intensity of the electromagnetic wave for the electromagnetic field.

The intensity of the electromagnetic wave (I) in terms of the electromagnetic field is given by:

[tex] I = \frac{E^{2}*c*\epsilon_{0}}{2} [/tex]   (1)

Where:

c: is the speed of light = 3.00*10⁸ m/s  

E: is the magnitude of the electric field = 1.5 V/m

ε₀: is the permittivity of free space = 8.85*10⁻¹² C²/Nm²

Hence, the intensity of the electromagnetic wave (eq 1) is:

[tex] I = \frac{(1.5 V/m)^{2}*3.00 \cdot 10^{8} m/s*8.85 \cdot 10^{-12} C^{2}/(N*m^{2})}{2} = 0.00298 W/m^{2} [/tex]                                                                                          

b) Intensity of the electromagnetic wave for the magnetic field

We can calculate the intensity of the electromagnetic wave (I) in terms of the magnetic field with the following equation:

[tex] I = \frac{cB^{2}}{2\mu_{0}} [/tex]   (2)

Where:

B: is the magnitude of the magnetic field = 10⁻¹⁰ T

μ₀: is the vacuum permeability = 4π*10⁻⁷ m*T/A

Therefore, the intensity of the electromagnetic wave (eq 2) is:

[tex] I = \frac{3.00 \cdot 10^{8} m/s*(1\cdot 10^{-10} m*T/A)^{2}}{2*4\pi \cdot 10^{-7} T/A} = 1.193 \cdot 10^{-6} W/m^{2} [/tex]

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I hope it helps you!

(1) When the driver is at rest, the restoring force exerted by spring is equal in magnitude to the driver's weight, so that

∑ F = s - mg = 0   ==>   s = mg = 617.4 N

If the spring is compressed 0.015 m, then the spring constant k is such that

617.4 N = k (0.015 m)   ==>   k = 41,160 N/m ≈ 41 kN/m

(2) The total mass of the passengers is

24 (68 kg) + 3 (15 kg) + 5 (3 kg) + 25 kg = 1717 kg

so that if everyone is at rest, the spring is compressed a distance x such that

kx = (1717 kg) g   ==>   x ≈ 0.41 m

Answer:

Explanation:

The formula for angular velocity is

[tex]\omega=\frac{\theta}{t}[/tex] where omega is the angular velocity, theta is the change in the angular rotation, and t is the time in seconds. First and foremost, we have the angular rotation in minutes and the time in seconds, so that's a problem we have to amend. Let's change the angular rotation to rotations per second:

[tex]281.133\frac{r}{min}*\frac{1min}{60s}=4.68555\frac{r}{s}[/tex]

Now we're ready to set up the problem:

[tex]4.68555=\frac{\theta}{3.686}[/tex] and we multiply both sides by 3.686 to get the rotations per seconds:

θ = 17.27 rotations

Answer:

The current is more in the parallel combination than in the series combination.

Explanation:

two resistances, R1 and R2 are connected to a battery of voltage V.

When they are in series,

R = R1 + R2

In series combination, the current is same in both the resistors, and it is given by Ohm's law.

V = I (R1 + R2)

[tex]I = \frac{V}{R_1 + R_2}[/tex]..... (1)

When they are connected in parallel.

the voltage is same in each resistor.

The effective resistance is R.

[tex]R = \frac{R_1R_2}{R_1 + R_2}[/tex]

So, the current is

[tex]I = \frac{V(R_1+R_2)}{R_1 R_2}[/tex]..... (2)

So, the current is more is the parallel combination.

Answer:

(a) emf = 0.507 V

(b) emf = 0.0507 V

(c) emf = 0.00234 V

Explanation:

Given;

number of turns of the coil, N = 40 turns

diameter of the coil, d = 11 cm

radius of the coil, r = 5.5 cm = 0.055 m

magnitude of the magnetic field, B = 0.4 T

The magnitude of the induced emf is calculated as;

[tex]emf = - N\frac{d\phi}{dt} \\\\where;\\\\\phi \ is \ magnetic \ flux= BA \\\\A \ is the \ area \ of \ the \ coil = \pi r^2 = \pi (0.055)^2 = 0.0095 \ m^2\\\\emf = - N \frac{dB.A}{dt} = -NA\frac{dB}{dt} \\\\emf = -NA\frac{(B_2 - B_1)}{t} \\\\emf = NA \frac{(B_1 - B_2)}{t} \\\\the \ final \ magnetic \ field \ is \ reduced \ to \ zero;\ B_2 = 0\\\\emf = \frac{NAB_1}{t}[/tex]

(a) when the time, t = 0.3 s

[tex]emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{0.3} = 0.507 \ V[/tex]

(b) when the time, t = 3.0 s

[tex]emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{3} = 0.0507 \ V[/tex]

(c) when the time, t = 65 s

[tex]emf = \frac{NAB_1}{t} = \frac{40\times 0.0095\times 0.4}{65} = 0.00234 \ V[/tex]

Answer:

the tendency of electron dipole moments to align with an applied magnetic field

Explanation:

Paramagnetism has to do with possession of unpaired electrons. Substances that possess unpaired electrons are said to be paramagnetic.

When an external magnetic field is applied to a paramagnetic substance, the magnetic field causes the electrons spins of the paramagnetic substance to align parallel to the field,which leads to a net attraction.

Hence, paramagnetism is closely associated with the tendency of electron dipole moments to align with an applied magnetic field.

Answer:

[tex]v_1=87.40m/s[/tex]

Explanation:

From the question we are told that:

Mass of arrow [tex]m=52g[/tex]

Mass of rock [tex]m_r=1.50kg[/tex]

Height [tex]h=0.47m[/tex]

Generally the equation for Velocity is mathematically given by

 [tex]v = \sqrt{(2gh)}[/tex]

 [tex]v=\sqrt{(2 * 9.8m/s² * 0.47m) }[/tex]

 [tex]v= 3.035m/s[/tex]

Generally the equation for conservation of momentum is mathematically given by

 [tex]m_1v_1=m_2v_2[/tex]

 [tex]0.052kg * v = 1.5 * 3.03m/s[/tex]

 [tex]v_1=87.40m/s[/tex]

Answer:

[tex]\theta=30 \textdegree[/tex]

Explanation:

From the question we are told that:

Current [tex]I=2.0A[/tex]

Length [tex]L=0.60m[/tex]

Magnetic field [tex]B=0.30T[/tex]

Force [tex]F=0.18N[/tex]

Generally the equation for Force is mathematically given by

[tex]F = BIL sin\theta[/tex]

[tex]sin\theta=\frac{F}{BIL}[/tex]

[tex]\theta=sin^{-1}\frac{0.18}{0.3*2*0.6}[/tex]

[tex]\theta=30 \textdegree[/tex]

Answer:

The mass of Al is 89.027 kilograms.

The mass of Jo is 104.973 kilograms.

The magnitude of the force of Jo on Al is 596.481 newtons.

Explanation:

Given the absence of external forces, this situation can be described will by Principle of Linear Momentum Conservation and Impact Theorem on each skater:

Al:

[tex]m_{1}\cdot (v_{1, f}-v_{1, o}) = -F \cdot \Delta t[/tex] (1)

Jo:

[tex]m_{2}\cdot (v_{2,f}-v_{2,o}) = F\cdot \Delta t[/tex] (2)

Total mass:

[tex]m_{1} + m_{2} = 194\,kg[/tex]

Where:

[tex]m_{1}[/tex], [tex]m_{2}[/tex] - Masses of the skaters, in kilograms.

[tex]v_{1,o}[/tex], [tex]v_{1,f}[/tex] - Initial and final velocities of Al, in meters per second.

[tex]v_{2,o}[/tex], [tex]v_{2,f}[/tex] - Initial and final velocities of Jo, in meters per second.

[tex]F[/tex] - Impact force between skaters, in newtons.

[tex]\Delta t[/tex] - Impact time, in seconds.

If we know that [tex]v_{1,o} = 0\,\frac{m}{s}[/tex], [tex]v_{1,f} = -7.9\,\frac{m}{s}[/tex], [tex]\Delta t = 1\,s[/tex], [tex]v_{2,o} = 0\,\frac{m}{s}[/tex] and [tex]v_{2,f} = 6.7\,\frac{m}{s}[/tex], then the masses of the skaters are, respectively:

[tex](194-m_{2})\cdot (-7.9) = -F[/tex] (1b)

[tex]m_{2} \cdot 6.7 = F[/tex] (2b)

(2b) in (1b):

[tex](194-m_{2})\cdot (-7.9) = -m_{2}\cdot 6.7[/tex]

[tex]-1532.6 +7.9\cdot m_{2} = -6.7\cdot m_{2}[/tex]

[tex]14.6\cdot m_{2} = 1532.6[/tex]

[tex]m_{2} = 104.973\,kg[/tex]

[tex]m_{1} = 194\,kg - 104.973\,kg[/tex]

[tex]m_{1} = 89.027\,kg[/tex]

And the magnitude of the force is:

[tex]F = 6.7\cdot m_{2}[/tex]

[tex]F = 596.481\,N[/tex]

The mass of Al is 89.027 kilograms.

The mass of Jo is 104.973 kilograms.

The magnitude of the force of Jo on Al is 596.481 newtons.

Answer:

Gap left = Change in length on heating

Gap=Initial length×Coefficient of linear expansion×change in temperature

Gap=10×0.000012×15m

⟹Gap=0.0018 m

this is an example u have to put your equation in it

Answer:

speed is the gradient of the graph

Answer:

Speed is the slope of a distance time graph.

Explanation:

Speed= d/t

Slope is equal to rise/run

If the rise of the graph is the distance and the run is the time, calculating slope is the equivalent of calculating average speed.

When the accuracy in measuring the velocity of a particle increases, that of its position decreases. The correct option is d. decrease.

The Heisenberg's uncertainty principle states that there is always an uncertainty in any attempt to measure accurately the value of any two complementary variables simultaneously. This implies that measuring of position and momentum of a particle simultaneously would lead to uncertainty in their values.

So that;

Δx.ΔP ≥ [tex]\frac{h}{2\pi }[/tex]

Where Δx is the uncertainty in the value of its position, ΔP is the uncertainty in the value of momentum and h is the Planck's constant.

This principle simply explains and provides the required answer to the given question. So that according to Heisenberg's uncertainty principle, the accuracy in measuring its position will definitely decrease.

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Answer:

The elastic energy is 245 J.

Explanation:

Length, L = 5 m

Diameter, D = 10^-3 m

Stretch, l = 3 x 10^-4 m

Load, F = 10 x 9.8 = 98 N

Let the elastic energy is U.

[tex]U = \frac{1}{2}\times stress\times strain\times volume\\\\U = 0.5\times \frac{Force}{area}\times \frac{l}{L}\times Area\times L\\\\U = 0.5 \times F\times l\\\\U = 0.5\times 98\times 5\\\\U = 245 J[/tex]

Answer:

the magnitude of the magnetic force on the wire segment is 6.03 x 10⁻⁶ N

Explanation:

Given;

length of the conductor, L = 1 cm = 0.01 m

current carried by the solenoid, I₁ = 15 A

radius of the solenoid, r = 4 cm

number of turns per length of the solenoid, n = 800 turns/m

current carried by the solenoid, I₂ = 40 mA = 0.04 A

The magnetic field of the solenoid is calculated as;

B = μnI₂

where;

μ is the permeability of free space = 4π x 10⁻⁷ Tm/A

B = ( 4π x 10⁻⁷) x (800) x (0.04)

B = 4.022 x 10⁻⁵ T

The magnitude of the magnetic force on the wire segment is calculated as;

F = BI₁L sinθ

where

θ is the angle made by the wire segment against the solenoid = 90⁰

F = (4.022 x 10⁻⁵) x (15) x (0.01) x sin(90)

F = 6.03 x 10⁻⁶ N

Therefore, the magnitude of the magnetic force on the wire segment is 6.03 x 10⁻⁶ N

Solution :

We know,

Distance,

[tex]$S=ut+\frac{1}{2}at^2$[/tex]

[tex]$S=ut+0.5(a)(t)^2$[/tex]

For the first 20 ms,

[tex]$S=0+0.5(220)(0.020)^2$[/tex]

S = 0.044 m

In the remaining 30 ms, it has constant velocity.

[tex]$v=u+at$[/tex]

[tex]$v=0+(220)(0.020)[/tex]

v = 4.4 m/s

Therefore,

[tex]$S=ut+0.5(a)(t)^2$[/tex]

[tex]$S'=4.4 \times 0.030[/tex]

S' = 0.132 m

So, the required distance is = S + S'

                                              = 0.044 + 0.132

                                              = 0.176 m

Therefore, the tongue can reach = 0.176 m or 17.6 cm

Answer:

The total distance is 0.176 m.

Explanation:

For t = 0 s to t = 20 ms

initial velocity, u = 0

acceleration, a = 220 m/s^2

time, t = 20 ms

Let the final speed is v.

Use first equation of motion

v = u + at

v = 0 + 220 x 0.02 = 4.4 m/s

Let the distance is s.

Use second equation of motion

[tex]s = u t + 0.5 at^2\\\\s = 0 + 0.5 \times 220 \times 0.02\times 0.02\\\\s = 0.044 m[/tex]

Now the distance is

s' = v x t

s' = 4.4 x 0.03 = 0.132 m

The total distance is

S = s + s' = 0.044 + 0.132 = 0.176 m

Answer:

40 because if it is the same weight then there is no weight to make the ride slower so it 40

Explanation:

Answer:

A cloud can discharge as much as 20 coulombs in a lightning bolt.

Answer:

the distance of the fish (as  seen by the bird) is greater than the actual distance.

Reason-

it is due to the apparent depth and differences between the refractive indices.

Have a nice day!

Answer:

if you want to drop into the water at the greatest possible distance from the edge, you must hang for 1.662s.

Explanation:

The time period of the oscillation is,

[tex]T = 2\pi \sqrt{ \frac{I} {g }[/tex]

[tex]T = 2\pi \sqrt{\frac{11}{9.8} } \\\\T= 6.65 s[/tex]

This would be the time taken for the person to move from.

The duration of time he hangs over the river be one-fourth of the time period.

Here,

[tex]t= \frac{T}{4} \\\\t=\frac{6.65}{4}\\\\t = 1.662 s[/tex]

Answer:

[tex]u=34cm[/tex]

Explanation:

From the question we are told that:

Far point is [tex]V=34 cm[/tex]

Near point is [tex]u=17 cm[/tex]

Therefore

Focal Length

[tex]f=-34cm[/tex]

Generally the equation for the Lens is mathematically given by

[tex]\frac{1}{u}=\frac{1}{f}-\frac{1}{v}[/tex]

[tex]\frac{1}{u}=\frac{1}{-34}-\frac{1}{-17}[/tex]

[tex]u=34cm[/tex]