Answer quick tyyyyyyyyyyyyyy

Answer:

65

Step-by-step explanation:

Exterior angle = Sum of 2 interior angles

x + 31 = x + x - 34

x + 31 = 2x - 34

x - 2x = - 34 - 31

- x = - 65

x = 65

Step-by-step explanation:

A triangle's angles add up to 180°, and a straight line is 180 degrees, so 180 - x + 31 is the interior angle that isn't labeled.

[tex]x+x-34+180-x-31=180[/tex]

[tex]x=180-115[/tex]

[tex]x=65[/tex]

Answer:

Step-by-step explanation:

I'm going to use Physics here for this concept of vectors. Here are some stipulations I have set for the problem (aka rules I set and then followed throughout the problem):

** I am counting the 50 m as 2 significant digits even though it is only 1, and I am counting 200 as 3 significant digits even though it is only 1. 1 sig dig doesn't really give us enough accuracy, in my opinion.

** A bearing of .25 degrees is measured from the North and goes clockwise; that means that measured from the x axis, the angle is 89.75 degrees. This is the angle that is used in place of the bearing of .25 degrees.

** Due east has an angle measure of 0 degrees

Now let's begin.

We need to find the x and y components of both of these vectors. I am going to call the first vector A and the second B, while the resultant vector will be C. Starting with the x components of A and B:

[tex]A_x=50cos(89.75)[/tex] so

[tex]A_x=.22[/tex]

[tex]B_x=200cos(0)[/tex] so

[tex]B_x=200[/tex] and we need to add those results together. Due to the rules for adding significant digits properly, the answer is

[tex]C_x=200[/tex] (and remember I am counting that as 3 sig fig's even though it's only 1).

Now for the y components:

[tex]A_y=50sin(89.75)[/tex] so

[tex]A_y=50[/tex] (which I'm counting as 2 sig fig's)

[tex]B_y=200sin(0)[/tex] so

[tex]B_y=0[/tex] and we need to add those results together.

[tex]C_y=50[/tex]

Now for the resultant magnitude:

[tex]C_{mag}=\sqrt{(200)^2+(50)^2}[/tex]  and that gives us a final magnitude of

[tex]C_{mag}=206[/tex] m

Now for the angle:

Since both the x and y components of the resultant vector are in quadrant 1, we don't need to add anything to the angle to get it right, so

[tex]tan^{-1}(\frac{50}{200})=14[/tex]

The girl is 206 meters from her starting point at an angle of 14 degrees

Answer:

x=44

Step-by-step explanation:

20/x=30/22+x

20x+440=30x

440=10x

x=44

Answer:

[tex]y = - \frac{3}{2} x + 1[/tex]

Step-by-step explanation:

Slope -intercept form: y= mx +c, where m is the slope and c is the y-intercept.

Parallel lines have the same slope. Let's find the slope of the given line.

Given points: (-2, 0) and (0, -3)

[tex]\boxed{slope = \frac{y1 - y2}{x1 - x2} }[/tex]

slope of given line

[tex] = \frac{0 - ( - 3)}{ - 2 - 0} [/tex]

[tex] = \frac{0 + 3}{ - 2} [/tex]

[tex] = - \frac{3}{2} [/tex]

[tex]y = - \frac{3}{2} x + c[/tex]

Given that the y- intercept is 1, c= 1.

[tex]y = - \frac{3}{2} x + 1[/tex]

Answer:

B. 16

Step-by-step explanation:

You can find it by subtraction.

for example:

70-54=16

54-38=16

22-6=16

and so on

Answer:

44

Step-by-step explanation:

the smaller triangle is multiples of 9

(9, 18, 27, 36, 45, etc.)

and the bigger triangle is multiples of 11

(11, 22, 33, 44, 55, etc.)

Answer:

44

Step-by-step explanation:

22÷18=11/9

33÷27=11/9

x÷36=11/9

x=11/9×36

x=44

Step-by-step explanation:

Using R, I used the following code to create a histogram:

bowling.scores <- c(87, 104, 79, 94, 117, 82, 72, 116, 105, 95, 88, 93, 109, 119, 75,  

                   103, 112, 97, 73, 85, 91, 86, 102, 99, 106, 84, 98, 83, 81, 96, 92)

data.frame(bowling.scores)

ggplot(data.frame(bowling.scores), aes(x=bowling.scores)) +  

 xlim(c(70, 120)) +

 scale_y_continuous(breaks = seq(0, 10, by=1), "Frequency") +

 geom_histogram(breaks=seq(70, 120, by=10), color="black", fill="grey60") +

 labs(title="Histogram of Bowling Scores", x="Bowling Scores", y="Frequency")

The solutions are:

sin(a)  = 24/25

tan(a) = 24/7

For a given point (x, y) and an angle "a" measured counterclockwise from the positive x-axis to a ray that connects the origin with our point, we can think on the situation as a triangle rectangle.

Where the ray is the hypotenuse, the x-component is the adjacent cathetus, and the y-component is the opposite cathetus.

So we have:

x = adjacent cathetus

y = opposite cathetus

h = hypotenuse = √(x^2 + y^2)

Then the trigonometric relations become:

cos(a) = x/√(x^2 + y^2)

sin(a) = y/√(x^2 + y^2)

tan(a) = y/x

Now, we know that we have:

cos(a) = 7/25

then we can see that:

x = 7

and

h = 25 = √(7^2 + y^2)

We can solve the above equation for y:

25 = √(7^2 + y^2)

25 = √(49 + y^2)

25^2 = 49 + y^2

625 - 49 = y^2

√576 = y = 24

Then we have:

x = 7

y = 24

h = 25

Now we can return to our known trigonometric relations and get:

sin(a) = y/√(x^2 + y^2) = 24/25

tan(a) = y/x = 24/7

If you want to learn more about trigonometry, you can read:

https://brainly.com/question/14746686

Answer:

1/4

Step-by-step explanation:

2/5 divided by 8/5 is the same as 2/5 * 5/8. we cross out the same 5's to get 2/8. We simplify that to 1/4.

1/4 is our answer.

Answer:

∠ L ≈ 52°

Step-by-step explanation:

Using the cosine ratio in the right triangle

cosL = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{LM}{LN}[/tex] = [tex]\frac{8}{13}[/tex] , then

∡ L = [tex]cos^{-1}[/tex] ([tex]\frac{8}{13}[/tex] ) ≈ 52° ( to the nearest degree )

Answer:

[tex]x+3y\leq 0[/tex]        

[tex]x-y\geq 0[/tex]

[tex]1) x+3y=0[/tex]

[tex]x-y=0[/tex]

[tex]-----[/tex]

[tex]4y=0[/tex]

[tex]y=0[/tex]

[tex]x=0[/tex]

[tex](0,0)[/tex]

[tex]2)(x+3y=0)3[/tex]

[tex]3x-7y=16[/tex]

[tex]3x+9y=0[/tex]

[tex]3x-7y=16\\------\\16y=-16[/tex]

[tex]y=-1[/tex]

[tex](3,-1)[/tex]

[tex]3)(x-y=0)3[/tex]

[tex]3x-7y=16[/tex]

[tex]3x-3y=16[/tex]

[tex]3x-3y=0[/tex]

[tex]3x-7y=16\\------\\4y=-16[/tex]

[tex]y=-4[/tex]

[tex]x=4[/tex]

[tex](4,-4)[/tex]

[tex]Z=-x+5y[/tex]

[tex](0,0):z=0[/tex]

[tex](3,-1):z=-8[/tex]

[tex](4,-4):z=-24[/tex]

[tex]Maximum \:Value\: of\: z:0[/tex]

[tex]Minimum\: Value\: of\: z:-24[/tex]

OAmalOHopeO

Answer:

(2z-5)(2z-3)

if the "A" term in a quadratic Ax^2 + Bx + C is NOT a "1"

first check to see if there is a commpon factor of a,b,c that can be pulled out

for example 2x^2 + 4x + 6 you can pull

out a 2.... 2(x^2 + 2x +3)

if not you multiply the values a*c

in you case 4*15 which is 60

now you factor the 60

1*60

2*30

-1*-60

-2*-30

10*6

-10*-1

etc

when you find the combination that ADDS UP TO THE B TERM

you rewrite the B term using the factors you forud...

SO -16z becomes -10z - 6z

put it in the original problem

4z^2 -10z - 6z + 15

if you get this far , the GROUPS WILL ALWAYS WORK

pull out a 2z from "4z^2 -10z"

and pull out a -3 from "- 6z + 15"

and magically you will see that the "left over stuff" is the same

2z(2z-5) -3(2z-5)

pull out common item

(2z-5) (2z-3) ... all done

Step-by-step explanation:

multiple AC ... 15*4 = 60

factor 60  to end up with -16

-10 * -6 = 60

rewrite (factor by grouping)

4z^2 -10z - 6z + 15

find groups

2z(2z-5) -3(2z-5)

(2z-5)(2z-3)

Answer:

( 5.5 , 4 )

Step-by-step explanation:

Use mid point formula shown in image

first x= (X+X)/2

x=(4+7)/2

x=11/2

x=5.5

y=(Y+Y)/2

y=(2+6)/2

y=8/2

y=4

(5.5,4)

Answer:

R = [tex]\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right][/tex]

Step-by-step explanation:

P - Q + R = I ( I is the identity matrix )

[tex]\left[\begin{array}{ccc}2&4\\3&5\\\end{array}\right][/tex] - [tex]\left[\begin{array}{ccc}-2&2\\4&1\\\end{array}\right][/tex] + R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] ( subtract corresponding elements )

[tex]\left[\begin{array}{ccc}2-(-2)&4-2\\3-4&5-1\\\end{array}\right][/tex] + R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]

[tex]\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right][/tex] + R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex]

R = [tex]\left[\begin{array}{ccc}1&0\\0&1\\\end{array}\right][/tex] - [tex]\left[\begin{array}{ccc}4&2\\-1&4\\\end{array}\right][/tex] = [tex]\left[\begin{array}{ccc}-3&-2\\1&-3\\\end{array}\right][/tex]

Answer:

-25

Step-by-step explanation:

Withdrawal means to take out. So you're taking out $25 out of your account, therefore it would be a negative.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

The integer to represent a withdrawal of $25 would be -$25.

Option A is the correct answer.

An expression is a way of writing a statement with more than two variables or numbers with operations such as addition, subtraction, multiplication, and division.

Example: 2 + 3x + 4y = 7 is an expression.

We have,

Amount withdrawal = $25

The integer to represent a withdrawal of $25 would be -$25.

Because withdrawal means we are taking the amount out of our account.

Thus,

The integer to represent a withdrawal of $25 would be -$25.

Option A is the correct answer.

Learn more about expressions here:

https://brainly.com/question/3118662

#SPJ2

Answer:

Step-by-step explanation:

Answered by Gauthmath

Answer:

C.) [tex]350\pi[/tex] [tex]cm^{2}[/tex]

Step-by-step explanation:

Since we are given the radius of the cone's base and the slant height, we can use the following equation to solve for surface area:

[tex]A = \pi r^{2} + \pi rl[/tex]

Now we just plug in the given information and solve:

[tex]A = \pi (10cm)^2 + (\pi) (10cm)(25cm)\\A = 100\pi cm^2 + 250\pi cm^2\\A = 350\pi cm^2[/tex]

Answer:

Step-by-step explanation:

if you connect the 2 pointy parts of this shape at the top, what you have is a square. That means that the cut out part is a half circle. To find the area of the shaded portion, subtract the area of the half circle from the area of the square. Let's start with the square, cuz that's the super easy one.

A = s*s so

A = 64 in squared.

Now for the half circle. Let's just do this: let's find the area of the whole circle and then cut it in half, how about?

If the length of one of the sides is 8, then half that length is 4, right? Since the circle is touching the sides of the square, the diameter of the circle is the same as the measure of the side of the square. That means that the radius is 4. The area for the circle is

[tex]A=\pi r^2[/tex] and filling in:

[tex]A=(3.14)(4^2)[/tex] so

A = 50.24 in squared. Divide that in half and the area of half the circle is 25.12 in squared.

Subtract 25.12 from 64 to get 38.88 in squared

Answer:

5

Step-by-step explanation:

median means the number in the middle

Answer:

First option

Remove 2 tiles

Replace x with 3 and solve:

10 x 5^3

Simplify:

10 x 125 = 1250

Answer: y = 1250

(3 , 1250)

I got it right on my test.

Answer:

just add a small amount and and square the new number

between 2.82 and 2.83 seems a bit closer

Step-by-step explanation:

x      x^2

2.8         7.84

2.81         7.8961

2.82 7.9524

2.83 8.0089

2.84 8.0656

2.85 8.1225

2.86 8.1796

2.87         8.2369

Answer:

1536 cm^2 be the correct answ

Answer: Option 2

1536cm²

Lateral Area=32×(24/2)×4

=1536 (cm²)

Answered by Gauthmath must click thanks and mark brainliest

Answer:

Step-by-step explanation:

Given linear equation is,

y = [tex]\frac{2}{3}x[/tex]

t-chart Or table for the input-output values,

y       -2          0          2            4  

x       -3          0           3            6

Now we have to plot the ordered pairs given in the table,

(-3, -2), (0, 0), (3, 2), (6, 4)

Answer:

x ≤ 6

Step-by-step explanation:

Given

- 12x ≥ - 72

Divide both sides by - 12, reversing the symbol as a result of dividing by a negative quantity.

x ≤ 6