Angles CED and CBD subtend the same arc. Determine the measure of ∠CED.
Question options:
1)
100°
2)
150°
3)
310°
4)
50°
Answers
Answer:
[tex]50^{\circ}[/tex]
Step-by-step explanation:
Inscribed angles that form the same arc have the same angle measure, no matter where they lie on the circle. Since the measure of angle CBD forms the same arc as angle CED, the measure of angle CBD must be equal to the measure of angle CED, hence [tex]m\angle CED=\boxed{50^{\circ}}[/tex]
Answer:
the answer is 4)50°
Step-by-step explanation:
because it is same
Related Questions
Not sure how to do this
Answers
Air is being pumped into a spherical balloon at a rate of 5 cm^3/min. Determine the rate at which the radius of the balloon is increasing when the diameter of the balloon is 20 cm
Answers
0.08 cm/min
Step-by-step explanation:
Given:
[tex]\dfrac{dV}{dt}=5\:\text{cm}^3\text{/min}[/tex]
Find [tex]\frac{dr}{dt}[/tex] when diameter D = 20 cm.
We know that the volume of a sphere is given by
[tex]V = \dfrac{4\pi}{3}r^3[/tex]
Taking the time derivative of V, we get
[tex]\dfrac{dV}{dt} = 4\pi r^2\dfrac{dr}{dt} = 4\pi\left(\dfrac{D}{2}\right)^2\dfrac{dr}{dt} = \pi D^2\dfrac{dr}{dt}[/tex]
Solving for [tex]\frac{dr}{dt}[/tex], we get
[tex]\dfrac{dr}{dt} = \left(\dfrac{1}{\pi D^2}\right)\dfrac{dV}{dt} = \dfrac{1}{\pi(20\:\text{cm}^2)}(5\:\text{cm}^3\text{/min})[/tex]
[tex]\:\:\:\:\:\:\:= 0.08\:\text{cm/min}[/tex]
In a certain animal species, the probability that a healthy adult female will have no offspring in a given year is 0.24, while the probabilities of 1, 2, 3, or 4 offspring are respectively 0.25, 0.19, 0.17, and 0.15. Find the expected number of offspring.
Answers
Answer:
The expected number of offspring is 2
Step-by-step explanation:
The given parameters can be represented as:
[tex]\begin{array}{cccccc}x & {0} & {1} & {2} & {3} & {4} \ \\ P(x) & {0.24} & {0.25} & {0.19} & {0.17} & {0.15} \ \end{array}[/tex]
Required
The expected number of offspring
This implies that we calculate the expected value of the function.
So, we have:
[tex]E(x) = \sum x * P(x)[/tex]
Substitute known values
[tex]E(x) = 0 * 0.24 + 1 * 0.25 + 2 * 0.19+ 3 * 0.17 + 4 * 0.15[/tex]
Using a calculator, we have:
[tex]E(x) = 1.74[/tex]
[tex]E(x) = 2[/tex] --- approximated
A committee on community relations in a college town plans to survey local businesses about the importance of students as customers. From the 10,000 businesses listed in the telephone book, the committee chooses 150 businesses at random. Of these, 72 return the questionnaire mailed by the committee. The nonresponse rate is ______ percent. (Give your answer as a whole number.)
Answers
Answer:
The nonresponse rate is 52 percent.
Step-by-step explanation:
150 sampled:
72 returned and 150 - 72 = 78
The nonresponse rate is
Percentage that 78 is out of 150, that is:
78*100%/150 = 52%
The nonresponse rate is 52 percent.
help me please i’ll give brainliest the
Answers
Answer:
y=-1/2x+-1
Step-by-step explanation:
try desmos with this equation.
y=mx+b
m=the slope which is -1/2. It goes down 1 it is negative because it is going down, and to the right 2.
b=y-intercept meaning the point which the line crosses the line y .-1
300-20+100 divided by 4=
Answers
Answer:
95
Step-by-step explanation:
300-20=280
280+100=380
380÷4=95
There you go...
You are offered two stocks. The beta of A is 1.4 while the beta of B is 0.8. The growth rates of earnings and dividends are 10% and 5%, respectively. The dividend yields are 5% and 7%, respectively.
Since A offers higher potential growth, should it be purchased?
Investments- Individual Work 2 Page 3
Since B offers a higher dividend yield, should it be purchased?
If the risk-free rate of return were 7% and the return on the market is expected to be 14%, which of these stocks should be bought?
Answers
Answer:
a) Yes , Cause The Expected Returns of stock A is Higher than that of B
b) No, Cause The Expected Returns of stock B is Lower than that of A
Step-by-step explanation:
From the question we are told that:
Beta A \beta A=1.4
Beta B \beta B=0.8
Stock 1 Growth rates of earnings and dividends G_1=10\%
Stock 2 Growth rates of earnings and dividends G_2=5\%
Stock 1 Dividend yields D_1=5\%
Stock 2 Dividend yields D_2=7\%
Generally the equation for Expected Returns is mathematically given by
Expected Returns =Growth rates+Dividend yields
For Stock 1
Expected\ Returns =G_1+D_1
Expected\ Returns =5%+10%
Expected\ Returns =15%
For Stock 2
Expected\ Returns =G_2+D_2
Expected\ Returns =7%+5%
Expected\ Returns =12%
Therefore
a) Yes , Cause The Expected Returns of stock A is Higher than that of B
b) No, Cause The Expected Returns of stock B is Lower than that of A
What's an equivalent fraction of 3/4 that has a denominator of 32
Answers
Answer:
24/32
Step-by-step explanation:
[tex]\frac{3}{4} = \frac{x}{32}[/tex]
To get from 4 to 32, you multiply by 8
so to get from 3 to x, multiply by 8
The answer for this would be 24/32
Determine if the statement is always, sometimes, or never true:
An equilateral triangle is an acute triangle.
never
always
sometimes
Answers
The answer is always your welcome
Answer:
always
Step-by-step explanatia;won:
Surface area of the below shape
Answers
Solve all of the equations below and add all of the solutions to those equations to get your answer.
10x4x2=
8x4x2=
10x8=
(10x8)-(7x6)=
7x2x2=
6x2x2=
7x6=
Find the difference: -18 - (-18)
Answers
Answer:
0
Step-by-step explanation:
-18-(-18)
= -18+18 [(+) + (+)=(+)]
=0 [(-) + (-)=(-)]
The answer to this question please.
Answers
Answer:
Part A) y=1,100x + 4,500
Part B) 14,400
Step-by-step explanation:
Part A)
There is a base fee of $4,500, meaning that the line begins at y=4500 (i.e. The y-intercept is [0,4500], so 'b' in y=mx+b is 4,500). There is a $1,100 hourly rate, which is proportional to the value of x, the amount of hours filmed. Therefore, 'm' in y=mx+b is $1,100.
Thus, the final equation looks like:
y= 1,100x + 4,500
Part B)
x=9
y=1,100x+4,500
y=1,100(9)+4,500
y=9,900+4,500
y=14,400
HELP WITH 16 What is the value of X
Answers
Answer:
C - 136
(115+157)/2
Step-by-step explanation:
plzzzzzzzzzzz help i will give brainliest
Answers
Answer:
Below.
Step-by-step explanation:
IQR is the same
Number of data points is the same.
Mode - can't tell
Range - different
First quartile - same
Median - different.
What is the value of…
–13
–12
12
13
Answers
Answer:
-12
Step-by-step explanation:
that is b
A line passes through the point (-2,4) and has a slope of 7. Write an equation for this line
Answers
Answer: y = 7x + 18
Step-by-step explanation:
y = mx + b, (-2,4), m = 7
4 = 7(-2) + b
4 = -14 + b
b = 18
y = 7x + 18
Luis was worried about his Spanish final exam grade. The test had 200 questions, and he got
175 of them correct. His sister Marina took her French final exam, and she got 130 out of 150
questions. Who got the better percent score (round to the nearest tenths)?
Answers
Answer:
Luis:
[tex] \frac{175}{200} \times 100\% = 87.5\%[/tex]
Marina:
[tex] \frac{130}{150} \times 100\% = 86.6\%[/tex]
Answer: Marina got the better percent score than Luis
Marina:
The quadratic equation $ax^2+20x+c=0$ has exactly one solution. If $a+c=29$, and $a
Answers
Answer:
a² + c² = 641
Step-by-step explanation:
Given :-
ax² + 20x + c has exactly one solution .a + c = 29 .For exactly one Solution ,
b² - 4ac = 0 20² - 4*a*c = 0 4ac = 400 ac = 100Also ,
a + c = 29 ( a + c)² = 29²a² + c² + 2ac = 841 a² + c² + 2*100 = 841a²+ c² = 841 - 200 a² + c² = 641Which statement is sufficient to prove that quadrilateral ABCD is a parallelogram?
A) m∠A ≅ m∠C, m∠B ≅ m∠D
B) AB ≅ CD
C) AC ≅ BD
D) BC // AD
Answers
Answer:
A) m∠A ≅ m∠C, m∠B ≅ m∠D
Step-by-step explanation:
If both pairs of opposite angles are congruent, then the figure is a parallelogram.
An advertiser goes to a printer and is charged $36 for 80 copies of one flyer and $46 for 242 copies of another flyer. The printer charges a fixed setup cost plus a charge for every copy of single-page flyers. Find a function that describes the cost of a printing job, if xx is the number of copies made.
Answers
Answer:
ytre
Step-by-step explanation:
MY NOTES Verify that the function satisfies the three hypotheses of Rolle's Theorem on the given interval. Then find all numbers c that satisfy the conclusion of Rolle's Theorem. (Enter your answers as a comma-separated list.) f(x) = 2x2 − 4x + 3, [−1, 3
Answers
Answer:
b) [tex]c=1[/tex]
Step-by-step explanation:
From the question, we are told that:
Function
[tex]F(x)=2x^2-4x+9[/tex]
Given
Rolle's theorem states that if a function f is continuous on the closed interval [a, b] and differentiable on the open interval (a, b) such that f(a) = f(b), then f′(x) = 0 for some x with a ≤ x ≤ b.
Generally, the Function above is a polynomial that can be Differentiated and it is continuous
Where
-F(x) is continuous at (-1,3)
-F(x) Can be differentiated at (-1.3)
-And F(-1)=F(3)
Therefore
F(x) has Satisfied all the Requirements for Rolle's Theorem
Differentiating F(x) we have
[tex]F'(x)=4x-4[/tex]
Equating F(c) we have
[tex]F'(c)=0[/tex]
[tex]4(c)-4=0[/tex]
Therefore
[tex]c=1[/tex]
a. 1140
b. 1130
c. 1120
d. 115
Answers
Answer:
1130
Step-by-step explanation:
1109+7 = 1116
1116+7 = 1123
Adding 7 each time
1123+7 = 1130
A window is to be built in the shape of a rectangle surmounted by an isosceles triangle. The area of the window must be 6 square meters. Use Lagrange Multipliers to find the width and height of the rectangle for which the perimeter of the window will be as small as possible
Answers
Answer:
x = 2.536 m
y = 2 m
Step-by-step explanation:
Considering the three sides of the rectangle and the isosceles triangle
when resolving the width and height of the rectangle to achieve the smallest possible perimeter.
step 1 :
Area of window = xy + 1/2 xz , perimeter = x + 2y + 2c
c = [tex]\sqrt{z^2 + 1/4 x^2 }[/tex]
we are tasked with minimizing the perimeter ( p ) subject to A = 6
attached below is the detailed solution of the given problem
There is 3m wide path around a circular cricket ground having the diameter of 137 m. Find the area of the path.
Answers
Answer:
1320 m^2
Step-by-step explanation:
area of ground = π r ^2
= (22/7) × (137/2)^2
= 14,747.0714286 m^2
area of ground and path
=( 22/7)(143/2)^2
= 16,067.0714286 m^2
area of path
=16,067.0714286 -14,747.0714286
= 1320 m^2
note :
r = radius = diameter /2
area of a circle = π r^2
diameter of circle created with path and ground = 137 + 2 × width of path
= 137 + 2× 3 = 143 m
Silicone implant augmentation rhinoplasty is used to correct congenital nose deformities. The success of the procedure depends on various biomechanical properties of the human nasal periosteum and fascia. An article reported that for a sample of 10 (newly deceased) adults, the mean failure strain (%) was 24.0, and the standard deviation was 3.2.
Required:
a. Assuming a normal distribution for failure strain, estimate true average strain in a way that converys information about precision and reliability.
b. Predict the strain for a single adult in a way that conveys information about precision and reliability. How does the prediction compare to the estimate calculated in part (a)?
Answers
Solution :
Given information :
A sample of n = 10 adults
The mean failure was 24 and the standard deviation was 3.2
a). The formula to calculate the 95% confidence interval is given by :
[tex]$\overline x \pm t_{\alpha/2,-1} \times \frac{s}{\sqrt n}$[/tex]
Here, [tex]$t_{\alpha/2,n-1} = t_{0.05/2,10-1}$[/tex]
= 2.145
Substitute the values
[tex]$24 \pm 2.145 \times \frac{3.2}{\sqrt {10}}$[/tex]
(26.17, 21.83)
When the [tex]\text{sampling of the same size}[/tex] is repeated from the [tex]\text{population}[/tex] [tex]n[/tex] infinite number of [tex]\text{times}[/tex], and the [tex]\text{confidence intervals}[/tex] are constructed, then [tex]95\%[/tex] of them contains the [tex]\text{true value of the population mean}[/tex], μ in between [tex](26.17, 21.83)[/tex]
b). The formula to calculate 95% prediction interval is given by :
[tex]$\overline x \pm t_{\alpha/2,-1} \times s \sqrt{1+\frac{1}{n}}$[/tex]
[tex]$24 \pm 2.145 \times 3.2 \sqrt{1+\frac{1}{10}}$[/tex]
(31.13, 16.87)
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. The article "Properties of Waste Silk Shod Fiber/Cellulose Green Composite Films" (. of Composite Materials, 2012: 123-127) reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.3 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value?
Answers
Complete Question
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and inexpensive to manufacture. However, their nondegradable nature has prompted development of environmentally friendly composites using natural materials. An article reported that for a sample of 10 specimens with 2% fiber content, the sample mean tensile strength (MPa) was 51.1 and the sample standard deviation was 1.2. Suppose the true average strength for 0% fibers (pure cellulose) is known to be 48 MPa. Does the data provide compelling evidence for concluding that true average strength for the WSF/cellulose composite exceeds this value? (Use α = 0.05.)
t=8.169
P-value= ?
Answer:
a) [tex]P-value=0[/tex]
b) Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
Step-by-step explanation:
From the question we are told that:
Sample size [tex]n=10[/tex]
Mean [tex]\=x= 51.3[/tex]
Standard deviation [tex]\sigma=1.2[/tex]
Significance level is taken as [tex]\alpha=0.05[/tex]
t test statistics
[tex]t=8.169[/tex]
Therefore
[tex]P-Value=P(t>8.169)[/tex]
Critical point
[tex]t_{\alpha,df}[/tex]
[tex]\alpha=0.05[/tex]
[tex]df=10-1=>9[/tex]
Therefore
P-value from T distribution table
[tex]P-value=0[/tex]
Conclusion
[tex]P-value (0)< \alpha(0.05)[/tex]
We Reject the Null Hypothesis [tex]H_0[/tex]
Hence,We FAil to reject the alternative hypothesis and accept that the true average strength for the WSF/ cellulose composite exceeds 48 MPa.
Yooooo HELPPP
with this question plz
Answers
Answer:
Step-by-step explanation:
(x-2)(x+4)=x^2+4x-2x-8=0=> x =2, x=0
Answer:
A
Step-by-step explanation:
You can work a total of no more than 35 hours each week at your two jobs. Housecleaning pays $7 per hour and your sales job pays $9 per hour. You need to earn at least $314 each week to pay your bills. Write a system of inequalities that shows the various numbers of hours you can work at each job.
Answers
Answer: 7x + 9y >_ (more or equal) 314
X + Y <_ ( less or equal) 35
Step-by-step explanation:
Answer:
h+s≤35 and 7h + 9s >_314
Step-by-step explanation:
PLEASE HELP
Identify the first five terms of the sequence in which a, = 3n2 - 1.
Answers
Step-by-step explanation:
you cannot just put the actual numbers in and calculate ?
and you can't provide the correct problem statement, as it seems.
I assume you mean
an = 3n² - 1
a sequence starts with a1, so, n>=1
a1 = 3×1² - 1 = 3-1 = 2
a2 = 3×2² -1 = 3×4 - 1 = 12 - 1 = 11
a3 = 3×3² - 1 = 3×9 - 1 = 27 - 1 = 26
a4 = 3×4² - 1 = 3×16 - 1 = 48 - 1 = 47
a5 = 3×5² - 1 = 3×25 - 1 = 75 - 1 = 74
there, that is all there is to it. you really needed help with that ?
A store surveyed their customers to find out their ages. The bar graph below shows the number of customers in each age group. What percent of customers surveyed were over 50%? Round your answer to 1 decimal place.
Answers
Bar graphs are used to represent data, where the vertical axis represents the frequency and the horizontal axis.
The percentage that is over 50 is 15.6%:
The data on the bar graph can be represented as:
Under 17 [tex]\to[/tex] 25
18 - 24 [tex]\to[/tex] 35
25 - 34 [tex]\to[/tex] 40
35 - 50 [tex]\to[/tex] 35
Over 50 [tex]\to[/tex] 25
So, the total customer surveyed are:
[tex]Total = 25 + 35 + 40 + 35 + 25[/tex]
[tex]Total = 160[/tex]
The percentage over 50 are:
[tex]\%Over\ 50 = \frac{Over\ 50}{Total } * 100\%[/tex]
[tex]\%Over\ 50 = \frac{25}{160} * 100\%[/tex]
[tex]\%Over\ 50 = 0.15625* 100\%[/tex]
[tex]\%Over\ 50 = 15.625\%[/tex]
Approximate
[tex]\%Over\ 50 = 15.6\%[/tex]
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