A wave has a frequency of 15,500 Hz and a wavelength of 0.20 m. What is the
speed of the wave? Use the equation v=fx2.
A. 0.0000013 m/s
B. 3100 m/s
O C. 78,000 m/s
D. 0.00032 m/s

Answers

Answer 1

Answer:

it's B for a pe x

Explanation:


Related Questions

Cylindrical rod has equal and opposite forces applied perpendicular to its circular ends. The forces are directed away from the rod, stretching the rod. What type of stress is this rod subject to:_________A) The rod is subject to shear stress. B) The rod is subject to tensile stress. C) The rod is subject to compressive stress. D) The rod is subject to bulk stress.

Answers

Answer:

B) The rod is subject to tensile stress

Explanation:

Tensile stress is the force induced in the body per unit area in response to externally applied force, which stretches the body.

Tensile stress is attached with tensile forces. It is makes material elongate along the axis of the applied load.

It is given as magnitude (F) of the force that is applied along an elastic rod divided by the cross sectional area (A) of the rod in a direction that is perpendicular to the applied force.

materials such as Doctile have the ability to withstand the load while brittle materials who not have the ability they fail before reaching the ultimate material strength.

A 0.900-V potential difference is maintained across a 1.5m length of 2
tungsten wire that has a cross-sectional area of 0.600 mm . What is the current in the wire?

Answers

Answer:

I = 6.42 A

Explanation:

Given that,

Potential difference, V = 0.9 V

Length of the wire, l = 1.5 m

Area of cross section, [tex]A=0.6\ mm^2=6\times 10^{-7}\ m^2[/tex]

We need to find the current in the wire. Let I is current. We can find it using Ohm's law as follows :

V = IR

Where R is the resistance of the wire

[tex]I=\dfrac{V}{R}\\\\I=\dfrac{V}{\rho \dfrac{l}{A}}\\\\I=\dfrac{0.9}{5.6\times 10^{-8}\times \dfrac{1.5}{6\times 10^{-7}}}\\\\I=6.42\ A[/tex]

So, the current in the wire is 6.42 A.

Cindy has been working for 8 years and she’s built up a huge emergency fund

Answers

Answer:The answer will be B :) hope this helps!

Explanation:

A train slows from 44 m/s to 19 m/s in 9 seconds. What is the train's acceleration? Show your work.

Answers

Answer:

a = 2.77 [m/s²]

Explanation:

To solve this problem we must use the following equation of kinematics.

[tex]v_{f} =v_{o} -a*t[/tex]

where:

Vf = final velocity = 19 [m/s]

Vo = initial velocity = 44 [m/s]

a = acceleration [m/s²]

t = time = 9 [s]

Note: The negative sign in the above equation means that the train is decreasing its velocity.

19 = 44 - a*9

9*a = 44 -19

a = 2.77 [m/s²]

30.6*X+-2.56
Pls help

Answers

Answer:  10.16

Explanation:

What is an atom's nucleus made of?
(2 points)
protons and electrons
protons only
protons and neutrons
neutrons only

Answers

Answer:

nucleus made of protons and neutrons because the chemical atom is determined my a number

What would the distance be if a bicyclist traveled 4.5 hours at a speed of 20.0km/h?

Answers

5.5 is the answer i think

A sled with a mass of 25.0 kg rests on a horizontal sheet of essentially frictionless ice. It is attached by a 5.00-m rope to a post set in the ice. once given a push, the sled revolves uniformly in a circle around the post. If the sled makes five complete revolutions every minute, find the F exerted on it by the rope.​

Answers

Answer:

The value is  [tex]F = 34.3 \ N[/tex]

Explanation:

From the question we are told that

    The mass of the shed is  [tex]m = 25 \ kg[/tex]

    The length of the rope is  [tex]l = 5.0 \ m[/tex]

    The angular speed of the shed is [tex]w = 5 rev/minute = \frac{2* \pi * 5}{60 }= 0.524 \ rad/sec[/tex]

Generally the force exerted on the shed is mathematically represented as

     [tex]F = m * w^2 * l[/tex]

=>  [tex]F = 25 * 0.524^2 * 5[/tex]

=>  [tex]F = 34.3 \ N[/tex]    

The magnitude of the centripetal force on the sled by the rope is 34.3 N.

The given parameters:

mass of the sled, m = 25 kglength of the rope, r = 5 mnumber of revolution per minute, N = 5

The angular speed of the sled is calculated as follows;

[tex]\omega = 5 \ \frac{rev}{\min} \times \frac{2\pi \ rad}{1 \ rev} \times \frac{1 \min}{60 \ s} \\\\\omega = 0.524 \ rad/s[/tex]

The magnitude of the centripetal force on the sled by the rope is calculated as follows;

[tex]F = ma_c\\\\F = m\omega ^2 r\\\\F = 25 \times (0.524)^2 \times 5\\\\F = 34.3 \ N[/tex]

Learn more here:https://brainly.com/question/20905151

A roller coaster has a vertical loop with radius 29.5 m.What is the minimum speed of the roller coaster car can have at the top of the loop if the passengers do not lose contact with the seats?
A) 10.0 m/s
B) 14.0 m/s
C) 17.0 m/s
D) 19.0 m/s

Answers

Answer:the  Minimum speed , v of the roller coster = 17.0 m/s --c

Explanation:

According to Newton's First law  of Motion which state that all object will remain at rest unless an external force is applied on the body to act otherwise.

Therefore the   Force exerted/ acting  on the surface of  the roller coaster will be equal to 0,

Net Force = 0

Remember that , Force = mg = Mv ²/r = 0

 Net Force =mv ² / r - mg = 0

mv²/ r - mg = 0

(diving through by m)

v²/r -g = 0

v² = gr

v= [tex]\sqrt{gr}[/tex]

where g, acceleration due to gravity= 9.8m/s2 and radius, r = 29.5m

v=  [tex]\sqrt{9.8m/s2 X 29.5m }[/tex]

v =[tex]\sqrt{ 289}[/tex]

v=  17.0 m/s

Therefore, the  Minimum speed , v of the roller coaster = 17.0 m/s

an object with a mass of 7.5 kg accelerates 8.3 m/s2 when an unknown force is applied to it. what is the amount of the force?

Answers

Answer:

I believe the answer is 62.25 N

Explanation:

You just multiply 7.5 and 8.3 and you get 62.25

Answer:

62.25N or 62.25 newtons

Explanation:

F=ma where F is the force in newtons, m is the mass in kilograms (kg), and a is the acceleration

m=7.5kg

a=8.3m/s^2

Therefore, F=ma=7.5*8.3=62.25N

The amount of force is 62.25N or 62.25 newtons

A stone is dropped vertically downwards. What is the velocity of the rock after 4 seconds ? What is the displacement of the rock after 4 seconds ?

Answers

Answer:

Vf = 39.2 m/s

h = 78.4 m

Explanation:

Using first equation of motion for vertical motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s

g = 9.8 m/s²

t = time taken = 4 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(4 s)

Vf = 39.2 m/s

Now, we use second equation of motion

h = Vi t + (1/2)gt²

where,

h = height covered = ?

Therefore,

h = (0 m/s)(4 s) + (1/2)(9.8 m/s²)(4 s)²

h = 78.4 m

A barrel of oil contains roughly 6.1x109 J. How many kW-hr is this? Answer in
units of kW-hr

Answers

Answer:

[tex]1.694*10^3KW/hr[/tex]

Explanation:

Formula:

[tex]KW/hr=E_{(change)}[/tex]

[tex]P=\frac{E}{t}[/tex]

[tex](KW)(s)=1000J[/tex]

[tex](3600)(KW)(s)=3600*1000J[/tex]

[tex]KW=3.6*10^6[/tex]

[tex]\frac{6.1*10^9}{3.6*10^6}=\frac{x}{1KW}[/tex]

[tex]1.694*10^3KW/hr[/tex]

Hope it helps

Which phrase best completes the diagram?
Drawbacks of Trade Barriers
Less consumer choice
Retaliatory trade barriers
A. Domestic jobs put at risk
B. More competition for domestic industries
O
C. Increased reliance on other countries
D. Reduced economic efficiency

Answers

Answer:D

Explanation:

just got it right

Answer:D

Explanation:

taking the test

The mass of an empty flask is 49.74 g. Filled with 120 cm 3 of acetone, the mass of the flask is found to be 144.78 g. What is the density of acetone?

Answers

Answer:

0.79g/cm³

Explanation:

Given parameters:

Volume of acetone = 120cm³

Mass of empty flask  = 49.74g

Mass of flask + acetone  = 144.78g

Unknown:

Density of acetone = ?

Solution:

Density is the mass per given volume of a substance. It is mathematically expressed as;

   Density  = [tex]\frac{mass}{volume}[/tex]  

     Mass of acetone  =( mass of flask + acetone)   - mass of empty flask

     Mass of acetone = 144.78  - 49.74  = 95.04g

Now insert the parameters and solve;

 Density  = [tex]\frac{95.04}{120}[/tex]   = 0.79g/cm³

A sphere has a mass of 8.5 kg and a radius of 10cm. How much work is it necessary to do on the ball to get it to a speed of 6.0m/s?

Answers

Answer:

153J

Explanation:

Step one:

given data

mass m= 8.5kg

radius r= 10cm in meters = 0.01m

velocity v= 6m/s

The work done will be the same as the energy possessed by the sphere at such speed

Required

the work one in Joules

we know that

KE=1/2mv^2

KE=1/2*8.5*6^2

KE= 1/2*8.5*36

KE=306/2

KE=153J

8.
'A 6.00 kg ball, A, moving at velocity 3.00 m/s due east collides with a 6.00 kg ball, B, at rest.
After the collision, A moves off at 40.0°N of E and ball B moves off at 50.0° S of E
please help me.​

Answers

Answer:

brrrrrakabrrrrrrrrra

Explanation:

On Earth, you can lift a 10 kg object. What is the mass of that object on the moon? Is mass independent from gravity?​

Answers

Explanation:

An object's weight depends on the pull of the gravitating object but the object's mass is independent of the gravity.

True or false? An electric current is a continuous flow of electric charges through a material.

Answers

Answer is... if True
The Answer is True.

A ball rolls to the right across a grassy field slowing down as it does so. Which of the following must be true?

Answers

Answer: i could prolly answer if it made more sense. which of the following where?

Answer:

D: the ball is not accelerating because it is slowing down

Explanation:

if the was no friction, then the ball would most likely pick up speed and never stop, like it would with it being on a hill covered in ice, it would pick up speed and never slow down (well, it would slow down, just at a point where it looks like it would never stop.

The Doppler effect is the change in sound _____ caused by the motion of the sound source, motion of the listener, or both.
pitch
frequency
amplitude
speed

Answers

Frequency.
..........

A torque of 0.97 N m is applied to a bicycle wheel of radius 35 cm and mass 0.75 kg. Assuming the wheel can be modelled as a hoop, find the angular acceleration of the wheel.

Answers

Answer:

11 rad/s^2 approx.

Explanation:

Given

torque,τ= 0.97N

radius r= 35cm to m= 0.35m

mass m= 0.75kg

Required

angular acceleration

First, we need the  moment of inertial of the wheel

I=mr^2

I=0.75*0.35^2

I=0.75*0.1225

I=0.09kgm^2

Secondly, the angular moment of inertial is expressed as

a=τ/I

a=0.97/0.09

a=10.77rads/s^2

a=11 rad/s^2 approx.

A projectile is fired horizontally off the top of a cliff with an initial velocity of 30 m/s. It hits the ground 2.0 seconds later. What is the height of the cliff?

Answers

Answer:no

Explanation:

An airplane takes off northwest from Dallas to Amarillo. This is an example of-

a. Speed
b. Velocity
c. Acceleration

Answers

Answer:

the answers is C. acceleration

Can power be negative in physics? I am doing a lab in which I run down the stairs as quickly as possible. They are 5.4m tall and my work is 5321.7 J. After calculating work, I got -5321.7 J. I am supposed to calculate my power used over 3 trials. The time for trial 1 was 4.69 and the seconds for trials 2 and 3 are 4.25. After calculating my power I got -1134.69 W and -1252.16 W. I am not sure if I got my power right. Is my power really negative or is my power positive?

Answers

Answer:

Yes.

Explanation:

A negative power would just represent a loss of power. So in your case it lost -1252.16 W

what
material gives the soil its high fertility?

Answers

Answer:

Humus

Explanation:

Its Humus I believe. I remember learning something like this.

Check how you understand the principles of working of lenses. In some optical setup consisting of a single lens and an object magnification factor is measured as m-+4. We can conclude that:__________ a. Lens is converging, image is at the opposite side of lens from the object b. Lens is converging, image is the same side of lens as object c. Lens is diverging, image is at the opposite side of lens from the object d. Lens is diverging, image is the same side of lens as object

Answers

Answer:

b. Lens is converging, image is the same side of lens as object

Explanation:

A single converging lens is often used as a magnifying glass. The reason, behind its use as a magnifying glass is the configuration of the converging lens, when an object is placed inside its focal length. It forms the image of that object as magnified and at the same side as the object. So, the image is both magnified and erect. In this way, the converging lens serves as a magnifying glass with certain magnification factor, single handedly. The ray diagram of a magnifying glass is attached for reference. So, the correct option is:

b. Lens is converging, image is the same side of lens as object

A sound wave travels in a straight line at a constant speed of 660 mph. What is
the acceleration of the sound wave? Explain your answer.

Answers

Answer:

a = 0

Explanation:

The velocity of a sound wave in a straight line is 660 mph. The wave is moving with a constant velocity. It means that the change in velocity is equal to 0.

We know that acceleration of an object is equal to the change in velocity divided by time taken. But here the change in velocity is 0. As a result the acceleration of the sound wave is 0.

Whoever answers correctly gets brainlist!

Answers

Infared = used by police

gamma = short wavelength

radio = largest wavelength

visible = only ones we can see

Answer: police use infred waves,

radio waves have largest wave length, the

only part of the spectrum seen by humans is visible waves

gamma waves have shortest wave length

Explanation:

1. In a particular experiment to study the photoelectric effect, the frequency of the incident light and the temperature of the metal are held constant. Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, what happens if the intensity of the incident light is increased?A. The work function of the metal decreases. B. The number of electrons emitted from the metal per second increases. C. The maximum speed of the emitted electrons increases. D. The stopping potential increases.2. In another experiment, the intensity of the incident light and the temperature of the metal are held constant. Assuming that the initial light incident on the metal surface causes electrons to be ejected from the metal, what happens if the frequency of the incident light is increased? A. The work function of the metal increases. B. The number of electrons emitted from the metal per second increases. C. The maximum speed of the emitted electrons increases. D. The stopping potential increases.

Answers

Answer: 1. B. The number of electrons emitted from the metal per second increases.

2. The maximum speed of the emitted electrons increases.

The stopping potential increases

Explanation:

Photoelectric effect is simply referred to as the emission of electrons that occurs when there's an electromagnetic radiation. An example of such electromagnetic radiation is when material is being hit by light.

Assuming that the light incident on the metal surface causes electrons to be ejected from the metal, the number of electrons emitted from the metal per second increases if the intensity of the incident light is increased.

Also, if the initial light incident on the metal surface causes electrons to be ejected from the metal, the maximum speed of the emitted electrons increases and the stopping potential increases.

A computational model predicts the maximum potential energy a roller coaster car can have given its mass and its speed at the lowest point of its journey. Its mass is 350 kg, and it speed at a height of 0 m is 25 m/s. What is the prediction for its maximum potential energy?
109,375 J

765,625 J

218,750 J

87,750 J

Answers

Answer:

The prediction for its maximum potential energy is 109,375 J

Explanation:

Given;

mass of the coaster car, m = 350 kg

speed of the coaster car at the lowest point, v = 25 m/s

The coaster car will have maximum kinetic energy at the lowest point and based on law of conservation of mechanical energy, the maximum kinetic energy of the coaster car at the lowest point will be equal to maximum potential energy at the highest point.

[tex]K.E_{max} = P.E_{max}[/tex]

[tex]K.E_{max} = \frac{1}{2} mv^2\\\\K.E_{max} = \frac{1}{2} (350)(25)^2\\\\K.E_{max} =109,375 \ J[/tex]

[tex]Thus, P.E_{max} = 109,375 \ J[/tex]

Therefore, the prediction for its maximum potential energy is 109,375 J

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