Answer:
256
Step-by-step explanation:
since the the path surounds both sides of the garden you have to add 2 x instead of just x
let me show you what i mean. 10=garden width and 3=path width=x
since it is a square, we can calculate the area by taking one side and squaring it so you get (10+2x)^2 which is 16^2 since x is 3, the width of the garden
to do simaler problems just use thei formula (garden length+2path length)^2 or (garden length+2path length)times(garden length+2path length)
my third time posting this question plssss :(
Answer:
Answers are below in bold.
Step-by-step explanation:
The first answer is correct. 1 m² = 10,000cm²
A=2(wl+hl+hw) To find the surface area of the package, use this equation
A=2(18*50+20*50+20*18) Multiply in the parentheses
A=2(900+1000+360) Add in the parentheses
A=2(2260) Multiply
A=4520
The package has a surface area of 4520 cm²
The area of the package is less than the area of the wrapping paper.
So, Dayson can completely cover the package with the wrapping paper.
A miner is trapped in a mine containing 3 doors:1. The first door leads to a tunnel that will take him to safety after 3 hours of travel.2. The second door leads to a tunnel that will return him to the mine after 5 hours of travel.3. The third door leads to a tunnel that will return him to the mine after 7 hours.If we assume that the miner is at all times equally likely to choose any one of the doors (supposing themine shaft is so disorienting that he cannot tell which door he chose before), LetXdenote the lengthof time until the miner reaches safety.Compute the variance, Var(X).
Answer:
The miner should take door number 1
Lee put $10,000 into a stock market index mutual fund that grew at an average of 7% per year for 10 years. About how much is in Lee's mutual fund account after 10 years? Ignore compounding.
Answer:
17000
Step-by-step explanation:
we can use the equation I=PRT
I=10,000(10)(0.07)
I=100,000(0.07)
i=7000
7000+ the initial 10,000=17000
(x^2-7)(x^2-4) using the FOIL method, multiply the terms of the binomial
Answer:
[tex]x^{4} -11x^{2} +28[/tex]
Step-by-step explanation:
[tex](x^{2} -7)(x^{2} -4)[/tex]
[tex]x^{4} -4x^{2} -7x^{2} +28[/tex]
[tex]x^{4} -11x^{2} +28[/tex]
Sales of the first Quality Mini Buses were as follows: 250 yellow, 150, green, and 100 blue. Assume the relative frequency method is used to assign probabilities for color choice and the color of each car sold is independent of that of any other car sold.
What is the probability that the next bus sold will be yellow or green?
a. 0.10
b. 0.40
c. 0.80
d. 0.50
e. 0.70
Answer:
c. 0.80
Step-by-step explanation:
Probability from relative frequency:
The probability is the number of desired outcomes divided by the number of total outcomes.
What is the probability that the next bus sold will be yellow or green?
250+150+100 = 500 buses sold
Of those, 250+150 = 400 are yellow or green.
400/500 = 0.8
So the correct answer is:
c. 0.80
A company plans to manufacture a rectangular bin with a square base, an open top, and a volume of 13,500 in3. Determine the dimensions of the bin that will minimize the surface area. What is the minimum surface area
Answer:
Dimensions 30 in x 30 in x 15 in
Surface Area = 2,700 in²
Step-by-step explanation:
Let 'r' be the length of the side of the square base, and 'h' be the height of the bin. The volume is given by:
[tex]V=13,500=h*r^2\\h=\frac{13,500}{r^2}[/tex]
The total surface area is given by:
[tex]A=4*hr+r^2[/tex]
Rewriting the surface area function as a function of 'r':
[tex]A=4*\frac{13,500}{r^2} *r+r^2\\A=\frac{54,000}{r}+r^2[/tex]
The value of 'r' for which the derivate of the surface area function is zero, is the length for which the area is minimized:
[tex]A=54,000*r^{-1}+r^2\\\frac{dA}{dr}=0= -54,000*r^{-2}+2r\\\frac{54,000}{r^2}=2r\\ r=\sqrt[3]{27,000}\\r=30\ in[/tex]
The value of 'h' is:
[tex]h=\frac{13,500}{30^2}\\ h=15\ in[/tex]
The dimensions that will ensure the minimum surface area are 30 in x 30 in x 15 in.
The surface area is:
[tex]A=4*15*30+30^2\\A=2,700\ in^2[/tex]
Clay weighs 9 times as much as his baby sister clay weighs 63 pounds how much doea hiw baby sister weigh in ounces
Answer:
112 ounces
Step-by-step explanation:
Clay weighs 9 times as much as his baby sister .
Clay weighs 63 pounds.
His baby sister weigh 63/9.
His baby sister weighs 7 pounds.
But to be converted to ounce.
1 pound = 16 ounces
7 pounds = 7*16 ounces
7 pounds = 112 ounces
Please see picture of problem
Answer:
w = 9, l = 12
Step-by-step explanation:
If w is the width and l is the length, then:
l = 2w − 6
The area of the rectangle is width times length.
A = wl
Substituting and solving:
108 = w (2w − 6)
108 = 2w² − 6w
54 = w² − 3w
0 = w² − 3w − 54
0 = (w + 6) (w − 9)
w = -6 or 9
The width is 9, so the length is 12.
Lockheed Martin, the defense contractor designs and build communication satellite systems to be used by the U.S. military. Because of the very high cost the company performs numerous test on every component. These test tend to extend the component assembly time. Suppose the time required to construct and test (called build time) a particular component is thought to be normally distributed, with a mean equal to 60 hours and a standard deviation equal to 9.4 hours. To keep the assembly flow moving on schedule, this component needs to have a build time between 52 and 70 hours. Find the probability that the build time will be such that assembly will stay on schedule.
Answer:
[tex]P(52<X<70)=P(\frac{52-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{70-\mu}{\sigma})=P(\frac{52-60}{9.4}<Z<\frac{70-60}{9.4})=P(-0.851<z<1.064)[/tex]
And we can find this probability with this difference:
[tex]P(-0.851<z<1.064)=P(z<1.064)-P(z<-0.851)[/tex]
And if we use the normal standard distribution or excel we got:
[tex]P(-0.851<z<1.064)=P(z<1.064)-P(z<-0.851)=0.856-0.197=0.659[/tex]
Step-by-step explanation:
Let X the random variable that represent the time required to construct and test a particular component of a population, and for this case we know the distribution for X is given by:
[tex]X \sim N(60,9.4)[/tex]
Where [tex]\mu=60[/tex] and [tex]\sigma=9.4[/tex]
We want to find this probability:
[tex]P(52<X<70)[/tex]
And the best way to solve this problem is using the normal standard distribution and the z score given by:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
Using this formula we got:
[tex]P(52<X<70)=P(\frac{52-\mu}{\sigma}<\frac{X-\mu}{\sigma}<\frac{70-\mu}{\sigma})=P(\frac{52-60}{9.4}<Z<\frac{70-60}{9.4})=P(-0.851<z<1.064)[/tex]
And we can find this probability with this difference:
[tex]P(-0.851<z<1.064)=P(z<1.064)-P(z<-0.851)[/tex]
And if we use the normal standard distribution or excel we got:
[tex]P(-0.851<z<1.064)=P(z<1.064)-P(z<-0.851)=0.856-0.197=0.659[/tex]
Solve this inequality.
-35 – 2 >7
A.
B.
C.
D. > -3
Answer:
-2> 7+35
-2>42
0<21
the answer is 0 is less than 21
In a random sample of 25 laptop computers the mean repair cost was $150 with a standard deviation of $35. Compute the 99% confidence interval for u
Answer:
[tex]150-2.797\frac{35}{\sqrt{25}}=130.421[/tex]
[tex]150+2.797\frac{35}{\sqrt{25}}=169.579[/tex]
Step-by-step explanation:
Information given
[tex]\bar X=150[/tex] represent the sample mean for the sample
[tex]\mu[/tex] population mean
s=35 represent the sample standard deviation
n=25 represent the sample size
Confidence interval
The confidence interval for the mean is given by the following formula:
[tex]\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}[/tex] (1)
In order to calculate the critical value [tex]t_{\alpha/2}[/tex] we need to find first the degrees of freedom, given by:
[tex]df=n-1=25-1=24[/tex]
Since the Confidence is 0.99 or 99%, the value of [tex]\alpha=0.01[/tex] and [tex]\alpha/2 =0.005[/tex] and the critical value for this case [tex]t_{\alpha/2}=2.797[/tex]
Now we have everything in order to replace into formula (1):
[tex]150-2.797\frac{35}{\sqrt{25}}=130.421[/tex]
[tex]150+2.797\frac{35}{\sqrt{25}}=169.579[/tex]
Person A can complete a task in 1.5 hours. Person B does the same task in 1 hour 20 minutes. Write the ratio of these times in the simplest whole number form.
Answer:
9/8
Step-by-step explanation:
time A / time B = (3/2)/(4/3) = (3/2)(3/4) = (3·3)/(4·2)
time A / time B = 9/8
A patient is using Humulin insulin U100, the patient is to use 35units three times a day, how many milliliters will be used each day
Answer:
Step-by-step explanation:
(35 units three times a day) comes out to (35 units / day)(3 times per day), or
105 units per day
In un trapezio rettangolo la base minore, il lato obliquo e l'altezza misurano rispettivamente 60 cm. 95 cm è 76 cm. Calcola il perimetro e l'area del trapezio. THANKS
Answer:
[tex]2p=348 cm\: S=6726 cm^{2}[/tex]
Step-by-step explanation:
Ciao, come stai?
1) Per prima cosa, dobbiamo trovare la misura della base più grande. Scomponendo la figura possiamo visualizzare un triangolo e un quadrato. Ci sono somiglianze con gli angoli. Quindi è un triangolo rettangolo. Applichiamo il teorema di Pitagora:
[tex]a^2=b^2+c^2\\95^2=b^2+76^2\\57=b[/tex]
2) Perimetro:
[tex]2p=60+57+76+60+95\\2p=348 cm[/tex]
3) L' area
[tex]\frac{(B+b)h}{2} =\frac{(117+60)76}{2} =6726 \:cm^{2}[/tex]
Kindly tell me the answers of these three
Answer:
1) -4/5,3 Decimal form x= -0.8,3
2) ?
3)sq (x+2)(x+3)+sq x^2 +5x-4=0
Step-by-step explanation:
Hope this helps
Henry hoards a hundred hens. Every day, each hen lays an egg with probability 0.8 independently of all others. Henry sells each egg for 3 cents, except that on half the days, his dog Barkie breaks half the eggs laid that day (and 1.5 eggs is as sellable as 1), and on the remaining half of the days, Barkie breaks 30 eggs. What is the probability that Henry makes more than a $1.30 today
Answer:
99.27%
Step-by-step explanation:
We have to:
sample size (n) = 100
p = 0.8
1 egg = 3 * 0.01 = 0.03
eggs = 100 - 30 broken eggs = 70
Let's find the probability of winning more than $ 1.30 today:
p (x> 1.30) = p (z, (x -m) / sd)
average earnings:
per day would be:
m1 = 100 / 1.5 * 0.8 * 0.03
m1 = 1.6
sd1 = (m1 * (1 - p)) ^ (1/2) = (1.6 * (1 - 0.8)) ^ (1/2)
sd1 = 0.566
earnings for broken eggs:
m2 = 70 * 0.8 * 0.03
m2 = 1.68
sd2 = (m2 * (1 - p)) ^ (1/2) = (1.68 * (1 - 0.8)) ^ (1/2)
sd2 = 0.58
Now the total profit would be:
m = m1 + m2 = 1.6 + 1.68
m = 3.28
sd = sd1 ^ 2 + sd2 ^ 2 = 0.566 ^ 2 + 0.58 ^ 2
sd = 0.81
now yes, replacing:
p (x> 1.30) = p (z> (1.3 - 3.28) /0.81)
p (x> 1.30) = p (z> -2.44)
for this z = 0.0073
Therefore the probability would be:
1 - 0.0073 = 0.9927
That is, we would have a 99.27% probability of achieving the goal.
Employees from Company A and Company B both receive annual bonuses. What information would you need to test the claim that the difference in annual bonuses is greater than $100 at the 0.05 level of significance? Write out the hypothesis and explain the testing procedure.
Answer:
Step-by-step explanation:
This is a test of the mean difference between 2 independent groups or populations.
Let μ1 be the mean annual bonus of Company A's employees and μ2 be the mean annual bonus of Company B's employees.
The random variable is μ1 - μ2 = difference in the mean annual bonus of Company A's employees and the mean annual bonus of Company B's employees
We would set up the hypothesis.
The null hypothesis is
H0 : μ1 ≤ μ2 H0 : μ1 - μ2 ≤ 100
The alternative hypothesis is
H1 : μ1 > μ2 H1 : μ1 - μ2 > 100
This is a right tailed test because of the inequality sign at the alternative hypothesis. We need to take samples of annual bonuses from both company's employees and find the averages. Then we would determine the test statistic as well as the p value. We would use the p value with the level of significance to make decisions
What’s the correct answer for this?
Answer:
AP = 10
Step-by-step explanation:
According to secant-secant theorem
(PB)(AP)=(PD)(PC)
6(AP) = (5)(12)
AP = 60/6
AP = 10
Answer:
10
Step-by-step explanation:
Applying the secant theorem, we get:
(PB) * (AP) = (PD) * (PC)
6 * (AP) = (5) * (12)
AP = 60/6
= 10
Hope this helps!
Which of the following statements best describes the effect of replacing the graph of y = f(x) with the graph of y = f(x) – 9? (5 points)
O The graph of y = f(x) will shift up 9 units.
O The graph of y = f(x) will shift down 9 units.
The graph of yf(x) will shift left 9 units,
The groph of yf(x) will shift right 9 units.
Answer:
the graph of y=f(x)will shift up 9 units
If the Alpha company is 79% staffed and the Beta company is only 62% staffed, what is the relative change of staffing from the Alpha company to the Beta company?
Answer:
27.41%
Step-by-step explanation:
Data provided in the question
The staffed of Alpha company = 79%
The staffed of Beta company = 62%
Based on the above information, the relative change of staffing from Alpha to beta company is
As we know that
[tex]\bold {\ Relative \ change = \frac{\alpha- \beta }{\beta }}[/tex]
[tex]= \frac{(79 -62)}{62} \% \\\\= \frac{17}{62} \times 100\\\\=0.2741 \times 100\\\\=27.41\ \%[/tex]
By applying the above formula we can get the relative change and the same is to be applied so that the correct percentage could come
through: (-1,4), perpendicular to y = x
Answer:
y = -x + 3
Step-by-step explanation:
I graphed the equation on the graph below to show you that it goes through (-1,4) and is perpendicular to y = x.
Identify whether the following equation has a unique solution, no solution, or infinitely many solutions.
4( − 11) = 15 − 4
Answer:
no solution
Step-by-step explanation:
4( − 11) = 15 − 4
-44 = 11
Since this iS FALSE, it means that the equation given has no solution
Find the population density of domesticated dogs if there are 43,600,000 dogs in the United States and the area of the United States is 3,794,083 square miles. Round to the nearest 10th
Answer:
11.49 dogs/ square mile
Step-by-step explanation:
Population density of any place is number of living being living in that area per unit area.
Population density = number of living being/ area of the place
given
number of dogs= 43,600,000
area = 3,794,083 square miles
population density of domesticated dogs = 43,600,000 /3,794,083
= 11.4915 dogs/ square mile
population density of domesticated dogs, rounded to the nearest 10th
is 11.49 dogs/ square mile.
Rocky Mountain National Park is a popular park for outdoor recreation activities in Colorado. According to U.S. National Park Service statistics, 46.7% of visitors to Rocky Mountain National Park in 2018 entered through the Beaver Meadows park entrance, 24.3% of visitors entered through the Fall River park entrance, 6.3% of visitors entered through the Grand Lake park entrance, and 22.7% of visitors had no recorded point of entry to the park.† Consider a random sample of 175 Rocky Mountain National Park visitors. Use the normal approximation of the binomial distribution to answer the following questions. (Round your answers to four decimal places.)
(a) What is the probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance?
(b) What is the probability that at least 80 but less than 90 visitors had a recorded entry through the Beaver Meadows park entrance?
(c) What is the probability that fewer than 12 visitors had a recorded entry through the Grand Lake park entrance?(d) What is the probability that more than 55 visitors have no recorded point of entry?
Answer:
a) 0.6628 = 66.28% probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance
b) 0.5141 = 51.41% probability that at least 80 but less than 90 visitors had a recorded entry through the Beaver Meadows park entrance
c) 0.5596 = 55.96% probability that fewer than 12 visitors had a recorded entry through the Grand Lake park entrance.
d) 0.9978 = 99.78% probability that more than 55 visitors have no recorded point of entry
Step-by-step explanation:
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
[tex]E(X) = np[/tex]
The standard deviation of the binomial distribution is:
[tex]\sqrt{V(X)} = \sqrt{np(1-p)}[/tex]
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that [tex]\mu = E(X)[/tex], [tex]\sigma = \sqrt{V(X)}[/tex].
In this problem, we have that:
[tex]n = 175[/tex]
(a) What is the probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance?
46.7% of visitors to Rocky Mountain National Park in 2018 entered through the Beaver Meadows. This means that [tex]p = 0.467[/tex]. So
[tex]\mu = E(X) = np = 175*0.467 = 81.725[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{175*0.467*0.533} = 6.6[/tex]
This probability, using continuity correction, is [tex]P(X \geq 85 - 0.5) = P(X \geq 84.5)[/tex], which is 1 subtracted by the pvalue of Z when X = 84.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{84.5 - 81.725}{6.6}[/tex]
[tex]Z = 0.42[/tex]
[tex]Z = 0.42[/tex] has a pvalue of 0.6628.
66.28% probability that at least 85 visitors had a recorded entry through the Beaver Meadows park entrance.
(b) What is the probability that at least 80 but less than 90 visitors had a recorded entry through the Beaver Meadows park entrance?
Using continuity correction, this is [tex]P(80 - 0.5 \leq X < 90 - 0.5) = P(79.5 \leq X \leq 89.5)[/tex], which is the pvalue of Z when X = 89.5 subtracted by the pvalue of Z when X = 79.5. So
X = 89.5
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{89.5 - 81.725}{6.6}[/tex]
[tex]Z = 1.18[/tex]
[tex]Z = 1.18[/tex] has a pvalue of 0.8810.
X = 79.5
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{79.5 - 81.725}{6.6}[/tex]
[tex]Z = -0.34[/tex]
[tex]Z = -0.34[/tex] has a pvalue of 0.3669.
0.8810 - 0.3669 = 0.5141
51.41% probability that at least 80 but less than 90 visitors had a recorded entry through the Beaver Meadows park entrance
(c) What is the probability that fewer than 12 visitors had a recorded entry through the Grand Lake park entrance?
6.3% of visitors entered through the Grand Lake park entrance, which means that [tex]p = 0.063[/tex]
[tex]\mu = E(X) = np = 175*0.063 = 11.025[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{175*0.063*0.937} = 3.2141[/tex]
This probability, using continuity correction, is [tex]P(X < 12 - 0.5) = P(X < 11.5)[/tex], which is the pvalue of Z when X = 11.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{11.5 - 11.025}{3.2141}[/tex]
[tex]Z = 0.15[/tex]
[tex]Z = 0.15[/tex] has a pvalue of 0.5596.
55.96% probability that fewer than 12 visitors had a recorded entry through the Grand Lake park entrance.
(d) What is the probability that more than 55 visitors have no recorded point of entry?
22.7% of visitors had no recorded point of entry to the park. This means that [tex]p = 0.227[/tex]
[tex]\mu = E(X) = np = 175*0.227 = 39.725[/tex]
[tex]\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{175*0.227*0.773} = 5.54[/tex]
Using continuity correction, this probability is [tex]P(X \leq 55 + 0.5) = P(X \leq 55.5)[/tex], which is the pvalue of Z when X = 55.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]Z = \frac{55.5 - 39.725}{5.54}[/tex]
[tex]Z = 2.85[/tex]
[tex]Z = 2.85[/tex] has a pvalue of 0.9978
0.9978 = 99.78% probability that more than 55 visitors have no recorded point of entry
Which of the following tables shows a valid probability density function? a. x P(X=x) 0 38 1 14 2 38 b. x P(X=x) 0 0.2 1 0.1 2 0.35 3 0.17 c. x P(X=x) 0 910 1 −310 2 310 3 110 d. x P(X=x) 0 0.06 1 0.01 2 0.07 3 0.86 e. x P(X=x) 0 12 1 18 2 14 3 18 f. x P(X=x) 0 110 1 110 2 310 3
Answer:
Step-by-step explanation:
Since we know that for a distribution be a probability density function sum of all the probability events should be equal to 1 and all individual events should have probability between 0 and 1
a. x P(X=x)
0 -----3/8
1 -----1/4
2 -----3/8
P(X=0)+P(X=1)+P(X=2) = 3/8 + 1/4 + 3/8
P(X=0)+P(X=1)+P(X=2) = 6/8 + 2/8 = 1
This is a probability density function
b. x P(X=x)
0 ----0.2
1 ----0.1
2 ----0.35
3 ----0.17
P(X=0)+P(X=1)+P(X=2)+P(X=3) = 0.2 + 0.1 + 0.35 + 0.17
P(X=0)+P(X=1)+P(X=2)+P(X=3) = 0.65 + 0.17 = 0.82 ≠ 1
Therefore this is NOT a probability density function
c. x P(X=x)
0---- 9/10
1 ---- −3/10
2 ---- 3/10
3 ---- 1/10
Since P(X=1) is not between 0 and 1
Therefore this is NOT a probability density function
d. x P(X=x)
0 ----0.06
1 ----0.01
2 ----0.07
3 ----0.86
P(X=0)+P(X=1)+P(X=2)+P(X=3) = 0.06 + 0.01 + 0.07 + 0.86
P(X=0)+P(X=1)+P(X=2)+P(X=3) = 0.14 + 0.86 = 1
Therefore this is a probability density function
e. x P(X=x)
0 ----1/2
1 ----1/8
2 ----1/4
3 ----1/8
P(X=0)+P(X=1)+P(X=2)+P(X=3) = 1/2 + 1/8 + 1/4 + 1/8
P(X=0)+P(X=1)+P(X=2)+P(X=3) = 1/2 + 1/2 = 1
Therefore this is a probability density function
f. x P(X=x)
0 ----1/10
1 ----1/10
2 ----3/10
3 ----1/5
P(X=0)+P(X=1)+P(X=2)+P(X=3) = 1/10 + 1/10 + 3/10 + 1/5
P(X=0)+P(X=1)+P(X=2)+P(X=3) = 2/10 + 5/10 = 7/10 ≠ 1
Therefore this is NOT a probability density function
A restaurant manager determined that about 12 of all customers would wait 20 minutes or more for a table. Which simulation could NOT be used to answer questions about whether a customer would wait?
Answer:
spinner green or blue
Step-by-step explanation:
Flipping a coin is 1/2 probability
Rolling a die and getting a number less than 4 is 1/2 probability
spinner green or blue is (4/6) = 2/3
Marbles is 1/2
What’s the correct answer for this?
Answer:
P = 4/13
Step-by-step explanation:
In a deck of 52 cards, there are 3 aces(spade, heart, diamond), 1 club ace, and 12 remaining club cards
=> The probability of randomly drawing 1 card that is an ace card or a club card:
P = number of elements/total number of elements
P = (3 + 1 + 12)/52
P = 16/52
P = 4/13
=> Option A is correct
I NEEEED HELP RN the following table shows a proportional relationship. x y 2 9 5 22.5 8 36 write an equation to describe the relationship
Answer:
y = 4.5x
Step-by-step explanation:
y=ax is form of proportional relationship
checking the first pair of numbers:
9=2a ⇒ a= 4.5checking other lines
5*4.5= 22.5- correct8*4.5= 36 - correctSo the equation is:
y = 4.5xScott made a casserole for dinner. He gave equal portions of Ask Your Teacher of the casserole to 3 friends. What diagram could Scott use to find the fraction of the whole casserole that each friend got? what is the answer
Answer:
1/6
Question: Scott made a casserole for dinner he gave equal portions of 1/2 the casserole to 3 friends what diagram could scott use to find the fraction of the whole casserole that each friend got?
Step-by-step explanation:
Find attached the diagram Scott used to find the portion each friend got.
The shaded part indicate the portion of the casserole.
When Scott prepared the dinner = 1 portion of casserole
He shared 1/2 the portion to 3 of his friends:
Divide the diagram of the full portion into 2 to get ½ of the casserole
1/2 of the casserole = ½ × 1 portion = ½ portion
Each of his 3 friends would have equal portions = ⅓ of the ½ portion
The diagram of the ½ portion would be divided into 3 equal part
In terms of calculation = ½ × ⅓
= 1/6
Each of his friends would have 1/6 portion of the casserole.
Hello! I provided the answer to your problem in a picture.
Ex. (3/6)
Write a real-world situation that could be represented by the system
Y=3x+10
Y=5x+20
Answer:
I have two types of packages that i sell. one has 3 apples and 10 pears, another one has 5 apples and 20 pears. what are the minumum quantitys of each do i have to buy so i can make either all package #1 or only make package#2 with oout any left over pears and apples?
Step-by-step explanation:
i don't know how to explain it but i;ll try. you take the lcm i beleive of the two. i think i may have done it wrong
