Select a classification for File2 so that: Alice can read and write to File2 Bob and Charlie can write to File2, but can't read it. Eve can write to File1 but can't read it. Alice has Top Secret, {A,B,C}. Bob has Secret{A,B}, Charlie has Confidential,{C} and Eve is Unclassified. File2 should be classified as

Answer:

Following are the error in the given program are explain in the explanation part .

Explanation:

The main() function call the function getMileage() function after that the control moves to the getMileage() definition of function. In this firstly declared the  "mileage" variable after that it taking the input and module is finished we see that the "mileage" variable is local variable i,e it is declared inside the  " Module getMileage() "  and we prints in the main module that are not possible to correct these we used two technique.

Technique 1: Declared the mileage variable as the global variable that is accessible anywhere in the program.

Technique 2: We print the value of  "mileage" inside the Module getMileage() in the program .

Answer:

The area of the triangle is calculated as thus:

[tex]Area = 0.5 * b * h[/tex]

To calculate the perimeter of the triangle, the measurement of the slant height has to be derived;

Let s represent the slant height;

Dividing the triangle into 2 gives a right angled triangle;

The slant height, s is calculated using Pythagoras theorem as thus

[tex]s = \sqrt{b^2 + h^2}[/tex]

The perimeter of the triangle is then calculated as thus;

[tex]Perimeter = s + s + b[/tex]

[tex]Perimeter = \sqrt{b^2 + h^2} + \sqrt{b^2 + h^2} +b[/tex]

[tex]Perimeter = 2\sqrt{b^2 + h^2} + b[/tex]

For the volume of the cone,

when the triangle is spin, the base of the triangle forms the diameter of the cone;

[tex]Volume = \frac{1}{3} \pi * r^2 * h[/tex]

Where [tex]r = \frac{1}{2} * diameter[/tex]

So, [tex]r = \frac{1}{2}b[/tex]

So, [tex]Volume = \frac{1}{3} \pi * (\frac{b}{2})^2 * h[/tex]

Base on the above illustrations, the program is as follows;

#include<iostream>

#include<cmath>

using namespace std;

void CalcArea(double b, double h)

{

//Calculate Area

double Area = 0.5 * b * h;

//Print Area

cout<<"Area = "<<Area<<endl;

}

void CalcPerimeter(double b, double h)

{

//Calculate Perimeter

double Perimeter = 2 * sqrt(pow(h,2)+pow((0.5 * b),2)) + b;

//Print Perimeter

cout<<"Perimeter = "<<Perimeter<<endl;

}

void CalcVolume(double b, double h)

{

//Calculate Volume

double Volume = (1.0/3.0) * (22.0/7.0) * pow((0.5 * b),2) * h;

//Print Volume

cout<<"Volume = "<<Volume<<endl;

}

int main()

{

double b, h;

//Prompt User for input

cout<<"Base: ";

cin>>b;

cout<<"Height: ";

cin>>h;

//Call CalcVolume function

CalcVolume(b,h);

//Call CalcArea function

CalcArea(b,h);

//Call CalcPerimeter function

CalcPerimeter(b,h);

return 0;

}

Answer:

The color model used for an offset printing press should involve cyan, magenta, yellow and black. The combination of this creates a black color.

Offset printing doesn’t involve the direct contact of the ink with the paper. The ink usually comes in contact first with a rubber cylinder after which the cylinder makes the necessary imprints on the paper.

Answer:

the right answer is A

.....

Answer:

tumblelogs

Explanation:

Answer:

2. Logic

Explanation:

We all know that for the PC to come on, there must be a power input, this means that if the PC does not power on, then there is probably no power input into the PC. It is only logical for Bob to check if the PC is properly connected first when the power-on lights did not come on. People with no technical training should be able to apply this simple logic too.

Answer:

The correct answer to the following question will be "The user is prompted to retry".

Explanation:

NAS seems to be a category of server system a broader open internet as well as web through in-house and perhaps remotely associated user groups.

Answer:

Building relationships during your career exploration is called networking.

Answer: Provided in the explanation section

Explanation:

A YMS acts an interface between a WMS and TMS.The evaluation system with the key performance indicators are mentioned in the table below.

NOTE: The analysis follows in this order given below

Metric 1

Trailer utilization

Description :This captures the status of the trailer whether it is in the yard or is in transit

Comments : Helps in measuring the trailer productivity on a daily ,weekly or monthly basis

Metric 2

Driver utilization

Description : This captures the status of the driver whether the driver is in the yard or is in transit

Comments : Helps in measuring the driver productivity on a periodic basis

Metric 3

Trailer sequence

Description : This captures the order of movement of trailers in the yard on a given day, week or month

Comments : Helps in measuring the order fulfilment efficiency i.e. whether the priority orders have been serviced first or not

Metric 4

Total time in yard

Description : This captures the time spent by the trailer in the yard from the time it enters and leaves the yard

Comments : This helps in measuring the time taken to fulfill a particular request

⇒ Capturing these metrics need inputs from both WMS and TMS, and also the trailers need to have RFID tags attached to them.Then compare these performance metrics with the ones prior to the deployment of YMS to identify the percent gains in the overall operational productivity.

cheers i hope this helped !!

Answer:

The java program for the given scenario is as follows.

import java.util.*;

import java.lang.*;

public class Main

{

   //variables for bill and tip declared and initialized

   static double bill=47.28, tip=0.15;

   //variables for total bill and share declared

   static double total, share1;

public static void main(String[] args) {

    double total_tip= (bill*tip);

    //total bill computed

    total = bill + total_tip;

    //share of each friend computed

    share1 = total/2;

    System.out.printf("Each person needs to pay: $%.2f", share1);  

}

}

Explanation:

1. The variables to hold the bill and tip percent are declared as double and initialized with the given values.

static double bill=47.28, tip=0.15;

2. The variables to hold the values of total bill amount and total tip are declared as double.

3. All the variables are declared outside main() and at class level, hence declared as static.

4. Inside main(), the values of total tip, total bill and share of each person are computed as shown.

double total_tip= (bill*tip);

total = bill + total_tip;

share1 = total/2;

5. The share of each person is displayed to the user. The value is displayed with only two decimal places which is assured by %.2f format modifier. The number of decimal places required can be changed by changing the number, i.e. 2. This format is used with printf() and not with println() method.

System.out.printf("Each person needs to pay: $%.2f", share1);  

6. The program is not designed to take any user input.

7. The program can be tested for any value of bill and tip percent.

8. The whole code is put inside a class since java is a purely object-oriented language.

9. Only variables can be declared outside method, the logic is put inside a method in a purely object-oriented language.

10. As shown, the logic is put inside the main() method and only variables are declared outside the method.

11. Due to simplicity, the program consists of only one class.

12. The output is attached.

Answer:

bill =  47.28

tip = bill *.15

total = bill + tip

share = total

print( "Each person needs to pay: "+str(share) )

Explanation:

Answer:

Kroki i algorytmy są opisane i załączone w poniższych akapitach

Explanation:

1. algorytm mycia rąk

za. Iść do ręki była umywalka

b. Włącz kran

do. Przenieś ręce pod wodę

 dopóki nie zostanie przemoczony

re. Weź mydło

mi. Nanieś mydło na obie ręce

fa. Zwróć mydło

sol. Umieść dłonie pod bieżącą wodą z kranu na 2 sekundy

h. Złóż dłonie razem i potrzyj

ja. Przetrzyj jedną rękę dłonią drugiej

jot. Zablokuj palce i potrzyj je o siebie

l. Kciukami potrzyj obszar paznokci palców obu rąk

m. Pocieraj opuszki palców dłoni

n. Przyłóż kciuk i koniec nadgarstka kumplami i potrzyj

o. Spłucz całe mydło z rąk

2. algorytm przekraczania drogi

za. Obserwuj i planuj

ja. Dotrzyj do bezpiecznego miejsca do przejścia (najlepiej przejścia dla pieszych lub sygnalizacji świetlnej lub tam, gdzie jest dozorca ruchu) i zatrzymaj się tam

ii. Jeśli powyższe nie jest możliwe, poszukaj miejsca, w którym można wyraźnie zobaczyć wszystkie nadjeżdżające pojazdy i gdzie mogą cię zobaczyć

b. Zatrzymać

ja. Odsuń się trochę od krawędzi drogi na chodniku

ii. Cierpliwie rozejrzyj się, aby upewnić się, że jesteś w bezpiecznym miejscu

do. Patrz i słuchaj

i. Spójrz i nasłuchuj ruchu we wszystkich kierunkach

re. Pozostań na miejscu, dopóki nie będzie można bezpiecznie przejść

ja. Cierpliwie pozwalaj na ruch uliczny

ii. Przejdź przez jezdnię, gdy jest przerwa w ruchu, dzięki czemu jest wystarczająco dużo czasu, aby przejść szybciej

iii. Przejdź tylko wtedy, gdy masz pewność, że nie nadjeżdżają żadne pojazdy

mi. Patrz dalej i słuchaj

ja. Gdy nie ma nadjeżdżających pojazdów, a następnie przejeżdżasz przez ulicę, upewnij się, że cały czas szukasz ruchu (pojazdów)

1. Algorytm obliczania pola i obwodu prostokąta

W załączeniu wymagany schemat blokowy

2. Algorytm obliczania średniej prędkości pojazdu

W załączeniu wymagany schemat blokowy

Answer:

bc

1 without them you wouldn't be able to program

2 need for job interviews

3 important to be good and make the money

4 can be adaptable

5 easy to move from a business to another

Answer:

No its not a combustion its a formation.

Explanation:

sflpawkfowakfpowja0ifjhnaw0i

Answer:png, jpeg, jpg, hevc, raw, bmp, png, webp

Explanation:

Just look for all the Image file formats

Answer:It’s D

Explanation:

APEVX

The label of the next version of the document can probably be ProjectReport_v2.docx. The correct option is D.

A document's purpose is to enable the transmission of information from its author to its readers.

It is the author's responsibility to design the document so that the information contained within it can be interpreted correctly and efficiently. To accomplish this, the author can employ a variety of stylistic tools.

Documentation can be of two main types namely, products and processes. Product documentation describes the product under development and provides instructions on how to use it.

A document file name is the name given to a document's electronic file copy.

The file name of the document does not have to be the same as the name of the document itself. In fact, you can use the shortest possible version of the name.

As the document here is second version of the previous one, so its name should be ProjectReport_v2.docx.

Thus, the correct option is D.

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Answer:

In the question stated a we declared a set named as weights also an integer variable was the desired_weight

In python A set is regarded as  {12, 19, 6, 14, 22, 7}

Explanation:

Solution

The python program code is executed below:

# Declare a tuple

weights = (12, 19, 6, 14, 22, 7)

# Declare an integer variable to store desired weight.

desired_weight = 18

# Declare an integer variable to store actual_weight weight

actual_weight = weights[0]

# Create a for-loop to read each value in the tuple.

for each_weight in weights:

   # Create an if-statement to find the that is

   # closest weight but not greater than desired weight.

   if(each_weight > actual_weight and each_weight < desired_weight):

       actual_weight = each_weight

weights=list(weights)

# Delete the actual weight

weights.remove(actual_weight)

weights=tuple(weights)

# Display the actual weight

print("Actual Weight:",actual_weight)

# Display the resulted tuple.

print("Resulted set:",weights)

This program here is to declare a set which is as follows:

# Declare a set

weights = {12, 19, 6, 14, 22, 7}

# Declare an integer variable to store desired weight.

desired_weight = 18

# Declare an integer variable to store actual weight

# Assign first index element using list.

actual_weight = list(weights)[0]

# Create a for-loop to read each value in the tuple.

for each_weight in weights:

   # Create an if-statement to find the that is

   # closest weight but not greater than desired weight.

   if(each_weight > actual_weight and each_weight < desired_weight):

       actual_weight = each_weight

# Delete the actual weight using discard() method.

weights.discard(actual_weight)

# Display the actual weight

print("Actual Weight:",actual_weight)

# Display the resulted tuple.

print("Resulted set:",weights)

Answer:

Explanation:

#include <iostream>

using namespace std;

int* append(int*,int,int*,int);

int* merge(int*,int,int*,int);

void print(int*,int);

int main()

{ int a[] = {11,33,55,77,99};

int b[] = {22,44,66,88};

print(a,5);

print(b,4);

int* c = append(a,5,b,4); // c points to the appended array=

print(c,9);

int* d = merge(a,5,b,4);

print(d,9);

}

void print(int* a, int n)

{ cout << "{" << a[0];

for (int i=1; i<n; i++)

cout << "," << a[i];

cout << "}\n";

}

int* append(int* a, int m, int* b, int n)

{

int * p= (int *)malloc(sizeof(int)*(m+n));

int i,index=0;

for(i=0;i<m;i++)

p[index++]=a[i];

for(i=0;i<n;i++)

p[index++]=b[i];

return p;

}

int* merge(int* a, int m, int* b, int n)

{

int i, j, k;

j = k = 0;

int *mergeRes = (int *)malloc(sizeof(int)*(m+n));

for (i = 0; i < m + n;) {

if (j < m && k < n) {

if (a[j] < b[k]) {

mergeRes[i] = a[j];

j++;

}

else {

mergeRes[i] = b[k];

k++;

}

i++;

}

// copying remaining elements from the b

else if (j == m) {

for (; i < m + n;) {

mergeRes[i] = b[k];

k++;

i++;

}

}

// copying remaining elements from the a

else {

for (; i < m + n;) {

mergeRes[i] = a[j];

j++;

i++;

}

}

}

return mergeRes;

}

Answer:

The fundamental functionalities necessarily needs to considered while implementing any network model are (1) Scalability, (2)The quality of service (3) Fault tolerance (4) Security.

Explanation:

Solution:

Network must help a wide area of applications and administrations, just just as work over various sorts of links and devices that make up the physical infrastructure. The term network refers to the innovations that help the infrastructure and the customized administrations and rules, or protocols, that move messages over the network.

The following are some  fundamental functionalities necessarily needs to considered while implementing any network model which is stated below:

(1) Scalability :

A huge number of users and service providers connect with the Internet every week. All together for the Internet to help this fast measure of development, it must be scalable.

A scalable network can extend rapidly to help new clients and applications without influencing the performance of the administration being conveyed to existing clients.  

(2)Quality of Service :

Networks must provide predictable, quantifiable, and, now and again, ensured administrations.  

Networks also need mechanisms to carry on congested network traffic. Network bandwidth is the estimate of the data-transfer size of the network. As such, what amount of data can be transmitted inside a particular measure of time? Network data transfer capacity is estimated in the quantity of bits that can be transmitted in a solitary second, or bits every second (bps).  

(3) Fault Tolerance :

The Internet is consistently accessible to the a huge number of users who depend on it. This requires a network design that is worked to be fault tolerant.

A fault-tolerant network is one that constrains the impact of a failure, with the goal that the least number of devices are influenced by it. It is likewise worked in a manner that empowers fast recuperation when such a failure happens.

Faults-tolerant networks rely upon various ways between the source and destination of a message. On the off chance that one way comes up short, the messages can be immediately sent over an alternate connection.

(4) Security:  

The Internet has advanced from a firmly controlled inter network of instructive and government associations to a generally open methods for transmission of business and individual interchanges.

Subsequently, the security necessities of the network have changed. The network infrastructure, the system administrations, and the information contained on arrange appended gadgets are vital individual and business resources. Bargaining the respectability of these benefits could have genuine outcomes.

Answer:

B. External systems and technology architecture.

Explanation:

In such environment, you have to know what external systems are in place so have proper communication with External Systems whether be in message format or web/networks, Communication protocols, Security methods, Error detection and recovery,

Additionally, it consits of technology architecture so conforming to an existing technology architecture helps us discover and describe existing architecture

The two elements that describe the environment are external systems and technology architecture. Thus, the correct option for this question is B.

In computer and technology, the environment may be defined as anything which is present in the surrounding of computer and network connection. It significantly includes various protocols and their characteristics.

According to the environment of the computer, external systems are remarkably assisting in the proper communication, protocols, Security methods, Error detection, and recovery. It creates a supportive environment for the user. Apart from this, it also consists of technology architecture which confirms the process of existing technological perspectives.

Therefore, the two elements that describe the environment are external systems and technology architecture. Thus, the correct option for this question is B.

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Answer:

The Manchester encoding to describe the first octet pattern signal within the preamble is 10101010

Explanation:.

Solution

Given that:

The first octet value of Preamble is 10101010

The Manchester encoding to outline or describe the first octet of the signal pattern produced or created within the preamble is 10101010

Note: Kindly find an attached image of the first octet signal pattern produced below.

Answer:

Multiple ways.

Explanation:

Here are some examples. Modern people relay on technology alot! It shapes our lives. Like now you can order something without moving from you place using your smartphone. When you need a spare part for a lego for example you can now just 3D print it without buying another one. See plenty of ways. Looks around you and find more examples.

Answer:

A. 243

B. True

C. 0

Explanation:

Macro instruction is a line of coding used in computer programming. The line coding results in one or more coding in computer program and sets variable for using other statements. Macros allows to reuse code. Macro has two parts beginning and end. After the execution of statement of quiz4 x, 4 the macro x will contain 243. When the macro is invoked the statement will result in an error. When the macro codes are executed the edx will contain 0. Edx serve as a macro assembler.

Answer:

int withinArray(int * intArray, int size, int * ptr) {

      if(ptr == NULL) // if ptr == NULL return 0

            return 0;

      // if end of intArr is reached

      if(size == 0)

          return 0; // element not found

  else  

          {

            if(*(intArray+size-1) == *(ptr)) // check if (size-1)th element is equal to ptr

                   return 1; // return 1

            return withinArray(intArray, size-1,ptr); // recursively call the function with size-1 elements

         }

}

Explanation:

Above is the completion of the program.

Answer:

import java.util.Scanner;

public class SortStrings3 {

   public static void main(String args[]){

       Scanner scanner = new Scanner(System.in);

       String str1, str2, str3;

       System.out.print("Enter the first city: ");

       str1 = scanner.nextLine();

       System.out.print("Enter the second city: ");

       str2 = scanner.nextLine();

       System.out.print("Enter the third city: ");

       str3 = scanner.nextLine();

       System.out.print("The three cities in alphabetical order are ");

       if(str1.compareTo(str2) < 0 && str1.compareTo(str3) < 0){

           System.out.print(str1+" ");

           if(str2.compareTo(str3) < 0){

               System.out.print(str2+" ");

               System.out.println(str3);

           }

           else {

               System.out.print(str3+" ");

               System.out.println(str2);

           }

       }

       else if(str2.compareTo(str1) < 0 && str2.compareTo(str3) < 0){

           System.out.print(str2+" ");

           if(str1.compareTo(str3) < 0){

               System.out.print(str1+" ");

               System.out.println(str3);

           }

           else {

               System.out.print(str3+" ");

               System.out.println(str1);

           }

       }

       else{

           System.out.print(str3+" ");

           if(str1.compareTo(str2) < 0){

               System.out.print(str1+" ");

               System.out.println(str2);

           }

           else {

               System.out.print(str2+" ");

               System.out.println(str1);

           }

       }

   }

}

EXPLANATION:

Okay, we are given that a program should be written which will make user to enter three cities namely Atlanta, Chicago and Los Angeles (which should be done in ascending  alphabetical order).

So, we will be writting the code or program with a programming language known as JAVA(JUST ANOTHER VIRTUAL ACCELERATOR).

We will make use of java to write this program because Java can be used in Loading code, verifying codes and executing codes on a single or multiple servers.

The code or program can be seen in the attached file/document. Kindly check it.

Answer:

Explanation:

//Java program

class UnoCard{

  private String color;

  private int value;

  public UnoCard(String color , int val) {

      this.color = color;

      value = val;

  }

  public String getColor() {

      return color;

  }

  //set the color of the card

  public void setColor(String color ) {

      this.color = color;

  }

  //get the value of the card

  public int getValue() {

      return value;

  }

  //set the value of the card

  public void setValue(int val) {

      value = val;

  }

  //return true if card has same value or

  //same color as the card

  //return false otherwise

  public boolean isMatch(UnoCard card) {

      return (this.value==card.value)||(this.color==card.color);

  }

}

public class Card {

  public static void main(String args[]) {

      UnoCard card1 = new UnoCard("Red",10);

      UnoCard card2 = new UnoCard("Green",10);

      UnoCard card3 = new UnoCard("Blue",15);

      if(card1.isMatch(card2))System.out.println("Match");

      else System.out.println("No Match");

      if(card2.isMatch(card3))System.out.println("Match");

      else System.out.println("No Match");

  }

}

Answer: Provided in the section below

Explanation:

Using C# Code:

using System;

class Environment{

//temperature

private double temp;

//sets initial value of temp to 100 Fahrenheits

public Environment(){

temp=100;

}

//sets initial value to given temp

public Environment(double t) {

this.temp = t;

}

//returns temp

public double getTemp(){

return temp;

}

//calculates temp at given frequency

public void calcTemperature(double frequency){

temp=(frequency+40)/4.0;

}

}

class Cricket{

private Random r=new Random();

//frequency of birds

protected double frequency;

//sets frequency to a random value between 0-100

public Cricket(){

frequency=r.NextDouble()*100;

}

//sets frequency to a given frequency

public Cricket(double f) {

frequency = f;

}

//returns the frequency

public double getFrequency() {

return frequency;

}

//randomize the frequency

public virtual void randomFrequency() {

frequency = r.NextDouble()*100;

}

}

class ClemsonCricket: Cricket{

//sets the frequency to 80% of the parent's

public ClemsonCricket(): base(){

frequency=frequency*0.8;

}

//sets frequency to a given frequency

public ClemsonCricket(double f): base(f){}

//randomize frequency and sets it to 80% of the parent's

public override void randomFrequency(){

base.randomFrequency();

frequency=frequency*0.8;

}

}

public class testCrickets {

static void Main(){

Environment env=new Environment();

Console.WriteLine("Initial Temp: "+env.getTemp());

Cricket cricket=new Cricket();

env.calcTemperature(cricket.getFrequency());

Console.WriteLine(String.Format("Temp before changing Frequency: {0:0.00}",env.getTemp()));

cricket.randomFrequency();

env.calcTemperature(cricket.getFrequency());

Console.WriteLine(String.Format("\nTemp after changing Freqency: {0:0.00}",env.getTemp()));

Console.WriteLine("\nClemson Cricket: ");

ClemsonCricket clemsonCricket=new ClemsonCricket();

env.calcTemperature(clemsonCricket.getFrequency());

Console.WriteLine(String.Format("Temp before changing Frequency: {0:0.00}",env.getTemp()));

clemsonCricket.randomFrequency();

env.calcTemperature(clemsonCricket.getFrequency());

Console.WriteLine(String.Format("\nTemp after changing Freqency: {0:0.00}" ,env.getTemp()));

Console.WriteLine("\nPolymorphism Clemson Cricket: ");

Cricket Ccricket=new ClemsonCricket();

env.calcTemperature(Ccricket.getFrequency());

Console.WriteLine(String.Format("Temp before changing Frequency: {0:0.00}",env.getTemp()));

Ccricket.randomFrequency();

env.calcTemperature(Ccricket.getFrequency());

Console.WriteLine(String.Format("\nTemp after changing Freqency: {0:0.00}",env.getTemp()));

}

}

cheers i hope this helped !!

Answer:

3

Explanation:

2*1+1

2+1

hope this helps