Answer:
1336.4N
Explanation:
Given parameters:
Mass of the sumo wrestler = 330pounds
Unknown:
Amount of force the earth exerts on the wrestler = ?
Solution:
The force the earth exerts on the wrestler is the weight of the man;
Weight = mg
where;
m is the mass
g is the acceleration due to gravity
Now,
let us convert from pounds to kg;
2.2pounds = 1kg
300 pounds = [tex]\frac{300}{2.2}[/tex] = 136.4kg
Weight = 136.4kg x 9.8m/s² = 1336.4N
What is the [H 30 +) in a solution with [OH = 1x10-12 M?
Answer: The way to get the answer is to know and understand certain relationships between [H3O+] and [OH-]. One such relationship which you must know (memorize) is...
[H3O+] [OH-] = 1x10-14 = Kw (the rest is algebra)
[H3O+] [1x10-12] = 1x10-14
[H3O+] = 1x10-14 / 1x10-12
[H3O+] = 1x10-2 = 0.01 M
Explanation: HOPE IT HELPS!
The mass of an atom composed of 7 protons, 8 neutrons, and 7 electrons is
Answer:
Nitrogen
Explanation:
please help urgent!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
How can you safely turn on and off an electromagnet on and off?
The United States is one country that does not fully use the metric system for measurement.
Yes or No
Answer: yes
Explanation:
why is it necessary to use models to study submicroscopic objects such as atoms and molecules
Answer:
It is necessary to use models to study sub- microscopic objects such as atoms and molecules because they are too small to be seen.
Classify each of the following processes as spontaneous or nonspontaneous
how many molecules are present in 7 moles of h2o
Answer:
9moles of h20 hndi parin ako sure
Look at the balanced equation below:
C2H6O + 3 O2 → 2 CO2 + 3 H2O
If you produced 11.5 moles of H2O, how many moles of O2 were used?
11.5 moles O2
11.5 moles O, 2
34.5 moles O2
34.5 moles O, 2
3.83 moles O2
3.83 moles O, 2
7.67 moles O2
Answer:
11.5moles of oxygen gas
Explanation:
The reaction equation is shown below;
C₂H₆O + 3O₂ → 2CO₂ + 3H₂O
We were given 11.5moles of H₂O produced;
Since the equation is balanced;
3 mole of oxygen gas was used to produce 3 mole of water
11.5 moles of water will be produced [tex]\frac{11.5 x 3}{3}[/tex] = 11.5moles of oxygen gas
What would be a good hypothesis for this data ?
Answer:
Organism B produces pyruvic acid at a faster rate as the temperature increases than Organism A.
Explanation:
What is the 8th term in the geometric sequence described by this explicit formula?
An=6×3(n-1)
A.2187
B.612,220,032
C.13,122
D.39,366
Answer: C
Explanation: Answered this same question on a test before
Neutron moderation is used to counteract:
O A. the heat generated during nuclear fission reactions.
O B. the chain reactions that naturally occur with uranium-235.
O C. the low concentration of uranium-235 in nature.
O D. the minimal chance that the newly formed neutrons of a fission
reaction are absorbed by more atoms.
Answer:
(D) The minimal chance that the newly formed neutrons of a fission
Explanation:
I got it right on A P E X
Answer:
D. the minimal chance that the newly formed neutrons of a fission
reaction are absorbed by more atoms.
Explanation:
took test
A botfly lays an egg in the skin of an animal. When the larvae hatches from the egg, it burrows deep into the skin . The animal may become sick from having the larvae under its skin. What type of relationship is being describe, and what roles do each organism play?
Answer:
A botfly that lays an egg in the skin of an animal when the larvae hatches from the egg, it burrows deep into the skin. The animal that may become sick from having the larvae under its skin is called Mutualism.
Explanation:
The animal is the host while the botfly is the parasite. A mutualism in which one mutualistic partner removes parasites, as well as dead or diseased skin from another, in return receiving a steady supply of food is called Pollination. Nearly all pollination services involve a mutualism that has evolved over millions of years. Another example is reproduction.
Examples of using chemical equilibrium in our daily life (other that ammonia, homeostasis, and others)
Answer:
There are many examples of chemical equilibrium all around you. One example is a bottle of fizzy cooldrink. In the bottle there is carbon dioxide (CO2) dissolved in the liquid. There is also CO2 gas in the space between the liquid and the cap.
Is this ground or excited state?
1s2 2s2 2p6 3s1 3p1
Answer:
Explanation:
Ground : 1s2 2s2 2p6 3s2
Excited 1s2 2s2 2p6 3s1
it is excited
Please help I’ll mark brainliest!
Which statement is true?
A. Less reactive substances will not undergo chemical reactions.
B. Reactivity is the rate at which a substance undergoes a chemical reaction.
C. A substance's reactivity is determined by its location in the periodic table.
D. Every element in the periodic table reacts strongly with water.
Answer:
I answer is c I'm sorry if I'm wrong but please mark me brainlest I will mean a lot
HELLLPPPPP
The FDA Code requires that water supply systems include
a backflow or back-siphonage prevention device
pipage composed only of PVC or other plastic materials
regularly spaced emergency shutoff valves
a method of aerating the water at designated checkpoints
Answer:
its A.Explanation:
edge food and nutrition!!
1.
Based on the following information, arrange the A, B, C, and D from lowest to highest
activity (in order of increasing ability to act as reducing agents).
I. Only A, C and D react with 1 mol/L HCl to give H2(e).
II. When A is added to solutions of the other metal ions, metallic B and Care
formed but not D.
a) C
b) B
c) B
d) C
e) B
Order of metals from least reactive to most reactive: B <C <A <D
Further explanationReducing agents are substances that experience oxidation
Oxidizing agents are substances that experience reduction
The metal activity series is expressed in voltaic series
Li-K-Ba-Ca-Na-Mg-Al-Mn- (H2O) -Zn-Cr-Fe-Cd-Co-Ni-Sn-Pb- (H) -Cu-Hg-Ag-Pt-Au
The more to the left, the metal is more reactive (easily release electrons) and the stronger reducing agent
The more to the right, the metal is less reactive (harder to release electrons) and the stronger oxidizing agent
So that the metal located on the left can push the metal on the right in the redox reaction
Let's analyze the statement in the problem
I. Only A, C and D react with 1 mol/L HCl to give H₂(e)
M + HCl ⇒ MCl + H₂(MCl : alkali, MCl₂ : alkaline earth)
A, C and D can react with 1 mol / L HCl, meaning metals A, C and D are located to the left of element H (more reactive), and B in the right of element H
II. When A is added to solutions of the other metal ions, metallic B and C are formed but not D.
This means that metal A is more reactive than metals B and C, while D is more reactive than A, so metal D is the most reactive
The atmosphere that existed on early Earth was toxic, had no traces of oxygen and the was high levels of ultraviolet radiation from the Sun.
1.True
2.False
Addition of Silver Nitrate
1. Based upon the color, in which direction does the equilibrium shift?
Shifts Left.
2. Write an equation showing what happens when AgNO3 is added, and explain why the equilibrium shifts.
Addition of Water
3. Explain the equilibrium shift that occurs when water is added to the original equilibrium reaction.
Cu(H2O)62+(aq) + 4Cl–(aq) D CuCl42–(aq) + 6H2O(l)
blue green
Temperature Changes
4. Write "heat" on either the left or right side of this equation, based upon observations from the addition and removal of heat in steps 3 and 4, respectively, and the corresponding shifts in equilibrium.
____ + Cu(H2O)62+(aq) + 4Cl–(aq) D CuCl42–(aq) + 6H2O(l) + _____
Blue Green
Answer:
See explanation
Explanation:
When AgNO3 is added to the system the equilibrium position shifts towards the left hand side because of the formation of AgCl as a precipitate thereby sequestering the Cl^- from solution.
AgNO3(aq) + Cl^-(aq) ------> AgCl(s) + NO3^-(aq)
[Cu(H2O)6]^2+(aq) + 4Cl^–(aq) ------> [CuCl4]^2–(aq) + 6H2O(l)
The equilibrium of this reaction shifts towards the right as more Cl^– is added making the color of the solution to change from blue to green.
[Cu(H2O)6]^2+(aq) + 4Cl^–(aq) + heat ------> [CuCl4]^2–(aq) + 6H2O(l)
This reaction is endothermic. addition of heat makes the solution to turn green (equilibrium shifts towards the right) while removal of heat makes the solution to turn blue (equilibrium shifts towards the left).
Baking soda with hydrochloric acid combine and bubbles form. Chemical or physical change.
Answer:
I believe it is a chemical change.
If two forces are heading in the same direction, we ______ them to calculate net force.
options:
add
or
subtract
Answer:
add
Explanation:
how many moles are in 2.91 × 10²² atoms of He?
Answer:
0.048 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\[/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
[tex]n = \frac{2.91 \times {10}^{22} }{6.02 \times {10}^{23} } \\ = 0.04833887...[/tex]
We have the final answer as
0.048 molesHope this helps you
how many mole are in 5.25 × 10²⁵ atoms of Au
Answer:
87.21 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\[/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
[tex]n = \frac{5.25 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 87.209302...[/tex]
We have the final answer as
87.21 molesHope this helps you
A sample of an ideal gas at 1.00 atm and a volume of 1.98 L was placed in a weighted balloon and dropped into the ocean. As the sample descended, the water pressure compressed the balloon and reduced its volume. When the pressure had increased to 55.0 atm, what was the volume of the sample? Assume that the temperature was held constant.
Answer:
Final Volume = 0.036 L
Explanation:
Initial Pressure P1 = 1 atm
Initial Volume V1 = 1.98L
Final Pressure T1 = 55.0 atm
Final Volume V2 = ?
Temperature was held constant
The formulae relating these variables is Charles Law. This law states that the volume of a gas is inversely proportional to the pressure of a gas system provided temperature is held constant. The equations given as;
V1P1 = V2P2
V2 = V1P1 / P2
V2 = 1.98 * 1 / 55
V2 = 0.036 L
Analyze the following blood splatter pictures to determine the general direction, origin, and impact
Answer:
!!!!!!!!!!!!!!!!!!!!!!
Answer:
Figure 1: This blood spatter came from the right side. The impact was not hard. The blood may have come from a dripping wound though there is some evidence of movement, which may indicate the person with the wound was moving as the blood fell.
Figure 2: The elongated blood spatter shows that blood was traveling at a high velocity. The impact came from the right-hand side, and it was forceful.
Figure 3: This spatter shows circular drops, showing that the blood fell under the effect of gravity with no movement from the wound.
Explanation:
Plato
How many moles are in 5.6x1025 molecules of calcium oxide?
Answer:
93.02 molesExplanation:
To find the number of moles in a substance given it's number of entities we use the formula
[tex]n = \frac{N}{L} \\[/tex]
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
[tex]n = \frac{5.6 \times {10}^{25} }{6.02 \times {10}^{23} } \\ = 93.023...[/tex]
We have the final answer as
93.02 molesHope this helps you
A light absorbing chemical has a molar absorptivity constant of 487 L/mol*cm. For a system with a 1.00 cm path length, what chemical concentration would result in a recorded % transmittance of 31.6?a. None of these b. 974 M c. 0.000649 M d. 0.00103 M e. 0.0649 M
Answer:
The right answer is Option d (0.00103 M).
Explanation:
The given values are:
T = 31.6
e = 487 L mol cm
length, l = 1 cm
As we know,
Absorbance,
[tex]A=2-log_{10}(percent \ T)[/tex]
[tex]A=2-log_{10}(31.6)[/tex]
[tex]A=0.5003[/tex]
By using the Beer's law, we get
⇒ [tex]A=ecl[/tex]
⇒ [tex]c=\frac{A}{el}[/tex]
On substituting the values, we get
⇒ [tex]=\frac{0.5003}{487\times 1}[/tex]
⇒ [tex]=0.001027 \ \frac{mol}{L}[/tex]
⇒ [tex]=0.00103 \ M[/tex]
The complex [FeSCN]2+ has an absorptivity of 6.14×10−2 L/(mg⋅cm) at a wavelength of 580 nm. The transmittance of a solution sample was measured in a 1.00 cm cell, and the percent transmittance %T was 53.9%. Calculate the concentration of the solution in ppm.
Answer:
4.36 ppm
Explanation:
First we convert percent transmittance to absorbance:
A = 2 - log(%T)A = 0.268Then we calculate the concentration of the solution, using Lambert-Beer's equation:
A = ε*l*CIt is usually used with molar concentrations but given that the given absortivity is in ppm terms and the answer is also in ppm, we can simply use the given value.
0.268 = 6.14x10⁻²L·ppm⁻¹ * 1.00 cm * CC = 4.36 ppmThe concentration of the solution is 4.36 ppm when the percent transmittance measured in a 1.00 cm cell is 53.9%, the absorptivity is 6.14x10⁻² L/(mg*cm), and the wavelength is 580 nm.
We can calculate the concentration of the solution with the Beer-Lambert equation:
[tex] A= \epsilon Cl [/tex] (1)
Where:
A: is the absorbanceC: is the concentration =?l: is the length of the optical path = 1.00 cm ε: is the absorption coefficient = 6.14x10⁻² L/(mg*cm)With the transmittance, we can find the absorbance as follows:
[tex] A = -log T [/tex]
Where T is the transmittance = 53.9% = 0.539
So, the absorbance is:
[tex] A = -log T = -log(0.539) = 0.268 [/tex]
Finally, by solving equation (1) for C, we have:
[tex] C = \frac{A}{\epsilon l} = \frac{0.268}{6.14 \cdot 10^{-2} L/(mg*cm)*1.00 cm} = 4.36 mg/L [/tex]
Therefore, the concentration of the solution is 4.36 ppm.
You can find more about absorbance and transmittance here:
brainly.com/question/14919298brainly.com/question/6167291I hope it helps you!
calculate the volume of nitrogen gas produce by heating g of ammonia at 21c and 823 torr pressure
Answer:
final volume = 10.5 Liters N₂(g) at 21°C and 823Torr*
Explanation:
*Note=>No specified mass value of N₂(g) is defined in the problem. Therefore for a starting point, the gas sample is assumed to be 1.00 mole N₂(g) at STP conditions 22.4L
Determine volume of N₂(g) at 21°C(=294K) and 823 Torr (= 2.286 Atm).
Start with Volume of N₂(g) at 0°C and 1 Atm pressure => 22.4L and adjust to final volume of N₂(g) based upon 21°C(=294K) and 823 Torr (= 2.286 Atm).
V(final) = 22.4L(294K/273K)(360 Torr/823 Torr) = 22.4L(294/273)(360/823) = 10.55 Liters final volume.
Note: The volume of 1 mole (assumed) of any gas at STP (0°C/1 Atm) is 22.4 Liters. To convert to non-STP conditions, convert temperature and pressure factors (changes) that reflect what happens when the gas is expanded or decreased; but, these adjustments are taken independently for each variable of interest. The following notes explain.
For the increase in temperature from 0°C(=273K) to 21°C(=294K) one must apply a temperature ratio that will increase volume. That is, the change in volume due to the temperature change is 294K/273K. If a 273K/294K ratio were used the volume would have decreased. Not so for heating a sample of gas.
For the increase in pressure one should expect a decrease in volume. Therefore apply a pressure ration that will effectively decrease the volume of the gas. That is, to decrease a 22.4L sample at STP multiply the standard volume by a ratio of pressures that will decrease 22.4L to a smaller volume. That is, V(final by pressure effects) multiply by 360Torr/823Torr to decrease the STP VOLUME (22.4L) to the new non-standard volume. If 823Torr/360Torr were used, the final volume would not be smaller, but larger. Such is the physical effect of an increasing pressure change.
