A study is conducted to examine the correlation between Training Time and the Error Rate of employees. If the correlation coefficient of Training Time and Error Rate is -0.76, what is your conclusion?
(The answer is NOT B) HELP Please!!
A Moderate positive correlation
B Strong negative correlation
C No conclusion possible
D No correlation is shown
E Strong positive correlation

Answer:

40

Step-by-step explanation:

Based on the Proportional Transversal Theorem, the three parallel lines hat intersects the two transversals, divides the transversal lines proportionally.

Therefore, we would have the following ratio:

28/35 = ?/50

Cross multiply

35*? = 50*28

35*? = 1,400

Divide both sides by 35

? = 1400/35

? = 40

Answer:iiii

Step-by-step explanation:iiiii

Answer:

17.9

Step-by-step explanation:

Answer: 250%

since, 100% = 100/100

250% = 250/100

Step-by-step explanation:

Answer:

$26,179.82  

Step-by-step explanation:

FVA = PMT * n * (1 + i) ^ (n - 1)

FVA = 440 * 48* (1.00458)^(47)

Answer:

y=2x+1

Step-by-step explanation:

y is directly proportional to x if it increases as x increases

Answer:  

STEP 1  

M_{4,2} is set of 4x2 matrices hence each matrix has 4*2=8 entries. Each entry can be filled independently.  

Hence its basis has 8 linearly independent vectors.  

STEP 2  

Dimension= cardinality of basis = 8.

Answer:

a.) .0469

b.) .9961

c.) .9492

Rounded these check below for full answers

Step-by-step explanation:

a.)

[tex]{4\choose3}*.25^3*(1-.25)=.046875[/tex]

b.)

Porbability of at most 3 successes is equal to 1-p(4)

p(4)=

[tex]{4\choose4}*.25^4=.003690625[/tex]

1-.003690625=.99609375

c.)

two or more failures is equa lto

p(0)+p(1)+p(2)=

[tex]{4\choose0}*.25^0*(1-.25)^4+{4\choose1}*.25^1(1-.25)^3+{4\choose2}*.25^2*(1-.25)^2=.94921875[/tex]

[tex]\\ \sf\longmapsto y=(6x-5)\sqrt{8x-3}[/tex]

[tex]\\ \sf\longmapsto y=6(-4)-5\sqrt{8(-4)-3}[/tex]

[tex]\\ \sf\longmapsto y=-24-5\sqrt{-32-3}[/tex]

[tex]\\ \sf\longmapsto y=-29\sqrt{-35}[/tex]

[tex]\\ \sf\longmapsto y=-29\times 35i[/tex]

[tex]\\ \sf\longmapsto y=-1015i[/tex]

Answer:

Area of rectangle = 2H² - 5H

Step-by-step explanation:

Translating the word problem into an algebraic expression, we have;

Length =2H - 5

To write the algebraic expression to model the area of the rectangle;

Mathematically, the area of a rectangle is given by the formula;

Area of rectangle = L * H

Where;

Substituting the values into the formula, we have;

Area of rectangle = (2H - 5)*H

Area of rectangle = 2H² - 5H

Answer:

28 seconds ..............

Answer:

the answer is D

Step-by-step explanation:

v=πr²h

divide both side by πh

r²=v/πh

square both sides

r=√v/πh

Answer: SS Error

Step-by-step explanation:

The SS Error refers to the sum of the squares of the deviations of the observations, from their mean. It is simply the total variance from the observations on the study.

In performing a one-way ANOVA, the SS Error measures the variability of the observed values around their respective means and this is done through the summation of the squared differences between each observed value of the response and its corresponding treatment mean.

Answer:

Ture

Step-by-step explanation:

The rates of the same participatant are paired.

Answer:

D

Step-by-step explanation:

(x^2+3)(x-5)

That's the answer

Answer:

dv = surface area * dh

so

dv/dt = surface area * dh/dt

width at surface = 40 + (80-40)(30/40)

= 40 + 30 = 70 cm = 0.70 m

so

surface area = 9 * .7 = 6.3 m^2

so

.3 m^3/min = 6.3 m^2 * dh/dt

and

dh/dt = .047 meters/min or 4.7 cm/min

Step-by-step explanation:

Step-by-step explanation:

f(x)=log(x)

     =d(log(x)/dx)

=>y=1/x

Answer:

[tex]p =2.15n - 875[/tex]

Step-by-step explanation:

Given

[tex]CD_s= n[/tex]

[tex]Charges = 2.50[/tex] per CD

Expenses

[tex]E_1 = 875[/tex]

[tex]E_2 = 0.35[/tex] per CD

Required

The profit (p)

First, calculate the total income on n CDs

[tex]Total = Charges * n[/tex]

[tex]Total = 2.50 * n[/tex]

[tex]Total = 2.50n[/tex]

Next, the expenses on n CDs

[tex]Expenses = E_1 + E_2 * n[/tex]

[tex]Expenses = 875 + 0.35 * n[/tex]

[tex]Expenses = 875 + 0.35n[/tex]

The profit (p) is:

[tex]p = Total - Expenses[/tex]

[tex]p =2.50n - (875 + 0.35n)[/tex]

Open bracket

[tex]p =2.50n - 875 - 0.35n[/tex]

Collect like terms

[tex]p =2.50n - 0.35n - 875[/tex]

[tex]p =2.15n - 875[/tex]

Answer:

July 4th, 1776.

Step-by-step explanation:

By issuing the Declaration of Independence, adopted by the Continental Congress on July 4, 1776, the 13 American colonies severed their political connections to Great Britain. The Declaration summarized the colonists' motivations for seeking independence.

Answer:

1                  

-------------  

(x+2)(x-4)

Step-by-step explanation:

x+4                    x+3

-------------   * --------------

x^2+5x+6        x^2 -16

Factor

x+4                    x+3

-------------   * --------------

(x+3)(x+2)        (x+4)(x-4)

Cancel like terms

1                  1

-------------   * --------------

(1)(x+2)        (1)(x-4)

1                  

-------------    x cannot equal -3, -4, -2, 4  

(x+2)(x-4)

Answer:

Step-by-step explanation:multiple 5 times 108 and that gives you your answer..

Answer:

Following are the solution to the given points:

Step-by-step explanation:

As a result, Poisson for each driver seems to be the number of accidents.

Let X be the random vector indicating accident frequency.

Let, [tex]\lambda=[/tex]Expected accident frequency

[tex]P(X=0) = e^{-\lambda}[/tex]

For class 1:

[tex]P(X=0) = \frac{1}{(1-0.2)} \int_{0.2}^{1} e^{-\lambda} d\lambda \\\\P(X=0) = \frac{1}{0.8} \times [-e^{-1}-(-e^{-0.2})] = 0.56356[/tex]

For class 2:

[tex]P(X=0) = \frac{1}{(2-0.4)} \int_{0.4}^{2} e^{-\lambda} d\lambda\\\\P(X=0) = \frac{1}{1.6} \times [-e^{-2}-(-e^{-0.4})] = 0.33437[/tex]

For class 3:

[tex]P(X=0) = \frac{1}{(3-0.6)} \int_{0.6}^{3} e^{-\lambda} d\lambda\\\\P(X=0) = \frac{1}{2.4} \times [-e^{-3}-(-e^{-0.6})] = 0.20793[/tex]

The population is equally divided into three classes of drivers.

Hence, the Probability

[tex]\to P(X=0) = \frac{1}{3} \times 0.56356+\frac{1}{3} \times 0.33437+\frac{1}{3} \times 0.20793=0.36862[/tex]

Answer:

m=[tex]7\sqrt3[/tex]

n=7

Step-by-step explanation:

Hi there!

We are given a right triangle (notice the 90°) angle, the measure of one of the acute angles as 60°, and the measure of the hypotenuse (the side OPPOSITE from the 90 degree angle) as 14

We need to find the lengths of m and n

Firstly, let's find the measure of the other acute angle

The acute angles in a right triangle are complementary, meaning they add up to 90 degrees

Let's make the measure of the unknown acute angle x

So x+60°=90°

Subtract 60 from both sides

x=30°

So the measure of the other acute angle is 30 degrees

This makes the right triangle a special kind of right triangle, a 30°-60°-90°  triangle

In a 30°-60°-90° triangle, if the length of the hypotenuse is a, then the length of the leg (the side that makes up the right angle) opposite from the 30 degree angle is [tex]\frac{a}{2}[/tex], and the leg opposite from the 60 degree angle is [tex]\frac{a\sqrt3}{2}[/tex]

In this case, a=14, n=[tex]\frac{a}{2}[/tex], and m=[tex]\frac{a\sqrt3}{2}[/tex]

Now substitute the value of a into the formulas to find n and m to find the lengths of those sides

So that means that n=[tex]\frac{14}{2}[/tex], which is equal to 7

And m=[tex]\frac{14\sqrt3}{2}[/tex], which simplified, is equal to [tex]7\sqrt3[/tex]

Hope this helps!

Answer:

3 cups of sugar per 2 cups of flour

Step-by-step explanation:

just flip and simplify the fraction

4/6 = 6/4 = 3/2

The correct answer of the question is "0.7062" and "0.835". The further solution is provided below.

Given:

Probability of student smoke,

P = 27.7%

  = 0.277

Number of students (n) = 632

[tex]q = 1-p[/tex]

  [tex]=1-0.277[/tex]

  [tex]=0.723[/tex]

(i)

Here,

Number of students (n) = 60

then,

⇒ [tex]n_P=60\times 0.277[/tex]

         [tex]=16.62[/tex]

⇒ [tex]n_q=60\times 0.723[/tex]

        [tex]=43.38[/tex]

We can see that [tex]n_P > 10[/tex] and [tex]n_q>10[/tex] so the normal approximation condition are met.

Now,

[tex]\mu = n_P= 16.62[/tex]

[tex]\sigma = \sqrt{n_{Pq}}[/tex]

  [tex]= \sqrt{60\times 0.277\times 0.723}[/tex]

  [tex]=3.9664[/tex]

Now,

⇒ [tex]P(X<19) = P(X<18.5)[/tex]

                      [tex]=P(Z_{18.5})[/tex]

The Z-score is:

= [tex]\frac{18.5-16.62}{3.4664}[/tex]

= [tex]0.5423[/tex]

hence,

The probability will be:

⇒ [tex]P(Z_{18.5}) = 0.7062[/tex]

or,

⇒ [tex]P(Z<19) = 0.7062[/tex]

(ii)

Here,

Number of students (n) = 75

[tex]\mu = n_P = 75\times 0.277[/tex]

            [tex]=20.775[/tex]

[tex]\sigma = \sqrt{n_{Pq}}[/tex]

   [tex]=\sqrt{75\times 0.277\times 0.723}[/tex]

   [tex]=3.8756[/tex]

Now,

⇒ [tex]P(X>17) = P(X> 17.5)[/tex]

                      [tex]=1-P(X \leq 17.5)[/tex]

                      [tex]=1-P(Z_{17.5})[/tex]

The Z-score is:

= [tex]\frac{17.5-20.775}{3.8756}[/tex]

= [tex]-0.9740[/tex]

then, [tex]P(Z_{17.5}) = 0.165[/tex]

hence,

The probability will be:

⇒ [tex]P(X>17) = 1-0.165[/tex]

                      [tex]=0.835[/tex]    

Learn more about Probability here:

https://brainly.com/question/9825651

9514 1404 393

Answer:

  3. sign changes in the denominator need to be taken into account

  4. difference quotient: (f(x+h) -f(x))/h; It is the slope of the secant line. For linear functions, the slope is constant, as is the difference quotient.

Step-by-step explanation:

3. When solving the equation f(x) = 0, where f(x) is a rational function, only the numerator zeros need to be considered.

When solving the inequality f(x) ≤ 0, or f(x) < 0, both numerator and denominator zeros need to be considered. As with solving any inequality, multiplying or dividing by a negative number changes the sense of the comparison.

Example

f(x) = x/(x-2) changes sign at both x=0 and x=2. Then three regions need to be considered when solving f(x) < 0. Those are x < 0, 0 < x < 2, and 2 < x.

__

4. The difference quotient is defined as ...

  dq = (f(x +h) -f(x))/h

The difference quotient is essentially the average slope between (x, f(x)) and (x+h, f(x+h)). That is, it is the slope of the secant line between those two points.

For linear functions, the slope is a constant. The difference quotient is a constant equal to the slope of the line.

Example

f(x) = ax +b . . . . . a linear function with a slope of 'a'

The difference quotient is ...

  (f(x+h) -f(x))/h = ((a(x+h)+b) -(ax+b))/h = (ax+ah+b -ax -b)/h = ah/h = a

The difference quotient is the slope of the line.

Answer:

Imaginary roots

Step-by-step explanation:

The discriminant of a quadratic in standard form [tex]ax^2+bx+c[/tex] is given by [tex]b^2-4ac[/tex].

Given [tex]7x^2+1=5x[/tex], subtract 5x from both sides so that the quadratic is in standard form:

[tex]7x^2-5x+1=0[/tex]

Now assign variables:

The discriminant is therefore [tex](-5)^2-4(7)(1)=25-28=\textbf{-3}[/tex].

What does this tell us about the roots?

Recall that the discriminant is what is under the radical in the quadratic formula. The quadratic formula is used to find the solutions of a quadratic. Therefore, the solutions of this quadratic would be equal to [tex]\frac{-b\pm \sqrt{-3}}{2a}[/tex] for some [tex]b[/tex] and [tex]a[/tex]. Since the number under the radical is negative, there are no real roots to the quadratic (whenever the discriminant is negative, the are zero real solutions to the quadratic). Therefore, the quadratic has imaginary roots.

Answer:

M of aftershock = 4.90

Step-by-step explanation:

5.6 = log(x/1)

[tex]10^{5.6} = 398107.1 \\[/tex]

1/5 * 398,107.1 = 79,621.4

[tex]10^{m} =[/tex] 79,621.4

m = log (79,621.4) = 4.90  

Answer:

Step-by-step explanation:

x² + 7x + 10 = 0

x = [-7 ± √(7² - 4·1·10)]/(2·1) = [-7 ± √9[/2 = [-7 ± 3]/2 = -2, -5