A student makes the following claim:
The energy of electromagnetic waves increases with decreasing wavelength.
Which of the following statements support this claim?
O A. Dental patients need to wear lead aprons to protect themselves from X-rays but do not wear
protection from flashlights.
B. Both radio waves and gamma rays are invisible to human eyes.
C. Ultraviolet radiation causes sunburn but radio waves do not.
D. Microwaves are used for communication.
E. Gamma rays are used to kill cancer cells, but microwaves have no known effect on cancer
cells.

Answer:

20 m

Explanation:

Area under the speed-time graph = Distance Traveled

Area under Graph 1/2(2)(20)

=20 m

Answer:

that's fusion

Explanation:

Answer:

the answer is fusion for this

Answer:

C. 10⁻³ rads

Explanation:

Here, we shall use Rayleigh's Criterion to find out the angular resolution of Cat's eye during day light. Rayleigh's Criterion is written as follows:

θ = λ/a

where,

θ = angular resolution of Cat's eye = ?

λ = wavelength = 500 nm = 5 x 10⁻⁷ m

a = slit width of eye = 0.5 mm = 5 x 10⁻⁴ m

Therefore,

θ = (5 x 10⁻⁷ m/5 x 10⁻⁴ m)

Therefore,

θ = 0.001

θ = Sin⁻¹(0.001)

θ = 0.001 rad = 1 x 10⁻³ rad

Hence, the correct answer is:

C. 10⁻³ rads

Answer:

Streamline the body of the rocket to reduce drag

Keep weight to a minimum

Use higher pressures

Use the right amount of water

Answer:

E = 2.17 x 10⁻² V/m

Explanation:

First we will find out the current density by using the formula:

J = I/A

where.

J = Current Density = ?

I = Current = 5.5 A

A = Cross-Sectional Area = πr² = π(1.5 x 10⁻³ m)² = 7.068 x 10⁻⁶ m²

Therefore,

J = 5.5 A/7.068 x 10⁻⁶ m²

J = 0.778 x 10⁶ A/m²

Now, we calculate the magnitude of applied field:

E = ρJ

where,

E = Magnitude of applied field = ?

ρ = resistivity of Aluminum = 2.8 x 10⁻⁸ Ω.m

Therefore,

E = (2.8 x 10⁻⁸ Ω.m)(0.778 x 10⁶ A/m²)

E = 2.17 x 10⁻² V/m

Answer:

(a) ω = 1.57 rad/s

(b) ac = 4.92 m/s²

(c) μs = 0.5

Explanation:

(a)

The angular speed of the merry go-round can be found as follows:

ω = 2πf

where,

ω = angular speed = ?

f = frequency = 0.25 rev/s

Therefore,

ω = (2π)(0.25 rev/s)

ω = 1.57 rad/s

(b)

The centripetal acceleration can be found as:

ac = v²/R

but,

v = Rω

Therefore,

ac = (Rω)²/R

ac = Rω²

therefore,

ac = (2 m)(1.57 rad/s)²

ac = 4.92 m/s²

(c)

In order to avoid slipping the centripetal force must not exceed the frictional force between shoes and floor:

Centripetal Force = Frictional Force

m*ac = μs*R = μs*W

m*ac = μs*mg

ac = μs*g

μs = ac/g

μs = (4.92 m/s²)/(9.8 m/s²)

μs = 0.5

Answer:

The speed of the projectile upon returning to its starting point is 50 m/s.

Explanation:

Given;

initial velocity of the projectile, u = 50 m/s

The velocity of the projectile is maximum before hitting the ground. As the object moves upward, the velocity reduces as it approaches the maximum height, at the maximum height the velocity becomes zero. Also, as the object moves downward, the velocity starts to increase and becomes maximum before hitting the ground.

Therefore, the speed of the projectile upon returning to its starting point is 50 m/s.

Answer: If you want me to write them for you here they are

Explanation:

Net force causes  change in motion because  a net external force causes a change in motion; thus, we see that a net external force causes acceleration.

Not more likely to be Net force motion because if it doesnt say change then its gonna stay the same so Net force does cause change in a motion because  take for example if you are going to bounce a basketball its gonna change its position from one place to another thats how Net force causes Change in motion.  

Hope this helps :)

Answer:

66.7s

Explanation:

Given parameters:

Distance between Mars and Earth  = 2 x 10¹⁰m

Unknown:

Time it takes for light to travel  = ?

Solution:

The speed of light is given as 3 x 10⁸m/s

 Now;

   Speed  = [tex]\frac{distance}{time}[/tex]  

    Time  = [tex]\frac{distance}{speed}[/tex]

Insert the parameters and solve;

   Time  = [tex]\frac{2 x 10^{10} }{3 x 10^{8} }[/tex]   = 66.7s

Answer:

Explanation:

mass number is now 4 times less than the original value so alpha decay occur during alpha decay the mass number is decreased 4 times and atomic number decreased 2 times than the original value

Answer:3 N —->

Explanation:

In the case when  the forces act on the car as shown in the picture so here the net force should be 3N.

Since

A parachute in the back of the car is released to help slow down the car.

So here the net force should be

= 10 N - 7N

= 3 N

Hence, In the case when  the forces act on the car as shown in the picture so here the net force should be 3N.

Learn more about force here: https://brainly.com/question/21422036

Answer:

280.6N

Explanation:

According to Newton's second law;

Force = mass * acceleration

Given

Mass = 280kg

velocity = 10m/s

Time = 10 secs

Acceleration = velocity?/Time

Force = mass * velocity/time

Force = 280 + (16-10/10)

Force = 280 + 0.6

Force = 280.6N

Hence the force exerted by the snowmobile to accelerate is 280.6N

Answer:168 N

Explanation:

Answer:

5

Explanation:

Answer:

5

Explanation:

Explanation:

so sorry

don't know but please mark me as brainliest please

Answer:

The moment of inertia of this system is 68 kilogram-square meters.

Explanation:

We have two particles rotating about the z-axis, which is orthogonal to xy plane, the moment of inertia of the system ([tex]I_{z}[/tex]), measured in kilogram-square meters, is determined by the following formula:

[tex]I_{z} = \Sigma \limits_{i=1}^{2}m_{i}\cdot r_{i}[/tex] (1)

Where:

[tex]m_{i}[/tex] - Mass of the i-th particle, measured in kilograms.

[tex]r_{i}[/tex] - Distance of the i-th particle from axis of rotation, measured in meters.

By Pythagorean Theorem we calculate each distance:

[tex](x_{1}, y_{1}, z_{1}) = (4\,m, 0\,m,0\,m)[/tex]

[tex]r_{1}=\sqrt{(4\,m-0\,m)^{2}+(0\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]

[tex]r_{1} = 4\,m[/tex]

[tex](x_{2},y_{2}, z_{2}) = (0\,m, 3\,m, 0\,m)[/tex]

[tex]r_{2} = \sqrt{(0\,m-0\,m)^{2}+(3\,m-0\,m)^{2}+(0\,m-0\,m)^{2}}[/tex]

[tex]r_{2} = 3\,m[/tex]

If we know that [tex]m_{1} = 2\,kg[/tex], [tex]r_{1} = 4\,m[/tex], [tex]m_{2} = 4\,kg[/tex] and [tex]r_{2} = 3\,m[/tex], then the moment of inertia of the system is:

[tex]I_{z} = m_{1}\cdot r_{1}^{2}+m_{2}\cdot r_{2}^{2}[/tex] (1b)

[tex]I_{z} = (2\,kg)\cdot (4\,m)^{2}+(4\,kg)\cdot (3\,m)^{2}[/tex]

[tex]I_{z} = 68\,kg\cdot m^{2}[/tex]

The moment of inertia of this system is 68 kilogram-square meters.

Answer:

6.64 Newtons

On the moon that 40 kg child would have a weight of 6.64 Newtons (kg multiplied by gravity) because the moon's gravity is 1/6th of the Earth's gravity. Your mass on any planet on the solar system (Jupiter, Venus, Earth, or anywhere else) is the same because the amount of matter in you does not change.

Explanation:

Answer:

1.8m/s^2

Explanation:

Since the two ropes are going up, their combined force is 105+115=220N. With a gravitational force of 186N, the force of the two ropes pulling up the will be 220-186=34N.

Now we need the mass of the bucket itself in order to find the acceleration of the bucket (remember that F=ma and m is needed to find a). Since gravitational acceleration is 9.8m/s^2 and F=186N, 186/9.8=18.97959184 kg for the mass of the bucket.

Now that we have the mass of the bucket, we can find the acceleration of the bucket. Since F=34N from earlier, 34N/18.97959184kg=1.791397849m/s^2=1.8m/s^2 is the acceleration of the bucket.

Therefore, 1.8m/s^2 is the correct answer.

Please mark brainliest!

Answer:

1.8

Explanation:

honestly i jus took the test

Answer:

if he were to land on concrete, he would most likely die and stop all momentum and for the water, he'd most likely live/die (mostly live) and slow momentum to a stop and rise up to the surface

Explanation:

that's the explanation now i gotta execute order 66

We are Given:

Mass of the block (m) = 500 grams or 0.5 Kg

Initial velocity of the block (u) = 0 m/s

Distance travelled by the block (s) = 8 m

Time taken to cover 8 m (t)= 2 seconds

Acceleration of the block (a) = a m/s²

Solving for the acceleration:

From the seconds equation of motion:

s = ut + 1/2* (at²)

replacing the variables

8 = (0)(2) + 1/2(a)(2)²

8 = 2a

a = 4 m/s²

Therefore, the acceleration of the block is 4 m/s²

Answer:

1.

A. Vf = 29.4 m/s

B. h = 44.1 m

2.

A. Vf = 24.5 m/s

B. h = 30.625 m

3.

A. Vf = 5.5 m/s

4.

A. t = 3.03 s

B. Vf = 29.7 m/s  

Explanation:

1.

A.

using 1st equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s (since, book starts from rest)

g = 9.8 m/s²

t = time = 3 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(3 s)

Vf = 29.4 m/s

B.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

h = (0 m/s)(3 s) + (1/2)(9.8 m/s²)(3 s)²

h = 44.1 m

2.

A.

using 1st equation of motion:

Vf = Vi + gt

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 0 m/s (since, book starts from rest)

g = 9.8 m/s²

t = time = 2.5 s

Therefore,

Vf = 0 m/s + (9.8 m/s²)(2.5 s)

Vf = 24.5 m/s

B.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

h = (0 m/s)(2.5 s) + (1/2)(9.8 m/s²)(2.5 s)²

h = 30.625 m

3.

A.

using 3rd equation of motion:

2gh = Vf² - Vi²

where,

Vf = Final Velocity = ?

Vi = Initial Velocity = 3 m/s

g = 9.8 m/s²

h = height = 2 m

Therefore,

2(9.8 m/s²)(2 m) = Vf² - (3 ms)²

Vf² = 39.2 m²/s² - 9 m²/s²

Vf = √30.2 m²/s²

Vf = 5.5 m/s

4.

A.

using 2nd equation of motion:

h = Vi t + (1/2)gt²

where,

h = height = 45 m

Vi = Initial Velocity = 0 m/s (since, photo copier was initially at rest)

t = time = ?

g = 9.8 m/s²

45 m = (0 m/s)(t) + (1/2)(9.8 m/s²)(t)²

t² = 2(45 m)/(9.8 m/s²)

t = √9.18 s²

t = 3.03 s

B.

using 1st equation of motion:

Vf = Vi + gt

Vf = 0 m/s + (9.8 m/s²)(3.03 s)

Vf = 29.7 m/s

Answer:

the answer is b

Explanation:

An expression for the displacement as a function of time is x(t) = a sin wt.

Displacement is defined as the change in position of an object. It is a vector quantity and has a direction and magnitude. The spacing between two specified points is represented by displacement, a one-dimensional measure commonly known as length or distance.

Given in the question we have to find the displacement of the as function of time

The equation used of express displacement is.

d = V i t + 1 2 a t 2  

Displacement = Final position – initial position = change in position.

so, x = A sin wt is equation where A is amplitude and t is time period.

An expression for the displacement as a function of time is x(t) = a sin wt.

Thus, an expression for the displacement as a function of time is x(t) = a sin wt.

To learn more about displacement refer to the link:

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#SPJ2

Answer:

Different organelles play different roles in the cell — for instance, mitochondria generate energy from food molecules; lysosomes break down and recycle organelles and macromolecules; and the endoplasmic reticulum helps build membranes and transport proteins throughout the cell.

Explanation:

Hopefully this helped!

Answer:

As already mentioned, the mechanical energy of an object can be the result of its motion (i.e., kinetic energy) and/or the result of its stored energy of position (i.e., potential energy). The total amount of mechanical energy is merely the sum of the potential energy and the kinetic energy.

Explanation:

Answer:

Explanation:

potential energy of water is converted into heat energy

P E = mgh = m x 9.8 x 111

= 1087.8 m .

Let rise in temperature θ

m x s x θ = heat absorbed

m x s x θ =  1087.8 m

m x 4182 x θ =  1087.8 m

θ = 0.26 degree celsius .

The properties of fluids are Density,Viscosity,Temperature, Pressure,Specific Volume,Specific Weight,Specific Gravity.

The cart is pulled at a constant velocity, so it is in equilibrium. In particular, the net horizontal force is zero, and consists of only the pulling force and friction such that

p - f = 0

where p and f denote the magnitudes of the pulling force and friction.

So we have

p - 12 N = 0

p = 12 N

Compute the block's weight:

w = m g = (20 kg) (9.8 m/s²) = 196 N

The net vertical force is 0, so the normal force has the same magnitude:

n + (-w) = 0   →   n = 196 N

The frictional force (mag. f ) is proportional to the normal force by a factor of µ = 0.20 such that

f = 0.20 (196 N) = 39.2 N ≈ 39 N

The force of kinetic friction acting on the block of mass 20 Kg having a coefficient of kinetic friction of 0.2 is 39.2 N

Mass (m) = 20 Kg

Acceleration due to gravity (g) = 9.8 m/s²

N = mg

N = 20 × 9.8

Coefficient of kinetic friction (µ) = 0.2

Normal reaction (N) = 196

F = µN

F = 0.2 × 196

Therefore, the force of kinetic friction acting on the block is 39.2 N

Learn more: https://brainly.com/question/11902512