A rectangular tank 4 feet long, 3 feet wide, and 5 feet deep is full of oil with weight density 50 lb ft 3 lbft3 . Calculate the work required to pump all of the oil out over the top of the tank.

Answers

Answer 1

The work required for the given task of pumping all of the oil out over the top of the tank is 7,500 ft·lb

The known parameters;

The length of the rectangular tank, l = 4 feet

The width of the tank, w = 2 feet

The depth of the tank, h = 5 feet

The weight density of the oil with which the tank is filled, ρ × g = 50 lb/ft³

The unknown parameter

The work required to pump all of the oil out over the top of the tank

Method;

Calculate the force required to lift each slice (layer) of the oil to the top multiplied by the distance, y, the slice moves and summing the result as an integration as follows;

The volume of each slice, [tex]\mathbf{V_i}[/tex] = l × w × dy

The force required to move each slice, [tex]\mathbf{F_i}[/tex] = ρ × g × l × w × dy

The work done, [tex]\mathbf{W_i}[/tex], in moving the slice a distance, y, is given as follows;

[tex]\mathbf{W_i}[/tex] = ρ × g × l × w × y × dy

Therefore, the total work done, W, in pumping all the water located from y = 0, to y = 5, to the top of the tank, is given as follows;

[tex]\mathbf{W = \int\limits^5_0 {(\rho \times g \times l \times w \times y) } \, dy}[/tex]

Therefore;

W = (ρ × g × l × w × y²)/2

Plugging in the values, gives;

W = (50 lb/ft³ × 4 ft. × 3 ft. × (5 ft.)²)/2 = 7,500 ft·lb

The work required to pump all of the oil out over the top of the tank, W = 7,500 ft·lb.

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Related Questions

Find the radius of a circle with a diameter of 14 cm

Answers

Answer :-

R= 7

Explanation:-

The diameter is 2 times the radius

So the radius is 14/2 =7

Answer:

r = 7 cm

Step-by-step explanation:

The radius is 1/2 of the diameter

r = d/2

r =14/2

r = 7 cm

A ball is kicked from the ground. At 1 second it is 3 m off the ground. At 2 seconds it is 12 m off the ground, at 3 seconds it is 27 m off the ground After 3 bounces, how high is the ball

Answers

Answer:

the correct answer is 3 m............

13. Find the smallest number which when divided by 21,28,36 and 44 leaves a
remainder of 3 in each case?

Answers

Answer:

2775

Step-by-step explanation:

Well of course since the problem is not restricted, the smallest number is 3. I'm almost sure that's not what you mean. The next smallest number is 2775. I found that using a  programing language. I'm sure as well that does not satisfy the question, either.

I think you are intended to do this by finding the lowest common multiple and adding 3.

21: 3 * 7

28: 2 * 2 * 7

36: 2 * 2 * 3 * 3

44: 2 * 2 * 11

LCM = 2 * 2 * 3 * 3 * 7 * 11 = 2772

Now add 3 and the number you want is 2775

4 l to 250 miles ratio​

Answers

Answer:

See below.

Step-by-step explanation:

Are you sure it's 4 liters to 250 miles, and not 4 liters to 250 milliliters?

If it is 4 liters to 250 miles, then it equals

0.016 liter : 1 mile

If it is 4 liters to 250 ml, then it is

4 liters : 250 ml

4 liters : 0.25 liter

16 liters : 1 liter

16 : 1

The scale on a map is
1:25 000
(a) On a map, a distance
measures 5cm. What is this
in real life? Give your
answer in kilometres.
(b) In real life a distance is
2.2km. What would this be in
the map in centimetres?

Answers

Answer:

Step-by-step explanation:

a) 5 cm(25000)(1 m/100 cm)(1 km/1000 m) = 1.25 km

b) 2.2 km (1000 m/km)(100 cm/m) / 25000 = 8.8 cm

A group of hikers is descending a mountain at a rate of 400 feet per hour. After three hours, what integer represents their total change in elevation?

I am not sure if it's -1200 (because it said descending)
Or if it's just 1200

Answers

Answer:

Bro it will be +1200

Step-by-step explanation:

If you like my answer than please mark me brainliest thanks

Car drove 2hours at a speed of 100km per hour & 3 hour at a speed of 50 km per hour . What was the average speed of the car during the trip?

Answers

Answer:

200 kilometers and 150 kilometers

Explain why this quadrilateral is not a parallelogram.

Answers

Answer:

because this figure does not have two parallel sides

I'm Sorry for by bad English but I am italian

Find the slope of the line that contains (4, -6) and (4, 4)

Answers

Answer:

Undefined

Step-by-step explanation:

Slope formula = [tex]\frac{y_{2}-y_{1}}{y_{2}-y_{1}}[/tex]

[tex]\frac{4-(-6)}{4-4}[/tex]

[tex]\frac{10}{0}[/tex]

A number can not have a denominator of 0, therefore making the slope undefined.

Answer:

Undefined.

Step-by-step explanation:

Use the slope formula: [tex]\frac{y_1-y_2}{x_1-x_2}[/tex]

[tex]m=\frac{-6-4}{4-4}=\frac{-10}{0}=[/tex] Undefined

Which of the following is a valld conclusion for the quadratic equation?
x2 - 6x+8=0
OX-3 = 0 and x+ 5 = 0
Ox+ 4 = 0 and x + 2 = 0
O x-4 = 0 and x + 2 = 0
O x-4 = 0 and x - 2 = 0

Answers

Answer:

[tex]x-4=0\: and\: x-2=0[/tex]

Step-by-step explanation:

[tex]x^{2} -6x+8-0[/tex]

[tex]x^{2} -4x-2x+8-0[/tex]

[tex]x(x-4)-2(x-4)=0[/tex]

[tex](x-4)(x-2)=0[/tex]

[tex]x-4=0[/tex] and [tex]x-2=0[/tex]

----------------------

OAmalOHopeO

-----------------------

The valid conclusions for the quadratic equation x² - 6x + 8 = 0 are:

x - 4 = 0 and x - 2 = 0

Option D is the correct answer.

We have,

Quadratic equation x² - 6x + 8 = 0.

Now,

To solve the quadratic equation x² - 6x + 8 = 0, we can use the quadratic formula, which states that:

x = (-b ± √(b² - 4ac)) / (2a)

where a, b, and c are the coefficients of the quadratic equation.

In this case,

a = 1, b = -6, and c = 8.

Substituting these values into the quadratic formula, we get:

x = (-(-6) ± √((-6)² - 4(1)(8))) / (2(1))

x = (6 ± √(36 - 32)) / 2

x = (6 ± √(4)) / 2

x = (6 + 2) / 2 or x = (6 - 2) / 2

x = 4 or x = 2

Therefore,

The valid conclusions for the quadratic equation x² - 6x + 8 = 0 are:

x - 4 = 0 and x - 2 = 0

because the roots of the equation are x = 4 and x = 2,

which can be written in factored form as (x - 4)(x - 2) = 0.

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complete the equation describing how x and y are related.

Answers

Answer:

y=-2x+1

Step-by-step explanation:

The slope of the line is (y(2)-y(1))/(2-1)=(-3+1)/1=-2. The equation of the line is y=mx+(y intercept), y=-2x+1

The complete equation describes how x and y are related y=-2x+1.

We have given, the equation,

We have to determine the complete equation describing how x and y are related.

What is the formula for the slope?

The slope of the line is(m)=y2-y1/x2-x1

Where m is the slope,

Therefore we get,

(y(2)-y(1))/(2-1)

=(-3+1)/1

=-2.

The equation of the line is y=mx+(y-intercept), y=-2x+1.

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If Q(x) = x2 + 3x + 2, find Q(-4).

Answers

Q(x)=x^2+3x+2

[tex]\\ \sf\longmapsto Q(-4)[/tex]

[tex]\\ \sf\longmapsto (-4)^2+3(-4)+2[/tex]

[tex]\\ \sf\longmapsto 16+(-12)+2[/tex]

[tex]\\ \sf\longmapsto 16-12+2[/tex]

[tex]\\ \sf\longmapsto 4+2[/tex]

[tex]\\ \sf\longmapsto 6[/tex]

The value of the function at x = - 4 will be 6. Then the correct option is D.

What is a function?

A function is an assertion, concept, or principle that establishes an association between two variables. Functions may be found throughout mathematics and are essential for the development of significant links.

The definition of simplicity is making something simpler to achieve or grasp while also making it a little less difficult.

The function is given below.

Q(x) = x² + 3x + 2

The value of the function at x = - 4, then we have

Q(-4) = (-4)² + 3(-4) + 2

Simplify the equation, then we have

Q(-4) = (-4)² + 3(-4) + 2

Q(-4) = 16 - 12 + 2

Q(-4) = 18 - 12

Q(-4) = 6

The value of the function at x = - 4 will be 6. Then the correct option is D.

More about the function link is given below.

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vector v has a horizontal vector component with magnitude 19 and a vertical vector component with magnitude 35. what is the acute angle theta formed by v and positive x-axis?

Answers

9514 1404 393

Answer:

  61.5°

Step-by-step explanation:

The tangent relation is useful here. The angle is opposite the vertical side and adjacent to the horizontal side of the right triangle.

  Tan = Opposite/Adjacent

  tan(α) = 35/19

  α = arctan(35/19) ≈ 61.5°

The angle made by v and the positive x-axis is 61.5°.

Proceed as in Example 4 in Section 6.1 and find a power series solution y = [infinity] n = 0 cnxn of the given linear first-order differential equation. (Give your answer in terms of c0.) y' = xy

Answers

Let y be a solution to the given differential equation,

[tex]y' = xy[/tex]

where

[tex]\displaystyle y = \sum_{n=0}^\infty c_n x^n \\\\ y' = \sum_{n=0}^\infty nc_nx^{n-1} = \sum_{n=1}^\infty nc_nx^{n-1} = \sum_{n=0}^\infty (n+1)c_{n+1}x^n[/tex]

Substituting these series into the DE gives

[tex]\displaystyle \sum_{n=0}^\infty (n+1)c_{n+1}x^n = x\sum_{n=0}^\infty c_nx^n \\\\ \sum_{n=0}^\infty (n+1)c_{n+1}x^n = \sum_{n=0}^\infty c_nx^{n+1} \\\\ \sum_{n=0}^\infty (n+1)c_{n+1}x^n = \sum_{n=1}^\infty c_{n-1}x^n \\\\ c_1 + \sum_{n=1}^\infty (n+1)c_{n+1}x^n = \sum_{n=1}^\infty c_{n-1}x^n \\\\ c_1 + \sum_{n=1}^\infty \bigg((n+1)c_{n+1}-c_{n-1}\bigg)x^n = 0[/tex]

Then the coefficients [tex]c_n[/tex] in the series solution are governed by the recurrence,

[tex]\begin{cases}c_0 = c_0 \\ c_1 = 0 \\ (n+1)c_{n+1}-c_{n-1} = 0&\text{for }n\ge1\end{cases}[/tex]

We have

[tex](n+1)c_{n+1}-c_{n-1} = 0 \implies nc_n - c_{n-2} = 0 \implies c_n = \dfrac{c_{n-2}}n[/tex]

so it follows that [tex]c_1=c_3=c_5=\cdots = 0[/tex], while

[tex]c_0 = \dfrac{c_0}1 = \dfrac{c_0}{2^0\times0!} \\\\ c_2 = \dfrac{c_0}2 = \dfrac{c_0}{2^1\times1!}\\\\ c_4 = \dfrac{c_2}4 = \dfrac{c_0}{2\times4} = \dfrac{c_0}{2^2\times2!}\\\\ c_6 = \dfrac{c_4}6 = \dfrac{c_0}{2\times4\times6} = \dfrac{c_0}{2^3\times3!}[/tex]

and so on, with the general n-th coefficient being

[tex]c_n = \begin{cases}0&\text{if }n\text{ is odd} \\ \dfrac{c_0}{2^{n/2}\left(\frac n2\right)!} &\text{if }n\text{ is even}\end{cases}[/tex]

Then the power series solution is

[tex]\displaystyle y(x) = c_0 \sum_{n=0}^\infty \frac{x^n}{2^{n/2}\left(\frac n2\right)!} = c_0 \sum_{n=0}^\infty \frac1{\left(\frac n2\right)!} \left(\frac x{\sqrt2}\right)^n[/tex]

but this doesn't tell the whole story because it doesn't capture the odd-index-is-zero case.

More concisely: let n = 2k for integers k ≥ 0. Then

[tex]\displaystyle y(x) = c_0 \sum_{k=0}^\infty \frac{x^{2k}}{2^k k!} = c_0 \sum_{k=0}^\infty \frac1{k!} \left(\frac{x^2}2\right)^k[/tex]

and as a bonus, it's easier to get an exact solution for this DE,

[tex]y(x) = c_0e^{x^2/2}[/tex]

In the Brady's Family, each girl has twice as many brothers as she has sisters.
However, each boy has the same number of brothers as sisters. Is this possible; and
if so how many girls are there in the family, and how many boys?

Answers

Answer:

3 girls and 4 boys

Step-by-step explanation:

Writing the number of girls in the family as g and the number of boys in the family as b,

we know that each girl has twice as many brothers as sisters. Therefore, the amount of boys in the family (b, or how many brothers each girl has) is twice the number of the amount of girls in the family (g) minus 1 (g-1) (subtract 1 because each girl's number of sisters does not include the girl herself). We can write this as

b = 2(g-1)

Next,

we know that each boy has the same amount of brothers as sisters. Therefore, the amount of boys in the family minus 1 (b-1, subtracting 1 because we don't include the boy that has the brothers) is equal to the amount of girls in the family (g). we can write this as

b-1 = g

Therefore, we have

b = 2(g-1)

b-1 = g

Plugging b-1 = g into the first equation, we get

b = 2 (g-1)

2(g-1) = 2((b-1) - 1) = b

= 2(b-1-1)

= 2(b-2)

= 2b-4

b = 2b-4

subtract 2b from both sides to make it so that only b values and their coefficients are on one side

-b = -4

multiply both sides by -1 to solve for b

b=4

Therefore, there are 4 boys in the family and b-1 = 4-1 = 3 girls in the family.

In a café, I order a cup of tea and a piece of cake and it costs £1.10. The next time I order 2 cups of tea and one piece of cake and it costs £1.70. Find the cost of a piece of cake.​

Answers

Answer:

£0.50

Step-by-step explanation:

t = one cup of tea

c = one piece of cake

t + c = £1.10

2t + c = £1.70

the cost increases by £0.60 (£1.70 - £1.10) when you order one more cup of tea which means that one cup of tea costs £0.60

substitute £0.60 into t + c = £1.10

£0.60 + c = £1.10

rearrange to get c = £1.10 - £0.60 = £0.50

so one piece of cake costs £0.50

Answer: piece of cake is 0.5£

Explanation:

Tea + cake = 1.10
2 Tea + cake = 1.70

From that we can find the value of a cup of tea by simply 1.70 - 1.10 = 0.6£

If cup of tea = 0.6£

Then a cake = 1.10 - 0.6 = 0.5 £

If two people are splitting a total rent number of $1,120 a month, it would be $560 split evenly. However, if one roommate pays $60 more than the other, how much would that roommate be paying per month?

Answers

$560-$500

=$500

therefore, other roommate will be paying $500 per month

Parallelogram QRST has vertices Q(- 4, 2) . R(-2,4),5(0)) draw and label the image after a counterclockwise rotation of 270 degrees about the origia.please I need help.

Answers

Answer:

gr,wrgñegetjj

Step-by-step explanation:

jyyjytjjttj

Help me fast plz plz help

Answers

Answer:

5/8

Step-by-step explanation:

Add the two fractions

3/8 + 1/4

Get a common denominator

3/8 + 1/4 *2/2

3/8 + 2/8

5/8

How do you write it in digits
27 million, 200

Answers

Answer:

27,000,200

Step-by-step explanation:

Going by basic math you know a million has six 0's.

So; one million is represented as 1,000,000.

Hence twenty-seven million as 27,000,000.

Using you tens, hundreds and thousands you'll know 200 will fall into the last area.

I need to know about rounding the numbers up to 100

Answers

Step-by-step explanation:

Rounding number are important in world-problem. They help us in many ways like counting class, food, etc. It's the same thing as estimating.

Tens Place:

50-99: round to 100

100th place:

150-101: round to 100

There is still a lot I'm missing out on, but you could say does are the lowest group that can be round to 100. I'm not a expert, but I hope I could help! You can also ask for the other numbers, but it just depends on where you place or how you use the 100.

If two numbers differ by 9 the same of their squares is 653. What are the numbers?

Answers

Answer:

Two numbers differ by 9 and the sum of their square is 653. What are the numbers?

Well,that's a mathematical question from algebra and it's quite difficult to answer such questions by writing through the circumstances offered by apps like quora.

However,I have tried to answer your question in an understandable way.Hope you may not find it difficult to analyze.

Let the numbers be x and (9+x)

Therefore,according to given,

x^2 + (9+x)^2 =653

=>x^2 + (9)^2 + x^2 + 2×(9)×(x)=653 (Applying the formula of (a+b)^2)

=>x^2 + 81 + x^2 + 18x =653

=>2x^2 + 18x + (81-653)=0

=>2x^2 + 18x - 572=0

=>2x^2 + (44x - 26x) - 572=0

=>2x^2 + 44x - 26x - 572=0

=>2x(x + 22) - 26(x + 22)=0

=>(x + 22)(2x - 26)=0

But since the number can't be negative

Therefore, x=13

Hence,the required numbers are 13 and 22.

Step-by-step explanation:

in first hope you like it

what is a cell and atom​

Answers

Step-by-step explanation:

An atom is a chemical unit. It is the smallest particle of a chemical element. A cell is a biological unit. It is the smallest unit of any living beings. A cell is composed of molecules, and molecules are composed of atoms

find the surface area of the prism

Answers

Answer:

114 cm²

Step-by-step explanation:

Surface area of the rectangular prism,

2×(wl+hl+hw)

=2×(3×8+3×8+3×3)

= 2×(24+24+9)

= 2×(57)

=114 cm²

Find the length of AB

Answers

Answer:

C. 44.98

Step-by-step explanation:

Hi there!

We are given the right triangle ABC, m<B=12°, and CB =44

We want to find the length of AB

We can use trigonometry to do it

Let's find the ratio in reference to angle B, as that angle is given.

In reference to angle B the opposite angle is AC, the adjacent side is CB, and the hypotenuse is AB

Now let's recall the 3 most commonly used functions:

[tex]sine=\frac{opposite}{hypoptenuse}[/tex]

[tex]cosine=\frac{adjacent}{hypotenuse}[/tex]

[tex]tangent=\frac{opposite}{adjacent}[/tex]

Let's find the cosine of angle B, as it uses CB and AB, which are the given side and the side we need to find

In that case,

cos(12)=[tex]\frac{CB}{AB}[/tex]

cos(12)=[tex]\frac{44}{AB}[/tex]

Multiply both sides by AB

[tex]AB[/tex]*cos(12)=44

Divide both sides by cos(12)

AB=[tex]\frac{44}{cos(12)}[/tex]

Now plug [tex]\frac{44}{cos(12)}[/tex] into your calculator. Make sure your calculator is on degree mode

AB≈44.98

So the answer is C

Hope this helps!

Describe the translation y= (x-2) squared +5 -> y = (x+2) squared - 3

Answers

9514 1404 393

Answer:

  A.  T<-4, -8>

Step-by-step explanation:

To get the second equation, we had to replace x with x+4 (a translation left 4) and we had to add -8 to the function value (a translation down 8).

Left 4 and down 8 is the translation ...

  T<-4, -8>

A radio telescope has a parabolic surface, as shown below. A parabola opening up with vertex at the origin is graphed on the coordinate plane. The height of the parabola from top to bottom is 9 meters and its width from left to right is 12 meters. If the telescope is 9 m deep and 12 m wide, how far is the focus from the vertex?

Answers

The telescope shape and the characteristic equations of the telescope parameters are the same as parabolic equations

The distance between the focus and the vertex, of the parabola is 3.375 meters

The process for obtain the above values is as follows:

The known parameters of the parabola are;

The location of the vertex of the parabola= The origin = (0, 0)

The height of the parabola = 9 meters

The width of the parabola = 12 meters

The unknown parameter;

The distance between the focus and the vertex

Method:

Finding the coordinate of the focus from the general equations of the the parameters of a parabola

The equation of the parabola in standard form is y = a·(x - h)² + k

From which we have;

(x - h)² = 4·p·(y - k)

The coordinates of the focus, f = (h, k + p)

Where;

(h, k) = The coordinates of the vertex of the parabola = (0, 0)

a = 1/(4·p)

From the question, we have the following two points on the parabola,

given that the parabola is 12 meters wide at 9 meters above the origin and

it is symmetric about the y-axis;

Points on the parabola = (9, 6), and (9, -6)

Plugging in the values of the vertex, (h, k) and the two known points, in the equation, y = a·(x - h)² + k, we get;

6 = a·(9 - 0)² + 0 = 81·a

a = 6/81 = 2/27

p = 1/(4·a)

∴ p = 1/(4 × 2/27) = 27/8

The coordinate of the focus, f =  (h, k + p)

∴ f = (0, 0 + 27/8) = (0, 27/8)

The coordinate of the focus f = (0, 27/8)

Given the vertex and the focus of the parabola have the same x-values of 0, we have;

The distance between the focus and the vertex, d = the difference in their y-values;

d = 27/8 - 0 = 27/8 = 3.375

The distance between the focus and the vertex, d = 3.375 meters

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In AABC, mZA = 32°, mZB = 25°, and a = 18. Find c to the nearest tenth.

Answers

Answer:

Step-by-step explanation:

PLEASE SHOW YOUR WORK! I NEED THIS QUICK! THANK YOU!! POINTS AND RATES WILL BE GIVEN!!

Answers

Answer:

3

Step-by-step explanation:

Y is given by sin(theta). sin(-60)=-sqrt(3)/2

Let f(x) = 12/4x+2 Find f(-1). (1 point)

Answers

Answer:

-1

Step-by-step explanation:

let,x=-1

f(x)= 12/4x + 2

f(-1)= 12/4x(-1) + 2

=12/(-4) +2

= -3+2

= -1

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