A rectangle has side lengths 2x + 3 and 5x - 2.
Write an expression without brackets for the area of the rectangle

Answer:

3

Step-by-step explanation:

Easy pythagorean theorum question.

The law states that "A squared plus B squared, equals C squared."

A and B are the two sides that border the 90 degree mark.

C is the hypotenuse or the longest side/diagonal.

Since we know C and A (I chose to use A because why not) we can fill in the equation with what we know

2^2 + ?^2 = [tex]\sqrt{13^{2} }[/tex]

So

4 + ?^2 = [tex]\sqrt{13^{2} }[/tex]

Since the 13 is already squared in side of a root, it stays as 13

4 + x^2 = 13

4 - 4 + x^2 = 13 - 4

x^2 = 9

x^2 root = root of 9

x = 3

The missing side is 3.

Or you could use an online calculator xD

A square pyramid has 4 triangles and the square base.

Calculate the area of one triangle, multiply that by 4 then add the area of the base.

Area of triangle = 1/2 x base x height = 1/2 x 5 x 12 = 30 square yards.

30 x 4 = 120 square yards

Area of base = 5 x 5 = 25 square yards

Total = 120 + 25 = 145 square yards.

Let

ATQ

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 40x+50x=45000[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow 90x=45000[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow x=\dfrac{45000}{90}[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow x=500[/tex]

Now

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow Rita=50x=50(500)=25000[/tex]

[tex]\\ \qquad\quad\sf{:}\twoheadrightarrow Mina=40x=40(500)=20000[/tex]

Answer:

C' (-1,-2)

V' (-2,2)

N' (2,0)

Answered by GAUTHMATH

Answer:

[tex]a = \frac{1}{2} \\ b = - 3 \\ c = - 2[/tex]

Step-by-step explanation:

The explanation is in the picture!

Answer:

3.398

Step-by-step explanation:

log(2500)=log(25)+log(100)=2+2*0.699=3.398

Answer:

No symmetry

Step-by-step explanation:

The shape cannot be folded over any line to be equally matched up to the other side

Answer:

24 people

Step-by-step explanation:

((The numbers are up there, so I am not going to define each variable.))

For starters, there is no overlap between the double facilities groups, except the triple facility users, so:

19 + 9 + 16 - 4 = 40 people

Since there is overlap between single and double groups, you will need to subtract, so:

Gym: 73 - 19 - 16 = 38

Pool: 59 - 19 - 9 = 31

Track: 31 - 9 - 16 = 6

Total for 1 facility: 38 + 31 + 6 - 4 = 71 people

((Minus 4 because the 4 triple facility users overlap the double facility users (problem is in layers: layer 1 minus layer 2, then minus layer 3).))

Next, add the totals:

71 + 40 = 111 people (using facilities)

135 - 111 = 24 people (who didn't use any)

(((I'm not 100% sure on this answer, so if someone could check my work, that would be much appreciated.)))

The unknown sides are 60.81cm and 51.57cm while the unknown angle is 58degrees

4a) Given the following

Opposite side = 38cm (side facing the given angle)

Required

Adjacent and hypotenuse side

According to SOH CAH TOA

[tex]tan \theta = \frac{opp}{hyp}\\tan 32=\frac{38}{hyp}\\hyp=\frac{38}{tan 32}\\hyp=\frac{38}{0.6249}\\hyp= 60.81cm[/tex]

Next is to get the adjacent

[tex]Cos 32=\frac{adj}{60.81}\\adj=60.81cos32\\adj=60.81(0.8480)\\adj= 51.57cm[/tex]

Next is to get the missing angle

Since sum of angle in the triangle is 180degrees

32 + 90 + x = 180

122 + x = 180

x = 180 - 122

x = 58degrees

The unknown sides are 60.81cm and 51.57cm while the unknown angle is 58degrees.

Learn more about the properties of triangles here: https://brainly.com/question/16908652

Answer:

Step-by-step explanation:

I graphed this on my calculator to get the region of feasibility. You should learn how to use your calculator to help you do things like this. You should know by now how to graph by hand, which is tedious, so now it's time to use your calculator to sweat the small stuff and learn to do some useful things.

When you graph this inequality on your calculator, you can see the points of intersection which in turn translate to the vertices of the feasible region. They are located at:

(-14, -6), (-9, -11), (6, 4)

You could then use those vertices to maximize the profit equation or production equation or whatever it is this system pertains to.

Answer:

0.48 is ......

[tex]0.48 < 2.1[/tex]

Option C

Corresponding angles along parrellel lines are conguerent.

Answered by Gauthmath must click thanks and mark brainliest

Answer:

y = 4/3x+2/3

Step-by-step explanation:

the 2 coordinates provided are: (4,6) and (-5,-6)

y=mx+c

m= (y1-y2)/(x1-x2) = (-6-6)/(-5-4) = 4/3

sub x = 4, y = 6

6 = 4/3 * 4 + c

c = 2/3

Answer:

y = 4/3x+2/3

Step-by-step explanation:

Pick two points on the line to find the slope

(-5,-6) and (4,6)

m = (y2-y1)/(x2-x1)

m = ( 6 - -6)/( 4 - -5)

   = ( 6+6)/(4+5)

   = 12/9

  = 4/3

The slope intercept form of a line is y =mx+b where m is the slope and b is the y intercept

y = 4/3x+b

Substitute a point into the equation

6 = 4/3(4)+b

6 = 16/3+b

Subtract 16/3 from each side

18/3 - 16/3 =b

2/3 = b

y = 4/3x+2/3  

Answer: 16x^2 + 24x + 9

Step-by-step explanation:

Simplified version: (4x+3)^2

Answer:

363

Step-by-step explanation:

Formula for area of a circle

A = πr^2

Where r = radius

The circle has a given radius of 11

To find the area of the circle we simply substitute r in the formula with the value of the radius (11)

( Also note that the question says to use 3 for π )

A = πr^2

π = 3

r = 11

Substitute values in formula

A = (3)(11)^2

11^2 = 121

A = 121(3)

121(3) = 363

A = 363

The type of transformation in this situation is refelction on the x-axis.

It cannot possibly be translated or rotated around the origin.

Hope this helps!

Have a wonderful day!

Answer:

the decimal number 6.45 written in scientific notation is 6.45 × 100 and it has 3 significant figures.

Step-by-step explanation:

Answer:

I think the correct answer is F. y = 6x

We will see that the line equation is y = 6*x

A general linear equation is written as:

y = a*x + b

Where a is the slope and b is the y-intercept.

If we know that the line passes through two points (x₁, y₁) and (x₂, y₂) then we can write the slope as:

[tex]a = \frac{y_2 - y_1}{x_2 - x_1}[/tex]

In this case, the line passes through the points: (0, 0) and (-1/2, -3)

Then the slope is:

[tex]a = \frac{0 - (-3)}{0 - (-1/2)} = 6[/tex]

Then the line is of the form y = 6*x + b

To find the value of b, we use the fact that the line passes through the point (0, 0), then we have:

0 = 6*0 + b

0 = b

We can conclude that the line is y = 6*x

If you want to learn more about linear equations, you can read:

https://brainly.com/question/4074386

Answer:

(3x + 1)(x + 6)

3x^2 + 19x + 6

3x^2 + 18x + x + 6

3x^2 + 18x + x + 6

3x(x + 6) + x + 6

3x(x + 6) + x + 6

(3x + 1)(x + 6)

Haven't done this in a pretty long time so I might be wrong

Answer:

-10k×2+7

= -20k+7

Step-by-step explanation:

is the answer

ill add you if you follow my t i k t o k(:

Answer:

56 cm^2

Step-by-step explanation:

The area of a triangle is

A = 1/2 bh where b is the base and h is the height

A = 1/2 (14) (8)

A = 56 cm^2

Answer:

[tex]( - 11.7)[/tex]

Range 18

Step-by-step explanation:

Twice the amplitude.

Step-by-step explanation:

x/3 = 5/6

cross multiply

6x=15

x=2.5

Answer:

x=5/2

Step-by-step explanation:

Answer:

(√366 - 3)/24

Step-by-step explanation:

Given the following:

cos∝ = √3/8 and sinβ = √3/3

Sin(∝-β) = sin∝cosβ - cos∝sinβ

Get sin∝

Since cos∝ = √3/8

adj = √3

hyp = 8

opp = √8² - (√3)²

opp = √64 - 3

opp = √61

Recall that sin∝ = opp/hyp  

sin∝ = √61/8

Get cosβ

Since sinβ =  √3/3

opp = √3

hyp = 3

adj =√3² - (√3)²

adj = √9-3

adj = √6

Recall that cosβ = adj/hyp

cosβ = √6/3

Substitute the gotten values into the formula

Sin(∝-β) = sin∝cosβ - cos∝sinβ

Sin(∝-β) = ( √61/8)(√6/3)- (√3/8)(√3/3)

Sin(∝-β) = √366/24 - √9/24

Sin(∝-β) = (√366 - 3)/24

Answer:

Step-by-step explanation:

a1=219

d=a2-a1=226-219=7

2018=219+7n-7

1806=7n

n=258

S258=[(219+2018)/2*258

S258=288573.

Step-by-step explanation:

you're just going to switch x and y and then solve for y

Answer:

Hello,

Step-by-step explanation:

The problem is that the inverse function is not a function but

an union of 2 functions.

[tex]y=(x+6)^2+1\ is\ the\ orignal\ function\ f(x).\\\\Inverting\ x\ and\ y\ gives: \ x=(y+6)^2+1\\\\(y+6)^2=x-1 \ nota\ bene\ x-1\geq 0 \\(y+6)^2-(x-1)=0\\\\((y+6)-\sqrt{x-1} ) * ((y+6)+\sqrt{x-1}) =0\\\\y=-6+\sqrt{x-1}-6\ or\ y=-6-\sqrt{x-1}\\[/tex]

For the fun

,[tex]f_1(x)= (x+6)^2+1=0\ if\ x<6\\f_1^{-1}(x)=-6-\sqrt{x-1} =0\ if\ x<6\\\\f_2(x)=(x+6)^2+1=0\ if\ x \geq 6\\\\f_2^{-1}(x)=-6+\sqrt{x-1} =0\ if\ x\geq 6\\[/tex]

Answer:  [tex]\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right)[/tex]

We have something in the form log(x/y) where x = q^2*sqrt(m) and y = n^3. The log is base 2.

===========================================================

Explanation:

It seems strange how the first two logs you wrote are base 2, but the third one is not. I'll assume that you meant to say it's also base 2. Because base 2 is fundamental to computing, logs of this nature are often referred to as binary logarithms.

I'm going to use these three log rules, which apply to any base.

From there, we can then say the following:

[tex]\frac{1}{2}\log_{2}\left(m\right)-3\log_{2}\left(n\right)+2\log_{2}\left(q\right)\\\\\log_{2}\left(m^{1/2}\right)-\log_{2}\left(n^3\right)+\log_{2}\left(q^2\right) \ \text{ .... use log rule 3}\\\\\log_{2}\left(\sqrt{m}\right)+\log_{2}\left(q^2\right)-\log_{2}\left(n^3\right)\\\\\log_{2}\left(\sqrt{m}*q^2\right)-\log_{2}\left(n^3\right) \ \text{ .... use log rule 1}\\\\\log_{2}\left(\frac{q^2\sqrt{m}}{n^3}\right) \ \text{ .... use log rule 2}[/tex]